SQL Select All Record In Each Group (Name, DOB) - mysql

Question

I have table with ID DOB AMOUNT RECEIVER_NAME SENDER_NAME SETTLE_FEE columns.
Sample Data
ID DOB AMOUNT RECEIVER_NAME SENDER_NAME SETTLE_FEE
-------------------------------------------------------------------
1 10-06-1990 100 Jose Benn 12
2 12-06-1990 200 Jim Mike 12
3 10-06-1990 300 Kate Benn 12
4 12-06-1990 100 Amy Mike 12
5 10-06-1990 200 Alison Benn 12
6 12-06-1990 300 Mary Mike 12
Expected result
ID DOB SENDER_NAME
---------------------------
1 10-06-1990 Benn
|--------AMOUNT RECEIVER_NAME SETTLE_FEE
100 Jose 12
300 Kate 12
200 Alison 12
2 12-06-1990 Mike
|--------AMOUNT RECEIVER_NAME SETTLE_FEE
200 Jim 12
100 Amy 12
300 Mary 12
I need to get all the data of each sender name.
I tried using group_concat(), But, it can take only 1024 characters.
So, what is the efficient way to achieve this scenario.
I can't use PL/SQL and no session related values allowed.
I need all the receiver's name, amount, fee for all the sender_name. What is the efficient way to do it.
Thanks,
Jose

Answer 1

There is a solution:
Just use an ORDER BY:
SELECT ID, DOB,SENDER, AMOUNT, RECEIVER_NAME, SETTLE_FEE
FROM inputTable
ORDER BY SENDER,DOB;
In displaying as you want the data, you just use code like (dummy code, javscriptish):
var previousSender="";
while(var row=db.fetch()) {
if(row.sender!=previousSender) {
console.log(id+" "+row.dob+" "+row.sender);
previousSend=row.sender();
} else {
console.log(" |-------"+row.amount+" "+row.receiver_name+" "+row.settle_fee);
}
}
As you can see: id is random since it has no relation to the dob or sender in your model. It is just a row counter.