less than or greater than in where clause in codeigniter model - mysql

I want execute this query like
UPDATE `eventinfo` SET `Status` = '0' WHERE `EventDatetime`< `2015-05-12 01:17:23`.
I tried it in different ways like this
$whereClause = 'EventDatetime'.'<'.$check_date;
$this->db->where($whereClause);
but I failed.What is the correct way.

Different way to do this :
$data = array( 'status' => '0', );
$this->db->where('EventDatetime <', '2015-05-12 01:17:23');
$this->db->update('eventinfo', $data);

Using codeigniter way for less then and greater then
$this->db->set('Status',0);
$this->db->where('EventDatetime <', '2015-05-12 01:17:23');
$this->db->update('eventinfo');

You need quotes around dates in that format.
UPDATE `eventinfo`
SET `Status` = '0'
WHERE `EventDatetime`< '2015-05-12 01:17:23'
;

This is how you can do it
$data = array( 'Status' => '0', );
$this->db->where('EventDatetime <', '2015-05-12 01:17:23');
$this->db->update('eventinfo', $data);
NOTE:
Note the space between 'EventDatetime' and '<', if there is no space, you will get an error

there are many ways to do so
$data = array( 'status' => '0', );
$whereClass="eventdatetime < '2015-05-12 01:17:23'";
$this->db->where($whereClass,NULL,FALSE);
//or $this->db->where('eventdatetime < ' ,'2015-05-12 01:17:23');
$this->db->update('eventinfo', $data);
if still got error then there must database error ,may be a missing record or something

Related

codeigniter controller input default value as 1

How to insert datebase in codeigniter with default value = 1 for every row input
here's my controller
$data['status'] = $this->input->post(1);
your help would be very much appreciated
Try this
$data = array(
'title' => $title ,
'name' => $name,
'id2' => 1 # default value
);
$this->db->insert('mytable', $data);
or
In database set column to NOTNULL and set default value to 1
you can do like this in your model
if ($this->input->post('status')!='') {
$data['status'] = $this->input->post('status');
} else {
$data['status'] = 1;
}

How to use AND and OR in MySQL query?

I want to get those records whose date_last_copied field is empty or less than the current date. I tried this, but it did not give me the desired result:
$tasks = $this->Control->query("
SELECT *
FROM
`controls`
WHERE
`owner_id` = ".$user_id."
AND `control_frequency_id` = ".CONTROL_FREQUENCY_DAILY."
OR `date_last_copied` = ''
OR `date_last_copied` < ". strtotime(Date('Y-m-d'))."
");
Current query looks something like this, I think. That is, find the records with the correct owner_id and frequency_id, where the date_last_copied is null or less than a certain date. Is that logic correct?
SELECT *
FROM controls
WHERE owner_id = ::owner_id::
AND control_frequency_id = ::frequency_id::
AND (
date_last_copied IS NULL
OR date_last_copied < ::date::
)
But we should really be using the CakePHP query builder, rather than running raw SQL. This article gives some details. If I were to take a stab at a solution, we'd want something like the following. But we ideally want someone from the CakePHP community to chime in here. EDIT: Note that this seems to be for CakePHP 3.0, only.
// Build the query
$query = TableRegistry::get('controls')
->find()
->where([
'owner_id' => $ownerId,
'control_frequency_id' => $frequencyId,
'OR' => [
['date_last_copied IS' => null],
['date_last_copied <' => $date]
]
]);
// To make sure the query is what we wanted
debug($query);
// To get all the results of the query
foreach ($query as $control) {
. . .
}
I'm suggesting this, rather than the raw SQL string you have above, because:
We can now leverage the ORM model of CakePHP.
We don't have to worry about SQL injection, which you're currently vulnerable to.
EDIT: OK, this is a guess at the syntax applicable for CakePHP 2.0... YMMV
$controls = $this->controls->find('all', [
'conditions' => [
'owner_id' => $ownerId,
'control_frequency_id' => $frequencyId,
'OR' => [
['date_last_copied IS' => null],
['date_last_copied <' => $date]
]
]
];
Otherwise, we just use the raw query as a prepared statement:
$result = $this->getDataSource()->fetchAll("
SELECT *
FROM controls
WHERE owner_id = ?
AND control_frequency_id = ?
AND (
date_last_copied IS NULL
OR date_last_copied < ?
)",
[$ownerId, $frequencyId, $date]
);
Not sure about your whole logic but your final query statement should be something like:
SELECT * FROM `controls` WHERE (`owner_id` = <some owner_id>)
AND (`control_frequency_id` = <some id value>)
AND (`date_last_copied` = '' OR
`date_last_copied` IS NULL OR
`date_last_copied` < CURDATE() )
Use parentheses carefully to match your logic.
Always specify the version of cakePHP you are using for your App.
This query should work fine in CakePHP 3.0 for SQL AND and OR.
$query = ModelName>find()
->where(['colunm' => 'condition'])
->orWhere(['colunm' => 'otherCondition'])
->andWhere([
'colunm' => 'anotherContion',
'view_count >' => 10
])
->orWhere(['colunm' => 'moreConditions']);

how to get last insert id after insert query in codeigniter active record

I have an insert query (active record style) used to insert the form fields into a MySQL table. I want to get the last auto-incremented id for the insert operation as the return value of my query but I have some problems with it.
Inside the controller:
function add_post(){
$post_data = array(
'id' => '',
'user_id' => '11330',
'content' => $this->input->post('poster_textarea'),
'date_time' => date("Y-m-d H:i:s"),
'status' => '1'
);
return $this->blog_model->add_post($post_data);
}
And inside model:
function add_post($post_data){
$this->db->trans_start();
$this->db->insert('posts',$post_data);
$this->db->trans_complete();
return $this->db->insert_id();
}
I get nothing as the return of the add_post in model
Try this
function add_post($post_data){
$this->db->insert('posts', $post_data);
$insert_id = $this->db->insert_id();
return $insert_id;
}
In case of multiple inserts you could use
$this->db->trans_start();
$this->db->trans_complete();
A transaction isn't needed here, this should suffice:
function add_post($post_data) {
$this->db->insert('posts',$post_data);
return $this->db->insert_id();
}
$id = $this->db->insert_id();
From the documentation:
$this->db->insert_id()
The insert ID number when performing database inserts.
Therefore, you could use something like this:
$lastid = $this->db->insert_id();
Using the mysqli PHP driver, you can't get the insert_id after you commit.
The real solution is this:
function add_post($post_data){
$this->db->trans_begin();
$this->db->insert('posts',$post_data);
$item_id = $this->db->insert_id();
if( $this->db->trans_status() === FALSE )
{
$this->db->trans_rollback();
return( 0 );
}
else
{
$this->db->trans_commit();
return( $item_id );
}
}
Source for code structure: https://codeigniter.com/user_guide/database/transactions.html#running-transactions-manually
It is worth saying that the other answers relate to Codeigniter version 3. The answer in Version 4 (found https://codeigniter.com/user_guide/database/helpers.html) is to use $this->db->insertID()
because you have initiated the Transaction over the data insertion so,
The first check the transaction completed or not. once you start the transaction, it should be committed or rollback according to the status of the transaction;
function add_post($post_data){
$this->db->trans_begin()
$this->db->insert('posts',$post_data);
$this->db->trans_complete();
if ($this->db->trans_status() === FALSE){
$this->db->trans_rollback();
return 0;
}else{
$this->db->trans_commit();
return $this->db->insert_id();
}
}``
in the above, we have committed the data on the successful transaction even you get the timestamp
Just to complete this topic:
If you set up your table with primary key and auto increment you can omit the process of manually incrementing the id.
Check out this example
if (!$CI->db->table_exists(db_prefix() . 'my_table_name')) {
$CI->db->query('CREATE TABLE `' . db_prefix() . "my_table_name` (
`serviceid` int(11) NOT NULL PRIMARY KEY AUTO_INCREMENT,
`name` varchar(64) NOT NULL,
`hash` varchar(32) NOT NULL,
`url` varchar(120) NOT NULL,
`datecreated` datetime NOT NULL,
`active` tinyint(1) NOT NULL DEFAULT '1'
) ENGINE=InnoDB DEFAULT CHARSET=" . $CI->db->char_set . ';');
Now you can insert rows
$this->db->insert(db_prefix(). 'my_table_name', [
'name' => $data['name'],
'hash' => app_generate_hash(),
'url' => $data['url'],
'datecreated' => date('Y-m-d H:i:s'),
'active' => $data['active']
]);
**Inside Model**
function add_info($data){
$this->db->insert('tbl_user_info',$data);
$last_id = $this->db->insert_id();
return $last_id;
}
**Inside Controller**
public function save_user_record() {
$insertId = $this->welcome_model->save_user_info($data);
echo $insertId->id;
}
You must use $lastId = $this->db->insert_id();

Database Error Occurred Error Number: 1062

i tried to make option update three table with one execution for my CI with sql there, but why its still error?
this is the error warning:
A Database Error Occurred
Error Number: 1062
Duplicate entry '0' for key 1
UPDATE `t_publisher` SET `id_publisher` = NULL, `publisher` = NULL, `artis` = NULL, `id_label` = NULL WHERE `id_publisher` = '113'
this is the code:
function update($id_user=null)
{
if (($this->input->post('submit') == 'Update')){
$user=$this->input->post('username');
$pass=$this->input->post('userpassword');
$ussta=$this->input->post('userstatus');
$usty=$this->input->post('usertype');
$data = array(
'user_name' => $user,
'user_pass' => $pass,
'user_status' => $ussta,
'user_type' => $usty);
$this->db->where('user_id', $this->input->post('id'), $data);
$this->db->update("t_user",$data);
$data1 = array(
'id_publisher' => $id_publis,
'publisher' => $publis,
'artis' => $ar,
'id_label' => $id_lab);
$this->db->where('id_publisher', $this->input->post('id'), $data);
$this->db->update("t_publisher",$data1);
echo $this->db->last_query();
die();
$data2 = array(
'id_label' => $id_lab,
'label' => $label);
$this->db->where('id_label', $this->input->post('id'), $data);
$this->db->update("t_label",$data2);
echo $this->db->last_query();
die();
redirect("registrasi/reg");
}
$var['data'] = $this->db->query("select * from t_user where USER_ID= '$id_user'")->row_array();
$var1['data'] = $this->db->query("select * from t_publisher where id_publisher = '$id_publis'")->row_array();
$var2['data'] = $this->db->query("select * from t_label where id_label = '$id_lab'")->row_array();
$this->load->view('update', $var,$var1,$var2);
}
whats wrong with my code? please help. thanks before.
Your UPDATE clause is setting the id_publisher column to NULL, and, based on the name of the column and the error you're receiving, that column is the table's PRIMARY KEY with a setting of unsigned NOT NULL.
Because of this, when you do id_publisher = NULL, MySQL converts it to id_publisher = 0 due to the unsigned part. This will execute fine the first time, however, when you run it on a second row you will now be attempting to insert a second primary-key value of 0, which is not allowed.
Based on the location of the die() statement in your sample code, I'm assuming the following block is the culprit:
$data1 = array(
'id_publisher' => $id_publis,
'publisher' => $publis,
'artis' => $ar,
'id_label' => $id_lab);
$this->db->where('id_publisher', $this->input->post('id'), $data);
$this->db->update("t_publisher",$data1);
Here, your $id_publis variable is either empty or null.
I would suggest to either remove the id_publisher = NULL portion from the UPDATE clause which is as simple as removing 'id_publisher' => $id_publis, from the $data1 array, or rethink the reason you actually need to set it to null to begin with (in this case, would deleting the row be more beneficial?)

Unexpected T_CONSTANT_ENCAPSED_STRING error in SQL Query

I am getting an unexpected T_CONSTANT_ENCAPSED_STRING error in the following SQL query:
mysql_query (UPDATE 'wp_posts' SET 'post_status' = 'publish' WHERE 'post_id' = '$id');
Can you guys see where the error might be?
Here is the full code in case it helps:
$key = 'feed';
$post_ids = array(2263, 2249);
foreach ($post_ids as $id) {
$feedurl = get_post_custom_values($key, $id);
$feedurlstr = implode($feedurl);
// Ignore - it determines whether feed is live and returns $result
LiveOrNot($feedurlstr);
if ( $result == "live" ) {
mysql_query (UPDATE 'wp_posts' SET 'post_status' = 'publish' WHERE 'post_id' = '$id');
}
elseif ( $result == "notlive" ) {
mysql_query (UPDATE 'wp_posts' SET 'post_status' = 'draft' WHERE 'post_id' = '$id');
}
endif;
}
Wrap your SQL statements in quote-marks - ".
mysql_query ("UPDATE 'wp_posts' SET 'post_status' = 'publish' WHERE 'post_id' = '$id'");
mysql_query() takes a string. PHP is looking for constants interspersed with strings, which is not valid PHP grammer.
You need to delimit your strings, ' and " are popular choices, but there is also Heredoc syntax.
Read more about strings in PHP.