lets say I have this table:
| id | record_id | date_updated |
|----|-----------|--------------|
| 1 | 1 | 19-03-2015 |
| 2 | 1 | 18-03-2015 |
| 3 | 1 | 17-03-2014 |
| 4 | 2 | 01-01-2015 |
| 5 | 2 | 05-02-2015 |
so the results I am looking for are :
| id | record_id | date_updated |
|----|-----------|--------------|
| 1 | 1 | 19-03-2015 |
| 4 | 2 | 01-01-2015 |
I have array with record ids.
$records = [1,2];
So I can do something like:
select * from `mytable`
WHERE `record_id` IN ($records)
AND mytable.date_update > 01-01-2014
AND mytable.date_updated < 12-12-2015
so mysql will select records wich match date_updated criteria ( and record id ofc ), which are more then 1 for each record ID, basically I want to make him limit the rows for each $record_id to 1
If it is even possible.
//it is super hard to explain the problem, the real case is that this is a sub query of another query, but the real example is 10 rows query and 100 columns table, so it will be even more hard to explain the situation and for someone to read it / udnerstands it. Hopefully someone will understand my problem, if not I will try to explain more.
Thanks
You can try using the group by clause
SELECT *
FROM `mytable`
WHERE id IN (
SELECT min(id)
FROM `mytable`
WHERE `record_id` IN ($records)
AND mytable.date_update > 01-01-2014
AND mytable.date_updated < 12-12-2015
group by record_id
);
There are many ways to get the record per group, and since you need only once you can easily do as below
select t1.* from table_name t1
where (
select count(*) from table_name t2
where t1.record_id = t2.record_id
) > =0
and
t1.date_updated > '2014-01-01' and date_updated < '2015-12-12'
group by t1.record_id ;
There are other way too using left join
select t1.* from table_name t1
left join table_name t2 on t1.record_id = t2.record_id
and t1.id >t2.id where t2.id is null
This will give you data with asc order with id
If you need data with max(id) for a record_id you can use
t1.id < t2.id
instead of
t1.id >t2.id
The same comparison you can do with first query.
Related
My table:
id | request | subject | date
1 | 5 | 1 | 576677
2 | 2 | 3 | 576698
3 | 5 | 1 | 576999
4 | 2 | 3 | 586999
5 | 2 | 7 | 596999
Need to select unique records by two columns(request,subject). But if we have different pairs of request-subject(2-3, 2-7), this records should be excluded from resulted query.
My query now is:
SELECT MAX(id), id, request, subject, date
FROM `tbl`
GROUP BY request, subject
having count(request) > 1
order by MAX(id) desc
How to exclude record with id=4, id=5 from this query? Thanks!
You may group by request, and then check for every group if all subjects in it are equal. You could do it using MIN() and MAX():
SELECT request, MIN(subject) AS subject
FROM table_1
GROUP BY request
HAVING MIN(subject) = MAX(subject)
As for your update, I assume you want all the fields for the max ID in the group (in your example, ID 3). The query would then look like this one:
SELECT *
FROM table_1 t
WHERE t.id IN (SELECT MAX(s.id)
FROM table_1 s
GROUP BY s.request
HAVING MIN(s.subject) = MAX(s.subject))
ORDER BY t.id
You can try this.
select * from MyTable T1
WHERE NOT EXISTS( SELECT * FROM MyTable T2
WHERE T1.id <> T2.id
and T1.request = T2.request
and T1.subject <> T2.subject)
Sql Fiddle
I have a MySQL DB and in it there's a table with activity logs of employees.
+-------------------------------------------------+
| log_id | employee_id | date_time | action_type |
+-------------------------------------------------+
| 1 | 1 | 2015/02/03 | action1 |
| 2 | 2 | 2015/02/01 | action1 |
| 3 | 2 | 2017/01/02 | action2 |
| 4 | 3 | 2016/02/12 | action1 |
| 5 | 1 | 2016/10/12 | action2 |
+-------------------------------------------------+
And I would need 2 queries. First, to get for every employee his last action. So from this example table I would need to get row 3,4 and 5 with all columns. And second, get the latest action only for specified employee.
Any ideas how to achieve this? I'm using Spring Data JPA, but raw SQL Query would be also great.
Thank you in advance.
Ready for a fred ed...
SELECT x.*
FROM my_table x
JOIN
( SELECT employee_id
, MAX(date_time) date_time
FROM my_table
GROUP
BY employee_id
) y
ON y.employee_id = x.employee_id
AND y.date_time = x.date_time;
For your first query. Simply
SELECT t1.*
FROM tableName t1
WHERE t1.log_id = (SELECT MAX(t2.log_id)
FROM tableName t2
WHERE t2.employee_id = t1.employee_id)
For the second one
SELECT t1.*
FROM tableName t1
WHERE t1.employee_id=X and t1.log_id = (SELECT MAX(t2.log_id)
FROM tableName t2
WHERE t2.employee_id = t1.employee_id);
You can get the expected output by doing a self join
select a.*
from demo a
left join demo b on a.employee_id = b.employee_id
and a.date_time < b.date_time
where b.employee_id is null
Note it may return multiple rows for single employee if there are rows with same date_time you might need a CASE statement and another attribute to decide which row should be picked to handle this kind of situation
Demo
I'm trying to extract all rows from same Group until I hit breakpoint value B. The example data below is ordered virtual table:
+----+--------+------------+
| ID | Group | Breakpoint |
+----+--------+------------+
| 1 | 1 | A |
| 2 | 1 | A |
| 3 | 1 | B |
| 4 | 1 | A |
| 5 | 2 | A |
| 6 | 2 | A |
| 7 | 2 | A |
| 8 | 3 | A |
| 9 | 3 | B |
+----+--------+------------+
This would be my result.
+----+--------+------------+
| ID | Group | Breakpoint |
+----+--------+------------+
| 1 | 1 | A |
| 2 | 1 | A |
| 5 | 2 | A |
| 6 | 2 | A |
| 7 | 2 | A |
| 8 | 3 | A |
+----+--------+------------+
Notice that when there are both A and B breakpoint values within a group, I want to have the rows until the first A value in this order. If there are only A values for a group like in group 2, I want to have all of the items in the group.
Here's a simple solution that uses no subqueries or GROUP BY logic.
SELECT t1.ID, t1.Group, t1.Breakpoint
FROM MyTable AS t1
LEFT OUTER JOIN MyTable AS t2
ON t1.ID >= t2.ID AND t1.`Group` = t2.`Group` AND t2.Breakpoint = 'B'
WHERE t2.ID IS NULL
For each row t1, try to find another row t2 with 'B', in the same Group, with an earlier ID. If none is found, the OUTER JOIN guarantees that t2.ID is NULL. That will be true only up until the desired breakpoint.
From you example above, you are not really grouping the results. you just need to display the records where Breakpoint is A:
Select * From Table
Where Breakpint ='A'
You may use NOT EXISTS
select *
from your_table t1
where not exists (
select 1
from your_table t2
where t1.group = t2.group and t2.id <= t1.id and t2.breakpoint = 'B'
)
or ALL can work as well if you never have NULL in id
select *
from your_table t1
where t1.id < ALL(
select t2.id
from your_table t2
where t1.group = t2.group and t2.breakpoint = 'B'
)
Assuming that we are ordering by ID column, we could do something like this:
SELECT d.*
FROM mytable d
LEFT
JOIN ( SELECT bp.group
, MIN(bp.id) AS bp_id
FROM mytable bp
WHERE bp.breakpoint = 'B'
GROUP BY bp.group
) b
ON b.group = d.group
WHERE b.bp_id > d.id OR b.bp_id IS NULL
ORDER BY d.group, d.id
This takes into account cases where there is no breakpoint='B' row for a given group, and returns all of the rows for that group.
Note that the inline view b gets us the lowest id value from rows with breakpoint='B' for each group. We can outer join that to original table (matching on group), and then conditional tests in the WHERE clause to exclude rows that follow the first breakpoint='B' for each group.
SQL tables represent unordered sets. Hence, there is no "before" or "after" a particular row.
Let me assume that you have some column that specifies the ordering. I'll call it id. You can then do what you want with:
select t.*
from t
where t.id < (select min(t2.id) from t t2 where t2.group = t.group and t2.breakpoint = 'B');
To get all rows when if there are no 'B':
select t.*
from t
where t.id < (select coalesce(min(t2.id), t.id + 1) from t t2 where t2.group = t.group and t2.breakpoint = 'B');
I want to show my parent id with child record(duplicate record). Here is my table
ID|Name |Comments|
__|_____|________|_
1 |Test1|Unique |
2 |Test2|Unique |
3 |Test1|Unique |
4 |Test2|Unique |
5 |Test1|Unique |
6 |Test3|Unique |
Expected Result:
ID|Name |Comments |
__|_____|__________________|_
1 |Test1|Unique |
2 |Test2|Unique |
3 |Test1|Duplicate with: 1 |
4 |Test2|Duplicate with: 2 |
5 |Test1|Duplicate with: 1 |
6 |Test3|Unique |
not sure what the exact goal here, but here is a single query that get the job done:
mysql> select ID,tbl.Name,if(no!=ID,concat('Duplicate with: ',no),'Unique') Comments from tbl left join (select ID no,Name from tbl group by Name) T on T.Name=tbl.Name;
+----+-------+-------------------+
| ID | Name | Comments |
+----+-------+-------------------+
| 1 | Test1 | Unique |
| 2 | Test2 | Unique |
| 3 | Test1 | Duplicate with: 1 |
| 4 | Test2 | Duplicate with: 2 |
| 5 | Test1 | Duplicate with: 1 |
| 6 | Test3 | Unique |
+----+-------+-------------------+
Check This Live Demo using 'coalesce' and 'Case when'
Query :
select id
,name
,coalesce(
( select coalesce(case when min(id)>0 then concat('Duplicate with : ',min(id)) else null end,Comments)
from Yourtable t2 where t2.name = t.name and t2.id < t.id group by Comments)
,Comments) as Comments
from Yourtable t
order by id
Output :
hey you can try this query and it is giving expected result.
select t1.id,t1.`name`,
CASE WHEN (select count(`name`) from table_name t2 where t2.`name` = t1.`name` and t2.id <= t1.id ) = 1
then 'unique'
else CONCAT('Duplicate with :',(select min(t3.id) from table_name t3 where t3.name = t1.`name`))
end as 'comments'
from table_name t1
replace table_name with your table.
Hope this works for you. Ask if any doubt
Using only a single sub-query.
select id
,name
,coalesce
(
concat
(
'Duplicate with: '
,(select min(id) from mytable t2 where t2.name = t.name and t2.id < t.id)
)
,'Unique'
) as Comments
from mytable t
order by id
I have a table as so...
----------------------------------------
| id | name | group | number |
----------------------------------------
| 1 | joey | 1 | 2 |
| 2 | keidy | 1 | 3 |
| 3 | james | 2 | 2 |
| 4 | steven | 2 | 5 |
| 5 | jason | 3 | 2 |
| 6 | shane | 3 | 3 |
----------------------------------------
I'm running a select like so:
SELECT * FROM table WHERE number IN (2,3);
The problem im trying to solve is that I want to only grab get results from groups that have 1 or more rows of each number. For instance the above query is returning id's 1-2-3-5-6, when I'd like the results to exclude id 3 since the group of '2' can only return 1 result for the number of '2' and not for BOTH 2 and 3, since there's no row with the number 3 for the group 2 i'd like it to not even select id 3 at all.
Any help would be great.
Try it this way
SELECT *
FROM table1 t
WHERE number IN(2, 3)
AND EXISTS
(
SELECT *
FROM table1
WHERE number IN(2, 3)
AND `group` = t.`group`
GROUP BY `group`
HAVING MAX(number = 2) > 0
AND MAX(number = 3) > 0
)
or
SELECT *
FROM table1 t JOIN
(
SELECT `group`
FROM table1
WHERE number IN(2, 3)
GROUP BY `group`
HAVING MAX(number = 2) > 0
AND MAX(number = 3) > 0
) q
ON t.`group` = q.`group`;
or
SELECT *
FROM table1
WHERE `group` IN
(
SELECT `group`
FROM table1
WHERE number IN(2, 3)
GROUP BY `group`
HAVING MAX(number = 2) > 0
AND MAX(number = 3) > 0
);
Sample output (for both queries):
| ID | NAME | GROUP | NUMBER |
|----|-------|-------|--------|
| 1 | joey | 1 | 2 |
| 2 | keidy | 1 | 3 |
| 5 | jason | 3 | 2 |
| 6 | shane | 3 | 3 |
Here is SQLFiddle demo
On this, you can approach from a fun way with multiple joins for what you WANT qualified, OR, apply a prequery to get all qualified groups as others have suggested, but readability is a bit off for me..
Anyhow, here's an approach going through the table once, but with joins
select DISTINCT
T.id,
T.Name,
T.Group,
T.Number
from
YourTable T
Join YourTable T2
on T.Group = T2.Group AND T2.Group = 2
Join YourTable T3
on T.Group = T3.Group AND T3.Group = 3
where
T.Number IN ( 2, 3 )
So on the first record, it is pointing to by it's own group to the T2 group AND the T2 group is specifically a 2... Then again, but testing the group for the T3 instance and T3's group is a 3.
If it cant complete the join to either of the T2 or T3 instances, the record is done for consideration, and since indexes work great for joins like this, make sure you have one index for your NUMBER criteria, and another index on the (GROUP, NUMBER) for those comparisons and the next query sample...
If doing by more than this simple 2, but larger group, prequery qualified groups, then join to that
select
YT2.*
from
( select YT1.group
from YourTable YT1
where YT1.Number in (2, 3)
group by YT1.group
having count( DISTINCT YT1.group ) = 2 ) PreQualified
JOIN YourTable YT2
on PreQualified.group = YT2.group
AND YT2.Number in (2,3)
Maybe this,if I understand you
SELECT id FROM table WHERE `group` IN
(SELECT `group` FROM table WHERE number IN (2,3)
GROUP BY `group`
HAVING COUNT(DISTINCT number)=2)
SQL Fiddle
This will return all ids where BOTH numbers exist in a group.Remove DISTINCT if you want ids for groups where just one numbers is in.