The code below will create an arrow right below an <a> element:
JSFiddle
.btn {
position: relative;
display: inline-block;
width: 100px;
height: 50px;
text-align: center;
color: white;
background: gray;
line-height: 50px;
text-decoration: none;
}
.btn:after {
content: "";
position: absolute;
bottom: -10px;
left: 0;
width: 0;
height: 0;
border-width: 10px 50px 0 50px;
border-style: solid;
border-color: gray transparent transparent transparent;
}
Hello!
The problem is that we have to indicate the link width to get an arrow of a proper size because we cannot indicate the border width in pixels.
How to make a responsive triangle percent based?
You could use a skewed and rotated pseudo element to create a responsive triangle under the link :
DEMO (resize the result window to see how it reacts)
The triangle maintains it's aspect ratio with the padding-bottom property.
If you want the shape to adapt it's size according to it's content, you can remove the width on the .btn class
.btn {
position: relative;
display: inline-block;
height: 50px; width: 50%;
text-align: center;
color: white;
background: gray;
line-height: 50px;
text-decoration: none;
padding-bottom: 15%;
background-clip: content-box;
overflow: hidden;
}
.btn:after {
content: "";
position: absolute;
top:50px; left: 0;
background-color: inherit;
padding-bottom: 50%;
width: 57.7%;
z-index: -1;
transform-origin: 0 0;
transform: rotate(-30deg) skewX(30deg);
}
/** FOR THE DEMO **/
body {
background: url('http://i.imgur.com/qi5FGET.jpg');
background-size: cover;
}
Hello!
For more info on responsive triangles and how to make them, you can have a look at
Triangles with transform rotate (simple and fancy responsive triangles)
Another solution to this would be to use a CSS clip-path to clip a triangle out of a coloured block. No IE support however, but could be used for internal tools etc.
DEMO
Written with SCSS for ease.
.outer {
background: orange;
width: 25%;
position: absolute;
top: 50%;
left: 50%;
transform: translate(-50%, -50%);
padding: 1em;
p {
margin: 0;
text-align: center;
color: #fff;
}
&:after {
content: '';
position: absolute;
top: 100%;
left: 0;
right: 0;
padding-bottom: 10%;
background: orange;
-webkit-clip-path: polygon(0% 0%, 100% 0%, 50% 100%);
clip-path: polygon(0% 0%, 100% 0%, 50% 100%);
}
}
I found solution that works with any width/height. You can use two pseudo-elements with linear-gradient background, like this, (fiddle):
.btn {
position: relative;
display: inline-block;
width: 100px;
height: 50px;
text-align: center;
color: white;
background: gray;
line-height: 50px;
text-decoration: none;
}
.btn:before {
content: "";
position: absolute;
top: 100%;
right: 0;
width: 50%;
height: 10px;
background: linear-gradient(to right bottom, gray 50%, transparent 50%)
}
.btn:after {
content: "";
position: absolute;
top: 100%;
left: 0;
width: 50%;
height: 10px;
background: linear-gradient(to left bottom, gray 50%, transparent 50%)
}
A modified version of the below code can help you to achieve this
HTML
<div class="triangle-down"></div>
CSS
.triangle-down {
width: 10%;
height: 0;
padding-left:10%;
padding-top: 10%;
overflow: hidden;
}
.triangle-down:after {
content: "";
display: block;
width: 0;
height: 0;
margin-left:-500px;
margin-top:-500px;
border-left: 500px solid transparent;
border-right: 500px solid transparent;
border-top: 500px solid #4679BD;
}
For further reading on responsive triangles: CSS triangles made responsive
(archived link)
I tried the other answers and found them to be either too complex and/or unwieldy to manipulate the shape of the triangle. I decided instead to create a simple triangle shape as an svg.
The triangle height can be set to an absolute value, or as a percentage of the rectangle so it can be responsive in both directions if necessary.
html, body{
height:100%;
width:100%;
}
.outer{
width:20%;
height:25%;
background:red;
position:relative;
}
.inner{
height:100%;
width:100%;
background-color:red;
}
.triangle-down{
height:25%;
width:100%;
position:relative;
}
.triangle-down svg{
height:100%;
width:100%;
position:absolute;
top:0;
}
svg .triangle-path{
fill:red;
}
<div class="outer">
<div class="inner"></div>
<div class="triangle-down">
<svg xmlns="http://www.w3.org/2000/svg" preserveAspectRatio="none" viewBox="0 0 2 1">
<g>
<path class="triangle-path" d="M0,0 l2,0 l-1,1 z" />
</g>
</svg>
</div>
Tested FF, Chrome, IE, Edge, mob Safari and mob Chrome
Another option would be to use background liner gradients, and flex positioning to make sure that the triangle always scales to its parent container. No matter how wide or narrow you make that container, the triangle always scales with it. Here is the fiddle:
https://jsfiddle.net/29k4ngzr/
<div class="triangle-wrapper-100">
<div class="triangle-left"></div>
<div class="triangle-right"></div>
</div>
.triangle-wrapper-100 {
width: 100%;
height: 100px;
display:flex;
flex-direction: column;
flex-wrap: wrap;
}
.triangle-right {
right: 0px;
background: linear-gradient(to right bottom, #6940B5 50%, transparent 50%);
width: 50%;
height: 100px;
}
.triangle-left {
left: 0px;
background: linear-gradient(to right bottom, #6940B5 50%, transparent 50%);
width: 50%;
height: 100px;
transform: scaleX(-1);
}
I took #Probocop's answer and come up with the following:
<style>
.btn {
background-color: orange;
color: white;
margin-bottom: 50px;
padding: 15px;
position: relative;
text-align: center;
text-decoration: none;
}
.btn:after {
background-color: inherit;
clip-path: url('data:image/svg+xml;utf8,%3Csvg xmlns="http://www.w3.org/2000/svg"%3E%3Cdefs%3E%3CclipPath id="p" clipPathUnits="objectBoundingBox"%3E%3Cpolygon points="0 0, 1 0, 0.5 1" /%3E%3C/clipPath%3E%3C/defs%3E%3C/svg%3E#p'); /* fix for firefox (tested in version 52) */
clip-path: polygon(0% 0%, 100% 0%, 50% 100%);
content: '';
height: 50px;
left: 0;
position: absolute;
right: 0;
top: 100%;
}
</style>
Hello!
This works in Chrome and I've added a fix for Firefox. It doesn't work in Edge, however if you decrease the height of the down arrow then it doesn't look so bad.
Please note that if you are using bootstrap you will need to either change the name or override some of the styles it applies. If you decide to rename it then you also need to add the following to the .btn style:
box-sizing: content-box;
Related
I would like to know how I can make this top border in css and how it is called because i have no idea.
I tried messing with ::before and ::after but it simply wont look good.
.container {
margin-top: 50px;
background: grey;
width: 60%;
height: 300px;
border-radius: 10px;
position: relative;
}
.container:after {
content: '';
background: red;
width: 50%;
height: 100%;
position: absolute;
border-top-right-radius: 15px;
transform: rotate(-3deg);
}
<div class="container"></div>
You can use clip-path and polygon to create triangle on top. Use left and width property wisely so you dont see the left and right part of the traingle.
See the Snippet below:
.container {
margin-top: 50px;
background: #FFCC00;
width: 60%;
height: 300px;
border-radius: 10px;
position: relative;
}
.container:before{
content: '';
position: absolute;
display: block;
left: 2.5%;
top: -20px;
bottom: 0;
width: 95%;
height: 20px;
background: #FFCC00;
-webkit-clip-path: polygon(50% 30%, 0 100%, 100% 100%);
clip-path: polygon(50% 30%, 0 100%, 100% 100%);
}
<div class="container"></div>
You have two ways to do it
and you can learn how to make triangle here
https://www.w3schools.com/howto/howto_css_shapes.asp
I was able to make it using clip path.
This is the tool that I've used: https://bennettfeely.com/clippy/
I am trying to create an arrow label, using css :after
.one-line {
font-size: 2em;
width: 150px;
min-height: 50px;
height: auto;
background: blue;
margin: 5px;
position: relative;
color: #fff;
}
.one-line:after {
content: '';
display: block;
position: absolute;
top: 0;
left: 100%;
width: 0;
height: 0;
border-top: 25px solid transparent;
border-bottom: 25px solid transparent;
border-left: 25px solid red;
}
<div class="one-line">text<br>text<br></div>
I want the after element to take the same height which is of parent, how can I do this by either css or js?
Note: The text inside the label is dynamically populating. [Max length of text: 2 lines]
It might not be possible, as I am thinking, to adjust it any height of parent. Currently I am trying it to adjust for both one and two lines of text.
Here is a solution using clip-path. The idea is to use % values in the polygon to only show the needed shape and it will always work whatever the height is:
.one-line {
font-size: 2em;
width: 150px;
min-height: 50px;
height: auto;
background: blue;
margin: 5px;
position: relative;
color: #fff;
}
.one-line:after {
content: '';
display: block;
position: absolute;
top: 0;
bottom: 0;
width: 25px;
right: -25px;
background: red;
-webkit-clip-path: polygon(100% 50%, 0 0, 0 100%);
clip-path: polygon(100% 50%, 0 0, 0 100%);
}
<div class="one-line">text<br>text<br></div>
<div class="one-line">text<br>text<br>text<br></div>
<div class="one-line">text</div>
<div class="one-line">text<br>text<br>text<br>text<br>text<br>text<br>text<br></div>
Here is another solution that rely on both pseudo elements and some skew transformation to create the arrow. You will notice that this one will keep ratio of the arrow.
.one-line {
font-size: 2em;
width: 150px;
min-height: 50px;
height: auto;
background: blue;
margin: 5px;
position: relative;
color: #fff;
}
.one-line:after {
content: '';
display: block;
position: absolute;
top: 0;
height: 50%;
width: 50%;
right: -25px;
background: red;
transform: skewX(20deg) translateX(-33%);
transform-origin: top;
z-index: -1;
}
.one-line:before {
content: '';
display: block;
position: absolute;
bottom: 0;
height: 50%;
width: 50%;
right: -25px;
background: red;
transform: skewX(-20deg) translateX(-33%);
transform-origin: bottom;
z-index: -1;
}
<div class="one-line">text<br>text<br></div>
<div class="one-line">text<br>text<br>text<br></div>
<div class="one-line">text</div>
<div class="one-line">text<br>text<br>text<br>text<br>text<br>text<br>text<br></div>
Another way with only one pseudo element and linear-gradient.
.one-line {
font-size: 2em;
width: 150px;
min-height: 50px;
height: auto;
background: blue;
margin: 5px;
position: relative;
color: #fff;
}
.one-line:after {
content: '';
display: block;
position: absolute;
top: 0;
height: 100%;
width: 50px;
right: -50px;
background:
linear-gradient(to bottom left, transparent 49.4%, red 50%) top,
linear-gradient(to top left, transparent 49.4%, red 50%) bottom;
background-size:100% 50.2%;
background-repeat:no-repeat;
}
<div class="one-line">text<br>text<br></div>
<div class="one-line">text<br>text<br>text<br></div>
<div class="one-line">text</div>
<div class="one-line">text<br>text<br>text<br>text<br>text<br>text<br>text<br></div>
And finally without any pseudo element and only background on the main element:
.one-line {
font-size: 2em;
width: 200px;
padding-left:50px;
min-height: 50px;
height: auto;
background:
linear-gradient(blue,blue) left/calc(100% - 50px) 100%,
linear-gradient(to bottom left, transparent 49.4%, red 50%) top right/50px 50.2%,
linear-gradient(to top left, transparent 49.4%, red 50%) bottom right/50px 50.2%;
background-repeat:no-repeat;
margin: 5px;
position: relative;
color: #fff;
}
<div class="one-line">text<br>text<br></div>
<div class="one-line">text<br>text<br>text<br></div>
<div class="one-line">text</div>
<div class="one-line">text<br>text<br>text<br>text<br>text<br>text<br>text<br></div>
Well, you could opt to keep the arrow the same size and align it in the middle by changing top to top: 50%; and adding transform: translateY(-50%);
.one-line{
width: 150px;
min-height: 50px;
height: auto;
background: blue;
margin: 5px;
position: relative;
color: #fff;
}
.one-line:after{
content: '';
display: block;
position: absolute;
left: 100%;
width: 0;
height: 0;
border-top: 25px solid transparent;
border-bottom: 25px solid transparent;
border-left: 25px solid red;
top: 50%;
transform: translateY(-50%);
}
<div class="one-line">text<br>text<br>text<br>text</div>
<div class="one-line">text<br>text<br>text<br>text<br>text<br>text<br>text<br>text<br>text<br>text<br>text</div>
using an svg path as a background-image, you could stretch the background-size property to 100% 100%. Just make sure the svg has preserveAspectRatio="none"
.one-line:after {
background-image: url('data:image/svg+xml;charset=UTF-8,<svg version="1.1" id="Layer_1" xmlns="http://www.w3.org/2000/svg" xmlns:xlink="http://www.w3.org/1999/xlink" x="0px" y="0px" preserveAspectRatio="none" viewBox="0 0 25.1 50" style="enable-background:new 0 0 25.1 50;" xml:space="preserve"><polygon class="st0" points="0,50 0,50 25,25 0,0" fill="#ff0000"/></svg>');
position: absolute;
top: 0;
left:100%;
height: 100%;
width: 25px;
background-size: 100% 100%;
background-repeat:no-repeat;
display: block;
content:'';
}
https://jsfiddle.net/7jm54u6L/
I am trying to create an arrow label, using css :after
.one-line {
font-size: 2em;
width: 150px;
min-height: 50px;
height: auto;
background: blue;
margin: 5px;
position: relative;
color: #fff;
}
.one-line:after {
content: '';
display: block;
position: absolute;
top: 0;
left: 100%;
width: 0;
height: 0;
border-top: 25px solid transparent;
border-bottom: 25px solid transparent;
border-left: 25px solid red;
}
<div class="one-line">text<br>text<br></div>
I want the after element to take the same height which is of parent, how can I do this by either css or js?
Note: The text inside the label is dynamically populating. [Max length of text: 2 lines]
It might not be possible, as I am thinking, to adjust it any height of parent. Currently I am trying it to adjust for both one and two lines of text.
Here is a solution using clip-path. The idea is to use % values in the polygon to only show the needed shape and it will always work whatever the height is:
.one-line {
font-size: 2em;
width: 150px;
min-height: 50px;
height: auto;
background: blue;
margin: 5px;
position: relative;
color: #fff;
}
.one-line:after {
content: '';
display: block;
position: absolute;
top: 0;
bottom: 0;
width: 25px;
right: -25px;
background: red;
-webkit-clip-path: polygon(100% 50%, 0 0, 0 100%);
clip-path: polygon(100% 50%, 0 0, 0 100%);
}
<div class="one-line">text<br>text<br></div>
<div class="one-line">text<br>text<br>text<br></div>
<div class="one-line">text</div>
<div class="one-line">text<br>text<br>text<br>text<br>text<br>text<br>text<br></div>
Here is another solution that rely on both pseudo elements and some skew transformation to create the arrow. You will notice that this one will keep ratio of the arrow.
.one-line {
font-size: 2em;
width: 150px;
min-height: 50px;
height: auto;
background: blue;
margin: 5px;
position: relative;
color: #fff;
}
.one-line:after {
content: '';
display: block;
position: absolute;
top: 0;
height: 50%;
width: 50%;
right: -25px;
background: red;
transform: skewX(20deg) translateX(-33%);
transform-origin: top;
z-index: -1;
}
.one-line:before {
content: '';
display: block;
position: absolute;
bottom: 0;
height: 50%;
width: 50%;
right: -25px;
background: red;
transform: skewX(-20deg) translateX(-33%);
transform-origin: bottom;
z-index: -1;
}
<div class="one-line">text<br>text<br></div>
<div class="one-line">text<br>text<br>text<br></div>
<div class="one-line">text</div>
<div class="one-line">text<br>text<br>text<br>text<br>text<br>text<br>text<br></div>
Another way with only one pseudo element and linear-gradient.
.one-line {
font-size: 2em;
width: 150px;
min-height: 50px;
height: auto;
background: blue;
margin: 5px;
position: relative;
color: #fff;
}
.one-line:after {
content: '';
display: block;
position: absolute;
top: 0;
height: 100%;
width: 50px;
right: -50px;
background:
linear-gradient(to bottom left, transparent 49.4%, red 50%) top,
linear-gradient(to top left, transparent 49.4%, red 50%) bottom;
background-size:100% 50.2%;
background-repeat:no-repeat;
}
<div class="one-line">text<br>text<br></div>
<div class="one-line">text<br>text<br>text<br></div>
<div class="one-line">text</div>
<div class="one-line">text<br>text<br>text<br>text<br>text<br>text<br>text<br></div>
And finally without any pseudo element and only background on the main element:
.one-line {
font-size: 2em;
width: 200px;
padding-left:50px;
min-height: 50px;
height: auto;
background:
linear-gradient(blue,blue) left/calc(100% - 50px) 100%,
linear-gradient(to bottom left, transparent 49.4%, red 50%) top right/50px 50.2%,
linear-gradient(to top left, transparent 49.4%, red 50%) bottom right/50px 50.2%;
background-repeat:no-repeat;
margin: 5px;
position: relative;
color: #fff;
}
<div class="one-line">text<br>text<br></div>
<div class="one-line">text<br>text<br>text<br></div>
<div class="one-line">text</div>
<div class="one-line">text<br>text<br>text<br>text<br>text<br>text<br>text<br></div>
Well, you could opt to keep the arrow the same size and align it in the middle by changing top to top: 50%; and adding transform: translateY(-50%);
.one-line{
width: 150px;
min-height: 50px;
height: auto;
background: blue;
margin: 5px;
position: relative;
color: #fff;
}
.one-line:after{
content: '';
display: block;
position: absolute;
left: 100%;
width: 0;
height: 0;
border-top: 25px solid transparent;
border-bottom: 25px solid transparent;
border-left: 25px solid red;
top: 50%;
transform: translateY(-50%);
}
<div class="one-line">text<br>text<br>text<br>text</div>
<div class="one-line">text<br>text<br>text<br>text<br>text<br>text<br>text<br>text<br>text<br>text<br>text</div>
using an svg path as a background-image, you could stretch the background-size property to 100% 100%. Just make sure the svg has preserveAspectRatio="none"
.one-line:after {
background-image: url('data:image/svg+xml;charset=UTF-8,<svg version="1.1" id="Layer_1" xmlns="http://www.w3.org/2000/svg" xmlns:xlink="http://www.w3.org/1999/xlink" x="0px" y="0px" preserveAspectRatio="none" viewBox="0 0 25.1 50" style="enable-background:new 0 0 25.1 50;" xml:space="preserve"><polygon class="st0" points="0,50 0,50 25,25 0,0" fill="#ff0000"/></svg>');
position: absolute;
top: 0;
left:100%;
height: 100%;
width: 25px;
background-size: 100% 100%;
background-repeat:no-repeat;
display: block;
content:'';
}
https://jsfiddle.net/7jm54u6L/
How do I make half a hexagon shape with a border and over top a rectangle shape with a border and an image inside the half hexagon shape using CSS and HTML5
I have no code for this as I have tried but cannot figure out how to do it
I added an image of what I would like to be able to do.
You can create a trapezoid fairly easily with a rectangle and 2 CSS triangles made with some transparent borders using :before and :after.
Working Example:
body {
background: black;
}
.rectangle {
background: #ECECEC;
height: 20px;
}
.trapezoid {
width: 50px;
height: 50px;
position: relative;
margin: 0 auto;
background: #ECECEC;
}
.trapezoid:before,
.trapezoid:after {
content: '';
display: block;
position: absolute;
top: 0;
border: 25px solid transparent;
border-top-color: #ECECEC;
}
.trapezoid:before {
right: 100%;
border-right-color: #ECECEC;
}
.trapezoid:after {
left: 100%;
border-left-color: #ECECEC;
}
<div class="rectangle">
<div class="trapezoid"></div>
</div>
updated with shape and border-colors
div {
margin-top:1em;;
text-align: center;
padding: 0.5em;
border-top:1px solid lightgray;
background: linear-gradient(to bottom, #ECECEC 50%, lightgray 50%, lightgray 51%, transparent 52%);
}
img {
position: relative;
display: block;
margin: 10px auto;
z-index: 1;
}
span {
text-align: center;
display: inline-block;
width:320px;
position: relative;
overflow: hidden;
border-top:1px solid lightgray;
background: linear-gradient(to left, lightgray, lightgray) bottom center, linear-gradient(40deg, transparent 50px, lightgray, 50px, lightgray 52px, #ECECEC 52px)bottom left, linear-gradient(-40deg, transparent 50px, lightgray, 50px, lightgray 52px, #ECECEC 52px)bottom right;
background-repeat: no-repeat;
background-size: 50% 2px, 50% 100%, 50% 100%;
}
<div>
<span>
<img src="http://lorempixel.com/55/46/technics/1" alt="ico"/>
</span>
</div>
older codes
a single pseudo and overflow:hidden, can do it too:
div {
text-align: center;
padding: 0.5em;
background: linear-gradient(to bottom, gray 50%, black 50%);
}
img {
position: relative;
display: block;
padding: 0.5em 0;
z-index: 1;
}
span {
text-align: center;
display: inline-block;
padding: 0 3em;
position: relative;
overflow: hidden;
}
span:before {
position: absolute;
content: '';
bottom: 0;
left: 50%;
margin-left: -75px;
height: 150px;
width: 150px;
background: gray;
transform: rotate(45deg);
}
<div>
<span>
<img src="http://lorempixel.com/40/50/nature/3" alt="ico"/>
</span>
</div>
or a gradient (easier probably to draw borders or shadows if needed)
div {
text-align: center;
padding: 0.5em;
background: linear-gradient(to bottom, gray 50%, black 50%);
}
img {
position: relative;
display: block;
padding: 0.5em 0;
z-index: 1;
}
span {
text-align: center;
display: inline-block;
padding: 0 3em;
position: relative;
overflow: hidden;
background: linear-gradient(40deg, transparent 1.5em, gray 1.5em)bottom left, linear-gradient(-40deg, transparent 1.5em, gray 1.5em)bottom right;
background-repeat: no-repeat;
background-size: 50% 100%;
}
<div>
<span>
<img src="http://lorempixel.com/40/50/nature/3" alt="ico"/>
</span>
</div>
Here is a solution using pseudo elements with skew. The image can be overlayed without problems
.rect {
width: 100%;
height: 20px;
background-color: lightgrey;
border-bottom: 1px solid grey;
position: relative;
}
.hex {
width: 200px;
height: 40px;
position: absolute;
left: 50%;
transform: translateX(-50%);
}
.hex:before, .hex:after {
content: "";
position: absolute;
width: 200px;
height: 40px;
border-style: solid;
border-color: grey;
border-width: 0px 0px 1px 0px;
transform-origin: bottom center;
background-color: lightgrey;
}
.hex:before {
transform: skew(10deg);
border-left-width: 1px;
}
.hex:after {
transform: skew(-10deg);
border-right-width: 1px;
}
<div class="rect">
<div class="hex"></div>
</div>
You can create half octagon using :after.
.halfOctagon {
width: 100px;
height: 50px;
background: #f35916;
position: relative;
top:25px;
left:50px;
}
.halfOctagon:after {
content: "";
position: absolute;
bottom: 0;
left: 0;
border-top: 29px solid #f35916;
border-left: 29px solid #eee;
border-right: 29px solid #eee;
width: 42px;
height: 0;
}
you can try live example in https://jsfiddle.net/kb2tzxq4/
To move the half octagon adjust top and left in css for .halfOctagon
I am trying to create a footer according to a design I received ...
The background color on the left is different from the right one:
I have the following markup:
<div class"wrapper">
<div class="content">
The Text here should no go over the logo
</div>
</div>
My idea is Content DIV to have the logo as background image aligned left and no repeat.
But then I don't know how to create the different color on left and right ...
And I am not sure if I can control the height so that everything aligns.
The content div is centered and has the orange border on the image ...
Thank You,
Miguel
Try this http://codepen.io/nicknameless/pen/cblzB/
I've used CSS3 and no additional markup. This should work for you. It could be cleaned up I think, this is just a quick overview to get you started.
The HTML you provided
<div class="wrapper">
<div class="content">
The Text here should no go over the logo
</div>
</div>
The CSS
html, body {
padding: 0;
margin: 0;
}
div.wrapper {
height: 40px;
background: #850000;
width: 100%;
display: block;
position: relative;
overflow: visible;
top: calc( 100px - 40px );
}
div.wrapper:before {
background: transparent url('http://placehold.it/100x100') no-repeat 0 0;
content: " ";
width: 100px;
height: 100px;
position: absolute;
bottom: 0;
left: 10%;
}
div.content {
left: calc( 10% + 100px );
padding-left: 10px;
bottom: 0;
background-color: #C70000;
display: block;
height: 40px;
position: absolute;
width: calc( 100% - ( 10% + 100px ) );
}
It's was really a pain in the ass, I recommend to take the inner rectangle as a picture, but if you really want it in CSS, here it's: http://jsfiddle.net/B97ym/
HTML:
<div class='wrapper'>
<div class="content">The Text</div>
<div class='border'>
<div class='border2'></div>
<div class='border3'></div>
<div class='logodiv'>
<div class='rectangle'></div>
</div>
</div>
CSS:
.wrapper {
width: 500px;
height: 50px;
margin: 100px auto;
position: relative;
background: linear-gradient(to right, #9c9e9f 40%, #000000 40%);
}
.content{
margin: 0 0 0 50%;
color: #ffffff;
}
.border{
width: 4em;
height: 4em;
background: #FF0000;
position: absolute;
left: 33.7%;
top: -55%;
-ms-transform: rotate(45deg); /* IE 9 */
-webkit-transform: rotate(45deg); /* Chrome, Safari, Opera */
transform: rotate(45deg);
background: linear-gradient(to top, #000000 62%, #9c9e9f 62%);
}
.border2{
width: 0.8em;
height: 4em;
background: #9c9e9f;
position: absolute;
left: 80%;
}
.border3{
width: 0.8em;
height: 0.85em;
background: #000000;
position: absolute;
left: 80%;
top: 80%;
}
.logodiv {
width: 2.5em;
height: 2.5em;
background: #ffffff;
position: absolute;
top: 18%;
left: 18%;
}
.rectangle{
width: 2.1em;
height: 2.1em;
position: relative;
background: #ffffff;
top: -42%;
left: -42%;
-ms-transform: rotate(45deg); /* IE 9 */
-webkit-transform: rotate(45deg); /* Chrome, Safari, Opera */
transform: rotate(45deg);
}
Hope it's will be helpful to someone (:
Use a CSS background-image on the wrapper layer that contains the entire logo, bars an all. Add enough margin-left on the inner layer to shove the text beyond the logo.
Create a div with two div's inside with 50% width for left and right and fixed height. Make sure you overflow the logo.
I wonder if this FIDDLE will give you a place to start.
CSS
.holder {
width: 500px;
margin: 100px auto;
position: relative;
}
.leftdiv {
width: 40%;
height: 60px;
float: left;
background-color: red;
}
.rightdiv {
width: 60%;
height: 60px;
float: left;
background-color: blue;
}
.logodiv {
width: 44px;
height: 44px;
position: absolute;
left: 157px;
top: -42px;
background-color: white;
transform: rotate(45deg);
border-left: 20px solid blue;
border-right: 20px solid red;
border-top: 20px solid red;
border-bottom: 20px solid blue;
}
.whiteout {
background-color: white;
width: 30px;
height: 60px;
border: 0px solid black;
position: absolute;
top: -60px;
left: 183px;
}