I need to understand how mysql interprets or executes such a subquery:
SELECT SUM(tp),SUM(ep),SUM(mp) FROM
(
SELECT Avg(case date_format(PS_DATE,'%Y') when '2005' then nvl(tp,0) else 0 end) tp,
Avg(case date_format(PS_DATE,'%Y') when '2005' then nvl(ep,0) else 0 end) ep,
Avg(case date_format(PS_DATE,'%Y') when '2005' then nvl(mp,0) else 0 end) mp
FROM M_DAILY
WHERE PS_DATE >= date ('2005-01-01') and PS_DATE <= date ('2005-12-31');
) As T
Can someone interpret how such a query is interpreted (in words)please!
For the year 2005, it finds the SUM of average values of the columns tp, ep and mp. While doing this null values are considered as 0. As the dates are filtered for year 2005, the above code can be simplified as
SELECT SUM(tp),SUM(ep),SUM(mp) FROM
(
SELECT Avg(nvl(tp,0)) tp,
Avg(nvl(ep,0)) ep,
Avg(nvl(mp,0)) mp
FROM M_DAILY
WHERE PS_DATE >= date ('2005-01-01') and PS_DATE <= date ('2005-12-31');
) As T
Related
Currently I have 2 tables, a listing table and a logs table. With the following query I'm trying to get the listings of a product on a particular day, and it returns the right output.
with X as (
select
l.*,
(select status_from from logs where logs.refno = l.refno and logs.logtime >= '2021-10-01' order by logs.logtime limit 1) logstat
from listings l
where l.added_date < '2021-10-01'
)
, Y as (select X.*, ifnull(X.logstat, X.status) stat from X)
SELECT
status.text,
COUNT(Y.id) AS c
from status
left join Y on Y.stat = status.code
group by status.code, status.text;
This gives an output like this:
Here I've filtered the query by 1 date which in this case is 2021-10-01. Now I have 2 input forms where the user can select a from date and a to date. So I want to be able to get all the data between the date range provided. So basically if I choose a date between 2021-10-01 and 2021-10-02, it should show everything on and between that date. The output should look like:
Date
Publish
Action
Let
Sold
Draft
2021-10-01
0
3
0
1
1
2021-10-02
0
2
0
1
2
Dbfiddle: https://dbfiddle.uk/?rdbms=mysql_8.0&fiddle=5e0b8d484a41ac9104d0fb002e7f9a3c
I've formatted the table to show the entries in a row wise manner with the following query:
with X as (
select l.*,
(select status_from from logs where logs.refno = l.refno and logs.logtime >= '2021-10-01' order by logs.logtime limit 1) logstat
from listings l
where l.added_date < '2021-10-01'
)
, Y as (select X.*, ifnull(X.logstat, X.status) stat20211001 from X)
SELECT
sum(case when status.text= 'Action' and Y.id is not null then 1 else 0 end) as `Action`,
sum(case when status.text= 'Draft' and Y.id is not null then 1 else 0 end) as `Draft`,
sum(case when status.text= 'Let' and Y.id is not null then 1 else 0 end) as `Let`,
sum(case when status.text= 'Sold' and Y.id is not null then 1 else 0 end) as `Sold`,
sum(case when status.text= 'Publish' and Y.id is not null then 1 else 0 end) as `Publish`
from status
left join Y on Y.stat20211001 = status.code
Output for this statement:
If you open my dbfiddle and enter date as 2021-10-01 it gives correct output and if you enter 2021-10-02 it shows correct output. Now I just want a way to show these both together. Also if it is suppose 2021-10-01 and 2021-10-05, it should show everything in middle too which means 2021-10-01, 2021-10-02, 2021-10-03, 2021-10-04 and 2021-10-05
Your listings.added_date column has the DATETIME data type. Therefore, to select a date range of 2021-10-01 to 2021-10-02 you need to do this.
WHERE added_date >= '2021-10-01'
AND added_date < '2021-10-02' + INTERVAL 1 DAY
This pulls in all the rows from midnight on 1-October, up to but not including midnight on 3-October.
If you want to aggregate your results by day, you can use GROUP BY DATE(added_date).
A sample query -- to show all days in September -- might look like this:
SELECT DATE(added_date) day,
SUM(CASE WHEN status.text= 'Action' THEN 1 ELSE 0 END) AS `Action`,
SUM(CASE WHEN status.text= 'Draft' THEN 1 ELSE 0 END) AS `Draft`,
SUM(CASE WHEN status.text= 'Let' THEN 1 ELSE 0 END) AS `Let`
FROM tbl
WHERE added_date >= '2021-09-01'
AND added_date < '2021-09-01' + INTERVAL 1 MONTH
GROUP BY DATE(added_date);
Sorry to say, I don't understand how your sample query works well enough to rewrite it with GROUP BY. But this should get you started.
I'm new to SQL and trying to create a total summary of a working SQL query. It's listing the total results from one month of data.
Now I need the total values of the outcome of the query.
So I created a 'query in a query' piece of SQL, but it ain't working because my lack of SQL knowledge. I guess it's an easy fix for you pro's :-)
The working SQL query with the daily outcome of one month:
SELECT
DATE_FORMAT(date, '%d/%m/%y') AS Datum,
COUNT(*) AS Berichten,
SUM(CASE WHEN virusinfected>0 THEN 1 ELSE 0 END) AS Virus,
SUM(CASE WHEN (virusinfected=0 OR virusinfected IS NULL) AND isspam>0 THEN 1 ELSE 0 END) AS Ongewenst,
SUM(CASE WHEN (virusinfected=0 OR virusinfected IS NULL) AND (isspam=1) AND isrblspam>0 THEN 1 ELSE 0 END) AS RBL,
SUM(size) AS Grootte
FROM
maillog
WHERE
1=1
AND (1=1)
AND
date < '2017-04-01'
AND
date >= '2017-03-01'
AND
to_domain = 'domain1.nl'
OR
date < '2017-04-01'
AND
date >= '2017-03-01'
AND
to_domain = 'domain2.nl'
GROUP BY
Datum
ORDER BY
date
The incorrect query trying to create the monthly totals:
SELECT Datum,
SUM(Berichten) AS Berichten,
SUM(Virus) AS Virus,
SUM(Ongewenst) AS Ongewenst,
SUM(RBL) AS RBL,
SUM(Grootte) AS Grootte,
FROM ( SELECT
DATE_FORMAT(date, '%d/%m/%y') AS Datum,
COUNT(*) AS Berichten,
SUM(CASE WHEN virusinfected>0 THEN 1 ELSE 0 END) AS Virus,
SUM(CASE WHEN (virusinfected=0 OR virusinfected IS NULL) AND isspam>0 THEN 1 ELSE 0 END) AS Ongewenst,
SUM(CASE WHEN (virusinfected=0 OR virusinfected IS NULL) AND (isspam=1) AND isrblspam>0 THEN 1 ELSE 0 END) AS RBL,
SUM(size) AS Grootte
FROM
maillog
WHERE
1=1
AND (1=1)
AND
date < '2017-04-01'
AND
date >= '2017-03-01'
AND
to_domain = 'domain1.nl'
OR
date < '2017-04-01'
AND
date >= '2017-03-01'
AND
to_domain = 'domain2.nl'
GROUP BY
Datum
ORDER BY
date
) t
GROUP BY Datum;
Thanks in advance.
What you want can be done with just a little addition to your first SQL statement: add with rollup after the group by clause:
GROUP BY Datum WITH ROLLUP
It will run more efficiently than the version with sub-query, although it could work that way, but you should then remove the outer group by clause and not select Datum there, since you don't want the totals per date any more, but overall.
Still, you will lose the details and only get the overall totals then. You would have to use a union with your original query to get both levels of totals. You can imagine that the with rollup modifier will do the job more efficiently.
I have sales table and have two different date ranges.
i.e, I have total sales between (2016-12-21 - 2016-12-30) is 100 and for period (2016-12-11 - 2016-12-20) is 85.
Now the result I want is
100 (sales of 2016-12-21 - 2016-12-30), 85 (sales of 2016-12-11 - 2016-12-20), 15 (difference of both periods) through single query.
What I am thinking is
select *, (a.sales - b.sales) as diff
from (select id, sum(sales) as sales from salestable where date >= '2016-12-21' and date <= '2016-12-30') a
join (select id, sum(sales) as sales from salestable where date >= '2016-12-11' and date <= '2016-12-20') b
on a.id = b.id;
Is there any other better way to do this?
You can use conditional aggregation:
select sum(case when date >= '2016-12-21' and date <= '2016-12-30' then sales else 0
end) as sales_a,
sum(case when date >= '2016-12-11' and date <= '2016-12-20' then sales else 0
end) as sales_b,
sum(case when date >= '2016-12-21' and date <= '2016-12-30'
then sales else 0
when date >= '2016-12-11' and date <= '2016-12-20'
then -sales
else 0
end) as sales_diff
from salestable;
If you want the overall sum by id (as suggested by your inclusion of id), then add id to the select and add group by id.
You can use case to do a conditional sum like this:
select id,
sum_21_to_30,
sum_11_to_20,
sum_21_to_30 - sum_11_to_20 diff
from (select id,
sum(case when date >= '2016-12-21' and date <= '2016-12-30' then sales else 0 end) sum_21_to_30,
sum(case when date >= '2016-12-11' and date <= '2016-12-20' then sales else 0 end) sum_11_to_20
from table group by id) t;
I Have wrote sql query something like this :
SELECT `petugas_input`,
COUNT(`petugas_input`) AS `01-MAR`,
COUNT(`petugas_input`) AS `02-MAR`,
COUNT(`petugas_input`) AS `03-MAR`
FROM `tabel_arsip`
WHERE `tgl_input_arsip`>='2016-03-01 00:00:00' AND `tgl_input_arsip`<='2016-03-01 23:59:59'
GROUP BY `petugas_input`
and its generate result like this
My question is how to add criteria to the aliases column so that it will show different value on different date. (not the same value in the date column as above)
You'd have to rely on a little complex grouping:
SELECT
`petugas_input`,
SUM(CASE WHEN DATE(tgl_input_arsip) = '2016-03-01' THEN 1 ELSE 0 END) AS `01-MAR`,
SUM(CASE WHEN DATE(tgl_input_arsip) = '2016-03-02' THEN 1 ELSE 0 END) AS `02-MAR`,
SUM(CASE WHEN DATE(tgl_input_arsip) = '2016-03-03' THEN 1 ELSE 0 END) AS `03-MAR`,
FROM `tabel_arsip`
WHERE `tgl_input_arsip`>='2016-03-01 00:00:00' AND `tgl_input_arsip`<='2016-03-01 23:59:59'
GROUP BY `petugas_input`
You should not think for these hard-coded column aliases rather make a query for each petugas_input and for each date (within the given date range) along with the count.
Something like this:
SELECT
`petugas_input`,
DATE(`tgl_input_arsip`) `date`,
COUNT(*) total
FROM `tabel_arsip`
WHERE `tgl_input_arsip`>='2016-03-01 00:00:00' AND `tgl_input_arsip`<='2016-03-01 23:59:59'
GROUP BY `petugas_input`,`date`;
And you will get the following output structure:
petugas_input date total
A yyyy-mm-dd n1
B yyyy-mm-dd n2
Try this one:
SELECT `petugas_input`,
COUNT(CASE WHEN DATE(tgl_input_arsip) = '2016-03-01' THEN petugas_input ELSE 0 END) AS `01-MAR`,
COUNT(CASE WHEN DATE(tgl_input_arsip) = '2016-03-02' THEN petugas_input ELSE 0 END) AS `02-MAR`,
COUNT(CASE WHEN DATE(tgl_input_arsip) = '2016-03-03' THEN petugas_input ELSE 0 END) AS `03-MAR`
FROM `tabel_arsip`
WHERE `tgl_input_arsip`>='2016-03-01 00:00:00' AND `tgl_input_arsip`<='2016-03-03 23:59:59'
GROUP BY `petugas_input`;
:)
I have a table M_DAILY with fields
PS_DATE date,
tp int,
ep int,
mp int,
and have a working version of a user defined function nvl(x,y) which returns x if not null and y if x is null
My MySQL query is-
select sum(avg(case date_format(PS_DATE,'%Y') when '2005' then nvl(tp,0) else 0 end))tp, sum(avg(case date_format(PS_DATE,'%Y') when '2005' then nvl(ep,0) else 0 end)) ep, sum(avg(case date_format(PS_DATE,'%Y') when '2005' then nvl(mp,0) else 0 end)) mp
from M_DAILY
where PS_DATE >= date ('2005-01-01') and PS_DATE <= date ('2005-12-31')
group by PS_DATE;
I get the following error
#1111 - Invalid use of group function in mysql
Please help.
SUM(), COUNT(), AVG(), MIN(), MAX(), etc. are aggregate functions that
requires you to specify a GROUP BY, unless you're using them on every
column in your SELECT-list.
Remove Group By Clause
Try this
SELECT SUM(tp),SUM(ep),SUM(mp) FROM
(
SELECT Avg(case date_format(PS_DATE,'%Y') when '2005' then nvl(tp,0) else 0 end) tp,
Avg(case date_format(PS_DATE,'%Y') when '2005' then nvl(ep,0) else 0 end) ep,
Avg(case date_format(PS_DATE,'%Y') when '2005' then nvl(mp,0) else 0 end) mp
FROM M_DAILY
WHERE PS_DATE >= date ('2005-01-01') and PS_DATE <= date ('2005-12-31');
) As T