PDO MySQL insert multiple rows using select - mysql

Question

I have a table for storing people following others and another one for storing who has a certain book.
This is what I can do:
List users who follow $userid
$bookid = '000016';
$userid = '0000000000000156';
try {
$stmt = $conn->prepare("SELECT FOLLOW.USER_ID FROM FOLLOW WHERE FOLLOW.FOLLOW_ID = ?");
$stmt -> execute(array($userid));
while($row = $stmt->fetchAll(PDO::FETCH_ASSOC)) {
$output[] = $row;
$response["success"] = 1;
}
} catch(PDOException $e) {
echo 'ERROR: ' . $e->getMessage();
$response["success"] = 0;
}
List users who has $bookid
try {
$stmt = $conn->prepare("SELECT USERS_BOOKS.USERID FROM USERS_BOOKS WHERE USERS_BOOKS.BOOKID = ?");
$stmt -> execute(array($bookid));
while($row = $stmt->fetchAll(PDO::FETCH_ASSOC)) {
$output2[] = $row;
$response["success"] = 1;
}
} catch(PDOException $e) {
echo 'ERROR: ' . $e->getMessage();
$response["success"] = 0;
}
Now I want to insert those into a new table who follow $userid and has $bookid. This is what I tried with different versions:
try {
$stmt = $conn->prepare("INSERT INTO NOTI_COMPLETE2 (USERID_OWNER, USERID_COMPLETER, BOOKID)
SELECT FOLLOW.USERID FROM FOLLOW
LEFT JOIN USERS_BOOKS ON USERS_BOOKS.USERID = FOLLOW.USERID
WHERE FOLLOW.FOLLOW_ID = ? AND USERS_BOOKS.BOOKID = ?, ?, ?");
$query_params = array($userid, $bookid, $userid, $bookid);
$stmt->execute($query_params);
$response["success"] = 1;
} catch(PDOException $e) {
echo 'ERROR: ' . $e->getMessage();
}
So the result should look like this
ID, USERID_OWNER, USERID_COMPLETER, BOOKID
01, 000000000001, 0000000000000156, 000016
01, 000000000011, 0000000000000156, 000016
01, 000000000078, 0000000000000156, 000016
01, 000000000105, 0000000000000156, 000016
Meaning the table includes those USERID_OWNERs who follow USERID_COMPLETER and have BOOKID.
This throws an error (that's irrelevant I guess, because who knows how to do this, sees the problem).

Answer 1

You missed VALUES ('','','') and it should have exactly 3 columns fetched from your SELECT statement,
As I am not sure about USERID_COMPLETER. You have to place the exact 'table-name'.'column-name' there
INSERT INTO NOTI_COMPLETE2 (`USERID_OWNER`, `USERID_COMPLETER`, `BOOKID`)
VALUES ( SELECT FOLLOW.USERID, FOLLOW.FOLLOW_ID, USERS_BOOKS.BOOKID FROM FOLLOW
LEFT JOIN USERS_BOOKS ON USERS_BOOKS.USERID = FOLLOW.USERID
WHERE FOLLOW.FOLLOW_ID = ? AND USERS_BOOKS.BOOKID = ?);

Answer 2

try {
$stmt = $conn->prepare("INSERT INTO NOTI_COMPLETE2 (USERID_OWNER, USERID_COMPLETER, BOOKID)
SELECT FOLLOW.USER_ID, ?, ?, ? FROM FOLLOW
LEFT JOIN USERS_BOOKS ON USERS_BOOKS.USERID = FOLLOW.USER_ID
WHERE FOLLOW.FOLLOW_ID = ? AND USERS_BOOKS.BOOKID = ?");
$query_params = array($userid, $bookid, $userid, $bookid);
$stmt->execute($query_params);
$response["success"] = 1;
} catch(PDOException $e) {
echo 'ERROR: ' . $e->getMessage();
}