I am adding text to an existing string in HTML.
added = soup.find(text=re.compile('Summary|Experience'))
added.insert(0, NavigableString(code))
I would like to also add a line break after the text inserted so each string is on a different line.
I tried:
added.insert(0, NavigableString(code)+'<br/>')
And some other variations too...
Thanks,
You need to use .new_tag method to create your <br> tag
Demo
In [22]: from bs4 import BeautifulSoup
In [23]: soup = BeautifulSoup("""<p>Experience</p><strong>Summary</strong>""")
In [24]: newtg = soup.new_tag('br')
In [25]: soup.insert(0, newtg)
In [26]: soup
Out[26]: <br/><html><body><p>Experience</p><strong>Summary</strong></body></html>
Related
I want to extract the TEXT from this HTML element:
mail#1st-architects.com
all_profiles.find("a", {"???":"???"}).get_text(strip=True)
Consider that I have a list of 1000 companies and each company has a href="mailto:mail#1st-architects.com" different.
You could combine attribute = value css selector using starts with ^ and ends with $ operators to match on hrefs with specified substrings
emails = [i.text for i in all_profiles.select("[href^=mailto][href$='#1st-architects.com']")]
You could try something like this.
This code will print the text of all <a> with href as an email.
import re
from bs4 import BeautifulSoup
s = '''
mail#1st-architects.com
second_mail#2nd-architects.com
Some Link
mail#example.com
'''
soup = BeautifulSoup(s, 'lxml')
a = soup.find_all('a', attrs= {'href': re.compile(r'^mailto:')})
for i in a:
print(i.text.strip())
mail#1st-architects.com
second_mail#2nd-architects.com
mail#example.com
I'm trying to extract the text content from the HTML code below as a complete sentence however I am not able to. I tried using both Beautifulsoup.prettify() and Beautifulsoup.get_text() but those gave me 3 sentences. I would like to read the HTML below as a single proper sentence like
Recognized by Microsoft & Google, Inc., offices.
<li>Recognized by
<em>Microsoft</em> &
<em>Google, Inc.</em>, offices.</li>
I really don't understand what you need , but It'll help you to extract Content from the url of the website
import requests
import xlsxwriter
from bs4 import BeautifulSoup
#Text File where the content will be written
file = open("test.txt","w")
#Url from where the data will be extracted
urls ="https://www.pythonforbeginners.com/files/reading-and-writing-files-in-python"
page = requests.get(urls)
soup = BeautifulSoup(page.content, 'html.parser')
for link in soup.find_all('p'): #extracting all content of <P> tag from the url
#You can put the desired tag according to your need
file.write(link.get_text())
file.close()
You can use an HTML parser like BeautifulSoup to extract the text without tags (soup.text), then strip the text of duplicate whitespaces/newlines etc:
input_str = '''
<li>Recognized by
<em>Microsoft</em> &
<em>Google, Inc.</em>, offices.</li>
'''
from bs4 import BeautifulSoup
soup = BeautifulSoup(input_str,"html.parser")
text = " ".join(soup.text.split())
print(text)
Output:
Recognized by Microsoft & Google, Inc., offices.
Edit: based on your comments, in order to get a list of strings as an output (one for each li tag, you can do:
input_str = '''<ul> <li>This is sentence one in a order</li> <li>This is sentence two in a order</li> <li>This is sentence <em>Three</em> in a order </li> <li>This is sentence <em>four</em> in a order </li> </ul>'''
from bs4 import BeautifulSoup
soup = BeautifulSoup(input_str,"html.parser")
result = []
for li in soup.find_all('li'):
text = " ".join(li.text.split())
result.append(text)
print(result)
Output:
['This is sentence one in a order', 'This is sentence two in a order', 'This is sentence Three in a order', 'This is sentence four in a order']
I am trying to extract the name on this web page: https://steamcommunity.com/market/listings/730/AK-47%20%7C%20Redline%20%28Field-Tested%29
the element i am trying to grab it from is
<h1 class="hover_item_name" id="largeiteminfo_item_name" style="color:
rgb(210, 210, 210);">AK-47 | Redline</h1>
I am able to search for the ID "largeiteminfo_item_name" using selenium and retrieve the text that way but when i duplicate this with bs4 I can't seem to find the text.
Ive tried searching class "item_desc_description" but no text could be found there either. What am I doing wrong?
a = soup.find("h1", {"id": "largeiteminfo_item_name"})
a.get_text()
a = soup.find('div', {'class': 'item_desc_description'})
a.get_text()
I expected "AK-47 | Redline" but received '' for the first try and '\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n' for the second try.
The data you are trying to extract is not present in the HTML page, I guess it might be generated aside with JavaScript (just guessing).
However I managed to find the info in the div "market_listing_nav".
from bs4 import BeautifulSoup as bs4
import requests
lnk = "https://steamcommunity.com/market/listings/730/AK-47%20%7C%20Redline%20%28Field-Tested%29"
res = requests.get(lnk)
soup = bs4(res.text, features="html.parser")
elem = soup.find("div", {"class" : "market_listing_nav"})
print(elem.get_text())
This will output the following
Counter-Strike: Global Offensive
>
AK-47 | Redline (Field-Tested)
Have a look at the web page source for tag with better formatting or just clean up the on generated by my code.
I'm trying to strip out the Span tags from a html file.
I am using a page which has a lot of Span tags in it. I need to extract some numbers and add them together. However, I can't even get the lines I need out, so I am hoping someone can offer some advice.
My code is below:
from urllib.request import urlopen
from bs4 import BeautifulSoup
import ssl
# Ignore SSL certificate errors
ctx = ssl.create_default_context()
ctx.check_hostname = False
ctx.verify_mode = ssl.CERT_NONE
# url = input('Enter - ')
html = urlopen(url, context=ctx).read()
soup = BeautifulSoup(html, "html.parser")
# print(soup)
spans = soup.findAll('span')
for span in spans:
print span
Thanks
I am trying to pull all the text from the div class 'caselawcontent searchable-content'. This code just prints the HTML without the text from the web page. What am I missing to get the text?
The following link is in the 'finteredcasesdoc.text' file:
http://caselaw.findlaw.com/mo-court-of-appeals/1021163.html
import requests
from bs4 import BeautifulSoup
with open('filteredcasesdoc.txt', 'r') as openfile1:
for line in openfile1:
rulingpage = requests.get(line).text
soup = BeautifulSoup(rulingpage, 'html.parser')
doctext = soup.find('div', class_='caselawcontent searchable-content')
print (doctext)
from bs4 import BeautifulSoup
import requests
url = 'http://caselaw.findlaw.com/mo-court-of-appeals/1021163.html'
soup = BeautifulSoup(requests.get(url).text, 'html.parser')
I've added a much more reliable .find method ( key : value)
whole_section = soup.find('div',{'class':'caselawcontent searchable-content'})
the_title = whole_section.center.h2
#e.g. Missouri Court of Appeals,Southern District,Division Two.
second_title = whole_section.center.h3.p
#e.g. STATE of Missouri, Plaintiff-Appellant v....
number_text = whole_section.center.h3.next_sibling.next_sibling
#e.g.
the_date = number_text.next_sibling.next_sibling
#authors
authors = whole_section.center.next_sibling
para = whole_section.findAll('p')[1:]
#Because we don't want the paragraph h3.p.
# we could aslso do findAll('p',recursive=False) doesnt pickup children
Basically, I've dissected this whole tree
as for the Paragraphs (e.g. Main text, the var para), you'll have to loop
print(authors)
# and you can add .text (e.g. print(authors.text) to get the text without the tag.
# or a simple function that returns only the text
def rettext(something):
return something.text
#Usage: print(rettext(authorts))
Try printing doctext.text. This will get rid of all the HTML tags for you.
from bs4 import BeautifulSoup
cases = []
with open('filteredcasesdoc.txt', 'r') as openfile1:
for url in openfile1:
# GET the HTML page as a string, with HTML tags
rulingpage = requests.get(url).text
soup = BeautifulSoup(rulingpage, 'html.parser')
# find the part of the HTML page we want, as an HTML element
doctext = soup.find('div', class_='caselawcontent searchable-content')
print(doctext.text) # now we have the inner HTML as a string
cases.append(doctext.text) # do something useful with this !