I have a database with tree tables,
person: id, bio, name
book: id, id_person, title, info
file: id, id_book, location
Other information: Book is about ~50,000 rows, File is about ~ 300,000 rows.
What I'm trying to do is to select 12 different authors and select just one book and from that book select location from the table file.
What I tried is the following:
SELECT DISTINCT(`person`.`id`), `person`.`name`, `book`.`id`, `book`.`title`, `book`.`info`, `file`.`location`
FROM `person`
INNER JOIN `book`
ON `book`.`id_person` = `person`.`id`
INNER JOIN `file`
ON `file`.`id_book` = `book`.`id`
LIMIT 12
I have learned that the DISTINCT does not work the way one might expect. Or is it me that I'm missing something? The above code returns books from the same author and goes with the next one. Which is NOT what I want. I want 1 book from each one of the 12 different authors.
What would be the correct way to retrieve this information from the database? Also, I would want to retrieve 12 random people. Not people that are stored in consecutive order in the database,. I could not formulate any query with rand() since I couldn't even get different authors.
I use MariaDB. And I would appreciate any help, especially help that allows to me do this with great performance.
In MySQL, you can do this, in practice, using GROUP BY
SELECT p.`id`, p.`name`, b.`id`, b.`title`, b.`info`, f.`location`
FROM `person` p INNER JOIN
`book` b
ON b.`id_person` = p.`id` INNER JOIN
`file` f
ON f.id_book = b.id
GROUP BY p.id
ORDER BY rand()
LIMIT 12;
However, this is not guaranteed to return the non-id values from the same row (although it does in practice). And, although the authors are random, the books and locations are not.
The SQL Query to do this consistently is a bit more complicated:
SELECT p.`id`, p.`name`, b.`id`, b.`title`, b.`info`,
(SELECT f.location
FROM file f
WHERE f.id_book = b.id
ORDER BY rand()
LIMIT 1
) as location
FROM (SELECT p.*,
(SELECT b.id
FROM book b
WHERE b.id_person = p.id
ORDER BY rand()
LIMIT 1
) as book_id
FROM person p
ORDER BY rand()
LIMIT 12
) p INNER JOIN
book b
ON b.id = p.book_id ;
Related
I have two tables, in one table is news in another is images linked with id from news
news
id
title
main_image
services
1
New title
path_to_image_main_image
Photo
2
New title 2
path_to_image_main_image
Photo
images
id
file_name
new_id
1
IMG_8045.jpg
1
2
IMG_8046.jpg
1
3
IMG_8047.jpg
2
4
IMG_8048.jpg
2
5
IMG_8049.jpg
2
new_id is id from news table
My SQL query is
SELECT n.id, n.title, n.main_image, n.services, i.file_name FROM news AS n INNER JOIN images AS i ON n.id = i.new_id
I need to limit this query with 2 images from images table per id from news table
By MySQL version 10.5 I assume you mean MariaDB version 10.5... seeing as MySQL is only on version 8.0 at the moment ;)
I'm not too familiar with the syntax differences between MySQL and MariaDB, but here's a query that works in MySQL 8.0... which technically should work for you in MariaDB 10.5 (seeing as they've had window functions since 10.2 - https://mariadb.com/kb/en/window-functions-overview/)
SELECT
r.*
FROM
(
SELECT
n.id,
n.title,
n.main_image,
n.services,
i.file_name,
ROW_NUMBER() OVER (PARTITION BY i.new_id ORDER BY i.id) AS row_num
FROM news n
INNER JOIN images i ON i.new_id = n.id
) r
WHERE r.row_num <= 2;
Hope this helps :)
I have a solution that supports MySQL 5.6. It is such a mess but it works. I hope performance is not an issue.
Basically it runs the JOIN first time, grouping by id of first table concatenating the ids of second table as a comma separated list. Then do the original join limiting to the list of ids.
Substitute users with news and history with images to name your tables.
SELECT *
FROM
`users` AS u
LEFT JOIN `history` AS h ON u.id = h.user_id
WHERE
FIND_IN_SET(h.id, (SELECT `list` FROM
(SELECT user_id, SUBSTRING_INDEX(GROUP_CONCAT(id SEPARATOR ','), ',', 3) AS `list` FROM
(SELECT h.user_id, h.id
FROM
`users` AS u
LEFT JOIN `history` AS h ON u.id = h.user_id
) AS `a`
GROUP BY user_id
) AS `b`
WHERE b.user_id = u.id
) )
I need to find the author who has written the most volumes in my database, I have three tables "VOLUMES", "AUTHOR", "WRITTEN BY". Table VOLUMES has columns like title, volume_id(primary key), year, edition_year, etc. Table AUTHOR has columns for generic infos like name, surname, id,etc and table WRITTEN BY is used to connect AUTHOR and VOLUMES, it contains the columns volume_id and author_id.
My data can contain many copies of the same volumes so I guess I need to group every copy of the same volume.
The query I have written is:
SELECT A.NAME, A.SURNAME, COUNT(V.ID) no_of_volumes
FROM VOLUMES AS V, AUTHOR AS A JOIN WRITTEN_BY W
WHERE (V.ID = W.VOLUME_ID AND A.ID = W.A_ID)
GROUP BY A.NAME, A.SURNAME
ORDER BY no_of_volumes DESC
LIMIT 1;
Now, this should print just one author, but I want it to print EVERY author that has written the same number of volumes... How do I do that?
If you are allowed to change the scheme slightly (use unique ID-names) than this could do the trick
select AUTHOR.NAME
, count(*) VolumeCount
from AUTHOR
inner join WRITTEN_BY using(AUTHOR_ID)
inner join VOLUME using(VOLUME_ID)
group by a.AUTHOR_ID
order by VolumeCount desc
limit 1;
x
If not than this should do the trick:
select AUTHOR.NAME
, count(*) VolumeCount
from AUTHOR
inner join WRITTEN_BY on AUTHOR_ID = AUTHOR.ID
inner join VOLUME on VOLUME_ID = VOLUME.ID
group by a.AUTHOR_ID
order by VolumeCount desc
limit 1;
Please reserve where for filtering only. Using it for foreign-key makes messy code.
(And if your table and field names are uppercase it makes sense to use lowercase keywords)
You must aggregate twice inside written_by: once to get the max number of volumes written and then to get the author ids who wrote the max number of volumes.
Then join to authors to get the authors details:
SELECT a.*, t.no_of_volumes
FROM author a INNER JOIN (
SELECT author_id, COUNT(*) no_of_volumes
FROM written_by
GROUP BY author_id
HAVING COUNT(*) = (
SELECT COUNT(*) no_of_volumes
FROM written_by
GROUP BY author_id
ORDER BY no_of_volumes DESC LIMIT 1
)
) t ON t.author_id = a.id
The table volumes is not needed.
For MySql 8.0+ the code can be simplified with the use of the window function RANK():
SELECT a.*, t.no_of_volumes
FROM author a INNER JOIN (
SELECT r.*
FROM (
SELECT author_id, COUNT(*) no_of_volumes,
RANK() OVER (ORDER BY COUNT(*) DESC) rnk
FROM written_by
GROUP BY author_id
) r
WHERE r.rnk = 1
) t ON t.author_id = a.id
Here is my problem:
My database have table Book, Post. Each book has many post
Table posts has field 'book_id', that is foreign key reference table Book primary key (id).
This is my index page. The idea is to get latest post from each book and order by published date.
When I code on localhost, every thing is OK. I can get latest post from each book and order by publish date. But when I deploy it in vps. It didn't get latest post, it get first post from each book. I didn't have any experience about it. Please help, thanks
On localhost, I use: Apache-2.2, PHP-5.3, Mysql-5.5, ENGINE type for table is InnoDB.
On VPS, I use: Nginx 1.7.6, PHP-FPM 5.5.18, MariaDB, ENGINE type for table is MyIsam
I guest the problem is InnoDB and MyIsam, I try to fix it. But, if you have free time, please give me some good advise. Thanks a lot
p/s: Sorry about my poor english
SELECT * FROM `my_book_store`.`books`
AS `Book`
INNER JOIN
(
SELECT *
FROM posts
WHERE posts.published = 1 AND posts.published_date <= NOW()
ORDER BY posts.published_date DESC
) AS `Post`
ON (`Post`.`book_id` = `Book`.`id`)
WHERE 1 = 1
GROUP BY `Book`.`id`
ORDER BY `Post`.`published_date` desc
LIMIT 100
You can try the below queries which does the job of getting the last post from each book
select
b.id,
b.name,
p.content,
p.published_date
from book b
join post p on p.book_id = b.id
left join post p1 on p1.book_id = p.book_id and p1.published_date > p.published_date
where p1.id is null;
OR
select
b.id,
b.name,
p.content,
p.published_date
from book b
join post p on p.book_id = b.id
where not exists(
select 1 from post p1
where p.book_id = p1.book_id
and p1.published_date > p.published_date
)
DEMO
Try this:
SELECT b.*, p.*
FROM my_book_store.books AS b
INNER JOIN posts p ON b.id = p.book_id
INNER JOIN (SELECT p.book_id, MAX(p.published_date) published_date
FROM posts p
WHERE posts.published = 1 AND posts.published_date <= NOW()
GROUP BY p.book_id
) AS p1 ON p.book_id = p1.book_id AND p.published_date = p1.published_date
GROUP BY b.id
ORDER BY p.published_date DESC
LIMIT 100
The problem seems to be that you're only grouping by
Book.id but select a lot of other non-aggregated values,
so actual query results depend on the execution plan the
optimizer came up with. See also
MySQL extends the use of GROUP BY so that the select list can
refer to nonaggregated columns not named in the GROUP BY clause.
[...]
However, this is useful primarily when all values in each
nonaggregated column not named in the GROUP BY are the same for
each group.
THE SERVER IS FREE TO CHOOSE ANY VALUE from each
group, so unless they are the same, the values chosen are
indeterminate.
Furthermore, the selection of values from each
group cannot be influenced by adding an ORDER BY clause.
Different result query when use mysql and mariadb
I have the following query which gives me the right results. But it's super slow.
What makes it slow is the
AND a.id IN (SELECT id FROM st_address GROUP BY element_id)
part. The query should show from which countries we get how many orders.
A person can have multiple addresses, but in this case, we only only want one.
Cause otherwise it will count the order multiple times. Maybe there is a better way to achieve this? A distinct join on the person or something?
SELECT cou.title_en, COUNT(co.id), SUM(co.price) AS amount
FROM customer_order co
JOIN st_person p ON (co.person_id = p.id)
JOIN st_address a ON (co.person_id = a.element_id AND a.element_type_id = 1)
JOIN st_country cou ON (a.country_id = cou.id)
WHERE order_status_id != 7 AND a.id IN (SELECT id FROM st_address GROUP BY element_id)
GROUP BY cou.id
Have you tried to replace the IN with an EXISTS?
AND EXISTS (SELECT 1 FROM st_address b WHERE a.id = b.id)
The EXISTS part should stop the subquery as soon as the first row matching the condition is found. I have read conflicting comments on if this is actually happening though so you might throw a limit 1 in there to see if you get any gain.
I found a faster solution. The trick is a join with a sub query:
JOIN (SELECT element_id, country_id, id FROM st_address WHERE element_type_id = 1 GROUP BY
This is the complete query:
SELECT cou.title_en, COUNT(o.id), SUM(o.price) AS amount
FROM customer_order o
JOIN (SELECT element_id, country_id, id FROM st_address WHERE element_type_id = 1 GROUP BY element_id) AS a ON (o.person_id = a.element_id)
JOIN st_country cou ON (a.country_id = cou.id)
WHERE o.order_status_id != 7
GROUP BY cou.id
How can I use MySQL to count with a LEFT JOIN?
I have two tables, sometimes the Ratings table does not have ratings for a photo so I thought LEFT JOIN is needed but I also have a COUNT statement..
Photos
id name src
1 car bmw.jpg
2 bike baracuda.jpg
Loves (picid is foreign key with photos id)
id picid ratersip
4 1 81.0.0.0
6 1 84.0.0.0
7 2 81.0.0.0
Here the user can only rate one image with their IP.
I want to combine the two tables in order of the highest rating. New table
Combined
id name src picid
1 car bmw.jpg 1
2 bike baracuda.jpg 2
(bmw is highest rated)
My MySQL code:
SELECT * FROM photos
LEFT JOIN ON photos.id=loves.picid
ORDER BY COUNT (picid);
My PHP Code: (UPDATED AND ADDED - Working Example...)
$sqlcount = "SELECT p . *
FROM `pics` p
LEFT JOIN (
SELECT `loves`.`picid`, count( 1 ) AS piccount
FROM `loves`
GROUP BY `loves`.`picid`
)l ON p.`id` = l.`picid`
ORDER BY coalesce( l.piccount, 0 ) DESC";
$pics = mysql_query($sqlcount);
MySQL allows you to group by just the id column:
select
p.*
from
photos p
left join loves l on
p.id = l.picid
group by
p.id
order by
count(l.picid)
That being said, I know MySQL is really bad at group by, so you can try putting the loves count in a subquery in your join to optimize it:
select
p.*
from
photos p
left join (select picid, count(1) as piccount from loves group by picid) l on
p.id = l.picid
order by
coalesce(l.piccount, 0)
I don't have a MySQL instance to test out which is faster, so test them both.
You need to use subqueries:
SELECT id, name, src FROM (
SELECT photos.id, photos.name, photos.src, count(*) as the_count
FROM photos
LEFT JOIN ON photos.id=loves.picid
GROUP BY photos.id
) t
ORDER BY the_count
select
p.ID,
p.name,
p.src,
PreSum.LoveCount
from
Photos p
left join ( select L.picid,
count(*) as LoveCount
from
Loves L
group by
L.PicID ) PreSum
on p.id = PreSum.PicID
order by
PreSum.LoveCount DESC
I believe you just need to join the data and do a count(*) in your select. Make sure you specify which table you want to use for ambigous columns. Also, don't forget to use a group by function when you do a count(*). Here is an example query that I run on MS SQL.
Select CmsAgentInfo.LOGID, LOGNAME, hCmsAgent.SOURCEID, count(*) as COUNT from hCmsAgent
LEFT JOIN CmsAgentInfo on hCmsAgent.logid=CmsAgentInfo.logid
where SPLIT = '990'
GROUP BY CmsAgentInfo.LOGID, LOGNAME, hCmsAgent.SOURCEID
The example results form this will be something like this.
77615 SMITH, JANE 1 36
29422 DOE, JOHN 1 648
Hope that helps. Good Luck.