How to check each value is greater or less than zero in csv file using python? - csv

Question

I want to check each value of one column and according to the values give them label (trends) on the next column. For example, if the value is greater than zero or equal or less than zero, according to this positive , negative and same labels are to be written in next column.
My input file is look like this :
Weightage /// column name
0.000555
0.002333
0
-0.22222
And I want my output file is look like:
Weightage Labels // column name
0.000555 positive
0.002333 positive
0 same
-0.22222 negative
Any one can help me??
The code is:
print (results)
for r in results:
if r >0:
print("test")
label = "positive"
print(label)
elif r == 0.0:
label = "equal"
print(label)
else:
print("nothing")
I have problem in 'r' for loop.
The error occur :
Traceback (most recent call last):
File "C:\Python34\col.py", line 23, in <module>
if r >0:
TypeError: unorderable types: tuple() > int()

Answer 1

At first glance, it looks like you are confusing rows and columns. I suggest using more explicit names. It helps to avoid confusion. Also, do not compare strings to numeric types like integers. It will give surprising results in Python 2. In Python 3, it is an error.
for row in results:
column = row[0] # The first column of this row.
value = float(column) # The csv module returns strings, so we should
# turn them into floats for numeric comparison.
if value > 0:
print "positive"
elif value < 0:
print "negative"
else:
print "zero"