I have 2 tables.ms_expese and track_expense.Using this table generate a fact table
I want the expense_name in ms_expense,expense_amount from track_expense.
I want to get the sum of expense_amount for a particular expense_name based on date.The date in the order of 1,2...12 as month id
SELECT DATE_Format(a.date,'%b') as month_id,b.expense_name AS expense_type, sum(a.expense_amount) AS expense_amount FROM ms_expense b JOIN track_expense a on a.`expense_id`=b.`expense_id` group by DATE_Format(a.date,'%b')
how to put the month id in the order of 1,2,..12 and my date format y-m-d
I get the month in apr,aug and so on but i need jan as 1,feb as 2
I have 25 expenses(expense name).In this query i got the total expense amount of first expense only.I want the total expense of all expenses in every month
CREATE TABLE fact AS
(<your select query>)
Your select query can be in the following form
SELECT MONTH(date)as month_id,expense_name,sum(expense_amount)
FROM ms_expense JOIN track_expense using (expense_id)
group by expense_name,MONTH(date)
Related
I want to write a sql query to get best product of each year from a table . I have grouped the product-id and sum the qty to get the total number of products per id.
I converted the datetime function into year to get the year but output is wrong..
Anyone can help me with this?
SELECT Year(ModifiedDate), ProductID, SUM(OrderQty) AS TotalQuantity
from Sales.SalesOrderDetail
GROUP BY ProductID, year(ModifiedDate)
having count(*) > 3000
ORDER BY SUM(OrderQty) DESC
From your comment:
query is working fine if the set having condition to 2000. but if i
set it to 3000 it return nothing. if i use this "having count() >
2000" so i get two records. first of 2013 which return total quantity
3913 and record of 2014 with total quantity 2902. but when i change
condition to this "having count() > 3000 " it return nothing. but it
should return the 2013 record
You select the sum of OrderQty, yet you filter on the count and expect it to be the same. Count is the number of records, it doesn't care about the actual values in the records.
When you filter with
having sum(OrderQty) > 3000
you will only get the 2013 record.
We can do it in two-part.
I) create a temporary table for year-wise, id wise sum of qty.
create table tempSaleOrderDetail as select year(ModifiedDate) year,sum(OrderQty) orderqty, ProductID from Sales.SalesOrderDetail group by year(ModifiedDate), productId order by 1 desc,2 desc;
II) Fetch the data.
select A.* from tempSaleOrderDetail A inner join (select year ,max(orderqty) orderqty from tempSaleOrderDetail group by year) B on A.year=B.year and A.orderqty=B.orderqty ;
If any year has more than one Id's performance is same so this query will give both results.
So what i'm trying to do here, is that i am trying to count the number of repeat users (users who made more than one order) in a period of time, let it be month day or year, the case here is months
i'm currently running mysql mariadb and i'm pretty much a beginner in mysql, i've tried multiple subqueries but all have failed till now
This is what i have tried so far ..
This returns all the number of users with no ordering count condition
Since people are asking for sample data, here is what the data is looking like at the moment:
Order_Creation_Date - User_ID - Order_ID
2019-01-01 123 1
2019-01-01 123 2
2019-01-01 231 3
2019-01-01 231 4
This is the query i am using to get the result but it keeps on returning total number of users within the month
select month(o.created_at)month,
year(o.created_at)year,
count(distinct o.user_uuid) from orders o
group by month(o.created_at)
having count(*)>1
and this returns the number of users as 1 ..
select month(o.created_at)month,
year(o.created_at)year,
(select count(distinct ord.user_uuid) from orders ord
where ord.user_uuid = o.user_uuid
group by ord.user_uuid
having count(*)>1) from orders o
group by month(o.created_at)
Expected result will be from the sample data above
Month Count of repeat users
1 2
If you want the number of users that make more than one purchase in January, then do two levels of aggregations: one by user and month and the other by month:
select yyyy, mm, sum( num_orders > 1) as num_repeat_users
from (select year(o.created) as yyyy, month(o.created) as mm,
o.user_uuid, count(*) as num_orders
from orders o
group by yyyy, mm, o.user_uuid
) o
group by yyyy, mm;
I think you should try something like this which will return USer_ID list Month and Year wise who ordered more that once for the period-
SELECT
[user_uuid],
MONTH(o.created_at) month,
YEAR(o.created_at) year,
COUNT(o.user_uuid)
FROM orders o
GROUP BY
MONTH(o.created_at),YEAR(o.created_at)
HAVING COUNT(*) > 1;
For more, if you are looking for the count that how many users placed more that one order, you can just place the above query as a sub query and make a count on column 'user_uuid'
In oracle sql, how to get the count of newly added customers only for the month of april and may and make sure they werent there in the previous months
SELECT CUSTOMER ID , COUNT(*)
FROM TABLE
WHERE DATE BETWEEN '1-APR-2018' AND '31-MAY-2018' AND ...
If we give max (date) and min(date), we can compare the greater date to check if this customer is new , correct?
expected output is month count
april ---
may ---
should show the exact count how many new customers joined in these two months
One approach is to use aggregation:
select customer_id, min(date) as min_date
from t
group by customer_id
having min(date) >= date '2018-04-01 and
min(date) < date '2018-06-01';
This gets the list of customers (which your query seems to be doing). To get the count, just use count(*) and make this a subquery.
I have a query regarding a query in MySQL.
I have 2 tables one containing SalesRep details like name, email, etc. I have another table with the sales data which has reportDate, customers served and link to the salesrep via a foreign key. One thing to note is that the reportDate is always a friday.
So the requirement is this: I need to find sales data for a 13 week period for a given list of sales reps - with 0 as customers served if on a particular friday there is no data. The query result is consumed by a Java application which relies on the 13 rows of data per sales rep.
I have created a table with all the Friday dates populated and wrote a outer join like below:
select * from (
select name, customersServed, reportDate
from Sales_Data salesData
join `SALES_REPRESENTATIVE` salesRep on salesRep.`employeeId` = salesData.`employeeId`
where employeeId = 1
) as result
right outer join fridays on fridays.datefield = reportDate
where fridays.datefield between '2014-10-01' and '2014-12-31'
order by datefield
Now my doubts:
Is there any way where i can get the name to be populated for all 13 rows in the above query?
If there are 2 sales reps, I'd like to use a IN clause and expect 26 rows in total - 13 rows per sales person (even if there is no record for that person, I'd still like to see 13 rows of nulls), and 39 for 3 sales reps
Can these be done in MySql and if so, can anyone point me in the right direction?
You must first select your lines (without customersServed) and then make an outer join for the customerServed
something like that:
select records.name, records.datefield, IFNULL(salesRep.customersServed,0)
from (
select employeeId, name, datefield
from `SALES_REPRESENTATIVE`, fridays
where fridays.datefield between '2014-10-01' and '2014-12-31'
and employeeId in (...)
) as records
left outer join `Sales_Data` salesData on (salesData.employeeId = records.employeeId and salesData.reportDate = records.datefield)
order by records.name, records.datefield
You'll have to do 2 level nesting, in your nested query change to outer join for salesrep, so you have atleast 1 record for each rep, then a join with fridays without any condition to have atleast 13 record for each rep, then final right outer join with condition (fridays.datefield = innerfriday.datefield and (reportDate is null or reportDate=innerfriday.datefield))
Very inefficient, try to do it in code except for very small data.
I have a MySQL database populated with power consumption over 20 years.
I want to query the average of the power consumption over every month, from a given month.
For example with this database,
date power_consumption
2014/03/30 30
2014/04/30 40
2014/05/30 50
2014/06/30 20
The result would be, from 2014/04
month average_so_far_from_april_2014
2014/04 40.0
2014/05 45.0
2014/06 36.667
If I cannot achieve this in one query, what query should I go for to retrieve the most useful data for this task? (My naive approach is to query the whole table out and calculate the average in my application.)
Join the table of sub query against the consumption table which gets the unique months against the table of consumption, with a join condition that the year / month is less than or equal to the one from the sub query and use the AVG aggregate function on the power consumption from the table grouped by the year / month
Something like this:-
SELECT consumption_month,
AVG(b.power_consumption)
FROM
(
SELECT DISTINCT DATE_FORMAT(`date`, '%Y%m') AS consumption_month FROM consumption_table a
) a
INNER JOIN consumption_table b
ON consumption_month >= DATE_FORMAT(b.`date`, '%Y%m')
WHERE b.`date` >= '2014/04/01'
GROUP BY consumption_month
SQL fiddle:-
http://www.sqlfiddle.com/#!2/16588/2
If you only had one record per month you could simplify it more by just doing a join of the table against itself without the need for the sub query.
GROUP BY is for this kind of problems. The average is calculated for each distinct value of the expression the the GROUP BY clause.
SELECT DATE_FORMAT(date, '%Y/%m'), AVG(power_consumption)
FROM table_name
WHERE date > ...
GROUP BY DATE_FORMAT(date, '%y/%m')
ORDER BY DATE_FORMAT(date, '%y/%m')
You get the average for each month, DATE_FORMAT(date, '%y/%m') is year and month in format YYYY/MM