Return Everyday from MYSQL - mysql

Question

I want to fill in the dates between today and 30 days ago in mysql.
eg:
Date Value
2015-08-05 1
2015-08-04 2
2015-08-03 0
......
2015-07-05 1
Below is mysql:
SELECT IFNULL(SUM(units.price), 0) as price, DATE(units.solddate) as date, DAY(units.solddate) as day,
(
select a.Date
from (
select curdate() - INTERVAL (a.a + (10 * b.a) + (100 * c.a)) DAY as Date
from (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as a
cross join (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as b
cross join (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as c
) a
where a.Date >= DATE_SUB(NOW(), INTERVAL 30 day)
) as onemonth
FROM (tables)
GROUP BY date
However, I got this error: #1242 - Subquery returns more than 1 row I understood this error.
Please advice. Thank you.

Answer 1

This is a solution by correcting your approach
SELECT
`dates`.`date` ,SUM( COALESCE( `units`.`price` ,0 ) ) AS `price`
FROM
(
-- Start of query for making dates
SELECT
`dates`.`date`
,CONCAT( `dates`.`date` ,' 00:00:00' ) AS `day_start_datetime`
,CONCAT( `dates`.`date` ,' 23:59:59' ) AS `day_end_datetime`
FROM
(
SELECT
DATE_SUB( CURDATE( ) ,INTERVAL `intervals`.`days` DAY ) AS `date`
FROM
(
SELECT
( `hundreds_place`.`num` * 100 )
+( `tens_place`.`num` * 10 )
+( `ones_place`.`num` * 1 ) AS `days`
FROM ( SELECT 0 AS `num` UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9 ) AS `ones_place`
JOIN ( SELECT 0 AS `num` UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9 ) AS `tens_place`
JOIN ( SELECT 0 AS `num` UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9 ) AS `hundreds_place`
) `intervals`
HAVING
`date` >= DATE_SUB( CURDATE() ,INTERVAL 30 DAY )
) `dates`
-- End of query for making dates
) `dates`
LEFT OUTER JOIN `units`
ON `units`.`sold_date` BETWEEN `day_start_datetime` AND `day_end_datetime`
WHERE
1
GROUP BY
`dates`.`date`
ORDER BY
`dates`.`date`

Answer 2

After getting better understanding of what you are trying to achieve , I have put together this MySQL query .
I have tested it and it worked for me .
SELECT
`dates_table`.`date`
-- ,`dates_table`.`day`
,SUM( COALESCE( `units`.`price` ,0 ) ) AS `price`
FROM
-- Start of query for making dates_table
(
SELECT
DATE( DATE_SUB( CURDATE( ) ,INTERVAL `intervals_table`.`days` DAY ) ) AS `date`
,DAY( DATE_SUB( CURDATE( ) ,INTERVAL `intervals_table`.`days` DAY ) ) AS `day`
FROM
(
SELECT 0 AS `days`
UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4
UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8
UNION SELECT 9 UNION SELECT 10 UNION SELECT 11 UNION SELECT 12
UNION SELECT 13 UNION SELECT 14 UNION SELECT 15 UNION SELECT 16
UNION SELECT 17 UNION SELECT 18 UNION SELECT 19 UNION SELECT 20
UNION SELECT 21 UNION SELECT 22 UNION SELECT 23 UNION SELECT 24
UNION SELECT 25 UNION SELECT 26 UNION SELECT 27 UNION SELECT 28
UNION SELECT 29 UNION SELECT 30 UNION SELECT 31
) `intervals_table`
HAVING
`date` >= DATE_SUB( CURDATE( ) ,INTERVAL 30 DAY )
)
-- End of query for making dates_table
`dates_table`
LEFT OUTER JOIN `units` ON
`units`.`sold_date` >= CONCAT( `dates_table`.`date` ,' 00:00:00' )
AND `units`.`sold_date` <= CONCAT( `dates_table`.`date` ,' 23:59:59' )
WHERE
1
GROUP BY
`dates_table`.`date`
ORDER BY
`dates_table`.`date`
The units table I have used for testing is :
CREATE TABLE IF NOT EXISTS `units` (
`id` int(11) NOT NULL AUTO_INCREMENT
,`price` int(11) NOT NULL
,`sold_date` datetime NOT NULL
,PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
INSERT INTO `units` (`id`, `price`, `sold_date`) VALUES
(1, 10, '2015-08-02 00:00:00'),
(2, 11, '2015-08-03 00:00:00'),
(3, 14, '2015-08-03 00:00:00'),
(4, 3, '2015-08-04 00:00:00');
Result
date price
---------- -----
2015-07-07 0
2015-07-08 0
2015-07-09 0
2015-07-10 0
2015-07-11 0
2015-07-12 0
2015-07-13 0
2015-07-14 0
2015-07-15 0
2015-07-16 0
2015-07-17 0
2015-07-18 0
2015-07-19 0
2015-07-20 0
2015-07-21 0
2015-07-22 0
2015-07-23 0
2015-07-24 0
2015-07-25 0
2015-07-26 0
2015-07-27 0
2015-07-28 0
2015-07-29 0
2015-07-30 0
2015-07-31 0
2015-08-01 0
2015-08-02 10
2015-08-03 25
2015-08-04 3
2015-08-05 0