mySql query giving result in wrong order - mysql

Question

I am using this mysql query to fetch data from DB
SELECT DISTINCT CONCAT( streetObj.street_type, ' ',streetObj.street_name, ', ', neighborhoodObj.name , ', ', cityObj.name, ', ', stateObj.abbreviation ) namet
FROM street streetObj
LEFT
JOIN cep cepObj1
ON cepObj1.street_id = streetObj.street_id
LEFT
JOIN neighborhood neighborhoodObj
ON neighborhoodObj.neighborhood_id = cepObj1.start_neighborhood_id
LEFT
JOIN city cityObj
ON streetObj.city_id = cityObj.city_id
LEFT
JOIN state stateObj
ON stateObj.state_id = cityObj.state_id
WHERE CONCAT(streetObj.street_type,streetObj.street_name) LIKE '%rua%'
AND CONCAT(streetObj.street_type,streetObj.street_name) LIKE '%Gomes%'
AND CONCAT(streetObj.street_type,streetObj.street_name) LIKE '%de%'
AND CONCAT(streetObj.street_type,streetObj.street_name) like '%Ca%'
AND cityObj.city_id = '9668'
ORDER
BY namet ASC
LIMIT 10;
This query is executed when I type
rua Gomes de Ca
And this query result is this
Rua Baltazar Gomes de Alarcão, Jardim Miriam, São ...
Rua Cabo José Gomes de Barros, Conjunto Habitacion...
Rua Cabo Luís Gomes de Quevedo, Parque Novo Mundo,...
Rua Gomes de Carvalho, Vila Olímpia, São Paulo, SP
Rua João Gomes de Mendonça, Jaraguá, São Paulo, SP
Rua João Gomes de Mendonça, Jardim Taipas, São Pau...
Rua Pedro Gomes de Camargo, Vila Rio Branco, São P...
So as you can see i want those results on top which find exact match, But its not working.
In this query i want
Rua Gomes de Carvalho, Vila Olímpia, São Paulo, SP
on top position.

Answer 1

You need to rank the results by the strength of the match, and sort by that. You will have to define the sort yourself. For example:
select ..
from...
ORDER BY
case
when text like "%all my search phrase%" then 1
when text like "%all my%" then 2
when text like "%search phrase%" then 2
when text like "%phrase%" then 3
else 1000 end
DESCENDING
or
ORDER BY
case when text like "%word%" then 1 else 0 end
+
case when text like "%second_word%" then 1 else 0 end
+
.....
DESC
Specifically for your example
select namet from
(select 'Rua Baltazar Gomes de Alarcão, Jardim Miriam, São ...' as namet
union all select 'Rua Cabo José Gomes de Barros, Conjunto Habitacion...'
union all select 'Rua Cabo Luís Gomes de Quevedo, Parque Novo Mundo,...'
union all select 'Rua Gomes de Carvalho, Vila Olímpia, São Paulo, SP'
union all select 'Rua João Gomes de Mendonça, Jaraguá, São Paulo, SP'
union all select 'Rua João Gomes de Mendonça, Jardim Taipas, São Pau...'
union all select 'Rua Pedro Gomes de Camargo, Vila Rio Branco, São P...')tbl
order by
case when namet like "%rua gomes de ca%" then 100 else 0 end+ #high score for full match
case when namet like "%rua%" then 1 else 0 end+ #lower score for partial matches
case when namet like "%Gomes%" then 1 else 0 end+
case when namet like "%de%" then 1 else 0 end+
case when namet like "%ca%" then 1 else 0 end desc LIMIT 10
Although you probably want to write something to split your search phrase into words, search for every word, and rank on number of words matched. You could also look into soundex or levenstein distance for ranking similarity. Doing it in sql though is harder than doing it programatically.