table:tr and gradient not working - html

I want to fill the table row background to x percent.
My problem is that when table cell's width is not 100%, the background color does not appear correctly.
Html :
<table>
<tbody>
<tr id="tr1">
<td>1</td>
<td>2</td>
<td>3</td>
</tr>
<tr id="tr2">
<td>1</td>
<td>2</td>
<td>3</td>
</tr>
<tr id="tr3">
<td>1</td>
<td>2</td>
<td>3</td>
</tr>
</tbody>
CSS :
table {
margin: 0 auto;
width: 500px;
border-spacing: 0;
}
#tr1 {
background: #7CB663; /* Old browsers */
background: -moz-linear-gradient(left,#7CB663 50%, #ffffff 50%); /* FF3.6+ */
background: -webkit-gradient(linear, left top, right top,
color-stop(50%,#7CB663), color-stop(50%,#ffffff)); /* Chrome,Safari4+ */
background: -webkit-linear-gradient(left,#7CB663 50%,#ffffff 50%); /*Chrome10+,Safari5.1+*/
background: -o-linear-gradient(left,#7CB663 50%,#ffffff 50%); /* Opera 11.10+ */
background: -ms-linear-gradient(left,#7CB663 50%,#ffffff 50%); /* IE10+ */
background: linear-gradient(to right,#7CB663 50%,#ffffff 50%); /* W3C */
background-attachment: fixed;
}
#tr2 {
background: #7CB663; /* Old browsers */
background: -moz-linear-gradient(left,#7CB663 40%, #ffffff 40%); /* FF3.6+ */
background: -webkit-gradient(linear, left top, right top, color-stop(40%,#7CB663),
color-stop(40%,#ffffff)); /* Chrome,Safari4+ */
background: -webkit-linear-gradient(left,#7CB663 40%,#ffffff 40%); /*Chrome10+,Safari5.1+*/
background: -o-linear-gradient(left,#7CB663 40%,#ffffff 40%); /* Opera 11.10+ */
background: -ms-linear-gradient(left,#7CB663 40%,#ffffff 40%); /* IE10+ */
background: linear-gradient(to right,#7CB663 40%,#ffffff 40%); /* W3C */
background-attachment: fixed;
}
#tr3 {
background: #7CB663; /* Old browsers */
background: -moz-linear-gradient(left,#7CB663 20%, #ffffff 20%); /* FF3.6+ */
background: -webkit-gradient(linear, left top, right top, color-stop(20%,#7CB663),
color-stop(20%,#ffffff)); /* Chrome,Safari4+ */
background: -webkit-linear-gradient(left,#7CB663 20%,#ffffff 20%); /*Chrome10+,Safari5.1+*/
background: -o-linear-gradient(left,#7CB663 20%,#ffffff 20%); /* Opera 11.10+ */
background: -ms-linear-gradient(left,#7CB663 20%,#ffffff 20%); /* IE10+ */
background: linear-gradient(to right,#7CB663 20%,#ffffff 20%); /* W3C */
background-attachment: fixed;
}
td {
border: 1px solid #000;
}
Output :
Has anyone a good solution for this problem?

I'm assuming your problem is that the gradient stops aren't relative to the table width, but to the width of body.
Looks like that's because you're setting background-attachment: fixed. Getting rid of that property did the trick for me.
edited JSfiddle

it is because your background gradient has been stopped at 50%, if you need to display color in full tr width, use following css
background: rgba(0, 0, 0, 0) linear-gradient(to right, #7cb663 50%, #ffffff 100%) repeat fixed 0 0;
this css will help you to repeat color in full width.

Related

Display image on a gradient background on hover via css

I have this background:
.background:hover {
background: #F4F4F4 url(../images/arrow_down_over.gif) no-repeat right;
}
that I would like to change into a gradient like this one :
.background:hover{
background: -moz-linear-gradient(top, #f4f4f4 0%, #eeeeee 100%); /* FF3.6+ */
background: -webkit-gradient(linear, left top, left bottom, color-stop(0%,#f4f4f4), color-stop(100%,#eeeeee)); /* Chrome,Safari4+ */
background: -webkit-linear-gradient(top, #f4f4f4 0%,#eeeeee 100%); /* Chrome10+,Safari5.1+ */
background: -o-linear-gradient(top, #f4f4f4 0%,#eeeeee 100%); /* Opera 11.10+ */
background: -ms-linear-gradient(top, #f4f4f4 0%,#eeeeee 100%); /* IE10+ */
background: linear-gradient(to bottom, #f4f4f4 0%,#eeeeee 100%); /* W3C */
filter: progid:DXImageTransform.Microsoft.gradient( startColorstr='#f4f4f4', endColorstr='#eeeeee',GradientType=0 );
} /* IE6-9 */
But I would like to keep the arrow image. I can't find a way to do it. I did try something like this:
background: -moz-linear-gradient(top, #f4f4f4 0%, #eeeeee 100%) url(../images/arrow_down_over.gif) no-repeat right; /* FF3.6+ */
or add this after the gradient properties but without any success.
background: url(../images/arrow_down_over.gif) no-repeat right;
I can't add another class so I have to deal with this CSS. Any idea how to do it?
You may try:
background: url(../images/arrow_down_over.gif), linear-gradient(...);
Multiple backgrounds must be comma-separated rather than space-separated, and they weirdly stack from top to bottom.
Also note that this is not necessarily supported by all browsers.
See http://css-tricks.com/stacking-order-of-multiple-backgrounds/ and https://developer.mozilla.org/en-US/docs/Web/Guide/CSS/Using_multiple_backgrounds for details

Building a Product Box using images w/ CSS

I designed a very basic looking box in Photoshop that I would like to use to show product information inside of. It basically consists of a Header, Body and Button (each a separate image) that look like the image below.
How can I use CSS/HTML to piece these together? I just need to show header text in the top box and bullet points in the body area, but not sure how to actually build this from the image files.
I know the HTML will look as such, I am just confused as to how to actually build the box, such as stacking the images and overlaying the button in that position over the body.
<div id="product_box">
<div id="header">Title Here</div>
<div id="body">
<ul>
<li>Point here</li>
<li>Point here</li>
<li>Point here</li>
</ul>
</div>
<div id="button></div>
</div>
Well Have a look at:
http://jsfiddle.net/2A2Fn/4/
You don't have to change your html markup just use css:
Here is relevant CSS:
#product_box{
border:2px solid #bbc;
border-radius:15px;
display:block;
width:50%;
height:100%;
position:relative;
box-shadow: 5px 5px 5px rgba(0,0,0,0.5);
padding:0px; !important
background: #b5bdc8; /* Old browsers */
/* Gradient */
background: -moz-linear-gradient(top, #b5bdc8 0%, #828c95 36%, #28343b 100%); /* FF3.6+ */
background: -webkit-gradient(linear, left top, left bottom, color-stop(0%,#b5bdc8), color-stop(36%,#828c95), color-stop(100%,#28343b)); /* Chrome,Safari4+ */
background: -webkit-linear-gradient(top, #b5bdc8 0%,#828c95 36%,#28343b 100%); /* Chrome10+,Safari5.1+ */
background: -o-linear-gradient(top, #b5bdc8 0%,#828c95 36%,#28343b 100%); /* Opera 11.10+ */
background: -ms-linear-gradient(top, #b5bdc8 0%,#828c95 36%,#28343b 100%); /* IE10+ */
background: linear-gradient(to bottom, #b5bdc8 0%,#828c95 36%,#28343b 100%); /* W3C */
filter: progid:DXImageTransform.Microsoft.gradient( startColorstr='#b5bdc8', endColorstr='#28343b',GradientType=0 ); /* IE6-9 */
}
#header{
background:#aaf;
width:100%;
height:50px;
border:0px;
border-bottom:1px solid #99b;
padding-top:15px;
padding-bottom:15px;
border-radius:5px;
background: #b5bdc8; /* Old browsers */
/* gradient */
background: -moz-linear-gradient(top, #b5bdc8 0%, #828c95 36%, #28343b 100%); /* FF3.6+ */
background: -webkit-gradient(linear, left top, left bottom, color-stop(0%,#b5bdc8), color-stop(36%,#828c95), color-stop(100%,#28343b)); /* Chrome,Safari4+ */
background: -webkit-linear-gradient(top, #b5bdc8 0%,#828c95 36%,#28343b 100%); /* Chrome10+,Safari5.1+ */
background: -o-linear-gradient(top, #b5bdc8 0%,#828c95 36%,#28343b 100%); /* Opera 11.10+ */
background: -ms-linear-gradient(top, #b5bdc8 0%,#828c95 36%,#28343b 100%); /* IE10+ */
background: linear-gradient(to bottom, #b5bdc8 0%,#828c95 36%,#28343b 100%); /* W3C */
filter: progid:DXImageTransform.Microsoft.gradient( startColorstr='#b5bdc8', endColorstr='#28343b',GradientType=0 ); /* IE6-9 */
}
#body{
padding-bottom:15px;
}
#button{
background:#756;
border:1px solid #645;
display:block;
width:150px;
height:50px;
border-radius:5px;
position:absolute;
bottom:-25px;
right:33%;
color:#fff;
box-shadow:5px 5px 5px rgba(0,0,0,0.4);
text-align:center;
font-weight:bolder;
font-size:15px;
background: #b5bdc8; /* Old browsers */
/* Gradient */
background: -moz-linear-gradient(top, #b5bdc8 0%, #828c95 36%, #28343b 100%); /* FF3.6+ */
background: -webkit-gradient(linear, left top, left bottom, color-stop(0%,#b5bdc8), color-stop(36%,#828c95), color-stop(100%,#28343b)); /* Chrome,Safari4+ */
background: -webkit-linear-gradient(top, #b5bdc8 0%,#828c95 36%,#28343b 100%); /* Chrome10+,Safari5.1+ */
background: -o-linear-gradient(top, #b5bdc8 0%,#828c95 36%,#28343b 100%); /* Opera 11.10+ */
background: -ms-linear-gradient(top, #b5bdc8 0%,#828c95 36%,#28343b 100%); /* IE10+ */
background: linear-gradient(to bottom, #b5bdc8 0%,#828c95 36%,#28343b 100%); /* W3C */
filter: progid:DXImageTransform.Microsoft.gradient( startColorstr='#b5bdc8', endColorstr='#28343b',GradientType=0 ); /* IE6-9 */
}
div{
text-align:center;
color:#fff;
font-weight:bold;
}
And Here is output of that:
EDIT
According to your comment here is updated code:
http://jsfiddle.net/2A2Fn/5/
and its output:
Hope it helps.
It can be done using only HTML/CSS.
Use CSS gradient for it.
Here is the DEMO
Seeing your CSS code would help. This is how I would achieve what you want:
Set a div element to the desired height of the box. Apply a border and border-radius property as desired, probably 2 px border and a radius of 10-15 px.
Take the header image, and crop it down to 1 pixel wide (for memory conservation). Then set a div element and use this 1pixel wide image as the background, repeat x, but not y. Set the height of the header to the height of the gradient image.
Then, make another div inside the container div. Take your second gradient image and again reduce it to a 1 pixel width. Set it as the background for this div with repeat-x. You'll have to set the height of the header div to the difference of the height of the header and the height of the container.
Your button can then be placed as a link, probably in another div element.
All this can be coded something like as follows:
CSS:
div.container
{
height: 400px;
width: 300px;
border: 2px solid #000;
border-radius: 12px;
}
div.header
{
background-image: url("header-grad.ext");
background-repeat: repeat-x;
height: 40px;
width: 100%;
}
div.content
{
background-image: url("content-grad.ext");
background-repeat: repeat-x;
height: 360px;
width: 100%;
}
And the HTML:
<div class="container">
<div class="header">text here</div>
<div class="content"><\div>
<div class="button></div>
</div>
This should do what you want. You'll need to specify the button CSS as well which I didn't do as I'm on mobile right now.
Hope this helps you!

Same line div tags

Sorry to ask such a stupid question, but it's been quite a long night and I cannot seem to get my code to display the divs on the same line.
I've searched all over Stack Overflow and none of the answers has helped. It might be a very stupid mistake I have done but I haven't noticed it.
<td>
<div class='sameline'>
<?php
echo "<div class='hbox'>Max Health: $hp</div><div class='mbox'>Max Mana: $mana</div>";
?>
</div>
</td>
.hbox {
color:white;
background: #dd0408; /* Old browsers */
background: -moz-linear-gradient(top, #dd0408 0%, #dd0408 0%, #bf0326 0%, #d30407 38%, #b20002 76%, #ba0003 100%); /* FF3.6+ */
background: -webkit-gradient(linear, left top, left bottom, color-stop(0%,#dd0408), color-stop(0%,#dd0408), color-stop(0%,#bf0326), color-stop(38%,#d30407), color-stop(76%,#b20002), color-stop(100%,#ba0003)); /* Chrome,Safari4+ */
background: -webkit-linear-gradient(top, #dd0408 0%,#dd0408 0%,#bf0326 0%,#d30407 38%,#b20002 76%,#ba0003 100%); /* Chrome10+,Safari5.1+ */
background: -o-linear-gradient(top, #dd0408 0%,#dd0408 0%,#bf0326 0%,#d30407 38%,#b20002 76%,#ba0003 100%); /* Opera 11.10+ */
background: -ms-linear-gradient(top, #dd0408 0%,#dd0408 0%,#bf0326 0%,#d30407 38%,#b20002 76%,#ba0003 100%); /* IE10+ */
background: linear-gradient(to bottom, #dd0408 0%,#dd0408 0%,#bf0326 0%,#d30407 38%,#b20002 76%,#ba0003 100%); /* W3C */
filter: progid:DXImageTransform.Microsoft.gradient( startColorstr='#dd0408', endColorstr='#ba0003',GradientType=0 ); /* IE6-9 */
text-align:center;
width:45%;
height:16px;
border:1px solid #333;
}
.mbox {
color:white;
background: #00a4f7; /* Old browsers */
background: -moz-linear-gradient(top, #00a4f7 1%, #00b7f9 43%, #009ec3 100%); /* FF3.6+ */
background: -webkit-gradient(linear, left top, left bottom, color-stop(1%,#00a4f7), color-stop(43%,#00b7f9), color-stop(100%,#009ec3)); /* Chrome,Safari4+ */
background: -webkit-linear-gradient(top, #00a4f7 1%,#00b7f9 43%,#009ec3 100%); /* Chrome10+,Safari5.1+ */
background: -o-linear-gradient(top, #00a4f7 1%,#00b7f9 43%,#009ec3 100%); /* Opera 11.10+ */
background: -ms-linear-gradient(top, #00a4f7 1%,#00b7f9 43%,#009ec3 100%); /* IE10+ */
background: linear-gradient(to bottom, #00a4f7 1%,#00b7f9 43%,#009ec3 100%); /* W3C */
filter: progid:DXImageTransform.Microsoft.gradient( startColorstr='#00a4f7', endColorstr='#009ec3',GradientType=0 ); /* IE6-9 */
text-align:center;
width:45%;
height:16px;
border:1px solid #333;
}
#sameline {
overflow: hidden;
white-space: nowrap;
}
.hbox, .mbox {
box-sizing: border-box;
-moz-box-sizing:border-box; /* Firefox */
display:inline-block;
}
Add float:left to both .mbox and .hbox.
I take it you need the two divs inside <div class="sameline"> to appear next to each other
so a css rule like
.hbox, .mbox {float:left}
Should do it
Just add .sameline div {float: left;}.
(BTW, try to avoid posting PHP when asking CSS/HTML questions, as it makes it harder to read/interpret the code‚though not too difficult here. Get the HTML from your browser's source code, if necessary.)
Also note that sameline is a class, so this won't work unless you change the # to a .:
#sameline {
overflow: hidden;
white-space: nowrap;
}
if you add float: left; to .mbox and .hbox it should work.
Example here.

stretch a background-image across a table's td using html/css

I have a table and want a certain background to be stretched across the width of the TD, whatever the width may be.
My CSS for the relevant td is currently like this:
.tools .theader
{
margin:1px;background-color:#ffffcc;
background:url(../images/td_bg.png) no-repeat center center;
}
and the HTML goes something like this:
<table class'tools'>
<tr>
<td class='theader' colspan=2>
Background
</td>
...
Here's an image of what I get in result:
So you can see the blue bevelled background fits exactly in the center of each td. I want it to stretch to reach the edges of the td so that the whole td looks bevelled. How can this be done?
You can use css gradient instead
HTML
<table class'tools'>
<tr>
<td class='theader' colspan="2">
<span>Background</span>
</td>
</tr>
</table>
CSS
.theader > span{
color:white;
padding:6px 10px;
background: #fffcfc; /* Old browsers */
background: -moz-linear-gradient(top, #fffcfc 0%, #2989d8 12%, #2989d8 51%, #207cca 96%, #ffffff 100%); /* FF3.6+ */
background: -webkit-gradient(linear, left top, left bottom, color-stop(0%,#fffcfc), color-stop(12%,#2989d8), color-stop(51%,#2989d8), color-stop(96%,#207cca), color-stop(100%,#ffffff)); /* Chrome,Safari4+ */
background: -webkit-linear-gradient(top, #fffcfc 0%,#2989d8 12%,#2989d8 51%,#207cca 96%,#ffffff 100%); /* Chrome10+,Safari5.1+ */
background: -o-linear-gradient(top, #fffcfc 0%,#2989d8 12%,#2989d8 51%,#207cca 96%,#ffffff 100%); /* Opera 11.10+ */
background: -ms-linear-gradient(top, #fffcfc 0%,#2989d8 12%,#2989d8 51%,#207cca 96%,#ffffff 100%); /* IE10+ */
background: linear-gradient(to bottom, #fffcfc 0%,#2989d8 12%,#2989d8 51%,#207cca 96%,#ffffff 100%); /* W3C */
filter: progid:DXImageTransform.Microsoft.gradient( startColorstr='#fffcfc', endColorstr='#ffffff',GradientType=0 ); /* IE6-9 */
}
DEMO
HERE is the best tool to generate CSS Gradient

Div going beyond the background color

What I want to do is that the background color will remain the same no matter how big the screen resolution is for the reader. I created a div where its height is set to auto.
.news-box{
margin-top:5%;
border-radius:6px;
background-color: #EEE;
border: 1px solid #EEE;
margin-left: 24%;
height:auto;
width:620px;
}
This how it looks like
And this my CSS rule for the whole html
I am using this body css rule. for my gradient
CSS RULE FOR THE WHOLE PAGE
html
{
height:100%;
}
THIS COMES BEFORE THE .news-box class
body
{
background: rgb(125,126,125); /* Old browsers */
background: -moz-linear-gradient(top, rgba(125,126,125,1) 39%, rgba(14,14,14,1) 100%); /* FF3.6+ */
background: -webkit-gradient(linear, left top, left bottom, color-stop(39%,rgba(125,126,125,1)), color-stop(100%,rgba(14,14,14,1))); /* Chrome,Safari4+ */
background: -webkit-linear-gradient(top, rgba(125,126,125,1) 39%,rgba(14,14,14,1) 100%); /* Chrome10+,Safari5.1+ */
background: -o-linear-gradient(top, rgba(125,126,125,1) 39%,rgba(14,14,14,1) 100%); /* Opera 11.10+ */
background: -ms-linear-gradient(top, rgba(125,126,125,1) 39%,rgba(14,14,14,1) 100%); /* IE10+ */
background: linear-gradient(to bottom, rgba(125,126,125,1) 39%,rgba(14,14,14,1) 100%); /* W3C */
filter: progid:DXImageTransform.Microsoft.gradient( startColorstr='#7d7e7d', endColorstr='#0e0e0e',GradientType=0 ); /* IE6-9 */
}
This how the page looks like without the Div
Any way to fix this?
Demo.....................................
Hey now used to min height 100% in you html and body as like this
html, body{
min-height:100%;
}
Demo