I have an Event model hasMany Attendances with event_id in the attendances. I want to select some fields in attendance table in my custom find method but the contain() method doesn't join the two tables.
public function findAttendanceDetails(Query $query)
{
return $query->contain('Attendances')
->select(['Gender' => 'Attendances.gender',
'Name' => 'Attendances.full_name'
]);
}
I am getting an error of Error: SQLSTATE[42S22]: Column not found: 1054 Champ 'Attendances.gender' inconnu dans field list and wondering what is missing.
When I use the ->Join() method instead of ->contain(), I get the results.
Contain doesn't quite work that way. You would be looking for something like:
return $query->contain(['Attendances']);
Which will just grab and return the full associated table Attendances. Contain looks for an array, not a string value.
If you want specific fields from the associated table, you could try:
return $query->contain(['Attendances' => function ($q) {
return $q
->select(['gender', 'full_name'])
}
]);
You can read more about using contain here.
Related
I have two tables, dpd and cabang. One cabang can only have one dpd and each cabang should have a dpd.
This is the relation in my "Cabang" model :
public function getIdDpd()
{
return $this->hasOne(Dpd::className(), ['id_dpd' => 'id_dpd']);
}
I try to access "dpd" attribute in "dpd" table in my view, I tried to var_dump it but still got the same error :
$model = Cabang::find()
->joinWith('idDpd')
->all();
var_dump($model->dpd);
Note : 'dpd' in var_dump($model->dpd) refered to the column name in 'Dpd' table. I have a column name 'dpd' in my 'dpd' table. I also tried $model->idDpd->dpd but it return the same error.
What am I doing wrong? Thanks
Your mistake is
$model->dpd
where you are trying to access it assuming that $model has the Dpd object, but it is holding the Cabang object and you should use the relation name to get the Dpd object and then call the field name like below.
$model->idDpd->dpd
EDIT: You are using ->all() in your query not ->one() and hence you cannot simply do $model->idDpd->dpd right after the query, you need to loop through the records and then call the relation, i thought you might be doing the same way but anyway see below how to use it.
$cabangs = Cabang::find()
->joinWith('idDpd')
->all();
foreach($cabangs as $index=>$model){
$model->idDpd->dpd;
}
I have a Active Record model "Event" with a hasOne relation 'getUser'.
Now, if I do :
$eventModels = Event::find()->joinWith([
'user' => function($q){
return $q;
}])->all();
----------------------------------------------------
foreach($eventModels as $m){
var_dump($m->user); //Everything good as $m->user returns the related user object
die('skdw');
}
But, if I add the "select" in the joinWith query, then related "user" object becomes null. Here is the issue :
$eventModels = Event::find()->joinWith([
'user' => function($q){
$q->select('email');// or, ['email'] or ['user.email'] etc. fields.
return $q;
}])->all();
----------------------------------------------------
foreach($eventModels as $m){
var_dump($m->user); // Returns NULL
die('skdw');
}
But, if I make it $q->select('*'), then $m->user working .
I believe it used to work in some previous versions of Yii 2 (Right now, I am working on Yii 2.0.9)
Is this expected behavior ? If yes, then what is the solution to fetch only some select fields for the related joinWith model ? I don't want to fetch all the related fields as some of the related fields might contain "TEXT" data type.
You need to select the primary key column for the relation for Yii to build them.
e.g. assuming your column is called id
$eventModels = Event::find()->joinWith(['user' => function($q){
$q->select(['id', 'email']);
}])->all();
Also, you don't need to return the $q variable.
I have a custom finder which gets notifications for current user for an item. Notifications are grouped by their messages like "new_comment". Wth query I have message, message_count in my results
Is there a way to convert this query within the finder in key => value format so I can have it in message => message_format
//finder code;
return $query->contain([
'Notifications' => function ($q)use($userId) {
$q->select(['item_id','message','message_count'=> 'COUNT(message)']);
$q->where(['Notifications.user_id' => $userId]);
$q->group(['Notifications.message']);
return $q;
}
]);
Use the Cake\Collection\Collection's combine method
Yii2 build relation many to many
I have 2 tables users and friends
Code query
$friends = Friends::find()
->select(['friends.user_id', 'users.name'])
->leftJoin('users','users.id = friends.friend_user')
->with('users')
->all();
In result error
Invalid Parameter – yii\base\InvalidParamException. app\models\Friends has no relation named "users".
Friends has a column called user_id and thus only belongs to one user. If you auto-generated the Friends ActiveRecord it probably has a function getUser (singular because it is only one) that will look something like this:
public function getUser() {
return $this->hasOne(User::className(), ['id' => 'user_id']);
}
So you're getting the error because no getUsers function exists (that returns a valid ActiveQuery object). Because there can only be one user per friend I think you should use the singular version. And if that still gives the same error you should implement the function above and maybe change it a bit to match your classname.
When you use with(['relation']) to load relations Yii will convert the entry to getRelation and call that function on the model to get the query that is needed to load the relation.
I'm new to cakephp. I'm trying to search through mysql tables. I want to use nested query.
class TableController extends AppController{
.
.
public function show(){
$this->set('discouns', $this->DiscounsController->query("SELECT * FROM discoun as Discoun WHERE gcil_id = 1"));//(SELECT id FROM gcils WHERE genre = 'Shoes' AND company_name = 'Adidas')"));
}
}
Error:
Error: Call to a member function query() on a non-object
I've also tried
public function show(){
$this->DiscounsController->query("SELECT * FROM count as Count WHERE ctr_id = (SELECT id FROM ctrs WHERE genre = 'Shoes' AND company_name = 'Adidas')");
}
Error:
Error: Call to a member function query() on a non-object
File: C:\xampp\htdocs\cakephppro\myapp\Controller\CountsController.php
Please help. I've been trying this for last few hours. :/
As mentioned in the comments there are a few problems with your code.
Firstly, you are trying to call the query() method on a Controller, whereas you should be executing it on a Model, as it is models that handle database queries and the controller should simply be used to call these methods to get the data and pass them to the view.
The second thing is that you are executing a very simple SQL query raw instead of using CakePHPs built in functions <- Be sure to read this page in full.
Now for your problem, as long as you have setup your model relationships correctly and followed the correct naming conventions, this should be your code to run your SQL query from that controller:
public function show(){
$this->set('discouns', $this->Discouns->find('all', array(
'conditions' => array(
'gcil_id' => 1,
'genre' => 'shoes',
'company_name' => 'Adidas'
)
));
}
query() is not a Controller, but a Model method. That's what the error (Call to a member function on a non-object) is trying to tell you.
So the correct call would be:
$this->Discount->query()
But you are calling this in a TableController, so unless Table and Discount have some type of relationship, you won't be able to call query().
If the Table does have a relationship defined you will be able to call:
$this->Table->Discount->query()
Please not that query() is only used when performing complex SQL queries in scenarios where the standard methods (find, save, delete, etc.) are less practical.
$this->Counts->find('all',array(
'conditions' => array(
'ctrs.genre' => 'Shoes',
'ctrs.company_name' => 'Adidas'
), 'recursive' => 1
));
The above is with tables named counts and ctrs.
This is assuming you have the model set up to have some sort of relationship between the counts table and the ctrs table. It's kind of hard to tell in your code exactly what you tables are.
The CakePHP book should have all the answers you need. One of the reasons to run CakePHP over regular PHP is the FIND statement. Once you have your models set up correctly, using the find statement should be really easy.
http://book.cakephp.org/2.0/en/models.html