I have a table of people, and I want to pull the most recent record of event, but there may not be one.
So my problem is that even though I'm left joining to make sure I'm getting a record for each person, I'm only bringing back people that have events because I'm pulling the Max of a date as a criteria.
SELECT *
FROM tbl_people
LEFT JOIN tbl_events ON
tbl_people.People_UID = tbl_events.People_UID
WHERE tbl_people.Active = 1
AND (
SELECT MAX(Event_Date) FROM tbl_events
)
Table People would have the following
People_UID
Table Events would have the following
Event_UID, People_UID, Event_Name, Event_Date
Like I said, what I'd like is an output like this:
Jen, Had a Baby, 7/10/2015
Shirley
Susan
Megan, Had a Baby, 8/5/2014
etc.
I hope that makes sense.
select * from
( SELECT *, row_number() over (partition by tbl_people.name order by tbl_events.Event_Date desc) as rn
FROM tbl_people
LEFT JOIN tbl_events
ON tbl_people.People_UID = tbl_events.People_UID
WHERE tbl_people.Active = 1 ) t
where t.rn = 1
It depends on the database.
If you're using MySQL, you could simply put the correlated subquery into the on clause of the outer join like this:
select *
from tbl_people p
left join tbl_events_latest e
on p.people_uid = e.people_uid
and e.event_date =
(select max(x.event_date) from tbl_events x where x.people_uid = e.people_uid)
where p.active = 1
In other databases, that might not be so. For example, in Oracle, you'd get an error. You could alternatively run:
with tbl_events_latest as
(select *
from tbl_events e
where event_date = ( select max(x.event_date)
from tbl_events x
where x.people_uid = e.people_uid ) )
select *
from tbl_people p
left join tbl_events_latest e
on p.people_uid = e.people_uid
where p.active = 1
One way to do this is to use a correlated subquery in the join that checks that there doesn't exists any event for the same person with a later date:
SELECT *
FROM tbl_people p
LEFT JOIN tbl_events e
ON p.People_UID = e.People_UID
AND NOT EXISTS (
SELECT 1 FROM tbl_Events
WHERE e.People_UID = People_UID
AND Event_Date > e.Event_Date
)
WHERE p.Active = 1
It might not be the most efficient solution though; maybe limiting the left joined set first is better. (Or come to think of it the exists should be better).
Given a sample data set like:
People_UID Event_UID People_UID Event_Name Event_Date
Jen 1 Jen Had a Baby 2015-07-10
Jen 3 Jen Bought a horse 2013-07-10
Shirley NULL NULL NULL NULL
Susan NULL NULL NULL NULL
Megan 2 Megan Had a Baby 2014-08-05
Megan 4 Megan Had another Baby 2015-08-05
This would be the result:
People_UID Event_UID People_UID Event_Name Event_Date
Jen 1 Jen Had a Baby 2015-07-10
Shirley NULL NULL NULL NULL
Susan NULL NULL NULL NULL
Megan 4 Megan Had another Baby 2015-08-05
Using joins it could look like this:
SELECT *
FROM tbl_people p
LEFT JOIN (
SELECT e.*
FROM tbl_events e
JOIN (
SELECT PEOPLE_UID, MAX(EVENT_DATE) MDATE
FROM tbl_Events GROUP BY People_UID
) A ON A.MDATE = E.event_date AND e.People_UID = A.People_UID
) B ON p.People_UID = b.People_UID
WHERE p.Active = 1
In case of Sql Server you can use OUTER APPLY:
SELECT *
FROM tbl_people p
OUTER APPLY(SELECT TOP 1 Event_Date
FROM tbl_events e
WHERE p.People_UID = e.People_UID
ORDER BY Event_Date DESC)oa
WHERE p.Active = 1
Or if you want to select just date then:
SELECT *
FROM tbl_people p
OUTER APPLY(SELECT MAX(Event_Date) AS Event_Date
FROM tbl_events e
WHERE p.People_UID = e.People_UID)oa
WHERE p.Active = 1
Related
I have two tables as follow:
table internetclient
(id,full_name,location,phone_number)
table internetclientdetails
(incdid,icid,date_sub, date_exp,isPaid,profile_sub)
the data in two table is as follow:
client
--------------------------------------------------------
id full_name location phone_number
-------------------------------------------------------
4 Joe Amine beirut 03776132
5 Mariam zoue beirut 03556133
client_subscription
--------------------------------------------------------------------------
incdid icid date_sub date_exp isPaid sub_price
----------------------------------------------------------------------------
6 4 2018-01-01 2018-01-30 0 2000
7 5 2017-01-01 2017-01-30 0 1000
8 4 2018-03-01 2018-03-30 1 50000
9 5 2018-05-01 2019-05-30 1 90000
note : incdid stands for internetClientDetailsId
and icid stands for internetClientId
Problem
I want to make a query that return client name along with all details depending on the latest client subscription date, the result should be as follow:
------------------------------------------------------------
full_name client_id date_sub sub_price
------------------------------------------------------------
Joe Amine 4 2018-03-01 50000
Mary 5 2018-05-01 90000
What i am tring
SELECT * FROM client c LEFT JOIN client_subscription c_s on c.id=c_s.client_id
UNION
SELECT * FROM client c RIGHT JOIN client_subscription c_S on c.id=c_s.client_id
WHERE
c.sub_date=(SELECT MAX(sub_date) from client_subscription c_s INNER JOIN client c on c.id=c_s.client_id GROUP BY c_s.client_id
i have been working on it all the night. Any help is appreciated a lot.
To get client_subscription for each client you could use a self join
select c.name, a.client_id, a.date_sub, a.sub_price
from client_subscription a
join (
select client_id, max(date_sub) date_sub
from client_subscription
group by client_id
) b on a.client_id = b.client_id and a.date_sub = b.date_sub
join client c on a.client_id = c.id
order by a.date_sub
Demo
Or using left join
select c.name, a.client_id, a.date_sub, a.sub_price
from client_subscription a
left join client_subscription b on a.client_id = b.client_id and a.date_sub < b.date_sub
join client c on a.client_id = c.id
where b.client_id is null
order by a.date_sub
Demo
Using your updated data set updated queries are
select c.full_name, a.icid, a.date_sub, a.sub_price
from internetclientdetails a
join (
select icid, max(date_sub) date_sub
from internetclientdetails
group by icid
) b on a.icid = b.icid and a.date_sub = b.date_sub
join internetclient c on a.icid = c.id
order by a.date_sub;
select c.full_name, a.icid, a.date_sub, a.sub_price
from internetclientdetails a
left join internetclientdetails b on a.icid = b.icid and a.date_sub < b.date_sub
join internetclient c on a.icid = c.id
where b.icid is null
order by a.date_sub
Updated Demo
Hi try below sample might help you.
DECLARE #tblClient AS TABLE (ID INT , Name varchar(100))
DECLARE #tblClientSub As TABLE (id INT,client_id INT,date_sub DATE,sub_price INT)
INSERT INTO #tblClient (id,Name)
VALUES
(1,'Linda'),
(2,'Mary'),
(3,'Joe')
INSERT INTO #tblClientSub(Id,client_id , date_sub , sub_price)
VALUES
(1,1,'2018/01/01',50),
(2,2,'2018/02/01',50),
(3,2,'2018/03/01',30),
(4,2,'2018/04/01',30),
(5,3,'2018/01/01',50),
(6,3,'2018/07/01',50),
(7,1,'2018/02/01',40)
SELECT c.Id,c.Name,cs.date_sub,cs.sub_price
FROM #tblClient c
CROSS APPLY (SELECT TOP (1)date_sub,sub_price
FROM #tblClientSub
WHERE client_id = c.Id
ORDER BY date_sub DESC) cs
select c.name as 'client_name',cs.client_id,max(cs.sub_date) as 'date_sub',cs.sub_price from client c ,
client_subscription cs where cs.client_id=c.id group by cs.client_id,cs.sub_price;
Try this
SELECT c.Name, c.id , MAX(date_sub), sub_price FROM client c LEFT JOIN client_subscription c_s on c.id=c_s.client_id
GROUP BY c.id
ORDER BY c.id ASC
I have 3 table, log, member, also guest, but my log i stored as customer(user)'s id only, which is either their guest_id or member_id. So here's the problem, because they're from different table, I'm not sure how to join & group together their data.
checkout_log table
id user_id checkout_as
--------------------------------------
1 1 member
2 2 guest
members table
id fullname
--------------------------------------
1 member01
2 member02
guests table
id fullname
--------------------------------------
1 guest01
2 guest02
What I wanted to Achieve - Result
id user_id fullname checkout_as
----------------------------------------------
1 1 member01 member
2 2 guest02 guest
Had tried following sql statement with UNION ALL, or GROUP BY , but had no luck.
SELECT * FROM
(
SELECT checkout_log.id,checkout_log.user_id,guests.fullname,guests.email,checkout_log.checkout_as
FROM checkout_log
LEFT JOIN checkout_product ON checkout_product.checkout_log_id = checkout_log.id
LEFT JOIN guests ON checkout_log.user_id = guests.id
UNION ALL
SELECT checkout_log.id,checkout_log.user_id,members.fullname,members.email,checkout_log.checkout_as
FROM checkout_log
LEFT JOIN checkout_product ON checkout_product.checkout_log_id = checkout_log.id
LEFT JOIN members ON checkout_log.user_id = members.id
) derivedTable
GROUP BY id
Try doing this with joins instead of union
select cl.id, cl.user_id,
coalesce(m.fullname, g.fullname) as fullname,
cl.checkout_as
from checkout_log cl left join
members m
on cl.user_id = m.id and cl.checkout_as = 'member' left join
guests g
on cl.user_id = g.id and cl.checkout_as = 'guest';
Assume tables
team: id, title
team_user: id_team, id_user
I'd like to select teams with just and only specified members. In this example I want team(s) where the only users are those with id 1 and 5, noone else. I came up with this SQL, but it seems to be a little overkill for such simple task.
SELECT team.*, COUNT(`team_user`.id_user) AS cnt
FROM `team`
JOIN `team_user` user0 ON `user0`.id_team = `team`.id AND `user0`.id_user = 1
JOIN `team_user` user1 ON `user1`.id_team = `team`.id AND `user1`.id_user = 5
JOIN `team_user` ON `team_user`.id_team = `team`.id
GROUP BY `team`.id
HAVING cnt = 2
EDIT: Thank you all for your help. If you want to actually try your ideas, you can use example database structure and data found here: http://down.lipe.cz/team_members.sql
How about
SELECT *
FROM team t
JOIN team_user tu ON (tu.id_team = t.id)
GROUP BY t.id
HAVING (SUM(tu.id_user IN (1,5)) = 2) AND (SUM(tu.id_user NOT IN (1,5)) = 0)
I'm assuming a unique index on team_user(id_team, id_user).
You can use
SELECT
DISTINCT id,
COUNT(tu.id_user) as cnt
FROM
team t
JOIN team_user tu ON ( tu.id_team = t.id )
GROUP BY
t.id
HAVING
count(tu.user_id) = count( CASE WHEN tu.user_id = 1 or tu.user_id = 5 THEN 1 ELSE 0 END )
AND cnt = 2
Not sure why you'd need the cnt = 2 condition, the query would get only those teams where all of users having the ID of either 1 or 5
Try This
SELECT team.*, COUNT(`team_user`.id_user) AS cnt FROM `team`
JOIN `team_user` ON `team_user`.id_team = `team`.id
where `team_user`.id_user IN (1,5)
GROUP BY `team`.id
HAVING cnt = 2
I've spent a couple of days creating this rather complicated SQL statement, and it now gives me exactly what I want. Now I'm wondering if there is a better/simpler way to do it. Also MySQL wont let me CREATE VIEW on this statement
SELECT name, a.user, liste, c.order, total_1kr, total_5kr, total_8kr, total_10kr, total_paid, differens, sbdato, spaid, sbreg, sfdato, sforbrug, sfreg
FROM (SELECT t.user, t.paid AS spaid, t.dato AS sbdato, t.registrant AS sbreg FROM(
SELECT user,MAX(dato) AS maksdato
FROM g_kiosk_f WHERE paid!=0
GROUP BY user) AS x
JOIN g_kiosk_f AS t ON x.user =t.user
AND x.maksdato = t.dato) AS a
JOIN (SELECT s.user, (s.1kr+(s.5kr)*5+(s.8kr)*8+(s.10kr)*10) AS sforbrug, s.dato AS sfdato, s.registrant AS sfreg FROM(
SELECT user,MAX(dato) AS maksdato
FROM g_kiosk_f WHERE 1kr!=0 OR 5kr!=0 OR 8kr!=0 OR 10kr!=0
GROUP BY user) AS y
JOIN g_kiosk_f AS s ON y.user=s.user
AND y.maksdato=s.dato) AS b
JOIN (SELECT t1.name, t2.user, t1.liste, t1.order, sum( t2.1kr ) AS total_1kr, sum( t2.5kr ) *5 AS total_5kr, sum( t2.8kr ) *8 AS total_8kr, sum( t2.10kr ) *10 AS total_10kr, sum( t2.paid ) AS total_paid, ( sum( t2.1kr ) + sum( t2.5kr ) *5 + sum( t2.8kr ) *8 + sum( t2.10kr ) *10 - sum( t2.paid )) AS differens
FROM g_kiosk_users AS t1
INNER JOIN g_kiosk_f AS t2 ON t1.nr = t2.user
GROUP BY t2.user
ORDER BY t1.name ASC) AS c
ON a.user=b.user AND a.user=c.user
I have a table 'g_kiosk_f' containing id (user), date (dato), 5 kinds of transactions (1kr, 5kr, 8kr, 10kr, and paid) a cashier (registrant). Another table, 'g_kiosk_users', contains name and id (nr).
I want a result set showing
the date, registrant and amount of newest transaction where paid!=0
the date, registrant and amount of newest transaction where 1kr!=0, 5kr!=0, 8kr!=0 or 10kr!=0
the total difference of sum(1kr+5kr+8kr+10kr) and sum(paid)
So the result should look something like
Name | id | difference | newest paid date | newest paid registrant | newest paid amount | newest kr date | newest kr registrant | newest kr amount |
In the above I've included the numbers needed to do the difference calculation by hand, because it was needed at some point, but is now obsolete. Does any of this even make sense?
It seems like it should be possible to rewrite you query like this:
SELECT t1.name AS name, a.user AS user, t1.liste, t1.order,
SUM(t2.1kr) AS total_1kr, SUM(t2.5kr) * 5 AS total_5kr,
SUM(t2.8kr) AS total_8kr, SUM(t2.10kr) * 5 AS total_10kr,
SUM(52.paid) AS total_paid,
SUM(t2.1kr + 5 * tt.5kr + 8 * t2.8kr + 10 * t2.10kr)
-SUM(t2.paid) AS differens
a.dato AS sbdato, a.paid AS spaid, a.registrant as sbreg,
b.dato as sfdato,
(b.1kr+(b.5kr)*5+(b.8kr)*8+(b.10kr)*10) AS sforbrug,
b.registrant AS sfreg
FROM g_kiosk_f AS a
INNER JOIN (SELECT user, MAX(dato) FROM g_kiosk_f
WHERE paid != 0
GROUP BY user) AS a2
ON a.user = a2.user AND a.dato = a2.dato
INNER JOIN g_kiosk_f as b ON b.user = a.user
INNER JOIN (SELECT user, MAX(dato) FROM g_kiosk_f
WHERE 1kr!=0 OR 5kr!=0 OR 8kr!=0 OR 10kr!=0
GROUP BY user) AS b2
ON b.user = b2.user AND b.dato = b2.dato
INNER JOIN g_kiosk_f as t2 ON t2.user = a.user
INNER JOIN g_kiosk_users as t1 ON t1.nr = t2.user
GROUP BY a.user
ORDER BY name ASC
This is the current table layout.
There are 3 legs
Each leg has 2 points, where is_start = 1 is the start of the leg, and is_start is the end of the leg.
When the user check in at a point, a entry in points_user are created.
In this application you have multiple legs which has 2 points where one marks the start of the leg, where the other marks the end of the leg. So the sum of User's (with id = 2) Leg (with id= 1) is points_users.created where points_users.leg_id = 1 and points_users.user_id = 2 and points_users.is_start = 0 minus points_users where is_start = 1 (and the other parameters stay the same). And that's for just one leg.
What I would like is to sum all the time differences for each leg, we get the data like this:
| User.id | User.name | total_time |
| 1 | John | 129934 |
Anyone know how I can join these tables and sum it up grouped by user?
(No, this is not homework)
As far as I got:
SELECT
( `end_time` - `start_time` ) AS `diff`
FROM
(
SELECT SUM(UNIX_TIMESTAMP(`p1`.`created`)) AS `start_time`
FROM `points_users` AS `pu1`
LEFT JOIN `points` AS `p1` ON `pu1`.`point_id` = `p1`.`id`
WHERE `p1`.`is_start` = 1
) AS `start_time`,
(
SELECT SUM(UNIX_TIMESTAMP(`pu2`.`created`)) AS `end_time`
FROM `points_users` AS `pu2`
LEFT JOIN `points` AS `p2` ON `pu2`.`point_id` = `p2`.`id`
WHERE `p2`.`is_start` = 0
) AS `end_time`
Try this:
select users.user_id,
users.user_name,
SUM(timeDuration) totalTime
from users
join (
select
pStart.User_id,
pStart.leg_id,
(pEnd.created - pStart.created) timeDuration
from (select pu.user_id, pu.leg_id, pu.created
from points_users pu
join points p on pu.id = p.point_id and pu.leg_id = p.leg_id
where p.is_start = 1 ) pStart
join (select pu.user_id, pu.leg_id, pu.created
from points_users pu
join points p on pu.id = p.point_id and pu.leg_id = p.leg_id
where p.is_start = 0 ) pEnd
on pStart.user_id = pEnd.user_id
and pStart.leg_id = pEnd.leg_id
) tt
on users.user_id = tt.user_id
group by users.user_id, users.user_name
Subquery gets the time duration for each user/leg, and main query then sums them for all the legs of each user.
EDIT: Added the points table now that I can see your attempt at a query.
The simplest way is to join points_users to itself:
select leg_start.user_id, sum(leg_end.created - leg_start.created)
from points_users leg_start
join points_users leg_end on leg_start.user_id = leg_end.user_id
and leg_start.leg_id = leg_end.leg_id
join points point_start on leg_start.point_id = point_start.id
join points point_end on leg_end.point_id = point_end.id
where point_start.is_start = 1 and point_end.is_start = 0
group by leg_start.user_id
Some people prefer to put those is_start filters in the join condition, but since it's an inner join that's mainly just a point of style. If it were an outer join, then moving them from the WHERE to the JOIN could have an effect on the results.