I have a table with three columns: Item, Quantity, and Date.
The values in the Item column may be duplicates, but the Quantity and Dates will be unique.
For example:
Item - Quantity - Date
Hammer - 3 - 1/12/15
Hammer - 7 - 5/18/15
Hammer - 6 - 8/1/15
Wrench - 8 - 2/24/15
Wrench - 3 - 6/10/15
I am trying to write a query that will only return:
Item - Quantity - Date
Hammer - 6 - 8/1/15
Wrench - 3 - 6/10/15
This is my code:
SELECT DISTINCT stock.stc_st AS Store, stock.art_st AS UPC, articles.descr AS Description, stock.quan_st AS Quantity, articles.rp AS Cost
FROM stock LEFT JOIN articles ON stock.art_st = articles.article
WHERE stock.ym_st =
(SELECT Max(stock.ym_st)
FROM stock t1
WHERE stock.art_st=t1.art_st
GROUP BY t1.art_st)
GROUP BY stock.stc_st, stock.art_st, articles.descr, stock.quan_st, articles.rp, articles.act, articles.stat
HAVING (((stock.stc_st)=[Which Store?]) AND ((articles.act)="Y") AND ((articles.stat)="Y"));
However, my code is returning all items when I only want it to return the items with the max date. If anyone could take a look at this and tell me what I am doing wrong, I would really appreciate it.
========================
Now I'm trying to use this code from the answers below and it's giving me a Syntax Error on JOIN on the Inner Join at tmaxdate.art_st. I'm sure this is something stupid like a parenthesis out of place. Could anyone more familiar with Access's SQL syntax tell me what I'm doing wrong? Thanks!
SELECT DISTINCT stock.stc_st AS Store, stock.art_st AS UPC, articles.descr AS Description, stock.quan_st AS Quantity, articles.rp AS Cost
FROM stock AS t1
INNER JOIN
(
SELECT tmaxdate.art_st, Max(tmaxdate.ym_st) AS MaxOfDate
FROM stock AS tmaxdate
GROUP BY tmaxdate.art_sc
) AS sub
ON (t1.ym_st = sub.MaxOfDate) AND (tmaxdate.art_st = sub.art_st)
LEFT JOIN articles ON stock.art_st = articles.article
GROUP BY stock.stc_st, stock.art_st, articles.descr, stock.quan_st, articles.rp, articles.act, articles.stat
HAVING (((stock.stc_st)=[Which Store?]) AND ((articles.act)="Y") AND ((articles.stat)="Y"));
I couldn't figure out how that sample data is distributed among your tables. So I stored those data in a table named YourTable.
First create a GROUP BY query to show you the most recent Date for each Item:
SELECT t1.Item, Max(t1.Date) AS MaxOfDate
FROM YourTable AS t1
GROUP BY t1.Item
Then you can use that as a subquery which you join back to the main table in order to select only its rows with the matching Item/Date pairs:
SELECT t2.Item, t2.Quantity, t2.Date
FROM
YourTable AS t2
INNER JOIN
(
SELECT t1.Item, Max(t1.Date) AS MaxOfDate
FROM YourTable AS t1
GROUP BY t1.Item
) AS sub
ON (t2.Date = sub.MaxOfDate) AND (t2.Item = sub.Item);
With your sample data in Access 2010, that query returns your requested output.
Since you don't actually have a single YourTable, you will need to adapt that approach for your actual tables, but this strategy should work there, too.
This has not been tested, but it is more along the lines of what you need.
It uses a subquery to find the maximum date for each primary key of stock table (I have assumed this is art_st )
SELECT stock.stc_st AS Store
, stock.art_st AS UPC
, articles.descr AS Description
, stock.quan_st AS Quantity
, articles.rp AS Cost
FROM ( stock
LEFT JOIN articles
ON stock.art_st = articles.article
)
INNER JOIN (SELECT t1.art_st, Max(stock.ym_st) AS t1MaxDate
FROM stock t1
GROUP BY t1.art_st
) AS TabMax
ON ( TabMax.art_st = stock.art_st
AND TabMax.t1MaxDate = stock.ym_st )
GROUP BY stock.stc_st
, stock.art_st
, articles.descr
, stock.quan_st
, articles.rp
, articles.act
, articles.stat
HAVING (((stock.stc_st)=[Which Store?]) AND ((articles.act)="Y") AND ((articles.stat)="Y"));
Related
Let's say we have a person table and survey table. survey is a set of attributes collected from a person at some point in time. Let's say survey has columns address and marriage_status
How do I select all persons whose address or marriage status has changed in the last survey?
Here's how I would write it if MySQL were able to magically interpret my intention:
SELECT *
FROM person
JOIN
(SELECT *
FROM survey
GROUP BY survey.person_id
ORDER BY survey.timestamp DESC
LIMIT 2 EACH) -- of course this part doesn't actually work. Trying to get last 2 records per person
surveys
ON surveys.person_id = person.id
WHERE surveys[0].address != surveys[1].address
OR surveys[0].marriage_status != surveys[1].marriage_status;
OR
SELECT *
FROM person
JOIN
(SELECT MOST RECENT survey FOR EACH person) latest_survey
ON latest_survey.person_id = person.id
JOIN
(SELECT SECOND MOST RECENT survey FOR EACH person) previous_survey
ON previous_survey.person_id = person.id
WHERE latest_survey.address != previous_survey.address
OR latest_survey.marriage_status != previous_survey.marriage_status;
This seems like a relatively straightforward query, but it's driving me crazy. I suspect I have tunnel vision and I'm not approaching this the right way.
EDIT: I am on MySQL v5. Based on the first couple answers, it seems like this might be the time to migrate to v8 (among other reasons)
So here's how I ended up doing it. It's a little long, but I think it's pretty straightforward? This felt amazing to get working.
(Note that underscores are used as prefixes in table aliases to help keep track of subquery depth)
SELECT person.*
FROM person
JOIN (
-- Join full survey data against each 'most recent' survey timestamp
SELECT s1.*
FROM survey s1
JOIN (
-- get most recent timestamp for each person
SELECT _s1.person_id, MAX(_s1.timestamp) timestamp
FROM survey _s1
GROUP BY person_id
) latest_surveys
ON latest_surveys.person_id = s1.person_id and latest_surveys.timestamp = s1.timestamp
) latest
ON latest.person_id = person.id
JOIN (
-- Join full survey data against each 'SECOND most recent' survey timestamp
select s2.*
from survey s2
JOIN (
-- to get SECOND most recent survey timestamp, do similar query, but exclude latest timestamp
SELECT _s2.person_id, MAX(_s2.timestamp) timestamp
FROM survey _s2
JOIN (
-- get most recent timestamp for each person (again)
SELECT __s2.person_id, MAX(__s2.timestamp) timestamp
FROM survey __s2
GROUP BY person_id
) _latest_surveys
-- Note the *NOT* equal here
ON _latest_surveys.person_id = _s2.person_id and _latest_surveys.timestamp != _s2.timestamp
GROUP BY _s2.person_id
) previous_surveys
ON previous_surveys.person_id = s2.person_id and previous_surveys.timestamp = s2.timestamp
) previous
ON previous.person_id = person.id
WHERE latest.address != previous.address
OR latest.marriage_status != previous.marriage_status;
Analytic functions make your question much more tractable. If you are not yet using MySQL 8+, then now would be a good time to upgrade. Assuming you are using MySQL 8+, we can try:
WITH cte AS (
SELECT *, ROW_NUMBER() OVER (PARTITION BY p.id ORDER BY s.timestamp DESC) rn
FROM person p
INNER JOIN survey s ON p.id = s.person_id
)
SELECT id
FROM cte
GROUP BY id
HAVING
MAX(CASE WHEN rn = 1 THEN address END) <> MAX(CASE WHEN rn = 2 THEN address END) OR
MAX(CASE WHEN rn = 1 THEN marriage_status END) <> MAX(CASE WHEN rn = 2 THEN marriage_status END);
The above query uses a pivot trick to isolate the latest, and second latest, addresses and marriage statuses for each person. It retains person id values for those whose latest and second latest addresses or marriage statuses are not identical.
This might be how you can achieve that:
SELECT *
FROM person
JOIN (
SELECT *,
MAX(survey_date) latest_survey,
SUBSTRING_INDEX(SUBSTRING_INDEX(GROUP_CONCAT(survey_date ORDER BY person_id, survey_date ASC),',',-2),',',1) previous_survey,
SUBSTRING_INDEX(GROUP_CONCAT(address ORDER BY person_id, survey_date ASC),',',-1) curadd,
SUBSTRING_INDEX(SUBSTRING_INDEX(GROUP_CONCAT(address ORDER BY person_id, survey_date ASC),',',-2),',',1) prevadd,
SUBSTRING_INDEX(GROUP_CONCAT(marriage_status ORDER BY person_id, survey_date ASC),',',-1) curms,
SUBSTRING_INDEX(SUBSTRING_INDEX(GROUP_CONCAT(marriage_status ORDER BY person_id, survey_date ASC),',',-2),',',1) prevms
FROM survey GROUP BY person_id
HAVING curadd != prevadd OR curms != prevms) A
ON person.id=A.person_id;
Using GROUP_CONCAT and SUBSTRING_INDEX to combine the data value then separate it again and using those to compare at the end. I know there are a bunch of ways to achieve without all these, like your second example is something that I think can be done but when I think about it, it's going to be a very long query. This query however, since you're not using MySQL 8+ is much shorter but the performance of this query is a concern especially on a large table.
It is not given, but I hope you have at least MySQL 8 or similar to have ability to use Common Table Expression. It can simplify the complex query.
The trick part is getting survey records #1 and #2 for each user. I will do it this way: see cte1 and cte2 definition
WITH
cte1 AS (
SELECT MAX(x1.id) AS id, x1.person_id
FROM survey x1
GROUP BY x1.person_id),
cte2 AS (
SELECT MAX(x2.id) AS id, x2.person_id
FROM survey x2
JOIN cte1 ON cte1.person_id = x2.person_id
AND cte1.id > x2.id
GROUP BY x2.person_id)
SELECT
p.*,
s1.address, s2.address address2,
s1.marriage_status, s2.marriage_status marriage_status2
FROM person AS p
JOIN (
cte1 JOIN survey s1 ON s1.id = cte1.id
) ON cte1.person_id = p.id
JOIN (
cte2 JOIN survey s2 ON s2.id = cte2.id
) ON cte2.person_id = p.id
WHERE
(s1.address <> s2.address)
OR (s1.marriage_status <> s2.marriage_status)
https://www.db-fiddle.com/f/hLwdHiZin4MkdUZ4aBz67H/2
Update: Thanks to Ian, I replaced MIN to MAX to get recent records
I am trying to return the price of the most recent record grouped by ItemNum and FeeSched, Customer can be eliminated. I am having trouble understanding how I can do that reasonably.
The issue is that I am joining about 5 tables containing hundreds of thousands of rows to end up with this result set. The initial query takes about a minute to run, and there has been some trouble with timeout errors in the past. Since this will run on a client's workstation, it may run even slower, and I have no access to modify server settings to increase memory / timeouts.
Here is my data:
Customer Price ItemNum FeeSched Date
5 70.75 01202 12 12-06-2017
5 70.80 01202 12 06-07-2016
5 70.80 01202 12 07-21-2017
5 70.80 01202 12 10-26-2016
5 82.63 02144 61 12-06-2017
5 84.46 02144 61 06-07-2016
5 84.46 02144 61 07-21-2017
5 84.46 02144 61 10-26-2016
I don't have access to create temporary tables, or views and there is no such thing as a #variable in C-tree, but in most ways it acts like MySql. I wanted to use something like GROUP BY ItemNum, FeeSched and select MAX(Date). The issue is that unless I put Price into the GROUP BY I get an error.
I could run the query again only selecting ItemNum, FeeSched, Date and then doing an INNER JOIN, but with the query taking a minute to run each time, it seems there is a better way that maybe I don't know.
Here is my query I am running, it isn't really that complicated of a query other than the amount of data it is processing. Final results are about 50,000 rows. I can't share much about the database structure as it is covered under an NDA.
SELECT DISTINCT
CustomerNum,
paid as Price,
ItemNum,
n.pdate as newest
from admin.fullproclog as f
INNER JOIN (
SELECT
id,
itemId,
MAX(TO_CHAR(pdate, 'MM-DD-YYYY')) as pdate
from admin.fullproclog
WHERE pdate > timestampadd(sql_tsi_year, -3, NOW())
group by id, itemId
) as n ON n.id = f.id AND n.itemId = f.itemId AND n.pdate = f.pdate
LEFT join (SELECT itemId AS linkid, ItemNum FROM admin.itemlist) AS codes ON codes.linkid = f.itemId AND ItemNum >0
INNER join (SELECT DISTINCT parent_id,
MAX(ins1.feesched) as CustomerNum
FROM admin.customers AS p
left join admin.feeschedule AS ins1
ON ins1.feescheduleid = p.primfeescheduleid
left join admin.group AS c1
ON c1.insid = ins1.feesched
WHERE status =1
GROUP BY parent_id)
AS ip ON ip.parent_id = f.parent_id
WHERE CustomerNum >0 AND ItemNum >0
UNION ALL
SELECT DISTINCT
CustomerNum,
secpaid as Price,
ItemNum,
n.pdate as newest
from admin.fullproclog as f
INNER JOIN (
SELECT
id,
itemId,
MAX(TO_CHAR(pdate, 'MM-DD-YYYY')) as pdate
from admin.fullproclog
WHERE pdate > timestampadd(sql_tsi_year, -3, NOW())
group by id, itemId
) as n ON n.id = f.id AND n.itemId = f.itemId AND n.pdate = f.pdate
LEFT join (SELECT itemId AS linkid, ItemNum FROM admin.itemlist) AS codes ON codes.linkid = f.itemId AND ItemNum >0
INNER join (SELECT DISTINCT parent_id,
MAX(ins1.feesched) as CustomerNum
FROM admin.customers AS p
left join admin.feeschedule AS ins1
ON ins1.feescheduleid = p.secfeescheduleid
left join admin.group AS c1
ON c1.insid = ins1.feesched
WHERE status =1
GROUP BY parent_id)
AS ip ON ip.parent_id = f.parent_id
WHERE CustomerNum >0 AND ItemNum >0
I feel it quite simple when I'd read the first three paragraphs, but I get a little confused when I've read the whole question.
Whatever you have done to get the data posted above, once you've got the data like that it's easy to retrive "the most recent record grouped by ItemNum and FeeSched".
How to:
Firstly, sort the whole result set by Date DESC.
Secondly, select fields you need from the sorted result set and group by ItemNum, FeeSched without any aggregation methods.
So, the query might be something like this:
SELECT t.Price, t.ItemNum, t.FeeSched, t.Date
FROM (SELECT * FROM table ORDER BY Date DESC) AS t
GROUP BY t.ItemNum, t.FeeSched;
How it works:
When your data is grouped and you select rows without aggregation methods, it will only return you the first row of each group. As you have sorted all rows before grouping, so the first row would exactly be "the most recent record".
Contact me if you got any problems or errors with this approach.
You can also try like this:
Select Price, ItemNum, FeeSched, Date from table where Date IN (Select MAX(Date) from table group by ItemNum, FeeSched,Customer);
Internal sql query return maximum date group by ItemNum and FeeSched and IN statement fetch only the records with maximum date.
I would like to know how I can write a SQL Script so a within a group of individuals initially selected:
SELECT [RECORDS].[CONSTITUENT_ID]
,[RECORDS].[FIRST_NAME]
,[RECORDS].[LAST_NAME]
,[DATEADDED]
,[DTE]
,[Amount]
,[REF]
,[TYPE]
FROM [re7].[dbo].[GIFT]
INNER JOIN [re7].[dbo].[RECORDS]
ON GIFT.CONSTIT_ID LIKE RECORDS.ID
WHERE ([DTE] BETWEEN '2/7/2015' AND '2/8/2015')
ORDER BY [DATEADDED] DESC
select only individuals who are "First Time Donors" (or someone who only has one gift in [re7].[dbo].[GIFT].
[RECORDS] is a table of all the constituents.
[GIFT] is a table of all recorded Gifts.
The output of the above Query, is just a table with:
CONSTITUENT_ID, FIRST_NAME, LAST_NAME, DATEADDED, DTE, Amount, REF, TYPE
I pretty much want to see the same output format, but I would like the query to select only CONSTITUENT_ID who only have 1 GIFT (by their Record ID) in [re7].[dbo].[GIFT].
I apologize for the lack of data to show. I wish I could describe better....
SELECT [RECORDS].[CONSTITUENT_ID]
,[RECORDS].[FIRST_NAME]
,[RECORDS].[LAST_NAME]
,[DATEADDED]
,[DTE]
,[Amount]
,[REF]
,[TYPE]
FROM [re7].[dbo].[GIFT]
INNER JOIN [re7].[dbo].[RECORDS]
ON GIFT.CONSTIT_ID LIKE RECORDS.ID
WHERE ([DTE] BETWEEN '2/7/2015' AND '2/8/2015')
AND GIFT.CONSTIT_ID IN (
SELECT CONSTIT_ID FROM re7.dbo.Gift GROUP BY CONSTIT_ID HAVING COUNT(*) = 1
) /* another option is to add a subquery to the query you already had */
ORDER BY [DATEADDED] DESC
This solution simply selects all the constituents who have made only one donation and then joins to that, thereby limiting the result set.
SELECT
r.[CONSTITUENT_ID]
,r.[FIRST_NAME]
,r.[LAST_NAME]
,[DATEADDED]
,[DTE]
,[Amount]
,[REF]
,[TYPE]
FROM
(select [CONSTIT_ID] from [re7].[dbo].[GIFT] group by [CONSTIT_ID] having count([CONSTIT_ID]) = 1) g1
inner join [re7].[dbo].[GIFT] g
on g.[CONSTIT_ID] = g1.[CONSTIT_ID]
INNER JOIN [re7].[dbo].[RECORDS] r
ON g.CONSTIT_ID LIKE r.RECORDS.ID
WHERE ([DTE] BETWEEN '2/7/2015' AND '2/8/2015')
ORDER BY [DATEADDED] DESC
I have this MySQL query to get the total amount of only the first invoice for each client on a given month:
SELECT SUM(InvoiceProductTotal)
FROM tblinvoiceproduct
WHERE InvoiceID IN (
SELECT MIN(tblinvoice.InvoiceID) AS InvoiceID
FROM tblinvoice
WHERE tblinvoice.ClientID IN (
SELECT tblclient.ClientID
FROM tblclient
LEFT JOIN tblenquiry ON tblclient.EnquiryID = tblenquiry.EnquiryID
WHERE NOT tblclient.EnquiryID IS NULL
AND YEAR(EnquiryDate) = 2014
AND MONTH(EnquiryDate) = 9
)
GROUP BY tblinvoice.ClientID
);
When I run it, it seems to loop forever. If I remove the first part it gives me the list of invoices instantly. Am sure it is a small syntax detail but haven't been able to figure out what the problem is after nearly one hour trying to fix it.
Your assistance is appreciated.
This query can probably be done in a better way without all the sub queries as well, just I'm not so experienced with sub queries. :)
Solution was given but I should have included the full query rather than just the part I was having trouble with. The full query is:
SELECT AdvertisingID, AdvertisingTitle, AdvertisingYear,
AdvertisingMonth, AdvertisingTotal, AdvertisingVisitors,
IFNULL(
(SELECT SUM(InvoiceProductTotal)
FROM tblinvoiceproduct
JOIN
(SELECT MIN(tblinvoice.InvoiceID) AS InvoiceID
FROM tblinvoice
JOIN
(SELECT DISTINCT tblclient.ClientID
FROM tblclient
JOIN tblenquiry ON tblclient.EnquiryID = tblenquiry.EnquiryID
WHERE YEAR(tblenquiry.EnquiryDate)=tbladvertising.AdvertisingYear
AND MONTH(tblenquiry.EnquiryDate)=tbladvertising.AdvertisingMonth)
AS inq
ON tblinvoice.ClientID = inq.ClientID
GROUP BY tblinvoice.ClientID) AS inq2
ON tblinvoiceproduct.InvoiceID = inq2.InvoiceID)
, 0)
FROM tbladvertising
ORDER BY AdvertisingYear DESC, AdvertisingMonth DESC, AdvertisingTitle;
Now the problem is that the column with the sub query has no access to "tbladvertising.AdvertisingYear" or "tbladvertising.AdvertisingMonth"
A commenter mentioned that it's hard to understand what you're trying to do here. I agree. But I will take the risk of trying to puzzle it out.
As usual with this sort of query, it's helpful to take advantage of the structured part of structured query language, and try to build this up piece by piece. That's the secret to creating complex queries that actually do what you want them to do.
Your innermost query is this:
SELECT tblclient.ClientID
FROM tblclient
LEFT JOIN tblenquiry ON tblclient.EnquiryID = tblenquiry.EnquiryID
WHERE NOT tblclient.EnquiryID IS NULL
AND YEAR(EnquiryDate) = 2014
AND MONTH(EnquiryDate) = 9
It is saying, "give me the list of ClientID values which have enquiries in September 2014. There's a more efficient way to do this:
SELECT DISTINCT tblclient.ClientID
FROM tblclient
JOIN tblenquiry ON tblclient.EnquiryID = tblenquiry.EnquiryID
WHERE tblenquiry.EnquiryDate >= '2014-09-01'
AND tblenquiry.EnquiryDate < '2014-09-01' + INTERVAL 1 MONTH
Two changes here: First, the NOT ... IS NULL search is unnecessary because if the item you're searching on is null, there's no way for your EnquiryDate to be valid. So we just change the LEFT JOIN to an ordinary inner JOIN and get rid of the otherwise expensive NULL scan.
Second, we recast the date matching as a range scan, so it can use an index on tbl.EnquiryDate.
Cool.
Next, we have this query level.
SELECT MIN(tblinvoice.InvoiceID) AS InvoiceID
FROM tblinvoice
WHERE tblinvoice.ClientID IN (
/* that list of Client IDs from the innermost query */
)
GROUP BY tblinvoice.ClientID
That is pretty straightforward. But MySQL isn't too swift with IN () clauses, so let's recast it in the form of a JOIN as follows:
SELECT MIN(tblinvoice.InvoiceID) AS InvoiceID
FROM tblinvoice
JOIN (
/* that list of Client IDs from the innermost query */
) AS inq ON tblinvoice.ClientID = inq.ClientID
GROUP BY tblinvoice.ClientID
This gets us the list of invoice IDs which were the subject of the first enquiry of the month on behalf of each distinct ClientID. (It's hard for me to figure out the business meaning of this, but I don't understand your business.)
Finally, we come to your outermost query. We can also recast that as a JOIN, like so.
SELECT SUM(InvoiceProductTotal)
FROM tblinvoiceproduct
JOIN (
/* that list of first-in-month invoices */
) AS inq2 ON tblinvoiceproduct.InvoiceID = inq2.InvoiceID
So, this all expands to:
SELECT SUM(InvoiceProductTotal)
FROM tblinvoiceproduct
JOIN (
SELECT MIN(tblinvoice.InvoiceID) AS InvoiceID
FROM tblinvoice
JOIN (
SELECT DISTINCT tblclient.ClientID
FROM tblclient
JOIN tblenquiry ON tblclient.EnquiryID = tblenquiry.EnquiryID
WHERE tblenquiry.EnquiryDate >= '2014-09-01'
AND tblenquiry.EnquiryDate < '2014-09-01' + INTERVAL 1 MONTH
) AS inq ON tblinvoice.ClientID = inq.ClientID
GROUP BY tblinvoice.ClientID
) AS inq2 ON tblinvoiceproduct.InvoiceID = inq2.InvoiceID
That should do the trick for you. In summary, the big optimizing changes are
using a date range scan.
eliminating the NOT ... IS NULL criterion.
recasting your IN clauses as JOIN clauses.
The next step will be to create useful indexes. A compound index (EnquiryDate, EnquiryID) on your tblenquiry is very likely to help a lot. But to be sure you'll need to do some EXPLAIN analysis.
What if you modify your above posted query, to replace the subquery with JOIN (INNER JOIN) like below. Give it a try.
SELECT SUM(InvoiceProductTotal)
FROM tblinvoiceproduct
JOIN
(
SELECT MIN(ti.InvoiceID) as MinInvoice
FROM tblinvoice ti
JOIN
(
SELECT tblclient.ClientID
FROM tblclient
LEFT JOIN tblenquiry
ON tblclient.EnquiryID = tblenquiry.EnquiryID
WHERE NOT tblclient.EnquiryID IS NULL
AND YEAR(EnquiryDate) = 2014
AND MONTH(EnquiryDate) = 9
) tab
on ti.ClientID = tab.ClientID
GROUP BY ti.ClientID
) tab1
on tblinvoiceproduct.InvoiceID = tab1.MinInvoice
I'm hoping someone fluent in MySQL will be able to assist me with this. I'm trying to do a select on a select on a select, but the query doesn't seem to want to complete. Any help would be greatly appreciated.
SELECT
product as pid,
leg_name as name,
dimensions as dims
FROM
pmaint
WHERE
product in (
SELECT product
FROM qb_export_items_attributes
WHERE attribute_name = 'Z'
AND product in (
SELECT product
FROM pmainT
WHERE type_ID = (
SELECT ID
FROM type
WHERE SOFTCARTCATEGORY = 'End Table Legs'
)
)
AND attribute_value <= 3.5
)
Try to use INNER JOINs instead of IN subqueries
UPD: I've edited this query according you comment. the first JOIN subquery output all product where both attributes exists and true.
SELECT
pmaint.product as pid,
pmaint.leg_name as name,
pmaint.dimensions as dims
FROM
pmaint
JOIN (select product from qb_export_items_attributes
where ((attribute_name = 'Z') and (attribute_value <= 3.5))
OR
((attribute_name = 'top_square') and (attribute_value >= 4))
GROUP BY product HAVING COUNT(*)=2
)
t1 on (pmaint.product=t1.product )
JOIN type on (pmaint.type_ID=type.ID)
WHERE
type.SOFTCARTCATEGORY = 'End Table Legs'