select
OrderNo,
Sum(QtyIn) as QuantityIn,
Sum(QtyOut) as QuantityOut
from
tbl_Assign
group by
OrderNo
I want to select * from table also group by from table. How to do it?
To group by on all columns with a sum you cannot use *, you have to list all of the columns out and every column that isn't a function like Sum must be included in the group by.
So if you have other fields in your database such as OrderName, OrderedBy you can perform a group by like this:
Select
OrderNo,
OrderName,
OrderBy,
Sum(QtyIn) as QuantityIn,
Sum(QtyOut) as QuantityOut
From
tbl_Assign
Group By
OrderNo, OrderName, OrderBy
The following will create one row for every row in the tbl_Assign.
Each row will also show the summary information for the order.
This might not be what you need, but it's useful to understand it anyway.
SELECT T1.*, T2.*
FROM
( select * FROM tbl_Assign ) AS T1
LEFT JOIN ( select
OrderNo,
Sum(QtyIn) as QuantityIn,
Sum(QtyOut) as QuantityOut
from
tbl_Assign
group by
OrderNo
) AS T2
ON T1.OrderNo = T2.OrderNo
Harvey
Related
I have 2 different tables sharing the same column names. The tables list the same products which are identified by 'id'. The products have different revenues throughout both tables and are listed multiple times in each table.
I would like to sum the revenue of the same products across the 2 tables and ORDER BY the sum. Result is sorting the highest revenue products first.
I've tried JOIN and UNION but can't seem to figure out the right solution.
UNION query I tried...
SELECT id, SUM(rev) as total
FROM (
SELECT id, rev FROM table1 UNION ALL
SELECT id, rev FROM table2 UNION ALL
)
ORDER BY total DESC
JOIN query I tried...
SELECT table1.id,
table1.rev,
table2.id,
table2.rev,
(table1.rev + table2.rev) as revenue
FROM table1
INNER JOIN table2 ON table1.id = table2.id
ORDER BY revenue DESC
You were close. You needed:
one UNION ALL, not two.
a GROUP BY, that gives the break field.
An alias for the subquery (I used AllRevenue - you can use any valid name.)
SELECT id, SUM(rev) as total
FROM (
SELECT id, rev FROM table1 UNION ALL
SELECT id, rev FROM table2
) AS AllRevenue
GROUP BY id
ORDER BY total DESC
The join approach would have worked if you used a FULL OUTER JOIN, because some ids may be present in one table but not the other, but that is usually less performant.
Looks like you just need to group on the ID then... unless I'm missing something.
select d.* from (
SELECT
table1.id,
Sum(table1.rev) + Sum(table2.rev) as revenue
FROM table1
INNER JOIN table2 ON table1.id = table2.id
GROUP BY
table1.id) d
order by d.revenue
SELECT id, SUM(rev) as total
FROM (
SELECT id, rev FROM table1 UNION ALL
SELECT id, rev FROM table2
)
GROUP BY id
ORDER BY total DESC
I tried to display the entries in table where the order has more than one article: but it´s not working the way I tried it. Can somebody show me what´s wrong?!
Here´s what I tried:
SELECT *
FROM TableX
WHERE (SELECT COUNT(Ordernumber) FROM TableX AS a WHERE a>1);
One option is to use a subquery to identify the order numbers having more than one article, then join this subquery to your original table to obtain the full records for these matching orders.
SELECT t1.*
FROM TableX t1
INNER JOIN
(
SELECT Ordernumber
FROM TableX
GROUP BY Ordernumber
HAVING COUNT(*) > 1
) t2
ON t1.Ordernumber = t2.Ordernumber
This query assumes that all articles within a given order are unique. If duplicate articles could occur, and you would not count duplicates, then you can use the following HAVING clause instead:
HAVING COUNT(DISTINCT article) > 1
Another option:
SELECT *
FROM TableX
WHERE Ordernumber IN
(
SELECT Ordernumber
FROM TableX
GROUP BY Ordernumber
HAVING COUNT(*) > 1
)
If I can retrieve the most recent name for each id from a table in a MySQL database like so:
SELECT n.id, n.name, n.date
FROM $table AS n
INNER JOIN
(SELECT id, MAX(date) AS date
FROM $table GROUP BY id)
AS max
USING (id, date);
How could I retrieve the most recent name from three almost identical tables (call them $table, $table2, $table3)? They all share the same column structure and the id found from one table may or may not be present in the other two. Think of it as one large table split into three (but with two of them containing two extra columns that are irrelevant in this instance). Would UNION be the best solution? If so, is there a way to do it without a mile-long query?
Constraint:
id is not an auto-incrementing unique integer unfortunately
You can use union all. One slight simplification is the group_concat()/substring_index() trick:
select id, max(date) as date,
substring_index(group_concat(name order by date desc), ',', '') as MostRecentName
from (select t.* from $table1 t union all
select t.* from $table2 t union all
select t.* from $table3
) t
group by id;
This does make certain assumptions. The name cannot contain , (although it is easy enough to change the separator. In addition, the intermediate result for the group_concat() cannot exceed a certain threshold (which is determined by a user-settable system parameter).
You could try:
SELECT n.id, n.name, n.date
FROM table1 where id in (select max(id) from table1)
union
SELECT n.id, n.name, n.date
FROM table2 where id in (select max(id) from table2)
union
SELECT n.id, n.name, n.date
FROM table3 where id in (select max(id) from table3)
Every inner query selects the highest id from the table and then searches for the corresponding fields in the outer query.
This ended up being the only solution I could think of:
SELECT n.id, n.name, n.date FROM (
SELECT id, name, date FROM $table
UNION ALL
SELECT id, name, date FROM $table2
UNION ALL
SELECT id, name, date FROM $table3
) AS n INNER JOIN (
SELECT id, MAX(date) AS date FROM (
SELECT id, date FROM $table
UNION ALL
SELECT id, date FROM $table2
UNION ALL
SELECT id, date FROM $table3
) AS t
GROUP BY id
) AS max USING (id, date)
As sadly SQL is my weakest skill.
I'm trying to use UNION in a VIEW, where I can get statistics from two different tables with one query.
SELECT COUNT(*) AS `customer_count` FROM `Customers`
UNION
SELECT COUNT(*) AS `supplier_count` FROM `Suppliers`;
[Demo table]
However, it only returns customer_count, with two rows. Is there anyway, to make this work, so it returns customer_count and supplier_count separately?
You would need a cross join to see the results adjacent to each other in one row. So you would select from both the tables without a join condition.
select * from
(select count(*) as customer_count from Customers) x,
(select count(*) as supplier_count from Suppliers) y
select
(SELECT COUNT(*) FROM Customers) as customer_count,
(SELECT COUNT(*) FROM Suppliers) AS supplier_count
Using your Table Demo.
The key is use alias so the field names match on each union select.
In this case TableSource and Total
SELECT 'Customer' as TableSource, Count(City) as Total FROM Customers
UNION
SELECT 'Suppliers' as TableSource, Count(City) as Total FROM Suppliers;
CREATE VIEW `vw_count` AS
select (select count(0) from `tbl`) AS `customer_count`,
(select count(0) from `tbl2`) AS `supplier_count`;
I got a database named accounts and account table inside of this database, Also I got the database named players and player table inside of this database.
How can I get a rows count of this two tables in one query?
I've tried this:
SELECT
SUM(`account`.`account`.`id`) AS 'accounts',
SUM(`player`.`player`) AS 'players';
But it doesn't work.
If you need exactly rows count (not sum), than do something like this:
select
(select count(*) from accounts.account) as count1,
(select count(*) from players.player) as count2
or
select count(*) as `count`,"account" as `table` from accounts.account
union all
select count(*) as `count`,"player" as `table` from players.player
A simple UNION operation on two select statements will do:
SELECT COUNT(*), 'Accounts' FROM Accounts.Account
UNION
SELECT COUNT(*), 'Players' FROM Players.Player
And you have to qualify each table with the database name since they're in separate databases.
Try:
SELECT
COUNT(`account`.`id`) AS 'accounts',
COUNT(`player`.`player`) AS 'players'
FROM
`account`,
`player`
SELECT COUNT(*)
FROM (
SELECT Id
FROM accounts.account
UNION ALL
SELECT player
FROM players.player ) AS BothTables
with Value (nbr, name ) as
(
select count(*) amount, 'AccountsCount' as ab from accounts..account
union all
select count(*) amount, 'PlayersCount' as ab from players..player
)
select *
from value as s
PIVOT(sum(nbr) for name in (AccountsCount, PlayersCount) ) as pvt