mysql | calculate number of days in date range for selected Month - mysql

i have a query. query is all fine. just 1 logical thing remaining taking out the total number of days out of a date range for the selected month..
e-g i have to columns
1 ) project_assign_date //considering as start date
2 ) project_revoke_date // considering as end date
This is my total Query.
SELECT
E.employee_id AS EmployeeID,
ET.employment_id AS EmploymentID,
E.employee_code AS EmployeeCode,
EP.project_id AS ProjectID,
MLP.project_title AS ProjectTitle,
S.base_salary AS EmployeeBaseSalary,
IFNULL(EP.percentCharged, 0) AS PercentCharged,
A.allowance_amount AS EmployeeAllowance,
SUM(IFNULL(A.allowance_amount,0)) + IFNULL(S.base_salary, 0) AS MonthlySalary ,
project_assign_date AS ProjectAssignDate
FROM
(`employee_project` EP)
INNER JOIN `employment` ET
ON `ET`.`employment_id` = `EP`.`employment_id`
AND ET.trashed = 0
AND ET.current = 1
INNER JOIN `employee` E
ON `E`.`employee_id` = `ET`.`employee_id`
AND E.trashed = 0
AND E.enrolled = 1
INNER JOIN `ml_projects` MLP
ON `MLP`.`project_id` = `EP`.`project_id`
AND MLP.trashed = 0
INNER JOIN `salary` S
ON `S`.`employement_id` = `ET`.`employment_id`
AND S.trashed = 0
AND S.status = 2
LEFT JOIN `allowance` A
ON `A`.`employment_id` = `ET`.`employment_id`
AND A.trashed = 0
AND A.status = 2
LEFT JOIN `expense_claims` EC ON EC.employment_id = ET.employment_id AND EC.status = 2
WHERE `EP`.`trashed` = 0
AND EP.current = 1
AND CURRENT_DATE() >= MONTH(project_assign_date)
GROUP BY
E.employee_id,ET.employment_id,EP.project_id
im getting the result fine as showing below.
Array
(
[0] => stdClass Object
(
[EmployeeID] => 1
[EmploymentID] => 15
[EmployeeCode] => E-01
[EmployeeName] => Yasir Khan
[ProjectID] => 1
[ProjectTitle] => Human Resource Management
[ProjectAbbreviation] => HRM
[EmployeeBaseSalary] => 45000.00
[PercentCharged] => 60
[MonthlySalary] => 45000.00
)
[1] => stdClass Object
(
[EmployeeID] => 1
[EmploymentID] => 15
[EmployeeCode] => E-01
[EmployeeName] => Yasir Khan
[ProjectID] => 2
[ProjectTitle] => telenor
[ProjectAbbreviation] => ASD
[EmployeeBaseSalary] => 45000.00
[PercentCharged] => 40
[MonthlySalary] => 45000.00
)
[2] => stdClass Object
(
[EmployeeID] => 9
[EmploymentID] => 20
[EmployeeCode] => E-120
[EmployeeName] => Izhar Ali
[ProjectID] => 1
[ProjectTitle] => Human Resource Management
[ProjectAbbreviation] => HRM
[EmployeeBaseSalary] => 35000.00
[PercentCharged] => 50
[MonthlySalary] => 35000.00
)
[3] => stdClass Object
(
[EmployeeID] => 9
[EmploymentID] => 20
[EmployeeCode] => E-120
[EmployeeName] => Izhar Ali
[ProjectID] => 2
[ProjectTitle] => telenor
[ProjectAbbreviation] => ASD
[EmployeeBaseSalary] => 35000.00
[PercentCharged] => 50
[MonthlySalary] => 35000.00
)
[4] => stdClass Object
(
[EmployeeID] => 19
[EmploymentID] => 32
[EmployeeCode] => E-014
[EmployeeName] => Said Ullah
[ProjectID] => 1
[ProjectTitle] => Human Resource Management
[ProjectAbbreviation] => HRM
[EmployeeBaseSalary] => 20000.00
[PercentCharged] => 100
[MonthlySalary] => 54433.00
)
)
The Important Section starts where i need total number of days project has been assigned to certain employee..
If the whole month do get in the start and end date, then it would be 30 or 31 days but what if project has been assigned to employee in mid of month how would one can calculate total number of days then??

Related

Grouping MySQL results from query

I am trying to create a basic notification system. The function below works well, however I'd like to be able to group notifications for the same notification item into the same array item. So, any query result that has the same [item] and [item_id] would be grouped together and just update the count for that item group. So I guess adding a new array item count for that group? I have no idea how to approach this. Any help would be much appreciated.
Query Function:
function get_notifications($connect, $user_id) {
$query = "SELECT * FROM notifications WHERE for_id = {$user_id} AND seen = 0 ";
$result = mysqli_query($connect, $query) or die(mysql_error($connect));
while($row = mysqli_fetch_assoc($result)){
$notifs[] = $row;
}
return $notifs;
}
$notifs = get_notifications($connect, $_SESSION['user_id']);
Current Result:
Array
(
[0] => Array
(
[note_id] => 3
[for_id] => 20
[from_id] => 20
[item] => like_pp
[item_id] => 104
[seen] => 0
[date] => 2022-01-19 12:55:20
)
[1] => Array
(
[note_id] => 4
[for_id] => 20
[from_id] => 20
[item] => like_comment
[item_id] => 332
[seen] => 0
[date] => 0000-00-00 00:00:00
)
[2] => Array
(
[note_id] => 5
[for_id] => 20
[from_id] => 23
[item] => like_pp
[item_id] => 104
[seen] => 0
[date] => 0000-00-00 00:00:00
)
[3] => Array
(
[note_id] => 6
[for_id] => 20
[from_id] => 20
[item] => pp_like
[item_id] => 102
[seen] => 0
[date] => 2022-01-19 15:03:23
)
)
Desired Result: ([item] => like_pp and [item_id] => 104 were the same so combined and updated notification_count)
Array
(
[0] => Array
(
[note_id] => 3
[for_id] => 20
[from_id] => 20
[item] => like_pp
[item_id] => 104
[seen] => 0
[notification_count] => 2
[date] => 2022-01-19 12:55:20
)
[1] => Array
(
[note_id] => 4
[for_id] => 20
[from_id] => 20
[item] => like_comment
[item_id] => 332
[seen] => 0
[notification_count] => 1
[date] => 0000-00-00 00:00:00
)
[2] => Array
(
[note_id] => 6
[for_id] => 20
[from_id] => 20
[item] => pp_like
[item_id] => 102
[seen] => 0
[notification_count] => 1
[date] => 2022-01-19 15:03:23
)
)
I think what you need is a the query that groups by user_id (for who) and item_id (for what type of notif) and delivers the count of this group. Something like:
$query = "SELECT count(*) as notification_count, for_id, item_id FROM notifications WHERE for_id = {$user_id} AND seen = 0 group by for_id, item_id ";
Optionally, if you need in the output the name of the item, for displaying or other purposes, it can be also added:
$query = "SELECT count(*) as notification_count, for_id, item_id, item FROM notifications WHERE for_id = {$user_id} AND seen = 0 group by for_id, item_id, item ";
Use GROUP BY and aggregation functions.
SELECT MIN(note_id) AS note_id, MIN(for_id) AS for_id, MIN(from_id) AS from_id,
item, item_id, MIN(seen) AS seen, COUNT(*) AS notification_count, MIN(date) as date
FROM notifications
WHERE for_id = {$user_id} AND seen = 0
GROUP BY item, item_id

MySQL: show a row that not contains a specific value

I can't show in MySQL a specific row that not contains a value.
First of all this is my two tables:
And this is an array with the info of both tables:
Bills table:
[0] => Array
(
[id] => 1
[reference] => #001001
[seat_id] => 101
[client_id] => 10200
)
[1] => Array
(
[id] => 2
[reference] => #001002
[seat_id] => 102
[client_id] => 10400
)
[2] => Array
(
[id] => 3
[reference] => #001003
[seat_id] => 103
[client_id] => 10600
)
Accounting_seats table:
[0] => Array
(
[0] => Array
(
[id] => 1
[seat_id] => 101
[account_id] => taxes_qty
[value] => 0.99
[client_id] => 10200
)
[1] => Array
(
[id] => 2
[seat_id] => 101
[account_id] => tax_base
[value] => 4
[client_id] => 10200
)
[2] => Array
(
[id] => 3
[seat_id] => 101
[account_id] => total
[value] => 4.99
[client_id] => 10200
)
)
[1] => Array
(
[0] => Array
(
[id] => 4
[seat_id] => 102
[account_id] => taxes_qty
[value] => 2.00
[client_id] => 10400
)
[1] => Array
(
[id] => 5
[seat_id] => 102
[account_id] => tax_base
[value] => 8.00
[client_id] => 10400
)
[2] => Array
(
[id] => 6
[seat_id] => 102
[account_id] => shipping_cost
[value] => 2.00
[client_id] => 10400
)
[3] => Array
(
[id] => 7
[seat_id] => 102
[account_id] => total
[value] => 12.00
[client_id] => 10400
)
)
[2] => Array
(
[0] => Array
(
[id] => 8
[seat_id] => 103
[account_id] => taxes_qty
[value] => 3
[client_id] => 10600
)
[1] => Array
(
[id] => 9
[seat_id] => 103
[account_id] => tax_base
[value] => 7
[client_id] => 10600
)
[2] => Array
(
[id] => 10
[seat_id] => 103
[account_id] => shipping_cost
[value] => 3.99
[client_id] => 10600
)
[3] => Array
(
[id] => 11
[seat_id] => 103
[account_id] => total
[value] => 13.99
[client_id] => 10600
)
)
The problem is that I cannot show the bill where the accounting_seats not contain the value "shipping_cost". Only show the 2 bills with shipping_cost or all bills, but I need the bill without shiipping_cost value.
SELECT reference, seat_id FROM bills WHERE seat_id IN(101,102,103) AND seat_id IN (SELECT seat_id FROM accounting_seats WHERE account != 'shipping_cost');
Tons of thanks for any help!
I would reommend not exists:
select reference, seat_id
from bills b
where
b.seat_id in(101,102,103)
and not exists (
select 1
from accounting_seats acs
where acs.account = 'shipping_cost' and acs.seat_id = b.seat_id
)
As compared to not in, not exists usually scales better when the size of the underlying table increases (here, accounting_seats): the above query woulud take advantage of an index on accounting_seats(account, seat_id). Another upside of this approach is that not exists is safe as regard to null values in seat_id, while not in isn't.
Try this:
SELECT reference, seat_id
FROM bills
WHERE seat_id IN(101,102,103)
AND seat_id NOT IN (SELECT seat_id FROM accounting_seats WHERE account = 'shipping_cost');

How to return array while using GROUP BY

Right now, I have this query:
SELECT COUNT(*) AS Count, SUM(Ask) AS Ask, SUM(Cost) AS Cost, Provider, Factura FROM store_items
WHERE (
Provider NOT IN(SELECT Provider FROM store_provider_invoices)
AND Factura NOT IN(SELECT Factura FROM store_provider_invoices)
)
OR Factura NOT IN(SELECT Factura FROM store_provider_invoices)
GROUP BY Provider, Factura
This is working great, and returns the following array:
Array (
[0] => Array (
[Count] => 1
[ID] => 13
[Ask] => 20.00
[Cost] => 10.00
[Provider] => 5
[Factura] => 8
)
[1] => Array (
[Count] => 1
[ID] => 18
[Ask] => 125.01
[Cost] => 110.01
[Provider] => 5
[Factura] => 34
)
[3] => Array (
[Count] => 3
[ID] => 14
[Ask] => 210.00
[Cost] => 150.00
[Provider] => 6
[Factura] => 5
)
)
What I would like to do is to also return all the ID's that match the query from the store_items table, like:
Array (
[0] => Array (
[ID] => Array (
[0] => 101
)
[Count] => 1
[Ask] => 20.00
[Cost] => 10.00
[Provider] => 5
[Factura] => 8
)
[1] => Array (
[ID] => Array (
[0] => 102
)
[Count] => 1
[Ask] => 125.01
[Cost] => 110.01
[Provider] => 5
[Factura] => 34
)
[3] => Array (
[ID] => Array (
[0] => 103
[1] => 104
[2] => 105
)
[Count] => 3
[Ask] => 210.00
[Cost] => 150.00
[Provider] => 6
[Factura] => 5
)
)
So, for instance, in the last array element above, instead of just returning a Count of 3, also return the ID's of each row that it counted.
You can't really get nested results, but you could use
GROUP_CONCAT(DISTINCT store_items.ID ORDER BY ID) AS siIDs
to get a comma-separated list of id values.
You can also modify the separator
http://dev.mysql.com/doc/refman/5.7/en/group-by-functions.html#function_group-concat

Optimizing an union SQL query

I've got a big query that all contain same types I need for a feed that I list in my app. Now the problem is that this query isn't very fast. I'm thinking that if I limit each individual union it might speed it up a bit but I'm not sure.
So basically my question is how could I optimize this query to execute faster?
SELECT DISTINCT
alert_id,
uniquekey,
type,
user_id,
date_added
FROM
(
( SELECT
r.alert_id,
r.alert_id AS uniquekey,
'reply' AS `type`,
r.user_id,
r.date_added
FROM
`reply` r
LEFT JOIN `alerts` a
ON r.alert_id = a.alert_content_id
WHERE
r.user_id = :id
AND a.hide = '0'
ORDER BY
date_added DESC )
UNION
( SELECT
r.alert_id,
r.alert_id AS uniquekey,
'replyfromfollowing' AS `type`,
r.user_id,
r.date_added
FROM
`reply` r
LEFT JOIN `alerts` a
ON r.alert_id = a.alert_content_id
WHERE
r.user_id IN( '$followingstring' )
AND a.hide = '0'
ORDER BY date_added DESC )
UNION
( SELECT
i.alert_id,
i.alert_id AS uniquekey,
'liked' AS `type`,
i.user_id,
i.date_added
FROM
`interactions` i
LEFT JOIN `alerts` a
ON i.alert_id = a.alert_content_id
WHERE
i.user_id = :id
AND a.hide = '0'
GROUP BY
alert_id
ORDER BY
date_added DESC )
UNION
( SELECT
i.alert_id,
i.alert_id AS uniquekey,
'likedfromfollowing' AS `type`,
i.user_id,
i.date_added
FROM
`interactions` i
LEFT JOIN `alerts` a
ON i.alert_id = a.alert_content_id
WHERE
i.user_id IN ( '$followingstring' )
AND a.hide = '0'
GROUP BY
alert_id
ORDER BY
date_added DESC )
UNION
( SELECT
alerts as alert_id,
alert_content_id AS uniquekey,
'following' AS `type`,
user_id,
date_added
FROM
alerts a
LEFT JOIN `alerts_content` ac
ON ac.id = a.alert_content_id
WHERE
a.user_id IN ( '$followingstring' )
AND ac.anoniem = '0'
AND a.hide = '0'
GROUP BY
alert_id
ORDER BY
date_added DESC )
) joined
GROUP BY
uniquekey
ORDER BY
date_added DESC
LIMIT
".(int)$start.",20"
table structures
Reply table Structure:
id
user_id
alert_id
description
reply_on_alert
reply_on_reply
date_added
Interaction table Structure:
id
alert_id
action_id
reply_id
user_id
date_added
Alerts table structure(Yes i know BIG mistake naming `id` : `alerts`):
alerts
title
alert_content_id
user_id
cat
lat
lon
state
hide
date_added
alerts_content table structure:
id
alert_id
description
img
results of query:
Array
(
[0] => Array
(
[alert_id] => 173404
[uniquekey] => 173404
[type] => reply
[user_id] => 2
[date_added] => 2015-06-01 16:34:16
)
[1] => Array
(
[alert_id] => 172174
[uniquekey] => 172174
[type] => replyfromfollowing
[user_id] => 1380
[date_added] => 2015-06-01 16:01:04
)
[2] => Array
(
[alert_id] => 171772
[uniquekey] => 171772
[type] => liked
[user_id] => 2
[date_added] => 2015-06-01 15:58:44
)
[3] => Array
(
[alert_id] => 149423
[uniquekey] => 149423
[type] => reply
[user_id] => 2
[date_added] => 2015-06-01 15:25:56
)
[4] => Array
(
[alert_id] => 164742
[uniquekey] => 164742
[type] => reply
[user_id] => 2
[date_added] => 2015-05-12 09:46:39
)
[5] => Array
(
[alert_id] => 163344
[uniquekey] => 163344
[type] => replyfromfollowing
[user_id] => 3
[date_added] => 2015-05-12 09:44:46
)
[6] => Array
(
[alert_id] => 164205
[uniquekey] => 164205
[type] => liked
[user_id] => 2
[date_added] => 2015-05-11 11:06:39
)
[7] => Array
(
[alert_id] => 160890
[uniquekey] => 160890
[type] => replyfromfollowing
[user_id] => 1380
[date_added] => 2015-05-08 14:29:34
)
[8] => Array
(
[alert_id] => 163002
[uniquekey] => 163002
[type] => replyfromfollowing
[user_id] => 1380
[date_added] => 2015-05-08 13:31:12
)
[9] => Array
(
[alert_id] => 159123
[uniquekey] => 159123
[type] => replyfromfollowing
[user_id] => 48
[date_added] => 2015-04-30 15:10:32
)
[10] => Array
(
[alert_id] => 150546
[uniquekey] => 150546
[type] => replyfromfollowing
[user_id] => 16
[date_added] => 2015-04-21 21:52:49
)
[11] => Array
(
[alert_id] => 149497
[uniquekey] => 149497
[type] => reply
[user_id] => 2
[date_added] => 2015-04-10 15:19:06
)
[12] => Array
(
[alert_id] => 141078
[uniquekey] => 141078
[type] => liked
[user_id] => 2
[date_added] => 2015-04-10 15:15:32
)
[13] => Array
(
[alert_id] => 125466
[uniquekey] => 125466
[type] => replyfromfollowing
[user_id] => 3
[date_added] => 2015-04-09 00:15:22
)
[14] => Array
(
[alert_id] => 134592
[uniquekey] => 134592
[type] => replyfromfollowing
[user_id] => 3
[date_added] => 2015-04-09 00:11:04
)
[15] => Array
(
[alert_id] => 124194
[uniquekey] => 124194
[type] => likedfromfollowing
[user_id] => 3
[date_added] => 2015-04-09 00:08:35
)
[16] => Array
(
[alert_id] => 128645
[uniquekey] => 128645
[type] => likedfromfollowing
[user_id] => 3
[date_added] => 2015-04-09 00:07:29
)
[17] => Array
(
[alert_id] => 144867
[uniquekey] => 144867
[type] => replyfromfollowing
[user_id] => 3
[date_added] => 2015-04-06 13:59:19
)
[18] => Array
(
[alert_id] => 133355
[uniquekey] => 133355
[type] => liked
[user_id] => 2
[date_added] => 2015-03-31 16:16:15
)
[19] => Array
(
[alert_id] => 141075
[uniquekey] => 141075
[type] => liked
[user_id] => 2
[date_added] => 2015-03-30 15:17:01
)
)
Some possibilities, in no particular order:
Optimization #1:
Use LIMIT in the subqueries, too. However, since you are using OFFSET, it may not be obvious how to do it.
Before the query, calculate $start+20 and put it into, say, $limit. Then use LIMIT $limit for the inner queries. No, don't use an OFFSET on them. This guarantees that you get enough rows from each query to satisfy the outer OFFSET $start LIMIT 20.
Optimization #2:
Restructure the tables so that you don't need to JOIN to another table (alerts) to find out whether to show the record. That is, having hide prevents a number of potential optimizations. Before advising further, we need to understand the need for LEFT. Are there rows in reply, etc, that are not in alerts? If not, get rid of the LEFT and look into searching alerts with theOFFSETandLIMIT`, then joining to the 4 other tables.
Optimization #3:
Restructure the data so that there is one core table, with alerts and the 4 other tables hanging off it. Be sure to have most (all?) of the fields needed for this query in this new table.
Optimization #4:
The current structure requires the full scan of each of the 4 tables before even thinking about OFFSET and LIMIT. This smells like "pagination"; is it? For optimizing "pagination", the goals are to avoid the table scan and OFFSET; instead remember where you "left off" so that the query can be
WHERE ... AND x < $left_off
ORDER by x DESC
LIMIT 20
This should make it possible to read only 20 rows, not the entire table(s). That would make the query much faster, especially for later pages. (A bigger OFFSET costs more time`)
I discuss pagination optimization in my blog.

i can't access the id column of my table

i am trying to access the id column of one of my table but i get "Undefined property" error but i can access the other columns with no problems,here is my code
in the controller i get all records as follows
$employees=Employee::all();
return View::make('admin.employee',compact('tittle','heading','employees'));
and i my view
#foreach($employees as $employee)
<tr class="success">
<td>{{$employee->first_name}}</td>
<td>{{$employee->last_name}}</td>
<td>{{$employee->phone}}</td>
<td>{{$employee->salary}}</td>
<td>{{$employee->created_at}}</td>
<td>Edit</td>
<td>Resign</td>
<td>View</td>
</tr>
#endforeach
How can i access the id column from my table?
when i print_r($employees);
Illuminate\Database\Eloquent\Collection Object ( [items:protected] => Array ( [0] => Employee Object ( [fillable:protected] => Array ( [0] => profile_photo_id [1] => first_name [2] => last_name [3] => gender [4] => phone [5] => address [6] => age [7] => salary ) [connection:protected] => [table:protected] => [primaryKey:protected] => id [perPage:protected] => 15 [incrementing] => 1 [timestamps] => 1 [attributes:protected] => Array ( [id] => 4 [profile_photo_id] => 4 [first_name] => Jason [last_name] => cbvc [gender] => Female [phone] => 2147483647 [address] => jhjhjh [age] => 12 [salary] => 5566556 [created_at] => 2014-12-20 11:29:41 [updated_at] => 2014-12-20 11:29:41 ) [original:protected] => Array ( [id] => 4 [profile_photo_id] => 4 [first_name] => Jason [last_name] => cbvc [gender] => Female [phone] => 2147483647 [address] => jhjhjh [age] => 12 [salary] => 5566556 [created_at] => 2014-12-20 11:29:41 [updated_at] => 2014-12-20 11:29:41 ) [relations:protected] => Array ( ) [hidden:protected] => Array ( ) [visible:protected] => Array ( ) [appends:protected] => Array ( ) [guarded:protected] => Array ( [0] => * ) [dates:protected] => Array ( ) [touches:protected] => Array ( ) [observables:protected] => Array ( ) [with:protected] => Array ( ) [morphClass:protected] => [exists] => 1 ) [1] => Employee Object ( [fillable:protected] => Array ( [0] => profile_photo_id [1] => first_name [2] => last_name [3] => gender [4] => phone [5] => address [6] => age [7] => salary ) [connection:protected] => [table:protected] => [primaryKey:protected] => id [perPage:protected] => 15 [incrementing] => 1 [timestamps] => 1 [attributes:protected] => Array ( [id] => 5 [profile_photo_id] => 5 [first_name] => gugu [last_name] => cbvc [gender] => Female [phone] => 2147483647 [address] => jhjhjh [age] => 12 [salary] => 5566556 [created_at] => 2014-12-20 11:40:44 [updated_at] => 2014-12-20 11:40:44 ) [original:protected] => Array ( [id] => 5 [profile_photo_id] => 5 [first_name] => gugu [last_name] => cbvc [gender] => Female [phone] => 2147483647 [address] => jhjhjh [age] => 12 [salary] => 5566556 [created_at] => 2014-12-20 11:40:44 [updated_at] => 2014-12-20 11:40:44 ) [relations:protected] => Array ( ) [hidden:protected] => Array ( ) [visible:protected] => Array ( ) [appends:protected] => Array ( ) [guarded:protected] => Array ( [0] => * ) [dates:protected] => Array ( ) [touches:protected] => Array ( ) [observables:protected] => Array ( ) [with:protected] => Array ( ) [morphClass:protected] => [exists] => 1 ) ) )
Give us your $employees object , edit question with
print_r($employees).
Also there may be a chance the $id is protected, in that case use.
$employee->getOriginal('id');