Mysql Left outer join in my Query for optimize - mysql

I have two database table name called "tablestr table" and "restbookingtable":
tablestr:
str_id is primary key
restbooking:
bookingsection_id is foreign key
in booking table i storing str_id multiple values with comma separated and My query is
SELECT `str_id` FROM (`rest_tablestr`) WHERE str_id NOT IN (
SELECT SUBSTRING_INDEX(SUBSTRING_INDEX(t.bookingsection_id, ",", n.n), ",", -1) value FROM rest_restaurantbooking t
CROSS JOIN (
SELECT a.N + b.N * 10 + 1 n FROM (
SELECT 0 AS N
UNION ALL
SELECT 1
UNION ALL
SELECT 2
UNION ALL
SELECT 3
UNION ALL
SELECT 4
UNION ALL
SELECT 5
UNION ALL
SELECT 6
UNION ALL
SELECT 7
UNION ALL
SELECT 8
UNION ALL
SELECT 9) a , (
SELECT 0 AS N
UNION ALL
SELECT 1
UNION ALL
SELECT 2
UNION ALL
SELECT 3
UNION ALL
SELECT 4
UNION ALL
SELECT 5
UNION ALL
SELECT 6
UNION ALL
SELECT 7
UNION ALL
SELECT 8
UNION ALL SELECT 9)
b ORDER BY n ) n
WHERE n.n <= 1 + (LENGTH(t.bookingsection_id) -
LENGTH(REPLACE(t.bookingsection_id, ",", ""))) AND
t.res_id = 21 AND
t.booking_status not in ("cancelled","departed","noshow") AND
((t.bookingstart_time <= "2015-06-12 19:45:00" AND t.bookingend_time >= "2015-06-12 22:15:00") OR
(t.bookingend_time >= "2015-06-12 19:45:00" AND t.bookingend_time <= "2015-06-12 22:15:00") OR
(t.bookingstart_time >= "2015-06-12 19:45:00" AND t.bookingstart_time <= "2015-06-12 22:15:00") OR
(t.bookingstart_time >= "2015-06-12 19:45:00" AND t.bookingend_time <= "2015-06-12 22:15:00")) ) AND
`res_id` = '21' AND
`area_id` = '28' AND
`wait_table` = 'no' AND
`availability` = 'yes';
Result Set:
Can any body help me to rewrite query with left outer join or can be optimize query.

Related

Insert unique random number with recursive MySQL

I want to populate a table with unique random numbers without using a procedure.
I've tried using this reply to do it but not success.
What I'm trying to do is something like this but validating that numbers are not repeated:
INSERT into table (row1,row2)
WITH RECURSIVE
cte AS ( SELECT 0 num, LPAD(FLOOR(RAND() * 99999999),8,0) random_num
UNION ALL
SELECT num+1, LPAD(FLOOR(RAND() * 99999999),8,0) random_num
FROM cte WHERE num < 100000-1)
SELECT random_num, null
FROM cte;
In the example above, I am able to generate random values and insert them but without validating that the numbers are not repeated.
I have tried to do this:
INSERT into table (row1,row2)
WITH RECURSIVE
cte AS ( SELECT 0 num, LPAD(FLOOR(RAND() * 99999999),8,0) random_num
UNION ALL
SELECT num+1, LPAD(FLOOR(RAND() * 99999999),8,0) random_num
FROM cte WHERE num < 100000-1 AND random_num NOT IN (SELECT random_num FROM cte WHERE random_num IS NOT NULL))
SELECT random_num, null
FROM cte;
but the condition AND random_num NOT IN (SELECT random_num FROM cte WHERE random_num IS NOT NULL) in the where case, causes an SQL Error [4008] [HY000]: Restrictions imposed on recursive definitions are violated for table 'cte'
Any suggestions of how to do it? thank you!.
This could be an option. Generate all possible values, sort randomly and take desired number of entries.
CREATE TABLE random_data (
row1 INT PRIMARY KEY AUTO_INCREMENT,
row2 VARCHAR(10) NOT NULL,
UNIQUE KEY _Idx1 ( row2 )
);
INSERT INTO random_data (row2)
SELECT LPAD(num, 8, 0)
FROM (
SELECT h * 10000000 + g * 1000000 + f * 100000 + e * 10000 + d * 1000 + c * 100 + b * 10 + a AS num
FROM (SELECT 0 a UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) ta
JOIN (SELECT 0 b UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) tb
JOIN (SELECT 0 c UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) tc
JOIN (SELECT 0 d UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) td
JOIN (SELECT 0 e UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) te
JOIN (SELECT 0 f UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) tf
JOIN (SELECT 0 g UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) tg
JOIN (SELECT 0 h UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) th
) n
ORDER BY RAND()
LIMIT 100000;
If you have a table - any table - with e.g. 100 rows then you can generate million distinct random numbers between 0 and 99999999 as follows:
select distinct floor(rand() * 100000000)
from t as t0, t as t1, t as t2
limit 1000000
Note that because of distinct you will need to generate a bigger number of rows so that you get desired number of rows after distinct.

How to fill missing values in aggregate-by-time function

I have function (from this question) which groups values by every 5 minutes and calculate min/avg/max:
SELECT (FLOOR(clock / 300) * 300) as period_start,
MIN(value), AVG(value), MAX(value)
FROM data
WHERE clock BETWEEN 1200000000 AND 1200001200
GROUP BY FLOOR(clock / 300);
However, due to missing values, some five-minute periods are skipped, making the timeline inconsistent. How to make it so that in the absence of data for a certain period, the value of max / avg / min becomes 0, instead of being skipped?
For example:
If I have timestamp - value
1200000001 - 100
1200000002 - 300
1200000301 - 100
1200000601 - 300
I want to get this: (select min/avg/max, time between 1200000000 and 1200001200)
1200000000 - 100/200/300
1200000300 - 100/100/100
1200000600 - 300/300/300
1200000900 - 0/0/0
Instead of this: (time between 1200000000 and 1200001200)
1200000000 - 100/200/300
1200000300 - 100/100/100
1200000600 - 300/300/300
1200000900 - THIS LINE WILL NOT BE, I will only get 3 lines above. No data between 1200000900 and 1200001200 for calculation.
My Answer:
Generate first table with required time range, and then left join this generated table on query with common group by operator. Such like this:
select * from
(select UNIX_TIMESTAMP(gen_date) as unix_date from
(select adddate('1970-01-01',t4*10000 + t3*1000 + t2*100 + t1*10 + t0) gen_date from
(select 0 t0 union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t0,
(select 0 t1 union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t1,
(select 0 t2 union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t2,
(select 0 t3 union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t3,
(select 0 t4 union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t4) v
where gen_date between '2017-01-01' and '2017-12-31') date_range_table
left join (
SELECT (FLOOR(clock / 300) * 300) as period_start,
MIN(value), AVG(value), MAX(value)
FROM table
WHERE clock BETWEEN 1483218000 AND 1514667600
GROUP BY FLOOR(clock / 300)) data_table
on date_range_table.unix_date = data_table.period_start;
Use recursive CTE (available in MariaDB starting from 10.2.2) and generate base calendar table:
WITH RECURSIVE
cte AS ( SELECT #timestart timestart, #timestart + 300 timeend
UNION ALL
SELECT timestart + 300, timeend + 300 FROM cte WHERE timeend < #timeend)
SELECT cte.timestart,
COALESCE(MIN(value), 0) min_value,
COALESCE(AVG(value), 0) avg_value,
COALESCE(MAX(value), 0) max_value
FROM cte
LEFT JOIN example ON example.clock >= cte.timestart
AND example.clock < cte.timeend
GROUP BY cte.timestart;
https://dbfiddle.uk/?rdbms=mariadb_10.3&fiddle=f5c41b7596d56f1d7babe075f19302ec
I am not very sure but here's a link which can solve your problem
https://www.sqlservercurry.com/2009/06/find-missing-identity-numbers-in-sql.html
You can try this one;
with seq as (
select
(step-1)* 300 + (select (FLOOR(min(clock) / 300) * 300) from data) as step
from
(select row_number() over() as step from data) tmp
where
tmp.step-1 < (select(max(clock)-min(clock))/ 300 from data))
SELECT seq.step as period_start, MIN(value), AVG(value), MAX(value)
FROM seq left join data on (seq.step=(FLOOR(clock / 300) * 300))
WHERE clock BETWEEN 1622667600 AND 1625259600
GROUP BY period_start
Alternative answer is generate first table with required time range, and then left join this generated table on query with common group by operator.

Mysql find id gaps in temporary table

I need to find id gaps in a integer field of a temporary table.
Due to a temporary table limitation I cannot open the table twice and join it with itself.
This is the example:
CREATE TEMPORARY TABLE tmp_table (
id int(8) unsigned,
PRIMARY KEY (id)
);
INSERT INTO tmp_table VALUES (1),(2),(4),(7),(10),(11),(13);
and here I want to find this resultset:
3, 5, [6], 8, [9], 12
[#]=optional
A solution that works, but might be a better one.
This generates a range of numbers (so you will need to modify it for larger ranges - this copes up to 1000), and cross joins that range against the temp table. It finds the max and min ids from the temp table that are greater than or equal to or less or equal to (respectively) than generated value. Then in the HAVING clause check that the greater / less vales are not equal and also not null
SELECT 1 + units.i + tens.i * 10 + hundreds.i * 100 AS poss_num,
MAX(IF(tmp_table.id <= 1 + units.i + tens.i * 10 + hundreds.i * 100, tmp_table.id, NULL)) AS max_id,
MIN(IF(tmp_table.id >= 1 + units.i + tens.i * 10 + hundreds.i * 100, tmp_table.id, NULL)) AS min_id
FROM
(
SELECT 0 AS i UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9
) units
CROSS JOIN
(
SELECT 0 AS i UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9
) tens
CROSS JOIN
(
SELECT 0 AS i UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9
) hundreds
CROSS JOIN tmp_table
GROUP BY poss_num
HAVING min_id != max_id
AND min_id IS NOT NULL
AND max_id IS NOT NULL

How to select only particular word start with # from sentence mysql query

let's explain briefly
this is very new topic, I want to fetch only particular word start with # from sentence for example
i have sentence like
Hi Majjx Uxud Xhhxhd Hx Dhx #hdhd Jdhhdhshhfd Hxhhd #bhd Hxhd Hxhhd Dhhdh www.myinnos.in Hdhd Xfhhxhd Xhhdh Xhx 9560233669 ndhdh Hxhhdh Dhh
from above sentence I have to fetch #hdhd
got a solution for my question, now I want to count and show the repeated words as count
select val from(
select (substring_index(substring_index(a, ' ', n.n), ' ', -1)) val
from (select id, message as a from filmbooknewsfeed) t
cross join(
select a.n + b.n * 10 + 1 n
from
(select 0 as n union select 1 union select 2 union select 3 union select 4 union
select 5 union select 6 union select 7 union select 8 union select 9
) a,
(select 0 as n union select 1 union select 2 union select 3 union select 4 union
select 5 union select 6 union select 7 union select 8 union select 9
) b
order by n
) n
where n.n <= 1 + (length(t.a) - length(replace(t.a, ' ', '')))
order by val asc
)x where val like '#%'
As I said, you need to convert the sentence into rows. Just in case, if in sentence you have more than 1 words start with #.
select val from(
select (substring_index(substring_index(a, ' ', n.n), ' ', -1)) val
from (
select 'Hi Majjx Uxud Xhhxhd Hx Dhx #hdhd Jdhhdhshhfd Hxhhd #bhd Hxhd Hxhhd Dhhdh www.myinnos.in Hdhd Xfhhxhd Xhhdh Xhx 9560233669 ndhdh Hxhhdh Dhh' as a
) t
cross join(
select a.n + b.n * 10 + 1 n
from
(select 0 as n union select 1 union select 2 union select 3 union select 4 union
select 5 union select 6 union select 7 union select 8 union select 9
) a,
(select 0 as n union select 1 union select 2 union select 3 union select 4 union
select 5 union select 6 union select 7 union select 8 union select 9
) b
order by n
) n
where n.n <= 1 + (length(t.a) - length(replace(t.a, ' ', '')))
order by val asc
)x where val like '#%'
Will give you #hdhd. even if you has more than 1 # in the sentence. This would give you correct result.
edit
If you want to group by result and sort by most occurence words like twitter tranding topic, modify your query like this (as query on the question)
select val,count(val) as cnt from(
select (substring_index(substring_index(a, ' ', n.n), ' ', -1)) val
from (select id, message as a from filmbooknewsfeed) t
cross join(
select a.n + b.n * 10 + 1 n
from
(select 0 as n union select 1 union select 2 union select 3 union select 4 union
select 5 union select 6 union select 7 union select 8 union select 9
) a,
(select 0 as n union select 1 union select 2 union select 3 union select 4 union
select 5 union select 6 union select 7 union select 8 union select 9
) b
order by n
) n
where n.n <= 1 + (length(t.a) - length(replace(t.a, ' ', '')))
order by val asc
)x where val like '#%'
group by val
order by cnt desc
You can do this using substring_index():
select substring_index(substring_index(substring_index(sentence, '#', 2), '#', -1), ' ', 1)

Rewrite to not include subquery in FROM?

A great fellow helped me with developing the following statement. However, in mySQL - I cannot save a view with a subquery in the FROM clause. Any suggestions o nhow to rewrite this so that it can be saved into a mySQL server?
SELECT t.idPatternMetadata, SUBSTRING_INDEX(SUBSTRING_INDEX(t.sKeywords, ',', n.n), ',', -1) color , count(*) as counts
FROM tblPatternMetadata t CROSS JOIN
(
SELECT a.N + b.N * 10 + 1 n
FROM
(SELECT 0 AS N UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) a
,(SELECT 0 AS N UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) b
ORDER BY n
) n
WHERE n.n <= 1 + (LENGTH(t.sKeywords) - LENGTH(REPLACE(t.sKeywords, ',', '')))
group by color
THANKS in advance!
One option is to create a table that contains the 100 integer values, and reference that table in the query.
CREATE TABLE n (n INT UNSIGNED PRIMARY KEY);
INSERT INTO n (n)
SELECT a.n + b.n * 10 + 1 n
FROM ( SELECT 0 AS n UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3
UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6
UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9
) a
CROSS
JOIN ( SELECT 0 AS n UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3
UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6
UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9
) b
ORDER BY 1;
Then rewrite your query to reference the table in place of the inline view:
SELECT t.idPatternMetadata, SUBSTRING_INDEX(SUBSTRING_INDEX(t.sKeywords, ',', n.n), ',', -1) AS color
, count(*) AS counts
FROM tblPatternMetadata t
JOIN n
ON n.n <= 1 + (LENGTH(t.sKeywords) - LENGTH(REPLACE(t.sKeywords, ',', '')))
GROUP BY color