I am having 2 tables named table1, table2.
table1 columns are t1_id, t1_name, t1_status.
table2 columns are t1_id, t2_id, t2_name, t2_status.
When I do Some operation in frontend t1_id will be inserted into table2.
What I need is I want t1_id(s) from table1 which are not alloted or inserted in table2.
I've tried this query:
SELECT t1.t1_id, t1.t1_name
FROM table1 t1
LEFT OUTER JOIN table2 t2
ON t1.t1_id != t2.t1_id
The problem with query is when all t1_id(s) are inserted into table2, then all t1_id(s) are showing again.
How to resolve this issue? (I'am new to sql so please don't consider my mistakes.)
If i understand your question right, this must b the query you need:
SELECT t1.t1_id, t1.t1_name
FROM table1 t1
LEFT OUTER JOIN table2 t2
ON t1.t1_id = t2.t1_id
where t2.t1_id is null
Use is null to get rows from table1 which don't have any associations in table2
SELECT t1.t1_id, t1.t1_name
FROM table1 t1
LEFT OUTER JOIN table2 t2
ON t1.t1_id = t2.t1_id
WHERE t2.t1_id IS NULL
I think this answers your questions: Select rows which are not present in other table
SELECT t1.t1_id, t1.t1_name
FROM table1 t1
WHERE NOT EXISTS (
SELECT 1 --it's not so relevant what you put here
FROM table2 t2
WHERE t1.t1_id = t2.t1_id
)
I hope this helps. ;-)
Related
I basically want to join the result of two INNER JOINs.
On this scheme I want to get the three arrows results combined.
I've tried INNER / LEFT combinations but it doesn't do the trick.
I think a nested request could be the solution but how ?
Thanks
The answer was actually simple : UNION
SELECT t1.*
FROM
(SELECT t1.*
FROM table1 t1 JOIN table2 t2 ON t2.id = i.client_id
UNION
SELECT t1.*
FROM t1 t1 JOIN table3 t3 ON t1.id = t3.client_id) as q1
;
I'd use logic to express the condition T1.id exists in T2 or T3 more directly, and certainly avoid use of DISTINCT or UNION.
Options could be to use EXISTS directly (As this is immure to the possibility of duplication cause by 1:many joins)...
SELECT
t1.*
FROM
table1 t1
WHERE
EXISTS (SELECT * FROM table2 t2 WHERE t2.t1_id = t1.id)
OR
EXISTS (SELECT * FROM table3 t3 WHERE t3.t1_id = t1.id)
Or to LEFT JOIN twice and then exclude unwanted rows. (This assumes that the joins are never 1:many, which would introduce duplication, and the unwanted need for a DISTINCT.)
SELECT
t1.*
FROM
table1 t1
LEFT JOIN
table2 t2
ON t1.id = t2.t1_id
LEFT JOIN
table3 t3
ON t1.id = t3.t1_id
WHERE
t2.t1_id IS NOT NULL
OR
t3.t1_id IS NOT NULL
Say, myself having three MySQL tables as follows.
Table 1 contains table1id, value columns.
Table 2 contains table2id, value, table1id (as FK) columns.
Table 3 contains table3id, value, table1id (as FK) columns.
Then is the following relationship valid?
select * from table1 t1 inner join table2 t2 on t1.table1id = t2.table1id
Yes, It is possible.
This one is Joining for teable1 and table2
select * from test1 t1 inner join test2 t2 on t1.id = t2.id;
This one is joining all three tables,
SELECT * FROM test1 t1
INNER JOIN test2 t2 ON t1.id = t2.id
INNER JOIN test3 t3 ON t1.id = t3.id;
Output: ONLINE DEMO HERE
Try this
SELECT * FROM
table1 t1 INNER JOIN table2 t2
ON t1.table1id = t2.table2id
INNER JOIN table3 t3
ON t1.table1id = t3.table3id
You can also write it this way:
SELECT * FROM table1 t1, table2 t2, table3 t3
WHERE (t1.table1id=t2.table2id) AND (t1.table1id=t3.table3id);
** If you want to join only the first 2 tables--Use the code until the AND
*** If you want to join all the tables-- Use the entire code.
How to select all records in the table t2 which t2.t1_id has no coincidence with t1.id.
SELECT * FROM t2 LEFT JOIN t1 ON t1.id <> t2.t1_id
Any tips, link or code example would be useful.
If what you want is all t2 records without a matching id in t1, but no columns from t1, you could do:
Select * from t2
WHERE t2.t1_id NOT IN(Select id from T1)
This selects all records in t2, but then filters out those that exist in t1 based on t1_id
You can use a not in:
SELECT *
FROM t2
WHERE t2.t1_id not in (select id from t1)
SELECT t2.*
FROM t2
LEFT JOIN t1
ON t1.id = t2.t1_id
where t1.id is null
Just want to add, NOT EXIST is better in most cases:
SELECT *
FROM t2
WHERE NOT EXIST (SELECT 1 FROM t1
WHERE t2.t1_id = t1.id)
Otherwise, you can use NOT IN or LEFT JOIN with NULL
The example below shows the result for every Name that has a connection to Table2 (Table1 TId is PK, and TId in Table2 is the FK).
SELECT T1.Name, T1.Address
FROM Table1 AS T1
INNER JOIN Table2 AS T2
ON T1.TId = T2.TId;
I want a list of all Names from Table1 that have NO corresponding row in Table2. The other way around so to speak. How could this be done?
You need to use an Outer Join as shown below:
SELECT T1.Name, T1.Address
FROM Table1 AS T1
LEFT OUTER JOIN Table2 AS T2 ON T1.TId = T2.TId
WHERE T2.TId IS NULL
I have two tables. Both contains question id field. I want to get all records from first table that are not present in second one. I don't want to use "NOT IN" constrain as second table having more than 400000 records.
Try something like
SELECt t1.*
FROM Table1 t1 LEFT JOIN
Table2 t2 ON t1.questionID = t2.questionID
WHERE t2.questionID IS NULL
Typically you would do this using a LEFT JOIN combined with a WHERE clause selecting every row where the joined table returns no results.
SELECT t1.*
FROM Table1 t1
LEFT OUTER JOIN Table2 t2 ON t2.ID = t1.ID
WHERE t2.ID IS NULL
try:
select from t1
right join t2 on t2.id = t1.id where t2.id is null