I want to count number of months till last month where registeration is done.i wrote the query as
SELECT count(MONTH(`regdate`) < MONTH(CURDATE()) AND YEAR(`regdate`) <= YEAR(CURDATE())) FROM `client_details` WHERE hospitalid='apollo123'
Maybe you want this:
select month(regdate), count(*)
from client_details
where regdate < curdate()
and hospitalid = 'apollo123'
group by month(regdate);
This will, for each month prior to curdate() give you the count of registrations that happened in that month.
SELECT count (*)from (
select month(regdate)
from client_details
where regdate < curdate()
and hospitalid = 'apollo123'
group by month(regdate));
This will give you number of months till last month when registrations were done.
One solution is
select count(distinct(cast(MONTH(regdate) as nvarchar(10)) + cast(year(regdate) as nvarchar(10)))) from client_details where hospitalid = 'apollp123' and regdate < DATEADD(month, DATEDIFF(month, 0, GETDATE())-1, 0)
I tested this one on Sql Server, you should adjust the code for mySql .
Related
RDBMS: MySQL
The time column(s) datatype is of datetime
For every hour of the 24 hour day I need to retrieve the number of rows in which their start_time matches the hour OR the end_time is great than or equal to the hour.
Below is the current query I have which returns the data I need but only based off of one hour. I can loop through and do 24 separate queries for each hour of the day but I would love to have this in one query.
SELECT COUNT(*) as total_online
FROM broadcasts
WHERE DATE(start_time) = '2018-01-01' AND (HOUR(start_time) = '0' OR
HOUR(end_time) >= '0')
Is there a better way of querying the data I need? Perhaps by using group by somehow? Thank you.
Not exactly sure if i am following, but try something like this:
select datepart(hh, getdate()) , count(*)
from broadcasts
where datepart(hh, starttime) <=datepart(hh, endtime)
and cast(starttime as date)=cast(getdate() as date) and cast(endtime as date)=cast(getdate() as date)
group by datepart(hh, getdate())
Join with a subquery that returns all the hour numbers:
SELECT h.hour_num, COUNT(*) AS total_online
FROM (SELECT 0 AS hour_num UNION SELECT 1 UNION SELECT 2 ... UNION SELECT 23) AS h
JOIN broadcasts AS b ON HOUR(b.start_time) = h.hour_num OR HOUR(b.end_time) >= h.hour_num
WHERE DATE(b.start_time) = '2018-01-01'
GROUP BY h.hour_num
I have a table like this:
I need to sum how many messages were delivered per msisdn in last 8 weeks(but for each week) from date entered. Here is what I came up with:
SELECT count(*) as ukupan_broj, SUM(IF (sent_messages.delivered = 1,1,0 )) as broj_dostavljenih,
count(*) - SUM(IF (sent_messages.delivered = 1,1,0 )) as non_billed,
SUM(IF (sent_messages.delivered = 1,1,0 )) / count(*) as ratio,
`sent_messages`.`msisdn`,
MONTH(`sent_messages`.`datetime`) AS MONTH, WEEK(`sent_messages`.`datetime`) AS WEEK,
DATE_FORMAT(`sent_messages`.`datetime`, '%Y-%m-%d') AS DATE
FROM `sent_messages`
INNER JOIN `received_messages` on `received_messages`.`uniqueid`=`sent_messages`.`originalID`
and `received_messages`.`msisdn`=`sent_messages`.`msisdn`
WHERE `sent_messages`.`datetime` >= '2016-12-12'
AND `sent_messages`.`originalID` = `received_messages`.`uniqueid`
AND `sent_messages`.`datetime` <= '2017-12-30'
AND `sent_messages`.`datetime` >= `received_messages`.`datetime`
AND `sent_messages`.`datetime` <= ( `received_messages`.`datetime` + INTERVAL 2 HOUR )
AND `sent_messages`.`type` = 'PAID'
GROUP BY WEEK
ORDER BY DATE ASC
And because I'm grouping it by WEEK, my result is showing sum of all delivered, undelivered etc. but not per msisdn. Here is how result looks like:
And when I add msisdn in GROUP BY clause I don't get the result the way I need it.
And I need it like this:
Please help me to write optimized query to fetch these results for each msisdn per last 8 weeks, because I'm stuck.
WEEK(...) has a problem near the first of the year. Instead, you could use TO_DAYS:
WHERE datetime > CURDATE() - INTERVAL 8 WEEK -- for the last 8 weeks
GROUP BY MOD(TO_DAYS(datetime), 7) -- group by week
That is quite simple, but there is a bug in it. It only works if today is the last day of a "week". And if date%7 lands on the desired day of week.
WHERE datetime > CURDATE() - INTERVAL 9 WEEK -- for the last 8 weeks
GROUP BY MOD(TO_DAYS(datetime) - 3, 7) -- group by week
Is the first cut at fixing the bugs -- 9-week interval will include the current partial week and the partial week 8 weeks ago. The "- 3" (or whatever number works) will align your "week" to start on Monday or Sunday or whatever.
SUM(IF (sent_messages.delivered = 1,1,0 )) can be shortened to SUM(delivered = 1) or even SUM(delivered) if that column only has 0 or 1 values.
how can I found last month of records while from current month.
ex.
12-11-2015
12-12-2015
12-1-2016
12-2-2016
I wrote my query like this:
select * from tbl where MONTH(date) < MONTH(CURDATE());
It shows only one record 12-1-2016. But I want all record except last record 12-2-2016.
I think problem with different years.
Try this:
SELECT *
FROM tbl
WHERE (MONTH(date) < MONTH(CURDATE()) AND YEAR(date) = YEAR(CURDATE()))
OR
YEAR(date) < YEAR(CURDATE())
The predicates used in the above query essentially say: if both dates are on the same year, then you can compare month, otherwise you have to only compare the year value.
select * from tbl where MONTH(date) < MONTH(CURDATE()) OR YEAR(date) < YEAR(CURDATE());
I have a table with MLSNumber, ListingContractDate, CloseDate.
I want to summarize the activity grouped my month starting with the current month and going back to January 2000.
I have this statement which summarizes the ListingContractDate by month.
SELECT COUNT(MLSNumber) AS NewListings, DATE_FORMAT(ListingContractDate,'%M %Y')
FROM Listings
WHERE Neighbourhood = 'Beachside'
AND ListingContractDate >= '2000-01-01'
GROUP BY YEAR(ListingContractDate), MONTH(ListingContractDate)
ORDER BY ListingContractDate DESC
The two problems with this statement are if there is nothing found in a specific month it skips that month, and I would need to return a 0 so no months are missing, and I am not sure how to get the same count on the CloseDate field or if I just have to run a 2nd query and match the two results up by month and year using PHP.
An exceptionally useful item to have is a "tally table" which simply consists on a set of integers. I used a script found HERE to generate such a table.
With that table I can now LEFT JOIN the time related data to it as shown below:
set #startdt := '2000-01-01';
SELECT COUNT(MLSNumber) AS NewListings, DATE_FORMAT(T.Mnth,'%M %Y')
FROM (
select
tally.id
, date_add( #startdt, INTERVAL (tally.id - 1) MONTH ) as Mnth
, date_add( #startdt, INTERVAL tally.id MONTH ) as NextMnth
from tally
where tally.id <= (
select period_diff(date_format(now(), '%Y%m'), date_format(#startdt, '%Y%m')) + 1
)
) t
LEFT JOIN Temp On Temp.ListingContractDate >= T.Mnth and Temp.ListingContractDate < T.NextMnth
GROUP BY YEAR(T.Mnth), MONTH(T.Mnth)
ORDER BY T.Mnth DESC
Logc,
define a stating date
calculate the number of months from that date until now (using
PERIOD_DIFF + 1)
choose that number of records from the tally table
create period start and end dates (tally.Mnth & tally.NextMnth)
LEFT JOIN the actual data to the tally table using
Temp.ListingContractDate >= T.Mnth and Temp.ListingContractDate < T.NextMnth
group and count the data
see this sqlfiddle`
I have a table structure that looks like this:
I have a perfectly working query that counts how many records there have been per day the last 30 days. It looks likes this:
SELECT DATE(timestamp) AS date, COUNT(id) AS emails FROM 'emails WHERE timestamp >= now() - interval 1 month GROUP BY DATE(timestamp)
This outputs the following which is perfectly fine:
However, the next thing seems too difficult for me to imagine. Now I want to count how many records there have been per day the last 30 days BUT only where newsletter = 1.
I've tried to put a WHERE statement looking like this:
SELECT DATE(timestamp) AS date, COUNT(*) AS emails, nyhedsbrev FROM emails WHERE timestamp >= now() - interval 1 month AND nyhedsbrev = 1 GROUP BY DATE(timestamp)
... And that outputs the following:
The problem is, that its omitting the records with newsletter = 0 and there by I cant compare my first query against the new one, as the dates doesnt match. I know that is because I use WHERE newsletter = 1.
In stead of omitting the record I want a query that just puts a "0" from that date. How can I do this? The final query should be outputting this:
You should be able to simply use SUM() and IF() to get the desired output:
SELECT
DATE(timestamp) AS date,
COUNT(*) AS emails,
SUM(IF(nyhedsbrev > 0, 1, 0)) as nyhedsbrev_count
FROM
emails
WHERE
timestamp >= now() - interval 1 month
GROUP BY
DATE(timestamp)
SQLFiddle DEMO
Edit: You might even be able to simplify it, since it's a boolean, and simply use SUM(nyhedsbrev), but this REQUIRES that nyhedsbrev is only 0 or 1:
SELECT
DATE(timestamp) AS date,
COUNT(*) AS emails,
SUM(nyhedsbrev) as nyhedsbrev_count
FROM
emails
WHERE
timestamp >= now() - interval 1 month
GROUP BY
DATE(timestamp)
Possibly best to get a list of the dates and then left join that against sub queries to get the counts you require.
Something like this
SELECT Sub1.date, Sub2.emails, IFNULL(Sub3.emails, 0)
FROM (SELECT DISTINCT DATE(timestamp) AS date
FROM emails
WHERE timestamp >= now() - interval 1 month) Sub1
LEFT OUTER JOIN (SELECT DATE(timestamp) AS date, COUNT(id) AS emails
FROM emails WHERE timestamp >= now() - interval 1 month
GROUP BY DATE(timestamp)) Sub2
ON Sub2.date = Sub3.date
LEFT OUTER JOIN (SELECT DATE(timestamp) AS date, COUNT(*) AS emails
FROM emails
WHERE timestamp >= now() - interval 1 month AND nyhedsbrev = 1
GROUP BY DATE(timestamp)) Sub3
ON Sub1.date = Sub3.date
(you can probably optimise one subselect of this away, but I have done it in full to make it obvious how it is working)
Assuming newsletter is boolean 1/0 values then this might give you the table that you want:
SELECT DATE(timestamp) AS date, COUNT(*) AS emails, nyhedsbrev
FROM emails WHERE timestamp >= now() - interval 1 month GROUP BY DATE(timestamp),nyhedsbrev ;
Just adding another GROUP BY parameter.