MySQL - Unable to create and ENUM column - mysql

On MySQL 5.1.73 I've created a table with an Enum column as following:
create table IF NOT EXISTS rollover_profile
(
rollover_profile_id BIGINT(20) PRIMARY KEY NOT NULL AUTO_INCREMENT,
max_period INT(10) NOT NULL,
percentage INT(10) NOT NULL,
type VARCHAR(10) NOT NULL,
description VARCHAR(1024) NOT NULL,
logical_delete_yn ENUM('Y','N') NOT NULL DEFAULT 'N',
published_yn ENUM('Y','N') NOT NULL DEFAULT 'N'
);
but when I inspect the table logical_delete_yn and published_yn are defined as ENUM('','')
I tried on another MySQL server (ver 5.0.77) and there seems to be fine.
Is it some MySQL option wrong?

Turns out the charset on the new server had been changed to UCS2. Changing it to UTF8 solved the issue.
The weird thing is that changing the query to
create table IF NOT EXISTS rollover_profile
(
rollover_profile_id BIGINT(20) PRIMARY KEY NOT NULL AUTO_INCREMENT,
max_period INT(10) NOT NULL,
percentage INT(10) NOT NULL,
type VARCHAR(10) NOT NULL,
description VARCHAR(1024) NOT NULL,
logical_delete_yn ENUM('Y','N') NOT NULL DEFAULT 'N',
published_yn ENUM('Y','N') NOT NULL DEFAULT 'N'
);
or to anything where the two ENUMs don't have the same values works fine on UCS2.

Related

MySQL error #1064 on create table with DOUBLE column

I'm struggling to code this table as it's giving me a #1064 error, and this corresponds to a few potential issues. If someone could point out where I've made a mistake that would be great.
Here is an image of the code I've typed, and the error I've received:
The code:
CREATE TABLE `RENRMyLUoX`.`movie`(
`mID` INT(20) NOT NULL,
`title` VARCHAR(50) NULL DEFAULT NULL,
`relYear` YEAR(4) NULL DEFAULT NULL,
`category` VARCHAR(50) NULL DEFAULT NULL,
`runTime` INT(20) NOT NULL,
`studioName` VARCHAR(50) NULL DEFAULT NULL,
`description` VARCHAR(50) NULL DEFAULT NULL,
`rating` DOUBLE(20) NULL DEFAULT NULL,
PRIMARY KEY(`mID`(20))
) ENGINE = InnoDB CHARSET = latin1 COLLATE latin1_bin;
The DOUBLE datatype should be specified as either DOUBLE or DOUBLE(m, d). I don't understand what (20) is supposed to do... you can simply omit it:
rating DOUBLE NULL DEFAULT NULL,
TRY BELOW CODE
CREATE TABLE RENRMyLUoX.movie(
mID INT(20) NOT NULL,
title VARCHAR(50) NULL DEFAULT NULL,
relYear YEAR(4) NULL DEFAULT NULL,
category VARCHAR(50) NULL DEFAULT NULL,
runTime INT(20) NOT NULL,
studioName VARCHAR(50) NULL DEFAULT NULL,
description VARCHAR(50) NULL DEFAULT NULL,
rating DOUBLE(20) NULL DEFAULT NULL)ENGINE = InnoDB CHARSET = latin1 COLLATE latin1_bin;
ALTER TABLE RENRMyLUoX.movie
ADD PRIMARY KEY (mID)
ALTER TABLE RENRMyLUoX.movie
MODIFY mID int(20) NOT NULL AUTO_INCREMENT;
COMMIT;

Createdatetime columns is populating as 0000-00-00

I have created one table and inserting values in the table from a csv file using a python code .The createdatetime and updatedatetime columns are set to default CURRENT_TIMESTAMP.But when I am populating the data updatedatetime is populating the correct value but createdatetime is populating as 0000-00-00 00:00:00.
Here is my table definition:
CREATE TABLE `fico_details` (
`adf_contact_id` varchar(100) NOT NULL,
`sf_contact_id` varchar(100) DEFAULT NULL,
`Name` varchar(100) NOT NULL,
`BirthDate` date DEFAULT NULL,
`Address1` varchar(100) DEFAULT NULL,
`City` varchar(100) DEFAULT NULL,
`State` varchar(2) DEFAULT NULL,
`Zipcode` varchar(10) DEFAULT NULL,
`SSN` varchar(10) DEFAULT NULL,
`Address2` varchar(100) DEFAULT NULL,
`City2` varchar(100) DEFAULT NULL,
`State2` varchar(2) DEFAULT NULL,
`Zipcode2` varchar(10) DEFAULT NULL,
`Customerinput` varchar(10) DEFAULT NULL,
`AddrDiscrepancyFlg` varchar(10) DEFAULT NULL,
`Permid` varchar(10) DEFAULT NULL,
`score_date` varchar(10) DEFAULT NULL,
`reason_code_1` varchar(10) DEFAULT NULL,
`reason_code_2` varchar(10) DEFAULT NULL,
`reason_code_3` varchar(10) DEFAULT NULL,
`reason_code_4` varchar(10) DEFAULT NULL,
`CreateDateTime` TIMESTAMP not null DEFAULT CURRENT_TIMESTAMP,
`UpdateDateTime` TIMESTAMP not null DEFAULT CURRENT_TIMESTAMP,
`id` bigint(20) unsigned NOT NULL AUTO_INCREMENT,
PRIMARY KEY (`id`),
KEY `SSN` (`SSN`)
) ENGINE=InnoDB AUTO_INCREMENT=876800 DEFAULT CHARSET=utf8;
please help me to solve it.
I am working on same thing these days.
First of all I use timestamp as the datatype as apart from having datetime capabilities, it has MANY usable functions as a string as well as timestamp datatype.
I got the SAME issue as yours, what I did was alter my table was created, I would click on ALTER table using any Db tool (SQLYog in my case) and then Delete the 0000-00-00 00:00:00 value and uncheck the Not NULL check box.
This issue gets resolved EVERYTIME (whenever I create same type of table/columns)after this simple one step.
Hope this helps you too, let me know if anything still bothers you....!!

create table error in mysql. 1071 error

hi all can some one plz help me,
while creating table in mysql i am getting the following error
MySQL error 1071: Specified key was too long; max key length is 767 bytes
my table definition is as follows.
CREATE TABLE oauth_consumer (id char(36) NOT NULL ,
name varchar(255) NULL ,
date_entered datetime NULL ,
date_modified datetime NULL ,
modified_user_id char(36) NULL ,
created_by char(36) NULL ,
description text NULL ,
deleted bool DEFAULT '0' NULL ,
assigned_user_id char(36) NULL ,
c_key varchar(255) NULL ,
c_secret varchar(255) NULL,
PRIMARY KEY (id),
UNIQUE ckey (c_key)
);
No problem in your query. May be you are running old version of MySql. Use new version. If you are using new version try to use following query to create table
CREATE TABLE `oauth_consumer` (
`id` CHAR(36) NOT NULL,
`name` VARCHAR(255) NULL DEFAULT NULL,
`date_entered` DATETIME NULL DEFAULT NULL,
`date_modified` DATETIME NULL DEFAULT NULL,
`modified_user_id` CHAR(36) NULL DEFAULT NULL,
`created_by` CHAR(36) NULL DEFAULT NULL,
`description` TEXT NULL,
`deleted` TINYINT(1) NULL DEFAULT '0',
`assigned_user_id` CHAR(36) NULL DEFAULT NULL,
`c_key` VARCHAR(255) NULL DEFAULT NULL,
`c_secret` VARCHAR(255) NULL DEFAULT NULL,
PRIMARY KEY (`id`),
UNIQUE INDEX `ckey` (`c_key`)
)
COLLATE='latin1_swedish_ci'
ENGINE=InnoDB;
First of all, your database character set is most likely set to utf8, so your 255 characters get blown up to 765 characters; though close, that's not greater than the imposed limit of 767, but it gives an idea of why you're hitting that limit nonetheless.
Regardless, it's not recommended to use such a wide key; you could calculate an md5 or sha1 of the value and use that for the unique key instead (btw, you should use the binary representation of the hash).

why Mysql is giving me error 1280 "Wrong Index"

Can anyone explain why Mysql is giving me error 1280 ("wrong index for 'fk_chart_aid_aid' ") error whend I try to create the "CHART OF ACCOUNTS" table. I'm completly confused here. How can I fix this so I can create the table? The "ACCOUNT" table already exists in the database and has data in it.
Thanks for the help.
MYSQL Server version: 5.1.54
CHART OF ACCOUNTS:
DROP TABLE IF EXISTS `rst`.`acctg_chart_of_accounts` ;
CREATE TABLE IF NOT EXISTS `rst`.`acctg_chart_of_accounts` (
`acctg_chart_of_accounts_id` INT UNSIGNED NOT NULL AUTO_INCREMENT ,
`account_id` INT UNSIGNED NOT NULL ,
`account_nbr` VARCHAR(45) NULL ,
`description` VARCHAR(45) NULL ,
`account_type` INT UNSIGNED NULL ,
`commissionable` TINYINT UNSIGNED NULL ,
`hidden` TINYINT UNSIGNED NULL ,
`deduct_balance_from_owner_check` TINYINT UNSIGNED NULL ,
PRIMARY KEY (`acctg_chart_of_accounts_id`) ,
CONSTRAINT `fk_chart_aid_aid`
FOREIGN KEY (`account_id` )
REFERENCES `rst`.`account` (`account_id` )
ON DELETE CASCADE
ON UPDATE CASCADE)
ENGINE = InnoDB;
CREATE INDEX `fk_chart_aid_aid` ON `rst`.`acctg_chart_of_accounts` (`account_id` ASC) ;
ACCOUNTS TABLE THAT IS BEING REFERENCED:
CREATE TABLE IF NOT EXISTS `account` (
`account_id` int(10) unsigned NOT NULL AUTO_INCREMENT,
`account_status_id` int(10) unsigned NOT NULL,
`company_name` varchar(155) DEFAULT NULL,
`address1` varchar(155) DEFAULT NULL,
`address2` varchar(155) DEFAULT NULL,
`city` varchar(155) DEFAULT NULL,
`state` varchar(155) DEFAULT NULL,
`zip` varchar(45) DEFAULT NULL,
`country` varchar(255) DEFAULT NULL,
`work_phone` varchar(45) DEFAULT NULL,
`mobile_phone` varchar(45) DEFAULT NULL,
`time_zone` varchar(45) DEFAULT NULL,
`subdomain` varchar(155) DEFAULT NULL,
`cname_URL` varchar(255) DEFAULT NULL,
`promotion_code` varchar(45) DEFAULT NULL,
`can_we_contact_you` tinyint(4) DEFAULT NULL COMMENT '0=false, 1=true',
`units_managed_nbr` varchar(10) DEFAULT NULL,
`a_hear_about_us_list_id` tinyint(3) unsigned DEFAULT NULL COMMENT 'populated from dropdown list.',
`receive_special_offers` tinyint(4) DEFAULT NULL,
`receive_announcements` tinyint(4) DEFAULT NULL,
`receive_newsletter` tinyint(4) DEFAULT NULL,
`create_ts` timestamp NULL DEFAULT NULL,
`expires` timestamp NULL DEFAULT NULL,
`storage_capacity` varchar(255) DEFAULT NULL COMMENT '1073741824 = 1GB',
`logo` varchar(455) DEFAULT NULL,
`max_active_connections` int(11) DEFAULT '3',
`_product_id` int(11) DEFAULT NULL,
`report_footer` varchar(455) DEFAULT NULL,
`welcome_dialog` tinyint(4) DEFAULT '1',
`ARB_subscription_id` int(11) DEFAULT NULL,
`trashbin` tinyint(4) NOT NULL DEFAULT '1',
PRIMARY KEY (`account_id`),
KEY `fk_account_account_status_id` (`account_status_id`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8 AUTO_INCREMENT=58 ;
Are you getting the error after the CREATE TABLE statement, or after the subsequent CREATE INDEX?
Looks like you are attempting to name both a FOREIGN KEY constraint and an INDEX fk_chart_aid_aid. Try choosing a different name for either one of them.
Also, in the accounts table, account_id is INT(10). Try also to change the column definition in acctg_chart_of_accounts to:
`account_id` INT(10) UNSIGNED NOT NULL ,
Though, I think that mysql defaults type INT to INT(10) anyway...
I met the same issue; tried manually rename the index to a different name but don't like the idea of 'manually' and neither I don't really understand why we need to generate the index separately. so I decide to generate it within the create statement by unchecking the option of 'generate separate index statement' in 'forwarding engineer', and this fix the issue.

MySQL ucfirst doesn't work

I have this table:
CREATE TABLE IF NOT EXISTS `events` (
`evt_id` int(11) NOT NULL AUTO_INCREMENT,
`evt_name` varchar(50) CHARACTER SET utf8 NOT NULL DEFAULT 'ucfirst',
`evt_description` varchar(100) DEFAULT NULL,
`evt_startdate` date NOT NULL,
`evt_enddate` date DEFAULT NULL,
`evt_starttime` time DEFAULT NULL,
`evt_endtime` time DEFAULT NULL,
`evt_amtpersons` int(11) DEFAULT NULL,
`sts_id` int(11) NOT NULL,
`adr_id` int(11) DEFAULT NULL,
`evt_amtPersonsSubs` tinyint(4) NOT NULL DEFAULT '0',
`evt_photo` varchar(50) DEFAULT NULL,
`sys-mut-dt` timestamp NULL DEFAULT CURRENT_TIMESTAMP,
`sys-mut-user` varchar(20) DEFAULT NULL,
`sys-mut-id` int(11) NOT NULL DEFAULT '0',
PRIMARY KEY (`evt_id`),
KEY `sts_id` (`sts_id`),
KEY `adr_id` (`adr_id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=12 ;
But when I add in data into evt_name my first character is not capitalized. Any ideas?
Further information:
MySQL client version: 5.1.37
I want to do this in the database so that I don't have to do ucfirst with php always.
...what?
If I'm reading this right, it will just set the default value of evt_name to the string ucfirst. Try inserting a blank row and see if I'm reading that right.
If you're really against using ucfirst in PHP, you'll probably have to still call ucfirst every time in the query. Or you could only use ucfirst on display, and not in the database.
ucfirst is a function...you defined it as Default-Value for the cell. Use it like this:
INSERT INTO events SET evt_name = UCFIRST($value)