Display only one row for values that appear multiple times - mysql

I have multiple rows with the same name in this table, and I want to show only one of row of each. For example, with the following data:
| name | number |
+------+--------+
| exe | 1 |
| exe | 10 |
| exe | 2 |
| bat | 1 |
| exe | 3 |
| bat | 4 |
I would like to see the following results:
| name | number |
+------+--------+
| exe | 16 |
| bat | 5 |
How can I achieve this result?
Duplicate response: My question only have 1 table, the JOIN ..ON command creates confusion in understanding, i think this simple question can help many guys!

Try something like this:
SELECT t.`name`, SUM(t.`number`) AS `number`
FROM mytable t
GROUP BY t.`name`
ORDER BY `number` DESC
let the database return the result you want, rather than mucking with returning a bloatload of rows, and collapsing them on the client side. There's plenty of work for the client to do without doing what the database can do way more efficiently.

You can use an aggregation function for this:
SELECT name, SUM(number) AS total
FROM myTable
GROUP BY name;
Here is a reference on aggregate functions, and here is an SQL Fiddle example using your sample data.

Related

Separating a comma separated string to a new table

I inherited a project that has comma separated strings stored in a field called 'subsector' in a table named 'com_barchan_project'. I need to change this horrible design, since it's proving to be an issue trying to parse through this field. See HERE for the full story:
| id | name | sector | subsector |
+----+------+--------+-----------+
| 1 | test | 2 | 3,4,7 |
+----+------+--------+-----------+
| 2 | door | 5 | 2 |
I have created a new table called 'com_barchan_project_subsector_join' with the required fields and would like to move the values stored in 'com_barchan_project' to this new empty table.
Can anyone help me with the SQL statement that would accomplish this?
Here's what the new 'com_barchan_project_subsector_join' table should look like:
| id | project_id | subsector_id |
+----+------------+--------------+
| 1 | 1 | 3 |
+----+------------+--------------+
| 2 | 1 | 4 |
+----+------------+--------------+
| 3 | 1 | 7 |
+----+------------+--------------+
| 4 | 2 | 2 |
Once I move over the data, I will remove the 'subsector' field from the 'com_barchan_project' table and be done with it.
Thanks for your help!!!
John
Using shorter table names for brevity/clarity; and assuming you have (or can easily make) a comprehensive subsectors table...and assuming your csv are stored in a consistent format (no spaces at least).
INSERT INTO `project_subsectors` (project_id, subsector_id)
SELECT p.id, s.id
FROM projects AS p
INNER JOIN subsectors AS s ON p.subsector = s.id
OR p.subsector LIKE CONCAT(s.id, ',%')
OR p.subsector LIKE CONCAT('%,', s.id, ',%')
OR p.subsector LIKE CONCAT('%,', s.id)
;
I can't guarantee it will be fast; I'd be surprised if it was.
ON FIND_IN_SET(s.id, p.subsector) > 0 may work as well, but I am not as familiar with the behavior of that function.

MySQL query to SELECT rows with LIKE and create new column containing the matched string

I need some help with a MySQL query I am struggling for some time now.
So, I am trying to create a MySQL query to SELECT rows from a table that match a specific string like app.
My table is like this:
+-----+--------------+
| id | name |
+-----+--------------+
| 1 | Green Apple |
| 2 | Big Orange |
| 3 | application |
+-----+--------------+
I can find all rows that contain app string with SELECT and LIKE.
However, I also want to create new column that contains the string from name column which matches app and keep the database case sensitive format, i.e. with app as a match phrase the new column will contain App and app entires according to the string format in name.
My query so far goes like this:
SELECT *, 'what_to_put?' as new_column FROM table WHERE name LIKE '%".$app."%'
The desired output is the following:
+-----+--------------+-------------+
| id | name | new_column |
+-----+--------------+-------------+
| 1 | Green Apple | App |
| 2 | application | app |
+-----+--------------+-------------+
Any idea how to achieve this?
Without a separate regex library, you'll need to use the built-in string functions to find the location of the match, and then extract the matching sub-string:
SELECT
id,
name,
substring(name, locate('app', name), length('app')) as new_column
FROM yourTable
WHERE name LIKE '%app%'
Which gives the results:
+----+-------------+------------+
| id | name | new_column |
+----+-------------+------------+
| 1 | Green Apple | App |
| 3 | application | app |
+----+-------------+------------+
Sql Fiddle Here

MYSQL query fetching DATA from two table using IN method one as composition of multiple data

I have two tables
one as td_job which has these structure
|---------|-----------|---------------|----------------|
| job_id | job_title | job_skill | job_desc |
|------------------------------------------------------|
| 1 | Job 1 | 1,2 | |
|------------------------------------------------------|
| 2 | Job 2 | 1,3 | |
|------------------------------------------------------|
The other Table is td_skill which is this one
|---------|-----------|--------------|
|skill_id |skill_title| skill_slug |
|---------------------|--------------|
| 1 | PHP | 1-PHP |
|---------------------|--------------|
| 2 | JQuery | 2-JQuery |
|---------------------|--------------|
now the job_skill in td_job is actualy the list of skill_id from td_skill
that means the job_id 1 has two skills associated with it, skill_id 1 and skill_id 2
Now I am writing a query which is this one
SELECT * FROM td_job,td_skill
WHERE td_skill.skill_id IN (SELECT td_job.job_skill FROM td_job)
AND td_skill.skill_slug LIKE '%$job_param%'
Now when the $job_param is PHP it returns one row, but if $job_param is JQuery it returns empty row.
I want to know where is the error.
The error is that you are storing a list of id's in a column rather than in an association/junction table. You should have another table, JobSkills with one row per job/skill combination.
The second and third problems are that you don't seem to understand how joins work nor how in with a subquery works. In any case, the query that you seem to want is more like:
SELECT *
FROM td_job j join
td_skill s
on find_in_set(s.skill_id, j.job_skill) > 0 and
s.skill_slug LIKE '%$job_param%';
Very bad database design. You should fix that if you can.

MySQL: Sort by group and field

I have a table with the following (simplified) structure:
INT id,
INT type,
INT sort
What I need is a SELECT that sorts my data in a way, so that:
all rows of the same type are in sequency, sorted ascendingly by sort internally, and
all "blocks" of one type are sorted by their minimum sort.
Example:
If the table looks like this:
| id | type | sort |
| 1 | 1 | 3 |
| 2 | 3 | 5 |
| 3 | 3 | 1 |
| 4 | 2 | 4 |
| 5 | 1 | 2 |
| 6 | 2 | 6 |
The query should sort the result like this:
| id | type | sort |
| 3 | 3 | 1 |
| 2 | 3 | 5 |
| 5 | 1 | 2 |
| 1 | 1 | 3 |
| 4 | 2 | 4 |
| 6 | 2 | 6 |
I hope this makes it clear enough.
Looks to me, as this should be a very common requirement, but I didn't find any examples close enough to be able to transfer it to my use case on my own. I suppose I can't avoid at least one subquery, but I didn't figure it out on my own.
Any help is appreciated, thanks in advance.
By the way: I'm going to use this query with CakePHP 2.1, so if you know of a comfortable way to do it with Cake, please let me know.
This is simpler than it initially sounds. I believe the following should do the trick:
SELECT a.id, a.type, a.sort
FROM Some_Table as a
JOIN (SELECT type, MIN(sort) as min
FROM Some_Table
GROUP BY type) as b
ON b.type = a.type
ORDER BY b.min, a.type, a.sort
For best (fastest) results, you're probably going to want an index on (type, sort).
You want an additional sort by a.type (instead of (b.min, a.sort)), in case there are two groups with the same sort value (would result in mixed rows). If there are no duplicate values, you can remove it.
sort and type are reserved words on some databases and can cause you problems.
Have you tried?
ORDER BY TYPE DESC, SORT ASC

MySQL data in column wise which is stored in row based

I am having a table with data stored in row basis as shown below.
UID | DetailsID | Data|
----------------------|
1 | 1 | A |
1 | 2 | 200|
1 | 3 | 2010-10-11 08:32 |
2 | 1 | B |
2 | 2 | 600|
2 | 3 | 2011-05-20 14:56 |
From this I need the output as follows
UID|1|2|3
------------
1|A|200|2010-10-11 08:32
2|B|600|2011-05-20 14:56
Here main thing is, the number of entries of DetailsID values is not known.
I wanted this one in MySQL.
Please help me out of this.
Not quite what you want, but other than loads of left joins i can only suggest:
SELECT UID,GROUP_CONCAT(DetailsID SEPARATOR ",") "DetailsIDs",GROUP_CONCAT(Data SEPARATOR ",") "Data" FROM data_table GROUP BY UID;
Do that transformation in your coding language, not in SQL.
you didnt say where you need the output. If you need the output in PHP pages it is simple only by creating the loop for the entries in columns wise.