Split multiple count using in mysql with same table - mysql

Question

I have a query in below format:
SELECT ETM.etm_Taxonomy, COUNT( PE.pp_profileID ) AS total_counts
FROM expertise_taxonomymaster AS ETM
LEFT JOIN expertise_taxonomy AS ET ON ETM.etm_ID = ET.`et_Taxonomy`
LEFT JOIN expertise AS E ON E.et_Taxonomy = ET.`et_ID`
LEFT JOIN profile_expertise AS PE ON PE.pp_expertiseID = E.et_ID
WHERE PE.pp_profileID IN (
SELECT PJ.pj_profileID
FROM jobtitle_taxonomymaster AS JTM
LEFT JOIN jobtitle_taxonomy AS JT ON JTM.jtm_ID = JT.`jt_Taxonomy`
LEFT JOIN jobtitle AS J ON J.jt_taxonomy = JT.`jt_ID`
LEFT JOIN profile_jobtitle AS PJ ON PJ.pj_jobtitleID = J.jt_ID
WHERE JTM.jtm_Taxonomy = 'Associate'
OR JTM.jtm_Taxonomy = 'Partner'
)
AND et_lawfirmID in (195,196)
GROUP BY etm_Taxonomy
And I have results as follows:
etm_Taxonomy total_counts
Advertising 18
Antitrust 47
Banking 258
But I need below results, Count should be split based on the JTM.ttm_Taxonomy field
etm_Taxonomy Patners195 Partners196 Associates195 Associates196
Advertising 18 18 18 18
Antitrust 47 47 47 47
Banking 258 258 258 258

Answer 1

Try this way:
SELECT ETM.etm_Taxonomy,
SUM (CASE WHEN PJ_TAX.jtm_Taxonomy = 'Associate' THEN 1 ELSE 0 END) AS Associates,
SUM (CASE WHEN PJ_TAX.jtm_Taxonomy = 'Partner' THEN 1 ELSE 0 END) AS Partners,
SUM (CASE WHEN PJ_TAX.jtm_Taxonomy = 'Consultant' THEN 1 ELSE 0 END) AS Consultants,
SUM (CASE WHEN PJ_TAX.jtm_Taxonomy = 'Counsel' THEN 1 ELSE 0 END) AS Counsels,
COUNT(PE.pp_profileID ) AS total_counts
FROM expertise_taxonomymaster AS ETM
LEFT JOIN expertise_taxonomy AS ET ON ETM.etm_ID = ET.`et_Taxonomy`
LEFT JOIN expertise AS E ON E.et_Taxonomy = ET.`et_ID`
LEFT JOIN profile_expertise AS PE ON PE.pp_expertiseID = E.et_ID
INNER JOIN
(
SELECT DISTINCT PJ.pj_profileID,JTM.jtm_Taxonomy
FROM jobtitle_taxonomymaster AS JTM
LEFT JOIN jobtitle_taxonomy AS JT ON JTM.jtm_ID = JT.`jt_Taxonomy`
LEFT JOIN jobtitle AS J ON J.jt_taxonomy = JT.`jt_ID`
LEFT JOIN profile_jobtitle AS PJ ON PJ.pj_jobtitleID = J.jt_ID
WHERE JTM.jtm_Taxonomy = 'Associate'
OR JTM.jtm_Taxonomy = 'Partner'
OR JTM.jtm_Taxonomy = 'Consultant'
OR JTM.jtm_Taxonomy = 'Counsel'
) as PJ_TAX
ON PE.pp_profileID= PJ_TAX.pj_profileID
WHERE et_lawfirmID =195
GROUP BY etm_Taxonomy

Answer 2

First of all: Your left outer joins are no outer joins really, because in your WHERE clause you say you want certain ETs and PEs only.
Mainly you want to join everything, then see whether partner or associate and whether 195 or 196 and count accordingly. This can be done with a CASE construct inside COUNT. Only problem may be duplicates leading to incorrect counts. Im am not completely sure about your database structure. In case there can be duplicate profileIDs with your inner query, you need a derived query with distinct, rather than just joining everything directly. Check if this works for you:
select
etm.etm_taxonomy,
count(case when t.jtm_taxonomy = 'Partner' and et_lawfirmid = 195 then 1 end) as patners195,
count(case when t.jtm_taxonomy = 'Partner' and et_lawfirmid = 196 then 1 end) as patners196,
count(case when t.jtm_taxonomy = 'Associate' and et_lawfirmid = 195 then 1 end) as associates195,
count(case when t.jtm_taxonomy = 'Associate' and et_lawfirmid = 196 then 1 end) as associates196
from expertise_taxonomymaster as etm
join expertise_taxonomy as et on etm.etm_id = et.et_taxonomy
join expertise as e on e.et_taxonomy = et.et_id
join profile_expertise as pe on pe.pp_expertiseid = e.et_id
join
(
select distinct pj.pj_profileid, jtm.jtm_taxonomy
from jobtitle_taxonomymaster as jtm
join jobtitle_taxonomy as jt on jtm.jtm_id = jt.jt_taxonomy
join jobtitle as j on j.jt_taxonomy = jt.jt_id
join profile_jobtitle as pj on pj.pj_jobtitleid = j.jt_id
where jtm.jtm_taxonomy in ('Associate', 'Partner')
) as t on t.pj_profileid = pe.pp_profileid
where et.et_lawfirmid in (195,196);
group by etm.etm_taxonomy;