MySQL Stored Procedure, read from one table and insert to other - mysql

Question

I have this following code in PHP and I want to convert this into MySQL stored procedure. I do not want to check on duplication error at db level error code due to the requirement of the application, it has to be done the same way as is done in PHP.
$sql2 = "SELECT zip__ID FROM zip WHERE zip_code='" . $zip . "' ";
$result2 = mysql_query($sql2);
if (mysql_num_rows($result2) == 0) {
$sql3 = "INSERT INTO zips SET zip_code='" . ($zip) . "'";
mysql_query($sql3);
$newZip = mysql_insert_id();
} else {
$row2 = mysql_fetch_array($result2);
$newZip = $row2['zip_id'];
}
//Update: May 6, 2015.
I have total 6 tables.
Table 1 contains fields like zip, city, state, country. This is in varchar format.
|ID|ZIP|CITY|STATE|COUNTRY|
|1|33430|Fort Lauderdale|FL|USA
There are four more tables that are:
Table 2: zips (id,zip_code)
Table 3: cities (id,city_name)
Table 4: state (id,state_name)
Table 5: countries (id,country_name)
I want to insert the date from table 1 into table 6, which is the replica of table 1. The only difference is that in Table 6, I want to insert IDs of the data in table 1. Hence, for every insertion to be made in Table 6, I have to run a query in the 4 tables (2,3,4 and 5). For instance, if the zip code in Table 1 is 33430 and it does not exist in Table 2, first I need to insert it, get its ID and then insert in Table 6.
I have to do the same for all fields in Table 1.
So if I do it in PHP, what I will do it:
$sql = "SELECT * FROM Table1";
$result = mysql_query($sql);
while($row=mysql_fetch_array($result){
$zip = $row['zip'];
$city = $row['city'];
$state = $row['state'];
$country = $row['country'];
//Process zip code
$sql2 = "SELECT zip_id FROM zips WHERE zip_code='" . $zip . "' ";
$result2 = mysql_query($sql2);
if (mysql_num_rows($result2) == 0) {
$sql3 = "INSERT INTO zips SET zip_code='" . ($zip) . "'";
mysql_query($sql3);
$newZip = mysql_insert_id();
} else {
$row2 = mysql_fetch_array($result2);
$newZip = $row2['zip_id'];
}
mysql_free_result($result2);
//Process city
$sql2 = "SELECT city_id FROM cities WHERE city_name='" . $city . "' ";
$result2 = mysql_query($sql2);
if (mysql_num_rows($result2) == 0) {
$sql3 = "INSERT INTO cities SET city_name='" . ($city) . "'";
mysql_query($sql3);
$newCity = mysql_insert_id();
} else {
$row2 = mysql_fetch_array($result2);
$newCity = $row2['city_id'];
}
mysql_free_result($result2);
//process other two tables......
}mysql_free_result($result);

Answer 1

I'm no MySQL expert either, but this is what I could find. You have to check out the syntax though. But I want to stress this. I Googled 2 sources, and I typed this out for you. If I could do it, I'm sure you could've done it as well.
CREATE PROCEDURE UpdateTable6()
BEGIN
DECLARE done INT DEFAULT FALSE;
DECLARE i, a, b, c, d INT;
DECLARE va, vb, vc, vd CHAR(<yourmax>);
DECLARE CONTINUE HANDLER FOR NOT FOUND SET done = TRUE;
DECLARE cur1 CURSOR FOR SELECT id, zip, city, state, country FROM table1;
OPEN cur1;
read_loop: LOOP
FETCH cut1 into i, va, vb, vc, vd;
IF done THEN
LEAVE read_loop;
END IF;
--REPEAT THIS FOR ALL 4 TABLES
IF (SELECT 1 = 1 FROM Table2 WHERE zip_code=va) THEN
BEGIN
SELECT a = TableID FROM Table2 WHERE zip_code=va;
END;
ELSE
BEGIN
INSERT INTO Table2 (zip_code) VALUES(va);
SELECT a = LAST_INSERT_ID();
END;
END IF;
--CHECK DETAILS IN TABLE6
IF (SELECT 1 = 1 FROM Table6 WHERE id=i) THEN
BEGIN
UPDATE TABLE6 set zip_id = a, city_id = b, state_id = c, country_id = d where id = i
END;
ELSE
BEGIN
INSERT INTO Table6 (zip_id, city_id, state_id, country_id ) VALUES(a, b, c, d);
END;
END IF;
END LOOP;
CLOSE cur1;
END;
My source where https://dev.mysql.com/doc/refman/5.0/en/cursors.html