Mapping a JSON object to a Swift class/struct - json

I need to "replicate" an entiry which is returned from a remote web API service in JSON. It looks like this:
{
"field1": "some_id",
"entity_name" = "Entity1"
"field2": "some name",
"details1": [{
"field1": 11,
"field2": "some value",
"data": {
"key1": "value1",
"key2": "value2",
"key3": "value3",
// any other, unknown at compile time keys
}
}],
"details2": {
"field1": 13,
"field2": "some value2"
}
}
Here's my attempt:
struct Entity1 {
struct Details1 {
let field1: UInt32
let field2: String
let data: [String: String]
}
struct Details2 {
let field1: UInt32
let field2: String
}
let field1: String
static let entityName = "Entity1"
let field2: String
let details1: [Details1]
let details2: Details2
}
Is it a good idea to use structs instead of classes for such a goal
as mine?
Can I anyhow define a nested struct or a class, say
Details1 and create a variable of it at the same time?
Like this:
//doesn't compile
struct Entity1 {
let details1: [Details1 {
let field1: UInt32
let field2: String
let data: [String: String]
}]

You can use any if the following good open-source libraries available to handle the mapping of JSON to Object in Swift, take a look :
Mapper
ObjectMapper
JSONHelper
Argo
Unbox
Each one have nice a good tutorial for beginners.
Regarding the theme of struct or class, you can consider the following text from The Swift Programming Language documentation:
Structure instances are always passed by value, and class
instances are always passed by reference. This means that they are
suited to different kinds of tasks. As you consider the data
constructs and functionality that you need for a project, decide
whether each data construct should be defined as a class or as a
structure.
As a general guideline, consider creating a structure when one or more
of these conditions apply:
The structure’s primary purpose is to encapsulate a few relatively simple data values.
It is reasonable to expect that the encapsulated values will be copied rather than referenced when you assign or pass around an
instance of that structure.
Any properties stored by the structure are themselves value types, which would also be expected to be copied rather than referenced.
The structure does not need to inherit properties or behavior from another existing type.
Examples of good candidates for structures include:
The size of a geometric shape, perhaps encapsulating a width property and a height property, both of type Double.
A way to refer to ranges within a series, perhaps encapsulating a start property and a length property, both of type Int.
A point in a 3D coordinate system, perhaps encapsulating x, y and z properties, each of type Double.
In all other cases, define a class, and create instances of that class
to be managed and passed by reference. In practice, this means that
most custom data constructs should be classes, not structures.
I hope this help you.

HandyJSON is exactly what you need. See code example:
struct Animal: HandyJSON {
var name: String?
var id: String?
var num: Int?
}
let jsonString = "{\"name\":\"cat\",\"id\":\"12345\",\"num\":180}"
if let animal = JSONDeserializer.deserializeFrom(json: jsonString) {
print(animal)
}
https://github.com/alibaba/handyjson

Details
Xcode 10.2.1 (10E1001), Swift 5
Links
Pods:
Alamofire - loading data
More info:
Codable
More samples of usage Codable and ObjectMapper in Swift 5
Task
Get itunes search results using iTunes Search API with simple request https://itunes.apple.com/search?term=jack+johnson
Full sample
import UIKit
import Alamofire
// Itunce api doc: https://affiliate.itunes.apple.com/resources/documentation/itunes-store-web-service-search-api/#searching
class ViewController: UIViewController {
override func viewDidLoad() {
super.viewDidLoad()
loadData()
}
private func loadData() {
let urlString = "https://itunes.apple.com/search?term=jack+johnson"
Alamofire.request(urlString).response { response in
guard let data = response.data else { return }
do {
let decoder = JSONDecoder()
decoder.keyDecodingStrategy = .convertFromSnakeCase
let result = try decoder.decode(ItunceItems.self, from: data)
print(result)
} catch let error {
print("\(error.localizedDescription)")
}
}
}
}
struct ItunceItems: Codable {
let resultCount: Int
let results: [ItunceItem]
}
struct ItunceItem: Codable {
var wrapperType: String?
var artistId: Int?
var trackName: String?
var trackPrice: Double?
var currency: String?
}

you could use SwiftyJson and let json = JSONValue(dataFromNetworking)
if let userName = json[0]["user"]["name"].string{
//Now you got your value
}

Take a look at this awesome library that perfectly fits your need, Argo on GitHub.
In your case, a struct is ok. You can read more on how to choose between a struct and a class here.

You can go with this extension for Alamofire https://github.com/sua8051/AlamofireMapper
Declare a class or struct:
class UserResponse: Decodable {
var page: Int!
var per_page: Int!
var total: Int!
var total_pages: Int!
var data: [User]?
}
class User: Decodable {
var id: Double!
var first_name: String!
var last_name: String!
var avatar: String!
}
Use:
import Alamofire
import AlamofireMapper
let url1 = "https://raw.githubusercontent.com/sua8051/AlamofireMapper/master/user1.json"
Alamofire.request(url1, method: .get
, parameters: nil, encoding: URLEncoding.default, headers: nil).responseObject { (response: DataResponse<UserResponse>) in
switch response.result {
case let .success(data):
dump(data)
case let .failure(error):
dump(error)
}
}

Related

JSON and Realm — do I have to maintain separate structs / classes?

When I receive JSON from an API call, when decoding it I have structs like this:
import Foundation
struct JSON: Codable {
var alpha: Alpha
var beta: Beta
var gamma: [Gamma]?
}
I want to save the JSON in my Realm database, to later use and traverse like JSON. It's my understanding that I can't just use the existing structs I have written, instead I have to rewrite a second (similar) class like this to use with Realm:
import Foundation
import RealmSwift
class RealmJSON: Object, Identifiable {
#Persisted (primaryKey: true) var id: ObjectId
#Persisted var alpha: RealmAlpha
#Persisted var beta: RealmBeta
#Persisted var gamma: RealmSwift.List<RealmGamma>?
override class func primaryKey() -> String? {
"id"
}
convenience init(id: ObjectId, alpha: RealmAlpha, beta: RealmBeta, gamma: RealmSwift.List<RealmGamma>?) {
self.init()
self.id = id
self.alpha = alpha
self.beta = beta
self.gamma = gamma
}
}
Obviously, this is inconvenient especially when dealing with large amounts of JSON. Moreover I want to use Swagger codegen to write the client code for me, but it kind of defeats the purpose if I then have to manually add the Realm classes manually.
Is this the only way for dealing with JSON and a Realm database, or am I missing something here?
EDIT: I realise a simple way is to store most of the JSON as a raw JSON string with properties to identify schema type / version. Then I can just fetch the correct schema I require and parse the rawJSON string with the existing JSON structs...
You can pass the json data directly to your objects. I can think of two ways.
The first way, conform to Codable.
class Dog: Object, Codable {
#Persisted var name: String
}
class Cat: Object, Codable {
#Persisted var name: String
}
class Kid: Object, Codable {
#Persisted var name: String
}
class Owner: Object, Codable {
#Persisted var name: String
#Persisted var dog: Dog?
#Persisted var cat: Cat?
#Persisted var kids: List<Kid>
}
Let's use the following method to make json data:
func makeData() -> Data {
let string = """
{
"name": "Tom",
"kids": [{"name": "Penelope"}, {"name": "Rob"}],
"cat": {"name": "Lilly"},
"dog": {"name": "Lucy"}
}
"""
return string.data(using: .utf8)!
}
Now we can create our objects:
func decodeOwner() {
let decoder = JSONDecoder()
let owner = try! decoder.decode(Owner.self, from: makeData())
print("Decoded:", owner)
}
Another way is to use JSONSerialization and use the result to pass to the value constructor:
extension Object {
convenience init(json: Data) throws {
let data = try JSONSerialization.jsonObject(with: json)
self.init(value: data)
}
}
func serializeOwner() {
let owner = try! Owner(json: makeData())
print("Serialization:", owner)
}

JSON decoder for Swift dealing with changing underlying JSON with Array and Dictionary

I am using a third-party API to get data. It is a rather complex payload but I'm experiencing a problem with one return. For this example I'm over-simplifying the structure. This structure actually has 53 entries, 34 of which are structures themselves.
struct MlsItemData: Codable, Hashable {
let mls_id: String
let photos: [MlsItemPhoto]?
let features: [MlsItemFeature]?
let address: MlsItemAddress
let move_in_date: String?
let stories: Int?
let client_flags: MlsItemClientFlags?
let tax_history: [MlsItemTaxHistory]? <-- our propblem child
let new_construction: Bool?
let primary: Bool?
let prop_common: MlsItemPropertyCommon?
There are a whole load of other data objects in this API's results but I'm focusing on one item with the label tax_history. When there is data to be shared the key contains an Array like below.
{
"tax_history": [
{
"assessment": {
"building": null,
"total": 3900,
"land": null
},
"tax": 683,
"year": "2020"
},
{
"assessment": {
"building": null,
"total": 4093,
"land": null
},
"tax": 698,
"year": 2019
}
]
}
When the API has no data to share I was expecting:
"tax_history": [ ]
or
"tax_history": null
or just not in the payload at all. But instead the API is sending:
"tax_history": { }
I'm having difficulty as to how to deal with this in the decoder. Obviously, the built in decoder returns the "Expected to decode Array but found a dictionary instead", but is there a simple way to write a custom decoder for "just" the tax_history key and how would it be written for either getting an Array or an empty dictionary?
Yes, it is possible to decode this unusual payload using JSONDecoder. One way to do so is to use a custom type to represent either the empty or non-empty scenarios, and implement a custom initializer function and attempt to decode both cases to see which one works:
struct TaxHistoryItem: Decodable {
let year: String
// ...
}
enum TaxHistory: Decodable {
case empty
case items([TaxHistoryItem])
init(from decoder: Decoder) throws {
let container = try decoder.singleValueContainer()
if let items = try? container.decode([TaxHistoryItem].self) {
self = .items(items)
} else {
struct EmptyObject: Decodable {}
// Ignore the result. We just want to verify that the empty object exists
// and doesn't throw an error here.
try container.decode(EmptyObject.self)
self = .empty
}
}
}
You could create a specific type that holds this array and then write a custom init(from:) for it.
In the init we try to decode the json as an array and if it fails we simply assign an empty array to the property (nil for an optional property is another possible solution but I prefer an empty collection before nil)
struct TaxHistoryList: Codable {
let history: [TaxHistory]
init(from decoder: Decoder) throws {
let container = try decoder.singleValueContainer()
if let list = try? container.decode([TaxHistory].self) {
history = list
} else {
history = []
}
}
}
struct TaxHistory: Codable {
let tax: Int
let year: String
// other stuff
}

how to Converting JSON into Codable in swift 4.2?

I am using Xcode 10.1 and Swift 4.2. When i try to convert JSON response into Codable class it gives an error that Expected to decode Array<Any> but found a string/data instead.
My Actual JSON response is Like this from API .
{
"d": "[{\"Data\":{\"mcustomer\":[{\"slno\":1000000040.0,\"fstname\":null}]},\"Status\":true}]"
}
My Model is Like this
class MainData: Codable{
var d: [SubData]
}
class SubData : Codable {
var Data : Customer
var Status : Bool?
}
class Customer : Codable {
var mcustomer : [Detail]
}
class Detail : Codable {
var slno : Double?
var fstname : String?
}
And I am Decode this Model using JSONDecoder()
let decoder = JSONDecoder()
let deco = try decoder.decode(MainData.self, from: data)
but, I am unable to Decode this Json into My Model.
Your API is wrong. You array in json shouldn't have quotation marks around it. Otherwise you're declaring that value for key "d" is string
"[...]"
[...]
Suggestions:
Variables and constants should start with small capital letter. Otherwise for example your Data property would cause confusion with Data type. For renaming it while decoding you can use CodingKeys
If you don't need to encode your model, you can just implement Decodable protocol
You can use struct instead of class for your model
The top-level JSON object is a dictionary with the key "d" and a string value, representing another JSON object (sometimes called "nested JSON"). If the server API cannot be changed then the decoding must be done in two steps:
Decode the top-level dictionary.
Decode the JSON object from the string obtained in step one.
Together with Robert's advice about naming, CodingKeys and using structs it would look like this:
struct MainData: Codable {
let d: String
}
struct SubData : Codable {
let data : Customer
let status : Bool
enum CodingKeys: String, CodingKey {
case data = "Data"
case status = "Status"
}
}
struct Customer : Codable {
let mcustomer : [Detail]
}
struct Detail : Codable {
let slno : Double
let fstname : String?
}
do {
let mainData = try JSONDecoder().decode(MainData.self, from: data)
let subData = try JSONDecoder().decode([SubData].self, from: Data(mainData.d.utf8))
print(subData)
} catch {
print(error)
}
For your solution to work, the JSON reponse has to be following format
let json = """
{
"d": [
{
"Data": {
"mcustomer": [
{
"slno": 1000000040,
"fstname": null
}
]
},
"Status": true
}
]
}
"""
But, as you can see, the JSON response you are getting is quite different than you are expecting. Either you need to ask to change the response or you need to change your model.

Decoding JSON array of different types in Swift

I'm trying to decode the following JSON Object
{
"result":[
{
"rank":12,
"user":{
"name":"bob","age":12
}
},
{
"1":[
{
"name":"bob","age":12
},
{
"name":"tim","age":13
},
{
"name":"tony","age":12
},
{
"name":"greg","age":13
}
]
}
]
}
struct userObject {
var name: String
var age: Int
}
Basically a JSON Array with two different object types
{ "rank":12, "user": {userObject} }
and a
"1" : array of [userObjects]
struct data: Decodable {
rank: Int
user: user
1: [user] <-- this is one area Im stuck
}
Thanks in advance
Just for fun:
First you need structs for the users and the representation of the first and second dictionary in the result array. The key "1" is mapped to one
struct User : Decodable {
let name : String
let age : Int
}
struct FirstDictionary : Decodable {
let rank : Int
let user : User
}
struct SecondDictionary : Decodable {
let one : [User]
private enum CodingKeys: String, CodingKey { case one = "1" }
}
Now comes the tricky part:
First get the root container.
Get the container for result as nestedUnkeyedContainer because the object is an array.
Decode the first dictionary and copy the values.
Decode the second dictionary and copy the values.
struct UserData: Decodable {
let rank : Int
let user : User
let oneUsers : [User]
private enum CodingKeys: String, CodingKey { case result }
init(from decoder: Decoder) throws {
let container = try decoder.container(keyedBy: CodingKeys.self)
var arrayContainer = try container.nestedUnkeyedContainer(forKey: .result)
let firstDictionary = try arrayContainer.decode(FirstDictionary.self)
rank = firstDictionary.rank
user = firstDictionary.user
let secondDictionary = try arrayContainer.decode(SecondDictionary.self)
oneUsers = secondDictionary.one
}
}
If this code is preferable over traditional manual JSONSerialization is another question.
If your JSON format is given then you are pretty much out of luck, since you will most likely have to parse your array as [Any] which is, to put it mildly, not very useful. If on the other hand you are able to modify the format of the JSON you should start from the other direction. Define your desired Swift object and encode it using JSONEncoder.encode(...) in order to quickly determine how your JSON should look like in order to make it parse in as typed a way as possible.
This approach will easily half your JSON handling code as your web service protocol will end up being structured much better. This will likely improve the structure of the overall system since it will yield a much more stable communication protocol.
Sadly enough this approach is not always possible which is when things get messy. Given your example you will be able to parse your code as
let st = """
{
"result":[
{
"rank":12,
"user":{
"name":"bob",
"age":12
}
},
{
"1":[
{
"name":"bob","age":12
},
{
"name":"tim","age":13
},
{
"name":"tony","age":12
},
{
"name":"greg","age":13
}
]
}
]
}
"""
let jsonData1 = st.data(using: .utf8)!
let arbitrary = try JSONSerialization.jsonObject(with: jsonData1, options: .mutableContainers)
This will let you access your data with a bunch of casts as in
let dict = arbitrary as! NSDictionary
print(dict["result"])
you get the idea. not very useful as you would very much like to use the Codable protocol as in
struct ArrayRes : Codable {
let result : [[String:Any]]
}
let decoder1 = JSONDecoder()
do {
let addrRes = try decoder.decode(ArrayRes.self, from: jsonData1)
print(addrRes)
} catch {
print("error on decode: \(error.localizedDescription)")
}
Unfortunately this does not work since Any is not Codable for slightly obvious reasons.
I hope you are able to change your JSON protocol since the current one will be the root cause of lot of messy code.

Automatic JSON serialization and deserialization of objects in Swift

I'm looking for a way to automatically serialize and deserialize class instances in Swift. Let's assume we have defined the following class …
class Person {
let firstName: String
let lastName: String
init(firstName: String, lastName: String) {
self.firstName = firstName
self.lastName = lastName
}
}
… and Person instance:
let person = Person(firstName: "John", lastName: "Doe")
The JSON representation of person would be the following:
{
"firstName": "John",
"lastName": "Doe"
}
Now, here are my questions:
How can I serialize the person instance and get the above JSON without having to manually add all properties of the class to a dictionary which gets turned into JSON?
How can I deserialize the above JSON and get back an instantiated object that is statically typed to be of type Person? Again, I don't want to map the properties manually.
Here's how you'd do that in C# using Json.NET:
var person = new Person("John", "Doe");
string json = JsonConvert.SerializeObject(person);
// {"firstName":"John","lastName":"Doe"}
Person deserializedPerson = JsonConvert.DeserializeObject<Person>(json);
As shown in WWDC2017 # 24:48 (Swift 4), we will be able to use the Codable protocol. Example
public struct Person : Codable {
public let firstName:String
public let lastName:String
public let location:Location
}
To serialize
let payload: Data = try JSONEncoder().encode(person)
To deserialize
let anotherPerson = try JSONDecoder().decode(Person.self, from: payload)
Note that all properties must conform to the Codable protocol.
An alternative can be JSONCodable which is used by Swagger's code generator.
You could use EVReflection for that. You can use code like:
var person:Person = Person(json:jsonString)
or
var jsonString:String = person.toJsonString()
See the GitHub page for more detailed sample code. You only have to make EVObject the base class of your data objects. No mapping is needed (as long as the json keys are the same as the property names)
Update: Swift 4 has support for Codable which makes it almost as easy as EVReflection but with better performance. If you do want to use an easy contractor like above, then you could use this extension: Stuff/Codable
With Swift 4, you simply have to make your class conform to Codable (Encodable and Decodable protocols) in order to be able to perform JSON serialization and deserialization.
import Foundation
class Person: Codable {
let firstName: String
let lastName: String
init(firstName: String, lastName: String) {
self.firstName = firstName
self.lastName = lastName
}
}
Usage #1 (encode a Person instance into a JSON string):
let person = Person(firstName: "John", lastName: "Doe")
let encoder = JSONEncoder()
encoder.outputFormatting = .prettyPrinted // if necessary
let data = try! encoder.encode(person)
let jsonString = String(data: data, encoding: .utf8)!
print(jsonString)
/*
prints:
{
"firstName" : "John",
"lastName" : "Doe"
}
*/
Usage #2 (decode a JSON string into a Person instance):
let jsonString = """
{
"firstName" : "John",
"lastName" : "Doe"
}
"""
let jsonData = jsonString.data(using: .utf8)!
let decoder = JSONDecoder()
let person = try! decoder.decode(Person.self, from: jsonData)
dump(person)
/*
prints:
▿ __lldb_expr_609.Person #0
- firstName: "John"
- lastName: "Doe"
*/
There is a Foundation class called NSJSONSerialization which can do conversion to and from JSON.
The method for converting from JSON to an object looks like this:
let jsonObject = NSJSONSerialization.JSONObjectWithData(data,
options: NSJSONReadingOptions.MutableContainers,
error: &error) as NSDictionary
Note that the first argument to this method is the JSON data, but not as a string object, instead as a NSData object (which is how you'll often times get JSON data anyway).
You most likely will want a factory method for your class that takes JSON data as an argument, makes use of this method and returns an initialize object of your class.
To inverse this process and create JSON data out of an object, you'll want to make use of dataWithJSONObject, in which you'll pass an object that can be converted into JSON and have an NSData? returned. Again, you'll probably want to create a helper method that requires no arguments as an instance method of your class.
As far as I know, the easiest way to handle this is to create a way to map your objects properties into a dictionary and pass that dictionary for turning your object into JSON data. Then when turning your JSON data into the object, expect a dictionary to be returned and reverse the mapping process. There may be an easier way though.
You can achieve this by using ObjectMapper library. It'll give you more control on variable names and the values and the prepared JSON. After adding this library extend the Mappable class and define mapping(map: Map) function.
For example
class User: Mappable {
var id: Int?
var name: String?
required init?(_ map: Map) {
}
// Mapping code
func mapping(map: Map) {
name <- map["name"]
id <- map["id"]
}
}
Use it like below
let user = Mapper<User>().map(JSONString)
First, create a Swift object like this
struct Person {
var firstName: String?;
var lastName: String?;
init() {
}
}
After that, serialize your JSON data you retrieved, using the built-in NSJSONSerialization and parse the values into the Person object.
var person = Person();
var error: NSError?;
var response: AnyObject? = NSJSONSerialization.JSONObjectWithData(data, options: NSJSONReadingOptions(), error: &error);
if let personDictionary = response as? NSDictionary {
person.firstName = personDictionary["firstName"] as? String;
person.lastName = personDictionary["lastName"] as? String;
}
UPDATE:
Also please take a look at those libraries
Swift-JsonSerialiser
ROJSONParser
Take a look at NSKeyValueCoding.h, specifically setValuesForKeysWithDictionary. Once you deserialize the json into a NSDictionary, you can then create and initialize your object with that dictionary instance, no need to manually set values on the object. This will give you an idea of how the deserialization could work with json, but you will soon find out you need more control over deserialization process. This is why I implement a category on NSObject which allows fully controlled NSObject initialization with a dictionary during json deserialization, it basically enriches the object even further than setValuesForKeysWithDictionary can do. I also have a protocol used by the json deserializer, which allows the object being deserialized to control certain aspects, for example, if deserializing an NSArray of objects, it will ask that object what is the type name of the objects stored in the array.