Combine results of two different queries into a single query - mysql

Question

I have a MySQL table containing login logs. Each entry contains user email, IP address, timestamp and the login result (0 fail, 1 success).
+------------+------------------+------------+--------+
| ip | email | datetime | result |
+------------+------------------+------------+--------+
| 2130706433 | user1#domain.com | 1426498362 | 0 |
| 2130706433 | user1#domain.com | 1426498363 | 1 |
| 2130706433 | user1#domain.com | 1426498364 | 0 |
| 1134706444 | user2#domain.com | 1426498365 | 0 |
+------------+------------------+------------+--------+
My goal is to create a unique query to extract the count of failed logins from a given timestamp, and the timestamp of the last login for user1#domain.com. In this case I would like to obtain (suppose for simplicity that all entries are after the required timestamp)
+--------+------------+
| count | datetime |
+--------+------------+
| 3 | 1426498364 |
+--------+------------+
Until now, I've created two separated queries to extract results separately
SELECT COUNT(result) as count FROM (SELECT result FROM accesslogs WHERE datetime>1426498360 AND result=0) as subt
SELECT MAX(datetime) as datetime FROM accesslogs WHERE email=`user1#domain.com`
Now I'm tring to combine them to get results with a single query. I was wondering about using JOIN statement, but I don't know a column where queries may join. What can I do?

Answer 1

You can use conditional aggregation for this, something as
select
sum(
case
when result=0 and datetime>1426498360
then 1 else 0 end
) as `count`,
max(
case
when email = 'user1#domain.com' then datetime end
) as datetime
from accesslogs ;
Here is an example
mysql> select * from test ;
+------------+------------------+------------+--------+
| ip | email | datetime | result |
+------------+------------------+------------+--------+
| 2130706433 | user1#domain.com | 1426498362 | 0 |
| 2130706433 | user1#domain.com | 1426498363 | 1 |
| 2130706433 | user1#domain.com | 1426498364 | 0 |
| 1134706444 | user2#domain.com | 1426498365 | 0 |
+------------+------------------+------------+--------+
4 rows in set (0.00 sec)
mysql> select
-> sum(
-> case
-> when result=0 and datetime>1426498360
-> then 1 else 0 end
-> ) as `count`,
-> max(
-> case
-> when email = 'user1#domain.com' then datetime end
-> ) as datetime
-> from test ;
+-------+------------+
| count | datetime |
+-------+------------+
| 3 | 1426498364 |
+-------+------------+
1 row in set (0.00 sec)

Answer 2

Try
select * from (selete statement a) a join (selete statement b) b

Answer 3

You could use UNION ALL but both queries must have same columns.
I would suggest add text column to each query descibing type of value in other column like:
SELECT COUNT(result) as count, 'count' AS TYPE FROM (SELECT result FROM accesslogs WHERE datetime>1426498360 AND result=0) as subt
UNION ALL
SELECT MAX(datetime) as datetime, 'max' AS TYPE FROM accesslogs WHERE email='user1#domain.com'
EDIT: Sorry but I realised that this is more what you are trying to do (this is t-sql code but should work)
SELECT a.email, a.count, b.datetime FROM (
SELECT COUNT(result) as count, email FROM (SELECT result, email FROM
accesslogs AND result=0) as subt
GROUP BY email) a
JOIN (
SELECT MAX(datetime) as datetime , email FROM accesslogs GROUP BY email) b
on a.email = b.email
WHERE a.email='user1#domain.com'
AND a.datetime >'2012-12-17'

Answer 4

Take a look at MySQLs GROUP BY and HAVING. See if this works for you:
Any email:
SELECT email, COUNT(resultSet) as loginAttempts,
COUNT(resultSet) - SUM(resultSet) as failedAttempts
FROM accesslogs
GROUP BY email;
Specific email:
SELECT COUNT(result) as count, MAX(logDate) FROM accesslogs
GROUP BY email
HAVING email='user1#example.com';