I tried to create one function, ie if username exist, will return random number and character as a single string, but I tried below code, throwing syntax error like below, can u help to find the issue, I know that having issue in declaring string and returning string, but unable to find the issue. Thanks to the replies in advance
DELIMITER //
create function verifyEmail(userName varchar(25))
RETURNS TEXT
BEGIN
if EXISTS(select * from userdetails where name = userName)
then
SELECT #randomPass := select concat( char(round(rand()*36)+1), char(round(rand()*36)+1), char(round(rand()*36)+1));
return #randomPass;
else
return "not_exist";
end if;
end //
DELIMITER //
#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'select concat( char(round(rand()*36)+1), char(round(rand()*36)+1), char(round(ra' at line 6
You are missing a closing ) on this line:
SELECT #randomPass := select concat( char(round(rand()*36)+1), char(round(rand()*36)+1), char(round(rand()*36)+1);
should be
SELECT #randomPass := select concat( char(round(rand()*36)+1), char(round(rand()*36)+1), char(round(rand()*36)+1));
Hooray, finally found answers.. This below code will help to solve the solution
DELIMITER //
create function verifyEmail(userName varchar(25))
RETURNS TEXT
BEGIN
DECLARE randomPass VARCHAR(8);
if EXISTS(select id from userdetails where name = userName)
THEN
SET randomPass = concat( char(rand()*25+65),char(rand()*25+65),char(rand()*25+65),char(rand()*25+65),char(rand()*25+65),char(rand()*25+65),char(rand()*25+65),char(rand()*25+65));
return randomPass;
else
return "not_exist";
end if;
end //
DELIMITER //
Related
I'm fairly new to MySQL but I'd like to create a function to validate a JSON objects that are stored in my database tables.
I looked up information on creating a function, but must be missing something as I can't seem to get it to work. It doesn't seem like it would be overly complicated but perhaps I'm not using the appropriate syntax.
Here is my code:
DELIMITER //
CREATE FUNCTION CHECKJSON( DB_NAME varchar(255), TABLE_NAME varchar(255), JSON_COLUMN varchar(255))
RETURNS varchar(300)
BEGIN
DECLARE notNullCount int;
DECLARE validJSONCount int;
DECLARE result varchar(300);
SET notNullCount = (SELECT count(*) FROM DB_NAME.TABLE_NAME WHERE JSON_COLUMN IS NOT NULL);
set validJSONCount = (SELECT count(*) FROM DB_NAME.TABLE_NAME WHERE JSON_VALID(JSON_COLUMN) > 0);
CASE
WHEN (validJSONCount = notNullCount) THEN
SET result = CONCAT('VALID JSON COUNT: ', validJSONCount)
ELSE
SET result = CONCAT('INVALID JSON COUNT: ', (notNullCount - validJSONCount))
END;
RETURN result;
END //
DELIMITER ;
When I try to run this code, I get the following error message:
"Error Code: 1064. You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'ELSE SET result = CONCAT('INVALID JSON COUNT: ', (notNullCount - validJSONC' at line 14"
Any thoughts on how I might improve this code? Thanks!
Since MySQL 5.7 you have a pretty and simple function for this:
JSON_VALID(value)
Returns 0 or 1 to indicate whether a value is valid JSON. Returns NULL if the argument is NULL.
https://dev.mysql.com/doc/refman/5.7/en/json-attribute-functions.html#function_json-valid
You're missing a couple of ; and to end the case it should be END CASE.
DELIMITER //
CREATE FUNCTION CHECKJSON( DB_NAME varchar(255), TABLE_NAME varchar(255), JSON_COLUMN varchar(255))
RETURNS varchar(300)
BEGIN
DECLARE notNullCount int;
DECLARE validJSONCount int;
DECLARE result varchar(300);
SET notNullCount = (SELECT count(*) FROM DB_NAME.TABLE_NAME WHERE JSON_COLUMN IS NOT NULL);
set validJSONCount = (SELECT count(*) FROM DB_NAME.TABLE_NAME WHERE JSON_VALID(JSON_COLUMN) > 0);
CASE
WHEN (validJSONCount = notNullCount) THEN
SET result = CONCAT('VALID JSON COUNT: ', validJSONCount) ;
ELSE
SET result = CONCAT('INVALID JSON COUNT: ', (notNullCount - validJSONCount)) ;
END CASE;
RETURN result;
END //
DELIMITER ;
I am trying to insert a new record into my database using SQL, but it keeps telling me that I have a syntax error in the from clause.
I don't see the error.
Here is the code:
procedure TForm1.BitBtn7Click(Sender: TObject);
var
sCategoryName :string;
begin
sCategoryName := InputBox('Category Name', 'Please enter your category name that you would like to add','');
with dmRecords do
begin
qryRecords.Active := False;
qryRecords.SQL.Add('INSERT INTO [Category of Income]([Category Name])');
qryRecords.SQL.Add('VALUES ' + '(' + QuotedStr(sCategoryName) + ')');
qryRecords.ExecSQL;
qryRecords.SQL.Add('SELECT * FROM [Category of Income] ORDER BY [Category ID]');
qryRecords.Active := True;
end;
end;
You haven't cleared the SQL from the previous statement. When you open the query, SQL has three lines of text.
Add qryRecords.SQL.Clear before adding the SELECT statement.
I want to create a function that will return an integer variable (or boolean) after check if there are any row in table RESERVATION have an RESERVATION_ID that equal to the reser_id I give to it. But my code seem wrong at the IF statement.
This is my query code:
CREATE OR REPLACE Function fcn_check (reser_id integer) RETURNS integer AS $$
BEGIN
IF (EXISTS (SELECT * FROM TICKET_TICKET WHERE reservation_id = reser_id) )
THEN SELECT 1 AS result;
ELSE SELECT 0 AS result;
END IF;
END
$$ LANGUAGE SQL;
The error messages is:
ERROR: syntax error at or near "IF"
LINE 2: IF (SELECT * FROM TICKET_TICKET WHERE reservation_id = rese...
^
********** Error **********
ERROR: syntax error at or near "IF"
SQL state: 42601
Character: 76
Im a newbie at pgsql and look like I didnt try hard enough to slove this, but please help me.
Many Thanks!
$$ LANGUAGE SQL;
You seem to be writing PL/PgSQL, but you've declared it as SQL.
Use LANGUAGE plpgsql.
I have what feels like a simple question, but can't seem to get it right. I'm just trying to execute a regular IF ... THEN ... logic, but can't seem to get it right:
set #var:=2;
if #var=1 THEN select 'hello';
I get:
ERROR 1064 (42000):
You have an error in your SQL syntax; check the
manual that corresponds to your MySQL server version for the right
syntax to use near 'if #var=1 THEN select 'hello'' at line 1
What am I missing?
You can use CASE instead.
SET #var:=2;
SELECT CASE WHEN #var=1 THEN 'hello' ELSE 'no hello' END;
--prints 'no hello'
SET #var:=2;
SELECT CASE WHEN #var:=1 THEN 'hello' ELSE 'no hello' END;
--prints 'hello'
I hope the idea is clear with above examples.
Edit: to address OP's additional concerns, You can incorporate selects in case statements, but you should enclose in brackets. For eg.
SET #var:=2;
SELECT CASE WHEN #var:=1 THEN (select 'hello') ELSE (select 'no hello') END;
One thing to notice is that it should return back only one value (from one row and a column)
You can, but only inside of functions, procedures and triggers like so:
DELIMITER //
DROP PROCEDURE IF EXISTS anyname//
CREATE PROCEDURE anyname()
BEGIN
IF #var1 = 1 THEN
SELECT 'hello';
END IF;
END//
SET #var1 := 1;
CALL anyname()//
I am trying to make this If Statement work, but I can't seem to make it do what I want. If I do a select #result, It'll give me the value 0, then why doesn't the IF statement work?
SET #message = '((sometihng here))';
select LEFT(#message, 1) into #firstChar;
select STRCMP(#firstChar,'(') into #result;
IF (#result = 0) THEN
SET #message = 'true';
//more selects and cals here;
END IF;
select #message;
I should get true, but I don't it shows me an error:
SQL query: IF( #result =0 ) THEN SET #message = 'true';
MySQL said:
1064 - You have an error in your SQL syntax; check the manual that
corresponds to your MySQL server version for the right syntax to use
near 'IF (#result = 0) THEN SET #message = 'true'' at line 1
try use function http://dev.mysql.com/doc/refman/5.0/en/control-flow-functions.html#function_if
SELECT IF(#result = 0, 'true', '((something here))') AS message
As Max Mara pointed out, that's a good work aroud. The reason the IF wasn't working is not because the syntax is incorrect, but because flow control functions like IF ... THEN are only valid inside of stored procedures or functions, All this thanks to #TehShrike
The IF .. THEN .. ELSE syntax in MySQL is only available for procedural code (stored precudures, functions, triggers..), but not for SELECT statements.
IF ELSE USED IN STORED PROCEDURE EXAMPLE BELOW
DELIMITER //
CREATE PROCEDURE NAME(IN Number INT)
BEGIN
IF roll= 1
THEN SELECT * FROM table1 WHERE id = roll;
ELSE
SELECT * FROM table2 WHERE id = 2;
END IF;
END //
DELIMITER ;