I have three tables
t1
CustId Name
1 XYZ
2 PQR
t2
CustId Income
1 100
1 200
2 50
2 100
t3
CustId Expense
1 50
1 70
2 30
2 40
I need to run a query where I get the below result
CustId Total Income Total Expense
1 300 120
2 150 70
I have tried the normal SUM and Group By but the result is very different from the expected...
The Query I attempted was
SELECT t1.custid, SUM(t2.Income), SUM(t3.Expense) FROM t1
LEFT JOIN t2 ON t1.custId = t2.CustId
LEFT JOIN t3 ON t1.CustId = t3.CustId
GROUP BY t1.CustId
Any help you would appreciated....
Try below query.
SELECT t1.CustID, IFNULL(tbl1.Income,0) AS 'TotalIncome', IFNULL(tbl2.Expenses,0) AS 'TotalExpenses'
FROM t1
LEFT JOIN (SELECT t2.CustID,SUM(Income) AS 'Income' FROM t2 GROUP BY t2.CustID) tbl1
ON t1.CustID = tbl1.CustID
LEFT JOIN (SELECT t3.CustID,SUM(Expenses) AS 'Expenses' FROM t3 GROUP BY t3.CustID) tbl2
ON t1.CustID = tbl2.CustID;
SQL Fiddle: http://sqlfiddle.com/#!9/ad05d/8
Try doing inner join all three tables and then grouping the result by customer id like:
SELECT t1.custId, SUM(t2.Income), SUM(t3.expense)
FROM t1 INNER JOIN t2
ON t1.custId = t2.custId
INNER JOIN t3
ON t2.custId = t3.custId
GROUP BY t1.custId
You can use the following query to achieve what you want
SELECT t1.custid, ti.Income, te.expense FROM t1 LEFT JOIN (select t2.custId, sum(t2.Income) as income from t2 group by t2.custId) as ti ON t1.custId = ti.CustId LEFT JOIN (select t3.custId, sum(t3.Expense) as expense from t3 group by t3.custId) as te ON t1.CustId = te.CustId
As far as why your previous query did not worked. I can give the following explanation.
In SQL when ever you do a join, the way database internally makes a cartesian product of all the entries and depending on the where clause the data is returned. So when you did
SELECT t1.custid, SUM(t2.Income), SUM(t3.Expense) FROM t1 LEFT JOIN t2 ON t1.custId = t2.CustId
You got 4 rows, where customerId is repeated in the rows, now when you join with t3 table by applying the equal condition on customerId, database would be able to match customerID in two records and hence you get 8 rows. That is why your query was not working
Related
Thanks for assisting with the previous query (SQL Query that selects a column in table 1 and uses that to select sum in table 2) of SUM from 2 tables, I now have a additional Condition for 1 of the tables. I would like to add WHERE Group1 = 1 AND IN/OUT = 'OUT'
I have 3 tables,
Names ,Groups
Names ,Payments
Names ,Payments and IN/OUT
I want to only SUM the OUT Payments in Table 3, I am getting total payments only So FAR is have:
SELECT t1.name1, SUM(t2.sale2),SUM(t3.sale3)
FROM table1 t1 JOIN table2 t2 ON t1.name1 = t2.name2
JOIN table3 t3 ON t1.name1 = t3.name3
WHERE group1 = 1
GROUP BY t1.name1
i would also like to add a zero if there is no data to sum instead of removing the whole record, Currently if a name has no payments in Table 3 but has payments in table 2 it deletes the record.
Please check the query below =>
To Get OutPayment group by Name
SELECT t1.Names,SUM(t3.Payments) As OutPayment
FROM TABLE3 as t3
INNER JOIN TABLE1 as t1 ON t1.Names = t3.Names
INNER JOIN TABLE2 as t2 ON t1.Names = t2.Names
WHERE t1.GroupID = 1 AND t3.INOROUT=2 --INOROUT =2 is OUT and 1 is IN
GROUP BY t1.Names;
To Get TotalOutPayment
SELECT SUM(t3.Payments) As TotalOutPayment
FROM TABLE3 as t3
INNER JOIN TABLE1 as t1 ON t1.Names = t3.Names
INNER JOIN TABLE2 as t2 ON t1.Names = t2.Names
WHERE t1.GroupID = 1 AND t3.INOROUT=2; --INOROUT =2 is OUT and 1 is IN
Note: Code is in DBFiddle too Check the Demo Query Link
First of all, I'm an amateur on SQL. Here it is the example. From this three tables I would like to know how is called the teacher who makes more money with the classes:
Table1:
LessonName TeacherID
Maths 3
Biology 2
Biology 1
Geology 1
Table2:
Lesson PricePerClass
Maths 200
Biology 100
Geology 150
Table3:
IDTeacher TeacherName
1 Mike
2 John
3 Lauren
My main problem is that I don't know how to deal with the repeated values from the first table when I'm doing the triple join.
So far "I've made" this:
select IDTeacher, PricePerClass
from Table1 as T1
inner join Table2 as T2 on t1.LessonName = t2.Lesson
inner join Table3 as T3 on t1.TeacherId = t3.idTeacher
...
And I don't know how to keep going. I will have to group the t1.LessonName but every time I try to do it I get syntax errors. As you can see I'm pretty lost.
EDIT: My expected result would be something like:
IDTeacher TotalRevenue
1 250
Thanks a lot.
join the tables, group by teacher to aggregate and get the top row after you sort by the total descending:
select t3.IDTeacher, sum(t2.PricePerClass) TotalRevenue
from Table3 t3
inner join Table1 as t1 on t1.TeacherId = t3.IDTeacher
inner join Table2 as t2 on t2.Lesson = t1.LessonName
group by t3.IDTeacher
order by TotalRevenue desc limit 1
Note that this query does not return ties, if any.
SELECT t3.IDTeacher, t3.TeacherName, sum(t2.PricePerClass) from table1 t1
inner join table3 t3 on t1.TeacherID = t3.IDTeacher
inner join table2 t2 on t1.Lessonname = t2.Lesson
group by t3.TeacherName
order by sum(t2.PricePerClass) desc limit 1;
I would like to left join three tables in one result and when I'm doing it like that: http://sqlfiddle.com/#!9/546c24/2 my result is wrong as you see.
I want COUNT(Test2.id) to be 2 and SUM(Test3.positive) to be 3 and not both 6.
That's my problem. I hope it's understandable.
You are getting a Cartesian product for each test1.id. You need to aggregate before the JOINs:
SELECT t1.id,Test1.name, t2.cnt_2,
t3.sum_pos, t3.sum_neg
FROM Test1 t1 LEFT JOIN
(SELECT ID_Test1, COUNT(*) as cnt_2
FROM Test2
GROUP BY ID_Test1
) t2
ON t1.id = t2.ID_Test1 LEFT JOIN
(SELECT ID_Test1, SUM(positive) as sum_pos, SUM(negative) as sum_neg
FROM Test3
GROUP BY ID_Test1
) t3
ON t1.id = t3.ID_Test1
GROUP BY t1.id;
Here is the SQL Fiddle.
I have 2 tables
table 1
id product
1 P1
2 P2
table 2
id amount product_t1
1 100 P1
2 200 P1
3 300 P2
4 400 P1
5 500 P2
I want my output to be:
product totalAmount(sum of amount)
P1 700
P2 800
EDIT: Here is my query so far
SELECT T1.product, SUM(T2.amount)
FROM table1 T1
INNER JOIN table2 T2
ON T1.product = T2.product_t1
Thanks!
you should use group by
SELECT T1.product, SUM(T2.amount)
FROM table1 T1
INNER JOIN table2 T2
ON T1.product = T2.product_t1
GROUP BY product
Since you're not using foreign keys you don't even need the table 1 for the desired result.
SELECT
product_t1 AS product,
SUM(amount) AS totalAmount
FROM table2
GROUP BY product_t1
What you're missing is the GROUP BY statement in order to get a separate row for each individual product
SELECT T1.product, SUM(T2.amount)
FROM table1 T1
INNER JOIN table2 T2
ON T1.product = T2.product_t1
GROUP BY product T1.product
Use the GROUP BY tag . Group by helps to group your result via value of product
Try to play with GROUP BY and AS
SELECT product_t1 as product, SUM(amount) AS totalAmount FROM table2
GROUP BY product
https://dev.mysql.com/doc/refman/5.7/en/group-by-modifiers.html
OR add to your code group by
SELECT T1.product, SUM(T2.amount)
FROM table1 T1
INNER JOIN table2 T2 ONT1.product = T2.product_t1
Gruop by T1.product
I have the following tables structure:
table_1
id title
------------
155 item1
156 item2
157 item3
table_2
id model
------------
155 100
156 100
157 200
table_3
id cid
------------
155 5
156 5
157 5
I want to group my results by model (from table_2) and make sure it returns the highest id (order by id descending).
I have tried the following, but the order by clause doesn't seem to work:
SELECT a.id, b.model FROM table_1 as a
INNER JOIN table_2 as b on b.id = a.id
INNER JOIN table_3 as c on c.id = a.id
WHERE c.cid = 5
GROUP BY b.model
ORDER BY a.id desc
What am I doing wrong?
SELECT max(a.id), b.model FROM table_1 as a
INNER JOIN table_2 as b on b.id = a.id
INNER JOIN table_3 as c on c.id = a.id
WHERE c.cid = 5
GROUP BY b.model
ORDER BY max(a.id) desc
Demo here: http://sqlfiddle.com/#!9/afb0b/2
The reason this works while your initial attempt did not, is that any field not present in the GROUP BY clause, or not used in an aggregate function (such as MAX), will have an indeterminate value (ie, the mysql engine makes no guarantees as to which value from the group you will get).
MySQL GROUP BY Handling
The server is free to choose any value from each group, so unless they are the same, the values chosen are indeterminate.
In fact, MySQL is one of the few (only?) sql databases that will let you put a non aggregated, non grouped field in the select clause without erroring.
You can do as
select
t1.id,
t2.model
from table_1 t1 join table_3 t3 on t3.id = t1.id
join (
select max(id) as id , model from table_2 group by model
)t2 on t1.id=t2.id
where t3.cid = 5;