I'm trying to export multiple MySQL tables into a single CSV file, these tables have different number of columns and have nothing in common. An example is below:
table1:
ID| Name
1 | Ted
2 | Marry
null| null
table2:
Married| Age | Phone
Y | 35 | No
N | 25 | Yes
Y | 45 | No
The result that I want to get is:
ID| Name | Married | Age | Phone
1 | Ted | Y | 35 | No
2 | Marry | N | 25 | Yes
null| null | Y | 45 | No
Is it possible to do using MySQL commands? I have tried all types of join but it doesn't give me the result that I need.
Try this query:
SELECT * FROM
(SELECT #n1:=#n1+1 as 'index', Table1.* FROM Table1, (select #n1:=0)t)t1
natural join (SELECT #n2:=#n2+1 as 'index', Table2.* FROM Table2, (select #n2:=0)t1)t2 ;
You can see in this fiddle a working example.
In the example we generate an index column for Table1 and Table2 and natural join the 2 tables.
This way the join is done using the row position as returned by the SELECT of tables without any ORDER operator and usually this is not a good idea!
I'm not quite sure you understand what you are asking but sure you can join two tables without really caring on which rows will be matched:
SET #i1=0;
SET #i2=0;
SELECT * INTO OUTFILE 'xyz' FIELDS TERMINATED BY ','
FROM (SELECT #i1:=#i1+1 as i1, table1.* FROM table1) AS a
JOIN (SELECT #i2:=#i2+1 as i2, table2.* FROM table2) b ON (a.i1=b.i2);
Related
I am trying to get different values on rows of one table, and I can't think of how to that.
Lets say for example:
table1
id | name | empCode | insCode
1 John | E101 | I101
table2
id | code | name | role
1 | E101 | Mich | 2
2 | I101 | Bran | 3
table1 has reference id of table2, and empCode and insCode in table1 dependes on code and role in table2.
What I want is like this:
id | code | name | empCode | insCode | role |
1 | ? | John | E101 | I101 | ? |
I honestly don't know if its possible to retrieve multiple rows in same table in one select query.
If its not, what other possible solutions can I go with?
There is problem in your table design but you can get as your expected with below query:
select
result1.id,
result1.code,
result1.name,
result1.empCode,
result1.insCode,
result1.role as role_of_empCode,
result2.role as role_of_insCode
from (
SELECT tbl1.id,
tbl2.code,
tbl1.name,
tbl1.empCode,
tbl1.insCode,
tbl2.role
FROM `table2` tbl2
INNER JOIN `table1` tbl1
on tbl2.code = tbl1.empCode
) as result1,
`table2` result2
where result1.insCode = result2.code
ORDER BY result1.id;
You can check in this link!
Try something like:
SELECT a.*, b.role FROM
table1 a inner join table2 b on a.id=b.id
Also you may want to consider removing empcode and inscode from table 2 since its being redundant in table 1 OR vice versa depending on what your objectives are.
For fast searching table , I need to separate a large table to two tables
example table:
+--------+--------+-------+------+
| source | target | count | prob |
+--------+--------+-------+------+
| test1 | test2 | 2 | 1 |
| cat | dog | 3 | 1.5|
| dog | cat | 1 | 0.5|
+--------+--------+-------+------+
Using the code below
INSERT INTO Table2 (source,target,count,prob)
SELECT source,target,count,prob FROM Table1 WHERE count <2;
then delete originals
DELETE FROM Table1 WHERE count<2;
And count will grouping up after separating table in Table1, and new same element will increase after separating.
For example:
source = 'dog' and target = 'cat' and count = 1 will be move to Table2 and Table1 will still grouping up like add the count or will be add new row source = 'dog' target ='cat' , count = 3.
How could I combine Table1 and Table2 (Table2 will not change after separating)
You can combine the result with UNION
SELECT source, target, count, prob FROM tbl1
UNION
SELECT source, target, count, prob FROM tbl2
Just note there are lots of better ways to get better performance on large tables
I have two tables
Table: color_document
+----------+---------------------+
| color_id | document_id |
+----------+---------------------+
| 180907 | 4270851 |
| 180954 | 4270851 |
+----------+---------------------+
Table: color_group
+----------------+-----------+
| color_group_id | color_id |
+----------------+-----------+
| 3 | 180954 |
| 4 | 180907 |
| 11 | 180907 |
| 11 | 180984 |
| 12 | 180907 |
| 12 | 180954 |
+----------------+-----------+
Is it possible for a query to get a result that looks something like this using multiple color id's to join the two tables?
Result
+----------------+--------------+
| color_group_id | document_id |
+----------------+--------------+
| 12 | 4270851 |
+----------------+--------------+
Since Color Group 12 is the only group that has the exact same set of Colors that Document 4270851 has.
I've got some bad data that i'm being forced to work with so I've had to manufacture the color groups by finding each unique set of color_id's associated with document_id's. I'm trying to then create a new relationship directly between my manufactured color groups and documents.
I know I could probably do something with a GROUP_CONCAT to make a pseudo key of concatenated color ids, but I'm trying to find a solution that would also work in, say, Oracle. Am I barking up the completely wrong tree with this logic?
My ultimate goal is to be able to have a single row in a table that would represent any number of Colors that are associated with a Document to be exported to a completely different system than the one I'm working with.
Any thoughts/comments/suggestions are greatly appreciated.
Thank you in advance for looking at my question.
Do a normal join of the two tables, and count the number of rows in each pairing. Then test whether this is the same as the number of times each of the items appears in the original tables. If all are the same, then all color IDs must match.
SELECT a.color_group_id, a.document_id
FROM (
SELECT color_group_id, document_id, COUNT(*) ct
FROM color_document d
JOIN color_group g ON d.color_id = g.color_id
GROUP BY color_group_id, document_id) a
JOIN (
SELECT color_group_id, COUNT(*) ct
FROM color_group
GROUP BY color_group_id) b
ON a.color_group_id = b.color_group_id and a.ct = b.ct
JOIN (
SELECT document_id, COUNT(*) ct
FROM color_document
GROUP BY document_id) c
ON a.document_id = c.document_id and a.ct = c.ct
SQLFIDDLE
If i understand your question correct you just have to join the two tables and then group the results by color_group_id an document_id.
SQL Fiddle
select color_group_id, document_id
from
color_document cd join
color_group cg
on cd.color_id = cg.color_id
group by color_group_id, document_id
That query will give you this result set:
COLOR_GROUP_ID DOCUMENT_ID
3 4270851
4 4270851
11 4270851
12 4270851
Is that what you want?
I have a table
--------------------
ID | Name | RollNO
--------------------
1 | A | 18
--------------------
2 | B | 19RMK2
--------------------
3 | C | 20
--------------------
My second table is
-----------------------
OldRollNo | NewRollNo
-----------------------
18 | 18RMK1
-----------------------
19 | 19RMK2
-----------------------
20 | 20RMK3
-----------------------
21 | 21RMK4
-----------------------
22 | 22RMK5
-----------------------
I want the resulting table like
----------------------------------
ID | Name | RollNo | LatestRollNo
----------------------------------
1 | A | 18 | 18RMK1
----------------------------------
2 | B | 19RMK2 | 19RMK2
----------------------------------
3 | C | 20 | 20RMK3
----------------------------------
What would be the select query like? This is just the replica of my problem. I have used CASE Statement with the select query but as the records in my table is large, it's taking too much time. In my second table the OldRollNo Column is unique.One more thing is that in the resultant RollNo column if the newly assigned RollNo is already present then it should be copied exactly to the next column i.e LatestRollNo. I have to check only those RollNo which are old.
Thanks.
Try something like this:
select t1.ID
, t1.Name
, t1.RollNO
, LatestRollNO = coalesce(n.NewRollNo, o.NewRollNo)
from t1
left join t2 o on t1.RollNO = o.OldRollNo
left join t2 n on t1.RollNO = n.NewRollNo
SQL Fiddle with demo.
It sounds like your issue is performance not logic; something like this should hopefully allow approriate index usage assuming you have the appropriate indexes on t2.OldRollNo and t2.NewRollNo.
The problem with OR or CASE in a WHERE clause is that these don't always lend themselves to efficient queries; hopefully this will be a bit more useful in your case.
select f.ID, f.name, f.RollNo, s.NewRollNo as "Latest RollNo"
from FirstTable f
inner join
SecondTable s on f.RollNo = s.OldRollNo or f.RollNo = s.NewRollNo
select t.id,t.name,t.rollno,tt.newrollno as latestrollno from
talble1 t
left join
table2 tt on t.rollno = tt.oldrollno
You need to use inner join.
SELECT t1.ID,t1.Name,t2.RollNo,t2.NewRollNo AS LatestRollNo
FROM Table1 t1
INNER JOIN Table2 t2
ON t1.RollNo=t2.OldRollNo OR t1.RollNo=t2.NewRollNo
Alright so I have a table, in this table are two columns with ID's. I want to make one of the columns distinct, and once it is distinct to select all of those from the second column of a certain ID.
Originally I tried:
select distinct inp_kll_id from kb3_inv_plt where inp_plt_id = 581;
However this does the where clause first, and then returns distinct values.
Alternatively:
select * from (select distinct(inp_kll_id) from kb3_inv_plt) as inp_kll_id where inp_plt_id = 581;
However this cannot find the column inp_plt_id because distinct only returns the column, not the whole table.
Any suggestions?
Edit:
Each kll_id may have one or more plt_id. I would like unique kll_id's for a certain kb3_inv_plt id.
| inp_kll_id | inp_plt_id |
| 1941 | 41383 |
| 1942 | 41276 |
| 1942 | 38005 |
| 1942 | 39052 |
| 1942 | 40611 |
| 1943 | 5868 |
| 1943 | 4914 |
| 1943 | 39511 |
| 1944 | 39511 |
| 1944 | 41276 |
| 1944 | 40593 |
| 1944 | 26555 |
If you do mean, by "make distinct", "pick only inp_kll_ids that happen just once" (not the SQL semantics for Distinct), this should work:
select inp_kll_id
from kb3_inv_plt
group by inp_kll_id
having count(*)=1 and inp_plt_id = 581;
Get all the distinct first (alias 'a' in my following example) and then join it back to the table with the specified criteria (alias 'b' in my following example).
SELECT *
FROM (
SELECT
DISTINCT inp_kll_id
FROM kb3_inv_plt
) a
LEFT JOIN kb3_inv_plt b
ON a.inp_kll_id = b.inp_kll_id
WHERE b.inp_plt_id = 581
in this table are two columns with
ID's. I want to make one of the
columns distinct, and once it is
distinct to select all of those from
the second column of a certain ID.
SELECT distinct tableX.ID2
FROM tableX
WHERE tableX.ID1 = 581
I think your understanding of distinct may be different from how it works. This will indeed apply the where clause first, and then get a distinct list of unique entries of tableX.ID2, which is exactly what you ask for in the first part of your question.
By making a row distinct, you're ensuring no other rows are exactly the same. You aren't making a column distinct. Let's say your table has this data:
ID1 ID2
10 4
10 3
10 7
4 6
When you select distinct ID1,ID2 - you get the same as select * because the rows are already distinct.
Can you add information to clear up what you are trying to do?