How I can get 100 new records everyday from a database comprised of 10,000 rows?
note : every day new 100 rows not edited
My current query is:
SELECT * FROM `invoices` WHERE DATE(`ModifiedTime`)=CURDATE()) Limit 100
How i can show 100 rows every day ?
The additional ")" after the curdate() function was removed to prevent the syntax error. See SQL Fiddle demo
Before
SELECT * FROM `invoices` WHERE DATE(`ModifiedTime`)=CURDATE()) Limit 100
After
SELECT * FROM `invoices` WHERE DATE(`ModifiedTime`)=CURDATE() Limit 100
Related
I have a table called 'Articles' in that table I have 2 columns that will be essential in creating the query I want to create. The first column is the dateStamp column which is a datetime type column. The second column is the Counter column which is an int(255) column. The Counter column technically holds the views for that particular field.
I am trying to create a query that will generate the last 30 days of records. It will then order the records based on most viewed. This query will only pick up 10 records. The current query I have is this:
SELECT *
FROM Articles
WHERE DATEDIFF(day, dateStamp, getdate()) BETWEEN 0 and 30
LIMIT 10
) TOP10
ORDER BY Counter DESC
This query is not displaying any records, but I don't understand what I am doing wrong. Any suggestions?
The MySQL version of the query would look like this:
SELECT a.*
FROM Articles a
WHERE a.dateStamp >= CURDATE() - interval 30 day
ORDER BY a.counter DESC
LIMIT 10;
Your query is generating an error. You should look at that error before fixing the query.
The query would look different in SQL Server.
I'd need to replace post dates from wordpress post table.
There are >800.000 post entries with the same date because of a migration.
How can I replace the date by "from row x to row"?
For example:
row 1 - 10.000 should have date 2013-01-02 09:20:10
row 10.001 - 20.000 should have date 2013-02-05 12:30:21
and so on...
Or maybe replacing by post id?
I know there is a sql query to do this, but I can not remember which one and how to use it correctly.
try adding a LIMIT to the sql to update rows:
UPDATE {table}
SET {datefield} = "{desired date}"
WHERE {datefield} = "{bad date}"
LIMIT 10000;
this will update 10000 rows at a time with a new date as desired, however it's not particularly picky about which ones get updated in which order, generally it will be in the database's internal order which is (roughly) chronological.
is there any other part of the data you can use to determine which records should be updated with which date?
This is not what you asked for, but might be better. You can create distinct timestamps, as if a post has been created every X seconds:
update posts
set created = timestamp('2013-01-02 12:00:00') + interval id * 140 second
where 1=1
http://sqlfiddle.com/#!9/a6c7e0/2
You can even make them look random:
update posts
set created =
timestamp('2013-01-02 12:00:00')
+ interval id * 140 second
+ interval floor(rand()*140) second
where 1=1
http://sqlfiddle.com/#!9/b394c/1
Hi i am trying to fetch last 5 minutes of data from oracle table.The query is written below and its not working somehow.
select * from mytable where (time_to_sec(timediff(now(),mytable.time_stamp)) <= 300)
Its showing this error ORA-00904.
I tried one more query.
select * from mytable where TIME_STAMP > (sysdate - numtodsinterval(5,'minute'))
Now, can you tell me the query which fetches data of last 5 minutes and which deletes data that is in the table for more than 12 hours.Thanks.
I need queries in both oracle and mysql. The mysql query i tried is here.
delete from mytable where (time_to_sec(timediff(now(),time_stamp))/3600 >12);
In oracle subtracting 1 from timestamp means one day. And You can substract a fraction of one. So,
current_timestamp - (5/(24*60))
gives You date from 5 minutes ago. Using that we can query:
select * from mytable where TIME_STAMP > current_timestamp - (5/(24*60)
Which should give You needed result. I find this method more straightfoward and simpler to remember than using special functions.
If You want filter out data from last 12 hours than You can query it like this:
select * from mytable where TIME_STAMP <= current_timestamp - 0.5
I want to make a sqlite query in such a way that the result should be sorted which has a LIMIT and the OFFSET. But the OFFSET should work in synch a manner that it should discard the last records from the result.
SELECT * FROM TempTable WHERE CLASS = 1 ORDER BY Date ASC LIMIT 100 OFFSET 5;
The above query just ignores the first 5 records from the table and give the remaining records. But instead I want it to ignore the first 5 latest entries.
Note:- the first 5 latest entries means since I am sorting it by date it should IGNORE the latest record inserted in the table respecting the date.
Sort backwards, with OFFSET 5 and resort again:
SELECT * FROM (
SELECT * FROM TempTable WHERE CLASS = 1 ORDER BY Date DESC LIMIT 100 OFFSET 5
) ORDER BY Date ASC;
I have an SQL table that stores running times and a score associated with each time on the table.
/////////////////////
/ Time * Score /
/ 1531 * 64 /
/ 1537 * 63 /
/ 1543 * 61 /
/ 1549 * 60 /
/////////////////////
This is an example of 4 rows in the table. My question is how do I select the nearest lowest time.
EXAMPLE: If someone records a time of 1548 I want to return the score for 1543 (not 1549) which is 61.
Is there an SQL query I can use to do this thank you.
Use SQL's WHERE clause to filter the records, its ORDER BY clause to sort them and LIMIT (in MySQL) to obtain only the first result:
SELECT Score
FROM my_table
WHERE Time <= 1548
ORDER BY Time DESC
LIMIT 1
See it on sqlfiddle.