I'm looking for a way to use component inside a cell, is there any way ?
I tried :
$this->loadComponent('SessionsActivity');
My Cell :
namespace App\View\Cell;
use Cake\Core\Configure;
use Cake\View\Cell;
class UserCell extends Cell
My query :
$user = $this->Users
->find()
->where([
'Users.id' => $this->request->id
])
->contain([
'Towns' => function ($q) {
return $q->find('short');
},
'Countries' => function ($q) {
return $q->find('short');
}
])
->map(function ($user) {
$user->online = $this->SessionsActivity->getOnlineStatus($user);
return $user;
})
->first();
Using the same example at the CakePHP cells documentation, suppose you want to show the inbox for the connected user. You'd want to access the Auth component to take the connected user id.
AFAIK, Cells act like view-controller, a view part display.ctp file, and a controller part where you access the model to generate data for the view.
I'm using CakePHP 3.0 and $this->_registry doesn't work.
You could try:
$this->SessionsActivity = $this->_registry->load('SessionsActivity');
it is another question if you should use a component here
Related
I have this code in my controller:
class ArchController extends Controller
{
public function actionIndex(string $date, array $rubric_id )
{
$articles = Article::find()->where('published < :date', [':date' => $date])
->andWhere(['in', 'rubric', $rubric_id])
->andWhere('ISNULL(arch)')->all();
...
It seems to me it is not safe because $rubric_id is user input. How can I make parametr binding, something like this:
':rubric_id' => $rubric_id
Yii uses parameter binding internally, so it is safe to use ->andWhere(['in', 'rubric', $rubric_id]). You can review implementation of InConditionBuilder to make sure of that.
I am trying to run simple test and insert two record in db via fixture dataFile.
What I get is :
[ReflectionException] Class C:\xampp\htdocs\codeception\frontend\tests/_data\user.php does not exist
The file is obviously there. My UserTest.php looks like this:
<?php
class UserTest extends \Codeception\Test\Unit
{
public function _fixtures()
{
return [
'class' => \frontend\tests\fixtures\UserFixture::className(),
'dataFile' => codecept_data_dir() . 'user.php'
];
}
public function testValidation()
{
$user = new \common\models\User();
$user->setUsername(null);
$this->assertFalse($user->validate(['username']));
$user->setUsername('aaaaaaaaaaaaaaaaaaaaaaaaaa');
$this->assertFalse($user->validate(['username']));
$user->setUsername('toma');
$this->assertTrue($user->validate(['username']));
}
public function testIfUserExist()
{
$this->tester->seeRecord('user', ['name' => 'Toma']);
}
}
I saw the linux like forward slash in the error but don't know how to change it. Not sure if this is the problem because I had the same path with some images and it was fine then. What can cause this ? Thank you!
You're using seeRecord() in a wrong way. First argument needs to by class name, including namespace, so you should use it like this:
$this->tester->seeRecord(\frontend\models\User::class, ['name' => 'Toma']);
I am passing static value to my following query, then it works well. If I change it dynamic, then it doesn't.
//works well
$users = $this->Users->find('all')
->where(['Users.role' => $role])
->innerJoinWith('UserDetail',function($query){
return $query->where(['UserDetail.state' => "chandigarh"]);
})->toArray();
// don't work
$state="chandigarh";
$users = $this->Users->find('all')
->where(['Users.role' => $role])
->innerJoinWith('UserDetail',function($query){
return $query->where(['UserDetail.state' => "$state"]);
})->toArray();
How can I pass my $state variable dynamic to this?
This is how PHP works, it's not really a CakePHP related problem
That variable is not available inside the scope of the anonymous function $query
see example 3 here: http://php.net/manual/en/functions.anonymous.php
You should inherit the variable from the parent scope by using the USE contruct like this:
$state="chandigarh";
$users = $this->Users->find('all')
->where(['Users.role' => $role])
->innerJoinWith('UserDetail',function($query) use ($state) {
return $query->where(['UserDetail.state' => $state]);
})->toArray();
you should remove "" that cover "$state" that should be: $query->where(['UserDetail.state' => $state]) not $query->where(['UserDetail.state' => "$state"])
I've got three tables
checkoutcounter {id, name}
user {id, username}
checkoutcounter_users { id, checkoutcounter_id, user_id}
I use gii and then add
in checkoutcounter model (I add and joinWith and find()->with but it still doesn't work):
public function getUser_display()
{
return $this->hasMany(User_display::className(), ['id' => 'user_id'])
->viaTable(CheckoutcounterUsers::tableName(), ['checkoutcounter_id' => 'id']
);
}
In checkoutcounter model search:
public function search($params)
{
$query = FinanceSettingsCheckoutcounter::find()->with('user_display');
$query->joinWith('user_display');
}
what should I add in checkoutcounter view to get usernames or user id's? Why when I add in gridview 'attribute'=>'user_display.id' it doesn't display any data?
echo yii\helpers\Json::encode($dataProvidercheckoutcounter);
shows
{"query":{"sql":null,"on":null,"joinWith":[[["user_display"],true,"LEFT JOIN"]],"select":null,"selectOption":null,"distinct":null,"from":null,"groupBy":null,"join":null,"having":null,"union":null,"params":[],"where":null,"limit":null,"offset":null,"orderBy":null,"indexBy":null,"modelClass":"app\\models\\FinanceSettingsCheckoutcounter","with":["user_display"],"asArray":null,"multiple":null,"primaryModel":null,"link":null,"via":null,"inverseOf":null},"key":null,"db":null,"id":null}
Im not sure how you're using your search() function, but you're not using $params.. And its not returning the results..
I belive the query should be like this:
public function search($params)
{
$result = FinanceSettingsCheckoutcounter::find()->with('user_display')->all();
echo yii\helpers\Json::encode($result);
}
if you are using this as part of a Search Model, returning a dataProvider, check out this link
http://www.ramirezcobos.com/2014/04/16/displaying-sorting-and-filtering-model-relations-on-a-gridview-yii2/
I am trying to create a JsonModel with an item in the variables 'html' containing the current rendered view. I would like to add this code to an event:
rather than this method: How to render ZF2 view within JSON response? which is in the controller, I would like to automate the process by moving it to an Event
I have the strategy in my module.config.php:
'strategies' => array(
'ViewJsonStrategy',
)
I have set up a setEventManager in the controller:
$events->attach(MvcEvent::EVENT_RENDER, function ($e) use ($controller) {
$controller->setRenderFormat($e);
}, -20);
Is this the best event to attach it to? would the RENDER_EVENT be better?
Now I would like to change the render of the page based on !$this->getRequest()->isXmlHttpRequest(), (commented out for debug)
public function setRenderFormat($e)
{
//if(!$this->getRequest()->isXmlHttpRequest())
//{
$controller = $e->getTarget();
$controllerClass = get_class($controller);
//Get routing info
$controllerArr = explode('\\', $controllerClass);
$currentRoute = array(
'module' => strtolower($controllerArr[0]),
'controller' => strtolower(str_replace("Controller", "", $controllerArr[2])),
'action' => strtolower($controller->getEvent()->getRouteMatch()->getParam('action'))
);
$view_template = implode('/',$currentRoute);
$viewmodel = new \Zend\View\Model\ViewModel();
$viewmodel->setTemplate($view_template);
$htmlOutput = $this->getServiceLocator()->get('viewrenderer')->render($viewmodel, $viewmodel);
$jsonModel = new JsonModel();
$jsonModel->setVariables(array(
'html' => $htmlOutput,
'jsonVar1' => 'jsonVal2',
'jsonArray' => array(1,2,3,4,5,6)
));
return $jsonModel;
//}
}
Strangely, (or not) this code works and produces the $jsonModel, however is doesn't overwite the normal HTML view with the json, but the same code (without the event) in a controller method, overwrites perfectly.
p.s Is there a better method to do the whole concept?
p.p.s how can I obtain the current View Template from within the controller, without resorting to 8 lines of code?
Thanks in advance!
Aborgrove
you are returning the view model from an event I thinks this doesn't have any effect in current viewmanager view model, fetch the current viewmodel from viewmanager and call setTerminal(true). or replace the created jsonmodel using the viewmanager