[
{
"cont": 9714494770,
"id": "1",
"name": "Kakkad"
},
{
"cont": 9714494770,
"id": "2",
"name": "Ashish"
}
]
The one above is a json array filled with JSON objects. I don't know how to parse through this with SwiftyJSON
Example from the SwiftyJSON page, adapted to your data:
let json = JSON(data: dataFromNetworking)
for (index, object) in json {
let name = object["name"].stringValue
println(name)
}
Assuming [{"id":"1", "name":"Kakkad", "cont":"9714494770"},{"id":"2", "name":"Ashish", "cont":"9714494770"}] is assigned to a property named jsonData.
let sampleJSON = JSON(data: jsonData)
let sampleArray = sampleJSON.array sampleArray is an optional array of JSON objects.
let firstDict = sampleArray[0] firstDict is an optional JSON dict.
let name = firstDict["name"] is an optional JSON object
let virtName = name.string is a optional string (In this case "Kakkad").
let realName = name.stringValue realName is a string or an empty string.
You could also use:
let longName = sampleJSON[0]["name"].stringValue
After you initialize the JSON object with data all of the elements are JSON types until you convert them to a swift type.
.string optional (string or null)
.stringValue string or "" empty
string
.dict optional ([String: AnyObject] or null)
.dictValue
([String: AnyObject] or String: AnyObject)
For Swift4 I have updated the code from Moritz answer
if let path : String = Bundle.main.path(forResource: "tiles", ofType: "json") {
if let data = NSData(contentsOfFile: path) {
let optData = try? JSON(data: data as Data)
guard let json = optData else {
return
}
//If it is a JSON array of objects
for (_, object) in json {
let name = object["name"].stringValue
print(name)
}
}
}
Swift 3 or 4 code like this:
let json = JSON(yourData)
for (_, object) in json {
let cont = object["cont"].stringValue
print(cont)
}
You can put index instead of _ if you use is anywhere in your code. If you don't use a variable, it's better to put _ (XCode also gives warnings).
Related
I am getting following JSON values in output:
[["category_title": Shelly], ["category_title": Thaddeus],
["category_title": Chantale], ["category_title": Adara],
["category_title": Mariko], ["category_title": Felicia]]
But I want it like below:
["Shelly","Thaddeus","Chantale", "Adara","Mariko","Felicia"]
I have the following Swift code. Please help me get above output.
func successGetTermsData(response: Any){
var UserRole : String = ""
var arrayOfDetails = response as? [[String: Any]] ?? []
UserRole = arrayOfDetails as? String ?? ""
print(arrayOfDetails)
}
You have to map the array of Dictionary arrayOfDetails to an array of String. flatMap ignores a missing key.
if let arrayOfDetails = response as? [[String: String]] {
let userRole = arrayOfDetails.flatMap { $0["category_title"] }
print(userRole)
}
There are many ways to do this. One way is to use flatmap to get just the values in your array of dictionaries:
let arrayOfValues = arrayOfDetails.flatMap { $0.values }
In order to get this to work, the names need to be inside double quotes: "Shelly", etc.
I would like to convert my json response to an array but it doesn't work and I got an error that says my items in the array are nil
func getcomments(){
RestApiManager.sharedInstance.getComments(TUTORIAL_ID: id){
response in
let comments = JSON(response)
for item in comments.array!{
let comment = Comment(memail: String(describing: item["email"]), mcomment: String(describing: item["comment"]), mcomment_date: String(describing: item["comment_date"]), manswer: String(describing: item["answer"]), manswer_date: String(describing: item["answer_date"]))
self.comments.append(comment)
}
}
}
it is my json response:
[{
"email": "-",
"comment": "\u0627\u0632 \u0627\u067e\u0644\u06cc\u06a9\u06cc\u0634\u0646 \u062e\u0648\u0628\u062a\u0648\u0646 \u0645\u0645\u0646\u0648\u0646\u0645",
"comment_date": "2017-07-15 19:30:00",
"answer": null,
"answer_date": null
},
{
"email": "S.M_Emamian#yahoo.com",
"comment": "salam",
"comment_date": "2017-07-11 19:30:00",
"answer": "\u062a\u0634\u06a9\u0631",
"answer_date": "2017-07-12 03:50:57"
}
]
I got nil error in this line:
unexpectedly found nil while unwrapping an Optional value
for item in comments.array!
According to your comment, response is actually a string. Therefore, you can't just create a JSON using init(_:). You need init(parseJSON:).
init(_:) will just create a JSON with just that string instead of a JSON object, which is obviously not what you want. init(parseJSON:) will actually parse your JSON string and allow you to access the different key value pairs.
func getcomments(){
RestApiManager.sharedInstance.getComments(TUTORIAL_ID: id){
response in
let comments = JSON(parseJSON: response)
It's easier if you decode it as an array of structures.
First, create the struct:
struct Comment: Codable {
var email: String
var comment: String
var comment_date: String
var answer: String
var answer_date: String
}
Then you can just call the JSON like that:
guard let url = Bundle.main.url(forResource: resource, withExtension: "json") else {
throw Errors.couldNotFindResource
}
data = try! JSONDecoder().decode([Comment].self, from: Data(contentsOf: url))
How do you convert an array to a JSON string in swift?
Basically I have a textfield with a button embedded in it.
When button is pressed, the textfield text is added unto the testArray.
Furthermore, I want to convert this array to a JSON string.
This is what I have tried:
func addButtonPressed() {
if goalsTextField.text == "" {
// Do nothing
} else {
testArray.append(goalsTextField.text)
goalsTableView.reloadData()
saveDatatoDictionary()
}
}
func saveDatatoDictionary() {
data = NSKeyedArchiver.archivedDataWithRootObject(testArray)
newData = NSJSONSerialization.JSONObjectWithData(data!, options: NSJSONReadingOptions(), error: nil) as? NSData
string = NSString(data: newData!, encoding: NSUTF8StringEncoding)
println(string)
}
I would also like to return the JSON string using my savetoDictionart() method.
As it stands you're converting it to data, then attempting to convert the data to to an object as JSON (which fails, it's not JSON) and converting that to a string, basically you have a bunch of meaningless transformations.
As long as the array contains only JSON encodable values (string, number, dictionary, array, nil) you can just use NSJSONSerialization to do it.
Instead just do the array->data->string parts:
Swift 3/4
let array = [ "one", "two" ]
func json(from object:Any) -> String? {
guard let data = try? JSONSerialization.data(withJSONObject: object, options: []) else {
return nil
}
return String(data: data, encoding: String.Encoding.utf8)
}
print("\(json(from:array as Any))")
Original Answer
let array = [ "one", "two" ]
let data = NSJSONSerialization.dataWithJSONObject(array, options: nil, error: nil)
let string = NSString(data: data!, encoding: NSUTF8StringEncoding)
although you should probably not use forced unwrapping, it gives you the right starting point.
Swift 3.0 - 4.0 version
do {
//Convert to Data
let jsonData = try JSONSerialization.data(withJSONObject: dictionaryOrArray, options: JSONSerialization.WritingOptions.prettyPrinted)
//Convert back to string. Usually only do this for debugging
if let JSONString = String(data: jsonData, encoding: String.Encoding.utf8) {
print(JSONString)
}
//In production, you usually want to try and cast as the root data structure. Here we are casting as a dictionary. If the root object is an array cast as [Any].
var json = try JSONSerialization.jsonObject(with: jsonData, options: JSONSerialization.ReadingOptions.mutableContainers) as? [String: Any]
} catch {
print(error.description)
}
The JSONSerialization.WritingOptions.prettyPrinted option gives it to the eventual consumer in an easier to read format if they were to print it out in the debugger.
Reference: Apple Documentation
The JSONSerialization.ReadingOptions.mutableContainers option lets you mutate the returned array's and/or dictionaries.
Reference for all ReadingOptions: Apple Documentation
NOTE: Swift 4 has the ability to encode and decode your objects using a new protocol. Here is Apples Documentation, and a quick tutorial for a starting example.
If you're already using SwiftyJSON:
https://github.com/SwiftyJSON/SwiftyJSON
You can do this:
// this works with dictionaries too
let paramsDictionary = [
"title": "foo",
"description": "bar"
]
let paramsArray = [ "one", "two" ]
let paramsJSON = JSON(paramsArray)
let paramsString = paramsJSON.rawString(encoding: NSUTF8StringEncoding, options: nil)
SWIFT 3 UPDATE
let paramsJSON = JSON(paramsArray)
let paramsString = paramsJSON.rawString(String.Encoding.utf8, options: JSONSerialization.WritingOptions.prettyPrinted)!
JSON strings, which are good for transport, don't come up often because you can JSON encode an HTTP body. But one potential use-case for JSON stringify is Multipart Post, which AlamoFire nows supports.
How to convert array to json String in swift 2.3
var yourString : String = ""
do
{
if let postData : NSData = try NSJSONSerialization.dataWithJSONObject(yourArray, options: NSJSONWritingOptions.PrettyPrinted)
{
yourString = NSString(data: postData, encoding: NSUTF8StringEncoding)! as String
}
}
catch
{
print(error)
}
And now you can use yourSting as JSON string..
Swift 5
This generic extension will convert an array of objects to a JSON string from which it can either be:
saved to the App's Documents Directory (iOS/MacOS)
output directly to a file on the Desktop (MacOS)
.
extension JSONEncoder {
static func encode<T: Encodable>(from data: T) {
do {
let jsonEncoder = JSONEncoder()
jsonEncoder.outputFormatting = .prettyPrinted
let json = try jsonEncoder.encode(data)
let jsonString = String(data: json, encoding: .utf8)
// iOS/Mac: Save to the App's documents directory
saveToDocumentDirectory(jsonString)
// Mac: Output to file on the user's Desktop
saveToDesktop(jsonString)
} catch {
print(error.localizedDescription)
}
}
static private func saveToDocumentDirectory(_ jsonString: String?) {
guard let path = FileManager.default.urls(for: .documentDirectory, in: .userDomainMask).first else { return }
let fileURL = path.appendingPathComponent("Output.json")
do {
try jsonString?.write(to: fileURL, atomically: true, encoding: .utf8)
} catch {
print(error.localizedDescription)
}
}
static private func saveToDesktop(_ jsonString: String?) {
let homeURL = FileManager.default.homeDirectoryForCurrentUser
let desktopURL = homeURL.appendingPathComponent("Desktop")
let fileURL = desktopURL.appendingPathComponent("Output.json")
do {
try jsonString?.write(to: fileURL, atomically: true, encoding: .utf8)
} catch {
print(error.localizedDescription)
}
}
}
Example:
struct Person: Codable {
var name: String
var pets: [Pet]
}
struct Pet: Codable {
var type: String
}
extension Person {
static func sampleData() -> [Person] {
[
Person(name: "Adam", pets: []),
Person(name: "Jane", pets: [
Pet(type: "Cat")
]),
Person(name: "Robert", pets: [
Pet(type: "Cat"),
Pet(type: "Rabbit")
])
]
}
}
Usage:
JSONEncoder.encode(from: Person.sampleData())
Output:
This will create the following correctly formatted Output.json file:
[
{
"name" : "Adam",
"pets" : [
]
},
{
"name" : "Jane",
"pets" : [
{
"type" : "Cat"
}
]
},
{
"name" : "Robert",
"pets" : [
{
"type" : "Cat"
},
{
"type" : "Rabbit"
}
]
}
]
SWIFT 2.0
var tempJson : NSString = ""
do {
let arrJson = try NSJSONSerialization.dataWithJSONObject(arrInvitationList, options: NSJSONWritingOptions.PrettyPrinted)
let string = NSString(data: arrJson, encoding: NSUTF8StringEncoding)
tempJson = string! as NSString
}catch let error as NSError{
print(error.description)
}
NOTE:- use tempJson variable when you want to use.
extension Array where Element: Encodable {
func asArrayDictionary() throws -> [[String: Any]] {
var data: [[String: Any]] = []
for element in self {
data.append(try element.asDictionary())
}
return data
}
}
extension Encodable {
func asDictionary() throws -> [String: Any] {
let data = try JSONEncoder().encode(self)
guard let dictionary = try JSONSerialization.jsonObject(with: data, options: .allowFragments) as? [String: Any] else {
throw NSError()
}
return dictionary
}
}
If you're using Codable protocols in your models these extensions might be helpful for getting dictionary representation (Swift 4)
Hint: To convert an NSArray containing JSON compatible objects to an NSData object containing a JSON document, use the appropriate method of NSJSONSerialization. JSONObjectWithData is not it.
Hint 2: You rarely want that data as a string; only for debugging purposes.
For Swift 4.2, that code still works fine
var mnemonic: [String] = ["abandon", "amount", "liar", "buyer"]
var myJsonString = ""
do {
let data = try JSONSerialization.data(withJSONObject:mnemonic, options: .prettyPrinted)
myJsonString = NSString(data: data, encoding: String.Encoding.utf8.rawValue) as! String
} catch {
print(error.localizedDescription)
}
return myJsonString
Swift 5
Make sure your object confirm Codable.
Swift's default variable types like Int, String, Double and ..., all are Codable that means we can convert theme to Data and vice versa.
For example, let's convert array of Int to String Base64
let array = [1, 2, 3]
let data = try? JSONEncoder().encode(array)
nsManagedObject.array = data?.base64EncodedString()
Make sure your NSManaged variable type is String in core data schema editor and custom class if your using custom class for core data objects.
let's convert back base64 string to array:
var getArray: [Int] {
guard let array = array else { return [] }
guard let data = Data(base64Encoded: array) else { return [] }
guard let val = try? JSONDecoder().decode([Int].self, from: data) else { return [] }
return val
}
Do not convert your own object to Base64 and store as String in CoreData and vice versa because we have something that named Relation in CoreData (databases).
For Swift 3.0 you have to use this:
var postString = ""
do {
let data = try JSONSerialization.data(withJSONObject: self.arrayNParcel, options: .prettyPrinted)
let string1:String = NSString(data: data, encoding: String.Encoding.utf8.rawValue) as! String
postString = "arrayData=\(string1)&user_id=\(userId)&markupSrcReport=\(markup)"
} catch {
print(error.localizedDescription)
}
request.httpBody = postString.data(using: .utf8)
100% working TESTED
You can try this.
func convertToJSONString(value: AnyObject) -> String? {
if JSONSerialization.isValidJSONObject(value) {
do{
let data = try JSONSerialization.data(withJSONObject: value, options: [])
if let string = NSString(data: data, encoding: String.Encoding.utf8.rawValue) {
return string as String
}
}catch{
}
}
return nil
}
I'm trying to get data drom the json array, this is the code that i'm trying, the thing is that i would like to get only the name that is inside this json
{
"tag": "getuser",
"success": 1,
"error": 0,
"uid": "56108b7e651ad2.95653404",
"user": {
"name": "2",
"phone": "2",
"email": "2"
}
}
I tryied this
let jsonData:NSDictionary = try NSJSONSerialization.JSONObjectWithData(urlData!, options:NSJSONReadingOptions.MutableContainers ) as! NSDictionary
let name = jsonData["user"]
print("Nombre del usuarioes: \(name)")
But this prints the whole user data, name, phone and email, how can i be able to print only the name or only the email?
You don't have to use a library and you don't have to use key-value coding.
The same way you're already using subscripting for your dictionary with this:
let name = jsonData["user"]
you just have to continue subscripting to find your value.
Example:
do {
let jsonData = try NSJSONSerialization.JSONObjectWithData(urlData!, options: []) as! NSDictionary
let user = jsonData["user"]!
let name = user["name"]
print(name)
} catch {
print(error)
}
Even better with safe unwrapping:
do {
if let data = urlData, let jsonData = try NSJSONSerialization.JSONObjectWithData(data, options: []) as? NSDictionary {
if let user = jsonData["user"] as? NSDictionary, let name = user["name"] as? String {
print(name)
}
}
} catch {
print(error)
}
Note: in JSON, a dictionary is defined by {} and an array is defined by []. What you have here is a dictionary containing a dictionary, not an array (cf your question title).
A great library to decode json is SwiftyJSON
you can get sub-scripted data from the json like so
import SwiftyJSON
if let dataFromString = jsonString.dataUsingEncoding(NSUTF8StringEncoding, allowLossyConversion: false) {
let json = JSON(data: dataFromString)
let name = json["user"]["name"].string
print(name)
}
Use your code, then get the field from jsonData by this:
let name = jsonData.valueForKeyPath("user.name") as! String
let email = jsonData.valueForKeyPath("user.email") as! String
Is there a way to properly deserialize a JSON response to Swift objects resp. using DTOs as containers for fixed JSON APIs?
Something similar to http://james.newtonking.com/json or something like this example from Java
User user = jsonResponse.readEntity(User.class);
whereby jsonResponse.toString() is something like
{
"name": "myUser",
"email": "user#example.com",
"password": "passwordHash"
}
SWIFT 4 Update
Since you give a very simple JSON object the code prepared for to handle that model. If you need more complicated JSON models you need to improve this sample.
Your Custom Object
class Person : NSObject {
var name : String = ""
var email : String = ""
var password : String = ""
init(JSONString: String) {
super.init()
var error : NSError?
let JSONData = JSONString.dataUsingEncoding(NSUTF8StringEncoding, allowLossyConversion: false)
let JSONDictionary: Dictionary = NSJSONSerialization.JSONObjectWithData(JSONData, options: nil, error: &error) as NSDictionary
// Loop
for (key, value) in JSONDictionary {
let keyName = key as String
let keyValue: String = value as String
// If property exists
if (self.respondsToSelector(NSSelectorFromString(keyName))) {
self.setValue(keyValue, forKey: keyName)
}
}
// Or you can do it with using
// self.setValuesForKeysWithDictionary(JSONDictionary)
// instead of loop method above
}
}
And this is how you invoke your custom class with JSON string.
override func viewDidLoad() {
super.viewDidLoad()
let jsonString = "{ \"name\":\"myUser\", \"email\":\"user#example.com\", \"password\":\"passwordHash\" }"
var aPerson : Person = Person(JSONString: jsonString)
println(aPerson.name) // Output is "myUser"
}
I recommend that you use code generation (http://www.json4swift.com) to create native models out of the json response, this will save your time of parsing by hand and reduce the risk of errors due to mistaken keys, all elements will be accessible by model properties, this will be purely native and the models will make more sense rather checking the keys.
Your conversion will be as simple as:
let userObject = UserClass(userDictionary)
print(userObject!.name)
Swift 2: I really like the previous post of Mohacs! To make it more object oriented, i wrote a matching Extension:
extension NSObject{
convenience init(jsonStr:String) {
self.init()
if let jsonData = jsonStr.dataUsingEncoding(NSUTF8StringEncoding, allowLossyConversion: false)
{
do {
let json = try NSJSONSerialization.JSONObjectWithData(jsonData, options: []) as! [String: AnyObject]
// Loop
for (key, value) in json {
let keyName = key as String
let keyValue: String = value as! String
// If property exists
if (self.respondsToSelector(NSSelectorFromString(keyName))) {
self.setValue(keyValue, forKey: keyName)
}
}
} catch let error as NSError {
print("Failed to load: \(error.localizedDescription)")
}
}
else
{
print("json is of wrong format!")
}
}
}
custom classes:
class Person : NSObject {
var name : String?
var email : String?
var password : String?
}
class Address : NSObject {
var city : String?
var zip : String?
}
invoking custom classes with JSON string:
var jsonString = "{ \"name\":\"myUser\", \"email\":\"user#example.com\", \"password\":\"passwordHash\" }"
let aPerson = Person(jsonStr: jsonString)
print(aPerson.name!) // Output is "myUser"
jsonString = "{ \"city\":\"Berlin\", \"zip\":\"12345\" }"
let aAddress = Address(jsonStr: jsonString)
print(aAddress.city!) // Output is "Berlin"
Yet another JSON handler I wrote:
https://github.com/dankogai/swift-json
With it you can go like this:
let obj:[String:AnyObject] = [
"array": [JSON.null, false, 0, "", [], [:]],
"object":[
"null": JSON.null,
"bool": true,
"int": 42,
"double": 3.141592653589793,
"string": "a α\t弾\n𪚲",
"array": [],
"object": [:]
],
"url":"http://blog.livedoor.com/dankogai/"
]
let json = JSON(obj)
json.toString()
json["object"]["null"].asNull // NSNull()
json["object"]["bool"].asBool // true
json["object"]["int"].asInt // 42
json["object"]["double"].asDouble // 3.141592653589793
json["object"]["string"].asString // "a α\t弾\n𪚲"
json["array"][0].asNull // NSNull()
json["array"][1].asBool // false
json["array"][2].asInt // 0
json["array"][3].asString // ""
As you see no !? needed between subscripts.
In addition to that you can apply your own schema like this:
//// schema by subclassing
class MyJSON : JSON {
override init(_ obj:AnyObject){ super.init(obj) }
override init(_ json:JSON) { super.init(json) }
var null :NSNull? { return self["null"].asNull }
var bool :Bool? { return self["bool"].asBool }
var int :Int? { return self["int"].asInt }
var double:Double? { return self["double"].asDouble }
var string:String? { return self["string"].asString }
var url: String? { return self["url"].asString }
var array :MyJSON { return MyJSON(self["array"]) }
var object:MyJSON { return MyJSON(self["object"]) }
}
let myjson = MyJSON(obj)
myjson.object.null // NSNull?
myjson.object.bool // Bool?
myjson.object.int // Int?
myjson.object.double // Double?
myjson.object.string // String?
myjson.url // String?
There's a great example by Apple for deserializing JSON with Swift 2.0
The trick is to use the guard keyword and chain the assignments like so:
init?(attributes: [String : AnyObject]) {
guard let name = attributes["name"] as? String,
let coordinates = attributes["coordinates"] as? [String: Double],
let latitude = coordinates["lat"],
let longitude = coordinates["lng"],
else {
return nil
}
self.name = name
self.coordinates = CLLocationCoordinate2D(latitude: latitude, longitude: longitude)
}
I personally prefer native parsing vs any 3rd party, as it is transparent and magic-less. (and bug less?)
Using quicktype, I generated your model and serialization helpers from your sample:
import Foundation
struct User: Codable {
let name: String
let email: String
let password: String
}
extension User {
static func from(json: String, using encoding: String.Encoding = .utf8) -> OtherUser? {
guard let data = json.data(using: encoding) else { return nil }
return OtherUser.from(data: data)
}
static func from(data: Data) -> OtherUser? {
let decoder = JSONDecoder()
return try? decoder.decode(OtherUser.self, from: data)
}
var jsonData: Data? {
let encoder = JSONEncoder()
return try? encoder.encode(self)
}
var jsonString: String? {
guard let data = self.jsonData else { return nil }
return String(data: data, encoding: .utf8)
}
}
Then parse User values like this:
let user = User.from(json: """{
"name": "myUser",
"email": "user#example.com",
"password": "passwordHash"
}""")!
I wrote this small open-source library recently that lets you quickly and easily deserialize dictionaries into Swift objects: https://github.com/isair/JSONHelper
Using it, deserializing data becomes as easy as this:
var myInstance = MyClass(data: jsonDictionary)
or
myInstance <-- jsonDictionary
And models need to look only like this:
struct SomeObjectType: Deserializable {
var someProperty: Int?
var someOtherProperty: AnotherObjectType?
var yetAnotherProperty: [YetAnotherObjectType]?
init(data: [String: AnyObject]) {
someProperty <-- data["some_key"]
someOtherProperty <-- data["some_other_key"]
yetAnotherProperty <-- data["yet_another_key"]
}
}
Which, in your case, would be:
struct Person: Deserializable {
var name: String?
var email: String?
var password: String?
init(data: [String: AnyObject]) {
name <-- data["name"]
email <-- data["email"]
password <-- data["password"]
}
}
If you would like parse from and to json without the need to manually map keys and fields, then you could also use EVReflection. You can then use code like:
var user:User = User(json:jsonString)
or
var jsonString:String = user.toJsonString()
The only thing you need to do is to use EVObject as your data objects base class.
See the GitHub page for more detailed sample code
I am expanding upon Mohacs and Peter Kreinz's excellent answers just a bit to cover the array of like objects case where each object contains a mixture of valid JSON data types. If the JSON data one is parsing is an array of like objects containing a mixture of JSON data types, the do loop for parsing the JSON data becomes this.
// Array of parsed objects
var parsedObjects = [ParsedObject]()
do {
let json = try NSJSONSerialization.JSONObjectWithData(jsonData, options: []) as [Dictionary<String, AnyObject>]
// Loop through objects
for dict in json {
// ParsedObject is a single instance of an object inside the JSON data
// Its properties are a mixture of String, Int, Double and Bool
let parsedObject = ParsedObject()
// Loop through key/values in object parsed from JSON
for (key, value) in json {
// If property exists, set the value
if (parsedObject.respondsToSelector(NSSelectorFromString(keyName))) {
// setValue can handle AnyObject when assigning property value
parsedObject.setValue(keyValue, forKey: keyName)
}
}
parsedObjects.append(parsedObject)
}
} catch let error as NSError {
print("Failed to load: \(error.localizedDescription)")
}
This way lets you get the user from a URL. It's parse the NSData to a NSDictionary and then to your NSObject.
let urlS = "http://api.localhost:3000/"
func getUser(username: Strung) -> User {
var user = User()
let url = NSURL(string: "\(urlS)\(username)")
if let data = NSData(contentsOfURL: url!) {
setKeysAndValues(user, dictionary: parseData(data))
}
return user
}
func setKeysAndValues (object : AnyObject, dictionary : NSDictionary) -> AnyObject {
for (key, value) in dictionary {
if let key = key as? String, let value = value as? String {
if (object.respondsToSelector(NSSelectorFromString(key))) {
object.setValue(value, forKey: key)
}
}
}
return object
}
func parseData (data : NSData) -> NSDictionary {
var error: NSError?
return NSJSONSerialization.JSONObjectWithData(data, options: NSJSONReadingOptions.MutableContainers, error: &error) as! NSDictionary
}
In Swift 4, You can use the Decoding, CodingKey protocols to deserialize the JSON response:
Create the class which confirm the decodable protocol
class UserInfo: Decodable
Create members of the class
var name: String
var email: String
var password: String
Create JSON key enum which inherits from CodingKey
enum UserInfoCodingKey: String, CodingKey {
case name
case password
case emailId
}
Implement init
required init(from decoder: Decoder) throws
The whole class look like :
Call Decoder
// jsonData is JSON response and we get the userInfo object
let userInfo = try JsonDecoder().decode(UserInfo.self, from: jsonData)
You do this by using NSJSONSerialization. Where data is your JSON.
First wrap it in an if statement to provide some error handling capablity
if let data = data,
json = try NSJSONSerialization.JSONObjectWithData(data, options: []) as? [String: AnyObject] {
// Do stuff
} else {
// Do stuff
print("No Data :/")
}
then assign them:
let email = json["email"] as? String
let name = json["name"] as? String
let password = json["password"] as? String
Now, This will show you the result:
print("Found User iname: \(name) with email: \(email) and pass \(password)")
Taken from this Swift Parse JSON tutorial. You should check out the tutorial as it goes a lot more in depth and covers better error handling.