I have the following query:
SELECT s.username FROM `instagram_shop` s
INNER JOIN `instagram_shop_picture` p
ON s.id = p.shop_id
WHERE s.`deletedAt` IS NULL
HAVING COUNT(p.id) = 0
GROUP BY s.id
and I keep getting the following error:
You have an error in your SQL syntax; check the manual that
corresponds to your MySQL server version for the right syntax to use
near 'GROUP BY s.id LIMIT 0, 30' at line 6
What is the issue here?
Move the HAVING clause after the GROUP BY clause.
MySQL is very specific about the order of keywords/clauses in a SELECT statement
Reference: 13.2.9 SELECT Syntax https://dev.mysql.com/doc/refman/5.6/en/select.html
Try the below one :
there is an syntax issue with your query,
Having should follow after GROUP BY caluse.
Also the columns which you mention in your GROUP BY
clause should be present in the SELECT list.
SELECT s.id,s.username FROM `instagram_shop` s
INNER JOIN `instagram_shop_picture` p
ON s.id = p.shop_id
WHERE s.deletedAt IS NULL
GROUP BY s.id,s.username
HAVING COUNT(s.id) = 0
Related
I am testing one of my project it's opencart
Basically i wanna know my table name for sure for example oc20_product and oc20_manufacturer are table names aren't them ? and this the others actual columns ?
What is my table and column name for sure ?
Thanks in advance
Notice:
Error: You have an error in your SQL syntax; check the manual that
corresponds to your MySQL server version for the right syntax to use
near '%' AND p.status = 1 GROUP BY m.manufacturer_id ORDER BY m.name
ASC' at line 4 Error No: 1064
SELECT m.manufacturer_id, m.name, COUNT(p.product_id) AS products_total
FROM oc20_product p
LEFT JOIN oc20_product_description pd
ON pd.product_id = p.product_id
LEFT JOIN oc20_manufacturer m
ON m.manufacturer_id = p.manufacturer_id
WHERE pd.name LIKE '%mycard'%' AND p.status = 1
GROUP BY m.manufacturer_id
ORDER BY m.name ASC in
wrong quote in like pattern you could use a concat for an easy pattern format
SELECT m.manufacturer_id
, m.name
, COUNT(p.product_id) AS products_total
FROM oc20_product p
LEFT JOIN oc20_product_description pd ON pd.product_id = p.product_id
LEFT JOIN oc20_manufacturer m ON m.manufacturer_id = p.manufacturer_id
WHERE pd.name LIKE concat('%',mycard,'%') AND p.status = 1
GROUP BY m.manufacturer_id, m.name
ORDER BY m.name ASC
I have one problem with my SELECT query in my blog page.
I want comment count of each blog when comment status=1.
I am apply following query..
SELECT CONCAT(u.first_name," ",u.last_name) name, r.*,
IF(c.status=1,COUNT(c.id)) as comment
FROM users u
RIGHT JOIN resources r ON u.id = r.created_by
LEFT JOIN comments c ON r.id = c.resource_id
WHERE r.type = 1
AND r.status=1
GROUP BY r.id
ORDER BY r.created_date DESC
LIMIT 0,5
but it giving SYNTAX ERROR..
Error: SQLSTATE[42000]: Syntax error or access violation: 1064 You have an error in your
SQL syntax; check the manual that corresponds to your MariaDB server version for the right
syntax to use near ') as comment FROM users u RIGHT JOIN resources r ON u.id = r.created_by
LEFT JOI' at line 1
Please tell me where I am wrong.
Thanks
If statement contains three expressions. First, the expression, second the value returned if condition is true and third if condition is false so you are missing the third expression.
Try the below code
SELECT CONCAT(u.first_name," ",u.last_name) name,r.*,IF(c.status=1,COUNT(c.id), 0) as comment
FROM users u RIGHT JOIN resources r ON u.id = r.created_by
LEFT JOIN comments c ON r.id = c.resource_id
WHERE r.type = 1
AND r.status=1
GROUP BY r.id
ORDER BY r.created_date DESC
LIMIT 0,5
Select concat(u.first_name," ",u.last_name) name,r.*,
case when c.status=1 then COUNT(c.id) end as comment
FROM users u RIGHT JOIN resources r ON u.id = r.created_by
LEFT JOIN comments c ON r.id = c.resource_id
WHERE r.type = 1
AND r.status=1
GROUP BY r.id
ORDER BY r.created_date DESC
LIMIT 0,5
https://www.w3schools.com/sql/func_mysql_case.asp
if function requires 3 parameters to be passed to it. IF(expression ,expr_true, expr_false) is how it should be used.
Have a look at https://www.w3resource.com/mysql/control-flow-functions/if-function.php
I've got the following SQL query and I'm trying to implement pagination, so I first want to get the COUNT of the result:
The normal query (works fine)
SELECT DISTINCT c.*, p1.*, username FROM candidate c
LEFT JOIN note p1 ON (c.candID = p1.candidateID)
LEFT JOIN user ON p1.userID = user.id
LEFT OUTER JOIN note p2 ON
(c.candID = p2.candidateID AND (p1.noteID < p2.noteID))
WHERE p2.candidateID IS NULL ORDER BY c.firstname ASC
I've tried the following, but it throws an error and I'm not sure what correct syntax to use:
Attempting to count the results (doesn't work)
SELECT COUNT(DISTINCT c.*, p1.*, username) FROM candidate c
LEFT JOIN note p1 ON (c.candID = p1.candidateID)
LEFT JOIN user ON p1.userID = user.id
LEFT OUTER JOIN note p2 ON
(c.candID = p2.candidateID AND (p1.noteID < p2.noteID))
WHERE p2.candidateID IS NULL ORDER BY c.firstname ASC
The error:
Syntax error or access violation: 1064 You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ', p1., username) FROM candidate c LEFT ' at line 1
One option is to use a subquery:
SELECT COUNT(*)
FROM (
SELECT DISTINCT c.*, p1.*, username FROM candidate c
LEFT JOIN note p1 ON (c.candID = p1.candidateID)
LEFT JOIN user ON p1.userID = user.id
LEFT OUTER JOIN note p2 ON
(c.candID = p2.candidateID AND (p1.noteID < p2.noteID))
WHERE p2.candidateID IS NULL
) t
Depending on your data, you may be able to do this without the subquery, but you cannot use multiple columns with the count aggregate -- that's what is causing your error.
I am wondering about another syntax error:
SELECT * FROM forum_question
WHERE category='art'
LEFT JOIN forum_answer ON (forum_question.id = forum_answer.question_id)
GROUP BY forum_question.id
ORDER BY a_datetime DESC;
The error I am getting is this:
You have an error in your SQL syntax; check the manual that
corresponds to your MySQL server version for the right syntax to use
near 'LEFT JOIN forum_answer ON (forum_question.id =
forum_answer.question_id) GROUP B' at line 1
Thanks.
The WHERE clause should be after the FROM clause. JOIN statements are part of the FROM clause
SELECT *
FROM forum_question
LEFT JOIN forum_answer
ON (forum_question.id = forum_answer.question_id)
WHERE category='art'
GROUP BY forum_question.id
ORDER BY a_datetime DESC;
The WHERE clause should be after the JOIN clause
SELECT *
FROM forum_question
LEFT JOIN forum_answer
ON (forum_question.id = forum_answer.question_id)
WHERE category='art'
GROUP BY forum_question.id
ORDER BY a_datetime DESC;
First join, then use the where clause:
SELECT * FROM forum_question
LEFT JOIN forum_answer ON (forum_question.id = forum_answer.question_id)
WHERE forum_question.category='art'
GROUP BY forum_question.id
ORDER BY a_datetime DESC;
I used a query like
select a.email,b.vuid
from user a
,inner join group b on a.uid = b.uid
where a.email='xx#xx.de' and a.kid=1 and b.vid=29
limit 1
but I always get this error.
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'inner join group b on a.uid = b.uid where a.email='xx#xx.de' at line 1
I think its because the inner join but I don't know really.. Could someone help me?
Remove the , after from user a.
Your query should be:
select a.email,b.vuid
from user a
inner join group b
on a.uid = b.uid
where a.email='xx#xx.de'
and a.kid=1
and b.vid=29
limit 1
select a.email,b.vuid from user as a inner join group as b on ...
Of course you can omit the as keyword as demonstrated by #FrustratedWithFormsDesigner but in my opinion it is much more readable this way.