Want to Calculate Hightest Pay Value For a table? - mysql

Question

I want a list of employees who
have worked on the activity that has the highest Total Pay value.
don't use code such as …where actid = 151…ect
• Note: Total Pay worked for an activity is the sum of the (Total Hours Worked * matching
Hourly Rate)
(e.g. Total Pay for Activity 151 is 10.5 hrs # $50.75 + 11.5 hrs # $25 + 3hrs # $33,)
You must use a subquery in your
solution.
ACTID HRSWORKED HOURLYRATE Total Pay
163 10 45.5 455
163 8 45.5 364
163 6 45.5 273
151 5 50.75 253.75
151 5.5 50.75 279.125
155 10 30 300
155 10 30 300
165 20 25 500
155 10 30 300
155 8 27 216
151 11.5 25 287.5
151 1 33 33
151 1 33 33
151 1 33 33
You time and effort much appreciated. Thanks !!

Answer 1

Without knowledge of the schema, I can only provide a possible sketch (you'll have to compute total pay and provide all necessary JOINs and predicates):
SELECT DISTINCT(employee id) -- reconfigure if more then just employee id
FROM <table(s)>
[WHERE...]
{ WHERE | AND } total pay = (SELECT MAX(total pay)
FROM <table(s)>
[WHERE...]);
I used DISTINCT because it's possible to have more than one activity with the same MAX value and overlapping employees. If you're including ACTID in the output, then you won't need DISTINCT because the same employee shouldn't be on a project twice (unless they are tracked by roles on a project in which case a single employee might have multiple roles - it all depends on the data set).