Gulp appending to files, not overwriting - gulp

I'm trying to concatenate my JS files and run them through Babel for a new project, but instead of overwriting the destination file on each task run, my gulpfile only appends changes to the file. So my destination file ends up looking like this:
console.log('hello');
//# sourceMappingURL=app.js.map
console.log('goodbye');
//# sourceMappingURL=app.js.map
What am I missing? Below is my gulpfile.
Thanks in advance.
var gulp = require('gulp');
var sourcemaps = require("gulp-sourcemaps");
var uglify = require('gulp-uglify');
var rename = require('gulp-rename');
var concat = require('gulp-concat');
var babel = require('gulp-babel');
var browserSync = require('browser-sync').create();
var reload = browserSync.reload;
gulp.task('js', function(){
return gulp.src("./app/js/*.js")
.pipe(sourcemaps.init())
.pipe(concat("app.js"))
.pipe(babel())
.pipe(sourcemaps.write("."))
.pipe(gulp.dest("./app/js/"));
});
gulp.task('js-reload', ['js'], reload);
gulp.task('serve', ['js'], function() {
browserSync.init({
server: "./app"
});
gulp.watch("./app/js/*.js").on('change', ['js-reload']);
gulp.watch("./app/*.html").on('change', reload);
});
gulp.task('default', ['js', 'serve']);

You're reading and writing to the same destination directory. Therefore the file app.js is first read, some stuff is added to it, and then the result is written to app.js, causing this appending behaviour. You should output to a different directory than you are reading from.

Related

Gulp css styles are not updated

I have problem. Yestrday I had to update the Node.js kernel and now that I change something in the LESS file, there will be no css update. Gulpfile is the same as before the update. Could someone advise me what's wrong with my gulpfile script?
The HTML file update is OK.
//*********** IMPORTS *****************
var gulp = require('gulp'),
browserSync = require('browser-sync');
var postcss = require('gulp-postcss');
var less = require('gulp-less');
var watch = require('gulp-watch');
var livereload = require('gulp-livereload');
var autoprefixer = require('gulp-autoprefixer');
var concat = require('gulp-concat-css');
var cssmin = require('gulp-cssmin');
/* BROWSERSYNC */
gulp.task('browserSync', function () {
var files = ['orient-spa/**'];
browserSync.init(files, {
server: {
baseDir: 'orient-spa/',
index: 'index.html'
},
logPrefix: 'OS01',
browser: ['chrome']
});
});
gulp.task('css', function () {
var processors = [
autoprefixer
];
return gulp.src('./orient-spa/skins/less/index-files.less')
.pipe(less())
.pipe(postcss(processors))
.pipe(gulp.dest('./orient-spa/skins/css/'))
.pipe(livereload());
});
gulp.task('watch', function() {
livereload.listen();
gulp.watch('./orient-spa/skins/less/*.less', ['css']);
gulp.watch('./orient-spa/skins/css/*.css', ['concatMinify']);
});
gulp.task('concatMinify', function () {
return gulp.src('./orient-spa/skins/css/*.css')
.pipe(concat("index.css"))
.pipe(cssmin())
.pipe(gulp.dest('./orient-spa/skins/css/compiled'))
.pipe(livereload());
});
gulp.task('default', ['browserSync', 'watch', 'css', 'concatMinify']);
Thanks for your advice :-)
I try this path, but problem remains.
Last version node.js was Node.js 7.2.1 (Node.js), now Node.js 9.8.0.
I attach an image to the console after changing 1 line in the LESS file.
Here I see that the set of commands does not call correctly. Or they are called repeatedly. Do not you see a mistake here, please?
Thanks for your advice

Concat and Minify not working / Gulp

I've got the following code to concatenate and minify my .css files :
var gulp = require('gulp'),
concatCSS = require('gulp-concat-css'),
minifyCSS = require('gulp-minify-css'),
rename = require('gulp-rename'),
notify = require('gulp-notify'),
browserSync = require('browser-sync').create(),
reload = browserSync.reload,
autoprefixer = require('gulp-autoprefixer');
//Concat CSS
gulp.task('concat', function () {
return gulp.src('css/*.css')
.pipe(concatCSS('css/bundle.css'))
.pipe(rename('bundle.min.css'))
.pipe(minifyCSS('bundle.min.css'))
.pipe(gulp.dest('out/'));
});
//Watch HTML and reload
gulp.task('serve', function () {
// Serve files from the root of this project
browserSync.init({
server: {
baseDir: "./app"
}
});
browserSync.watch("app/*.html").on("change", reload);
});
//Default
gulp.task('default', ['serve', 'concat']);
Although Terminal shows no errors the code for concatenation and minifying is not working.
What should I fix to solve the issue?
The structure of my project:
UPD!
In my case there were some syntactic mistakes in .css files. Works well after correcting them and removing minifyCSS since it's no longer supported.

Gulp: how to watch multiple files and perform a task for only the changes files?

I wanna do this thing:
I have a folder with many js files. When I save one of them, I want to save the minified file in other folder.
I got it partially, because my script watch many files and when I change one, all files are copied and minified to the destination folder.
I discover recently that gulp.run is not used anymore.
If someone could help me, I'll be greatful.
I was trying this way:
var gulp = require('gulp');
var jshint = require('gulp-jshint');
var uglify = require('gulp-uglify');
var watch = require('gulp-watch');
var files_dev = "./_sys/js/private/*.js";
var path_prod = "./_sys/js/public/";
gulp.task('dist-file', function(file) {
gulp.src(file)
.pipe(uglify())
.pipe(gulp.dest(path_prod));
});
gulp.task('default', function() {
gulp.watch(files_dev).on("change", function(file) {
gulp.run('dist-file');
});
dist-file doen't need to be a gulp task, you can make that a function which you can pass the file or glob to process. Also watch is part of gulp now so you shouldn't need gulp-watch.
var jshint = require('gulp-jshint');
var uglify = require('gulp-uglify');
var files_dev = "./_sys/js/private/*.js";
var path_prod = "./_sys/js/public/";
function uglifyFile (file) {
gulp.src([file])
.pipe(uglify())
.pipe(gulp.dest(path_prod));
}
gulp.task('watch-test', function() {
gulp.watch(files_dev).on("change", function (event) {
uglifyFile(event.path);
});
});

gulp filters javascript files and not css files

I am a newbie to gulp. I am trying to create one single vendor.css file and vendor.js file with gulp.
The vendor.css should be
-bootstrap.css
The vendor.js should be
-jquery.js
-bootstrap.js
-angular.js
-angular-ui-router.js
gulpfile.js
// Include Gulp
var gulp = require('gulp');
// Include plugins
var plugins = require("gulp-load-plugins")({
pattern: ['gulp-*', 'gulp.*'],
replaceString: /\bgulp[\-.]/
});
// Define default destination folder
var dest = 'public';
gulp.task('vendorjs', function(){
var filterJS = plugins.filter('**/*.js');
return gulp.src('./bower.json')
.pipe(plugins.mainBowerFiles( ))
.pipe(filterJS)
.pipe(plugins.concat('vendor.js'))
.pipe(plugins.uglify())
.pipe(filterJS.restore())
.pipe(gulp.dest(dest+"/vendor/js/"));
});
gulp.task('vendorcss', function(){
var filterCSS = plugins.filter('**/*.css');
return gulp.src('./bower.json')
.pipe(plugins.mainBowerFiles( ))
.pipe(filterCSS)
.pipe(plugins.concat('vendor.css'))
.pipe(plugins.uglify())
.pipe(filterCSS.restore())
.pipe(gulp.dest(dest+"/vendor/css/"));
});
gulp.task('default', function() {
// place code for your default task here
});
gulp.task('serve', ['vendorcss','vendorjs'], function () {
});
When i run gulp serve, it executes without error. But I end up with
public/vendor/css/angular/angular.js
public/vendor/css/angular-ui-router/release/angular-ui-router.js
public/vendor/css/bootstrap/dist/js/bootstrap.js
public/vendor/css/bootstrap/less/bootstrap.less
public/vendor/css/jquery/dist/jquery.js
public/vendor/js/vendor.js
public/vendor/js/bootstrap/less/bootstrap.less
Why do my css files are missing. Why do i get less file.
My output should be
public/vendor/vendor.js
public/vendor/vendor.css
How do i map the vendor.js and vendor.css with my html

Gulp shell delay

I'm trying to execute a shell command at the end of a series of gulp tasks. I noticed that the changes written to the project's files aren't being written before the shell command picks up some of the files and copies them elsewhere. I'm using gulp-shell to execute my shell commands.
I found that if I executed a 'ls' command before my file copy, there's enough of a delay that the files are all written before I try to copy them. Is there a cleaner way to do this?
Here's the gruntfile:
var gulp = require('gulp');
var shell = require('gulp-shell');
var jshint = require('gulp-jshint');
var changed = require('gulp-changed');
var imagemin = require('gulp-imagemin');
var minifyHTML = require('gulp-minify-html');
var concat = require('gulp-concat');
//Uncomment out this line before going to production
//var stripDebug = require('gulp-strip-debug');
var uglify = require('gulp-uglify');
var autoprefix = require('gulp-autoprefixer');
var minifyCSS = require('gulp-minify-css');
// JS hint task
gulp.task('jshint', function() {
gulp.src('./code/js/*.js')
.pipe(jshint())
.pipe(jshint.reporter('default'));
});
// minify new images
gulp.task('imagemin', function() {
var imgSrc = './code/img/**/*', imgDst = './www/img';
gulp.src(imgSrc)
.pipe(changed(imgDst))
.pipe(imagemin())
.pipe(gulp.dest(imgDst));
});
// minify new or changed HTML pages
gulp.task('htmlpage', function() {
var htmlSrc = './code/*.html', htmlDst = './www';
gulp.src(htmlSrc)
.pipe(changed(htmlDst))
.pipe(minifyHTML())
.pipe(gulp.dest(htmlDst));
});
// JS concat, strip debugging and minify
gulp.task('scripts', function() {
gulp.src(['./code/js/index.js', './code/js/*.js'])
.pipe(concat('script.js'))
//Uncomment out this line before going to production
//.pipe(stripDebug())
.pipe(uglify())
.pipe(gulp.dest('./www/'));
});
// CSS concat, auto-prefix and minify
gulp.task('styles', function() {
gulp.src(['./code/css/*.css'])
.pipe(concat('styles.css'))
.pipe(autoprefix('last 2 versions'))
.pipe(minifyCSS())
.pipe(gulp.dest('./www/'));
});
gulp.task('prepare', shell.task(['ls', 'cordova prepare']));
// default gulp task
gulp.task('default', ['imagemin', 'htmlpage', 'scripts', 'styles', 'prepare'], function() {
});
It's the prepare task - when it runs, the other files haven't finished executing yet.
It seems that I can set a dependent task that must finish before my prepare:
gulp.task('prepare', [styles], shell.task(['ls', 'cordova prepare']));
I haven't tested it, but I expect this will work?
Try gulp-run-sequence Gulp tasks are Async and this enables them to fire synchronously. Should solve your issue.