I have a json data like this
{key:value, key:value, detail:[{key:value, key:value, ...}]}
I want to delete the detail array in this data and throw the remaining elements into another json object, how can I do that?
I tried two ways as below but it doesn't work:
var master =(delivery.deliveryTemp?.toJson() as Map<String, dynamic>).removeWhere((key, value) => key != "detail" || value == null);
var master= delivery.deliveryTemp?.toJson().remove("detail");
This is how I solved it.
var master= delivery.deliveryTemp?.toJson();
master?.removeWhere((key, value) => key=="detail");
i'm trying to convert and existing text column to translatable. I find that when i add the column name to the the protected translatable array i am no longer able to access it as i did before ($model->key)
I assume that this is because its looked for a translation but can't find one. Is there a way for me to return to contents of the column? I want to retrieve the text and and replace it with a json
when I log $this i can see my object and the correct key: value pairs. Any attempt to access it or convert it to array causes the value to disappear completely
$array = json_decode(json_encode($this), true);
$object = json_decode(json_encode($this), false);
error_log('$this '.print_r($this,true)); // includes the key 'myKey' with correct value
error_log('$array '.print_r($array['mykey'],true)); // empty
error_log('$object '.print_r($object->mykey,true)); // empty
You can use this method if you want to get all translated values of a particular column as an array.
public function update(ModelName $modelItem)
{
return $modelItem->getTranslations('column_name');
}
//result
[
'en' => 'test',
'tr' => 'deneme',
]
Resource:
https://github.com/spatie/laravel-translatable#getting-all-translations-in-one-go
if you want to get the content that still not store as json translation, you can use this eloquent method.
$model->getRawOriginal('your translation's column name');
it will get your column value.
I try to access to my data json file:
[{"id":1,"name":"Maria","project":[{"id":5,"name":"Animals"},{"id":6,"name":"Cats"}]}
This is my approach:
data[0].name;
But like this I get only the result:
Animals
But I would need the result:
Animals, Cats
You are accessing only the name property of 0th index of project array.
To access all object at a time you need to loop over the array.
You can use Array.map for this.
var data = [{"id":1,"name":"Maria","project":[{"id":5,"name":"Animals"},{"id":6,"name":"Cats"}]}]
var out = data[0].project.map(project => project.name).toString()
console.log(out)
If that's your actual data object, then data[0].name would give you "Maria". If I'm reading this right, though, you want to get all the names from the project array. You can use Array.map to do it fairly easily. Note the use of an ES6 arrow function to quickly and easily take in the object and return its name.
var bigObject = [{"id":1,"name":"Maria","project":[{"id":5,"name":"Animals"},{"id":6,"name":"Cats"}]}];
var smallObject = [{"id":5,"name":"Animals"},{"id":6,"name":"Cats"}];
console.log("Getting the names from the full array/data structure: "+bigObject[0].project.map(obj => obj.name))
console.log("Getting the names from just the project array: "+smallObject.map(obj => obj.name))
EDIT: As per your comment on the other answer, you said you needed to use the solution in this function:
"render": function (data, type, row) {if(Array.isArray(data)){return data.name;}}
To achieve this, it looks like you should use my bottom solution of the first snippet like so:
var data = [{"id":5,"name":"Animals"},{"id":6,"name":"Cats"}];
function render(data, type, row){
if(Array.isArray(data)){
return data.map(obj => obj.name);
}
};
console.log("Render returns \""+render(data)+"\" as an array.");
I've a JSON object as below:
let data = [{"grade":"A","batch":"night", "rating":5}, {"grade":"B", "batch":"morning", "rating":6},
{"grade":"C", "batch":"night", "rating":7},
{"grade":"A", "batch":"morning", "rating":8}]
I want to filter json on two properties of object named "grade" and "batch"
How can I do this in javascript?
Here is sample code. you can add the filters object whichever data you want to filter and run the code. The result will be displayed in the console of the window.
You can try running the code snippet for output
function multiFilter(array, filters){
const filterKeys = Object.keys(filters);
// filters all elements passing the criteria
return array.filter((item) => {
// dynamically validate all filter criteria
return filterKeys.every(key => !!~filters[key].indexOf(item[key]));
});
}
let data = [{"grade":"A","batch":"night", "rating":5}, {"grade":"B", "batch":"morning", "rating":6},
{"grade":"C", "batch":"night", "rating":7},
{"grade":"A", "batch":"morning", "rating":8}]
let filters = {
"grade" : ["A", "B"],
"batch" : ["morning"]
};
let filtered = multiFilter(data, filters);
console.log(filtered);
I'm trying to use a PCRE regular expression to extract some JSON. I'm using a version of MariaDB which does not have JSON functions but does have REGEX functions.
My string is:
{"device_types":["smartphone"],"isps":["a","B"],"network_types":[],"countries":[],"category":["Jebb","Bush"],"carriers":[],"exclude_carriers":[]}
I want to grab the contents of category. I'd like a matching group that contains 2 items, Jebb and Bush (or however many items are in the array).
I've tried this pattern but it only matches the first occurrence: /(?<=category":\[).([^"]*).*?(?=\])/g
Does this match your needs? It should match the category array regardless of its size.
"category":(\[.*?\])
regex101 example
JSON not a regular language. Since it allows arbitrary embedding of balanced delimiters, it must be at least context-free.
For example, consider an array of arrays of arrays:
[ [ [ 1, 2], [2, 3] ] , [ [ 3, 4], [ 4, 5] ] ]
Clearly you couldn't parse that with true regular expressions.
See This Topic:
Regex for parsing single key: values out of JSON in Javascript
Maybe Helpful for you.
Using a set of non-capturing group you can extract a predefined json array
regex answer: (?:\"category\":)(?:\[)(.*)(?:\"\])
That expression extract "category":["Jebb","Bush"], so access the first group
to extract the array, sample java code:
Pattern pattern = Pattern.compile("(?:\"category\":)(?:\\[)(.*)(?:\"\\])");
String body = "{\"device_types\":[\"smartphone\"],\"isps\":[\"a\",\"B\"],\"network_types\":[],\"countries\":[],\"category\":[\"Jebb\",\"Bush\"],\"carriers\":[],\"exclude_carriers\":[]}";
Matcher matcher = pattern.matcher(body);
assertThat(matcher.find(), is(true));
String[] categories = matcher.group(1).replaceAll("\"","").split(",");
assertThat(categories.length, is(2));
assertThat(categories[0], is("Jebb"));
assertThat(categories[1], is("Bush"));
There are many ways. One sloppy way to do it is /([A-Z])\w+/g
Please try it on your console like
var data = '{"device_types":["smartphone"],"isps":["a","B"],"network_types":[],"countries":[],"category":["Jebb","Bush"],"carriers":[],"exclude_carriers":[]}',
res = [];
data.match(/([A-Z])\w+/g); // ["Jebb", "Bush"]
OK the above was pretty sloppy however a solid single regex solution to extract every single element regardless of the number, one by one and to place them in an array (res) is the following...
var rex = /[",]+(\w*)(?=[",\w]*"],"carriers)/g,
str = '{"device_types":["smartphone"],"isps":["a","B"],"network_types":[],"countries":[],"category":["Jebb","Bush","Donald","Trump"],"carriers":[],"exclude_carriers":[]}',
arr = [],
res = [];
while ((arr = rex.exec(str)) !== null) {
res.push(arr[1]); // <- ["Jebb", "Bush", "Donald", "Trump"]
}
Check it out # http://regexr.com/3d4ee
OK lets do it. I have come up with a devilish idea. If JS had look-behinds this could have been done simply by reversing the applied logic in the previous example where i had used a look-forward. Alas, there aren't... So i decided to turn the world the other way around. Check this out.
String.prototype.reverse = function(){
return this.split("").reverse().join("");
};
var rex = /[",]+(\w*)(?=[",\w]*"\[:"yrogetac)/g,
str = '{"device_types":["smartphone"],"isps":["a","B"],"network_types":[],"countries":[],"category":["Jebb","Bush","Donald","Trump"],"carriers":[],"exclude_carriers":[]}',
rev = str.reverse();
arr = [],
res = [];
while ((arr = rex.exec(rev)) !== null) {
res.push(arr[1].reverse()); // <- ["Trump", "Donald", "Bush", "Jebb"]
}
res.reverse(); // <- ["Jebb", "Bush", "Donald", "Trump"]
Just use your console to confirm.
In c++ you can do it like this
bool foundmatch = false;
try {
std::regex re("\"([a-zA-Z]+)\"*.:*.\\[[^\\]\r\n]+\\]");
foundmatch = std::regex_search(subject, re);
} catch (std::regex_error& e) {
// Syntax error in the regular expression
}
If the number of items in the array is limited (and manageable), you could define it with a finite number of optional items. Like this one with a maximum of 5 items:
"category":\["([^"]*)"(?:,"([^"]*)"(?:,"([^"]*)"(?:,"([^"]*)"(?:,"([^"]*)")?)?)?)?
regex101 example here.
Regards.