I have an Oracle Forms application. In the menu options I need to provide an option to open another application. I am using Replace_menu (File_Name) option to change the menu options of the new application.
The fmx file which I need to invoke is in a different folder but in the same parent directory.
If I pass the whole path including the file name this options works fine, however if I try to use the relative path it fails.
Consider I have the following folder structure:
C:\Sample\Sup
Forms1 and Forms2 are 2 folders.
The first application is in Forms1. I need to invoke form_menu.mmx inside Forms2 folder.
eg: Replace_menu(c:\Sample\Sup\Forms2\form_menu.mmx) - This works fine.
eg: Replace_menu(../Forms/form_menu.mmx) - Does not work
You only have a few options:
Include the full path in the code
Include the fully qualified path in FORMS_PATH
Pass the path in at runtime as a parameter.
Relative paths are not permitted.
Related
I'm using ReactJS to build a site, and I want to create a link (a href="relativepath") to a local HTML file so that when the user clicks on the link, it'll open up the html page. The local file is in a different folder X outside of the project, and I don't want to upload it into my src folder because the html file depends on a lot of other files in X. Is there a good way to do so?
I also want to upload a different local HTML file that is already within the src folder of my React App. I currently have something like this:
import htmlFile from "../links/htmlFile.html"; export default function Something(props) { return (<a href={htmlFile}></a>)}
and it says in my terminal that
You may need an appropriate loader to handle this file type, currently no loaders are configured to process this file. See https://webpack.js.org/concepts#loaders
> <html>| | <head> >
I already tried adding in webpack + an htmlLoader, but I think I followed the steps incorrectly as I wasn't able to get it to work. I uninstalled those packages, so I'm now back to square one.
Thank you so much!
Just linking to or importing from a local file in some other location won't work unless those local files are also deployed to the server in the same location relative to the app (and the web server has access to that location).
So you'll need to copy the file and its linked dependencies in a folder that will be deployed along with your react build, but not where it'll get treated as part of the react codebase so webpack will try to compile it (so not in src either).
If you used create-react-app to set up your application, for example, this would be the public folder; other webpack setups may use different names but the general concept is the same.
In PhpStorm (as well as other JetBrains IDEs, I'm sure), I'm setting up a File Watcher. In the Watcher Settings section, it asks me to specify the path to the program to be executed.
I want to use the executable file within the node_modules/.bin directory of my project. I don't want it installed globally because I may have other projects that use the same program, but may require a different version.
I could simply specify the absolute path to my project's node_modules/.bin directory, but then if I move the project, the file watcher will break.
In the Arguments and Output paths to refresh fields just below the Program field, it allows you to insert a macro, like $Projectpath$. This is exactly what I need, but it doesn't look like the Program field allows that.
Is there a way to specify a relative path for the Program field?
Here is a screenshot of the File Watcher setup window:
I could simply specify the absolute path to my project's node_modules/.bin directory, but then if I move the project, the file watcher will break.
That's not true -- at very least it does not break anything here -- got 3 projects that use local stuff.
Is there a way to specify a relative path for the Program field?
Sure. Use full path to the program :)
Internally (in config file) it will be stored using $PROJECT_DIR$ (AFAIK) special macro/variable but in actual field (in that dialog window) you will always see full path. Such conversion is done automatically.
You can read a bit more here (in comments): https://youtrack.jetbrains.com/issue/WEB-24376
If you are using the same project on different computers ... where path to the same program will be different but outside of the project (e.g. stored inside user-specific folder and user logins/names are different on such computers) ... you could use Path Variables functionality (Settings/Preferences | Appearance & Behavior | Path Variables) and specify the same variable on all of such computers that would point to correct path on that computer. IDE will automatically use that path variable to store the path.
So .. on one computer MY_TOOL_PATH will be pointing to /Users/Joe/MyTool and on another it could be /Users/Sam/AnotherTool.
I've started using a task runner to export all of my folders into a distribution folder using Gulp. The problem arises when I export images into the distribution folder, the path name is different from the one I'm using in my src file. So, as an example, when I target an image in HTML I type:
/assets/images/example.jpg
However, when the HTML file is distributed, it is supposed to target:
/images/example.jpg
It's still pointing to the assets folder, and creates a dead link. Should I be using a module like gulp-replace to automatically change these path names? Or should I just type in the assumed path name? Or, is there another method that I'm missing?
Sorry if I've phrased this badly, I'm working towards a new developer environment - let me know if I can provide you with any other details.
Should I be using a module like gulp-replace to automatically change
these path names?
Yes, gulp-replace will do the trick.
As an alternative you can place your index.html file into assets folder, so you don't need to change any paths when distributing the project.
currently in my test scripts for automated file upload to browser, the paths are already defined in the value column
command type
target //input[#type='file']
value /Users/.../.../.../filename.extension
in such cases, this script is unable to run on other computers because the path would be different.
my question will be is
is there a way to locate the file in a general folder (for example file is downloaded and in the "download" folder), by using selenium ide can we get the path of the file (/Users/.../downloads/filename.extension)
store the path of the file with its extension into a notepad which i will be using it for multiple test of file uploads later on.
right now if my colleague needs to run the script from his computer, he have to manually change the value to his path.
You could use a suite file that contains a "setup" file to only change the file name in 1 place and the variable is shared across tests in the suite. You could also select an agreed up on place to store the files: c:\test_info\image.jpg.
Or you can make the file available by URL & not local, Unfortunately javascript prevents that for security: How to get the current file path in javascript
Unfortunately I can't think of any other good way unless you all have the same path in a home directory and could do something like ~/test_dir/photo.jpg
i have a directory path of the computer and i will like to create a tree of that directory path.
For example, If i have a directory path of the desktop, i will like to create a tree of all the folders in the desktop and the subfolders.
The only way i can think of is to create a fileSystemTree object and set the directory to the path i want. If i were to set the directory as Desktop, it immediately show the folders under the desktop directory and not the Desktop root folder first.
So you'll need to use Tree control.
http://help.adobe.com/en_US/flex/using/WS2db454920e96a9e51e63e3d11c0bf69084-7d80.html
The trick is going to be adding the child nodes at runtime upon clicking open. A dataProvider has several methods that you implement on a dataProvider for retrieving the children. That's not to hard by creating your own dataProvider, but that's the first step. Write a FileCollection that conforms to the model. Read the manual and it should be pretty easy.