I want to SUM two columns from two different database and output the highest value.
trying to figure it out since last 1day but no luck. can anyone please help?
Table 1
mid points
1 20
2 10
1 10
1 30
3 10
Table 2
mid points
1 20
2 10
1 10
2 20
1 10
3 10
so the total should be
mid points
1 100
2 40
3 20
output that i want highest total mid is 1 = 100
Try this untested query:
select mid , sum(points) from (
select mid,points from table1
union all
select mid,points from table2
) as table3
group by mid
order by sum(points) DESC
limit 1
Related
I have a table like following
item_id link_id
1 10
1 20
2 100
2 40
2 10
3 10
3 30
4 10
4 20
4 30
I ran the query to find occurrence of each item_id
select `item_id`, count(`item_id`)
from `table`
group by `order_id`
which gave me the result
item_id count('item_id')
1 2
2 3
3 2
4 3
But I have to find out how many time did i had each value in result, something like this
count('item_id') Occurence
2 2
3 2
How should I update the query
Use two levels of aggregation:
select cnt, count(*), min(item_id), max(item_id)
from (select `item_id`, count(`item_id`) as cnt
from `table`
group by `order_id`
) i
group by cnt;
I also often add min(item_id), max(item_id) to such queries to get examples for each count.
Please help me with writing a query for the following condition. I have a table which I have listed below
ID Wt1 Wt1_Type Wt2 Wt2_Type Wt3 Wt3_Type Wt4 Wt4_Type
--------------------------------------------------------------
1 200 1 220 1 300 2 400 3
2 100 4 150 3 100 5 120 1
3 100 3 110 1 200 5 100 4
I want a query to sum all the the weights (wt1, wt2, wt3, wt4) grouped on the weight type (wt1_type, wt2_type, wt3_type, wt4_type).
The output should look like
Wt_type Total
1 650
2 300
3 650
4 200
5 300
Can someone please help me draft a mysql query to get this result ?
Thanks
You can try below - using union all and subquery
select Wt_Type,sum(Wt) as total from
(
select Wt1_Type as Wt_Type,Wt1 as Wt from tablename
union all
select Wt2_Type ,Wt2 from tablename
union all
select Wt3_Type ,Wt3 from tablename
union all
select Wt4_Type ,Wt4 from tablename
)A group by Wt_Type
Rather than giving the answer by #fa06, which should work for you, I am going to suggest using a better table design. Here is how you should be storing your data:
ID Type Wt
-------------
1 1 200
2 4 100
3 3 100
4 1 220
5 3 150
6 1 110
7 2 300
8 5 100
9 5 200
10 3 400
11 1 120
12 4 100
Note that there is a single column which stores the type and a single column for that type's weight. Now your expected output just requires a very simple query:
SELECT Type, SUM(Wt) AS Total
FROM yourTableUpdated
GROUP BY Type;
Databases are really good at performing operations across rows, much less so across columns.
Use this it should be work
select Wt_Type,sum(Wt) as total from ( select Wt1_Type as Wt_Type,Wt1 as Wt from tablename union all select Wt2_Type ,Wt2 from tablename union all select Wt3_Type ,Wt3 from tablename union all select Wt4_Type ,Wt4 from tablename )A group by Wt_Type
I have a database with a table called BOOKINGS containing the following values
main-id place-id start-date end-date
1 1 2018-8-1 2018-8-8
2 2 2018-6-6 2018-6-9
3 3 2018-5-5 2018-5-8
4 4 2018-4-4 2018-4-5
5 5 2018-3-3 2018-3-10
5 1 2018-1-1 2018-1-6
4 2 2018-2-1 2018-2-10
3 3 2018-3-1 2018-3-28
2 4 2018-4-1 2018-4-6
1 5 2018-5-1 2018-5-15
1 3 2018-6-1 2018-8-8
1 4 2018-7-1 2018-7-6
1 1 2018-8-1 2018-8-18
1 2 2018-9-1 2018-9-3
1 5 2018-10-1 2018-10-6
2 5 2018-11-1 2018-11-5
2 3 2018-12-1 2018-12-25
2 2 2018-2-2 2018-2-19
2 4 2018-4-4 2018-4-9
2 1 2018-5-5 2018-5-23
What I need to do is for each main-id I need to find the largest total number of days for every place-id. Basically, I need to determine where each main-id has spend the most time.
This information must then be put into a view, so unfortunately I can't use temporary tables.
The query that gets me the closest is
CREATE VIEW `MOSTTIME` (`main-id`,`place-id`,`total`) AS
SELECT `BOOKINGS`.`main-id`, `BOOKINGS`.`place-id`, SUM(DATEDIFF(`end-date`, `begin-date`)) AS `total`
FROM `BOOKINGS`
GROUP BY `BOOKINGS`.`main-id`,`RESERVATION`.`place-id`
Which yields:
main-id place-id total
1 1 24
1 2 18
1 5 5
2 1 2
2 2 20
2 4 9
3 1 68
3 2 24
3 3 30
4 1 5
4 2 10
4 4 1
5 1 19
5 2 4
5 5 7
What I need is then the max total for each distinct main-id:
main-id place-id total
1 1 24
2 2 20
3 1 68
4 2 10
5 1 19
I've dug through a large amount of similar posts that recommend things like self joins; however, due to the fact that I have to create the new field total using an aggregate function (SUM) and another function (DATEDIFF) rather than just querying an existing field, my attempts at implementing those solutions have been unsuccessful.
I am hoping that my query that got me close will only require a small modification to get the correct solution.
Having hyphen character - in column name (which is also minus operator) is a really bad idea. Do consider replacing it with underscore character _.
One possible way is to use Derived Tables. One Derived Table is used to determine the total on a group of main id and place id. Another Derived Table is used to get maximum value out of them based on main id. We can then join back to get only the row corresponding to the maximum value.
CREATE VIEW `MOSTTIME` (`main-id`,`place-id`,`total`) AS
SELECT b1.main_id, b1.place_id, b1.total
FROM
(
SELECT `main-id` AS main_id,
`place-id` AS place_id,
SUM(DATEDIFF(`end-date`, `begin-date`)) AS total
FROM BOOKINGS
GROUP BY main_id, place_id
) AS b1
JOIN
(
SELECT dt.main_id, MAX(dt.total) AS max_total
FROM
(
SELECT `main-id` AS main_id,
`place-id` AS place_id,
SUM(DATEDIFF(`end-date`, `begin-date`)) AS total
FROM BOOKINGS
GROUP BY main_id, place_id
) AS dt
GROUP BY dt.main_id
) AS b2
ON b1.main_id = b2.main_id AND
b1.total = b2.max_total
MySQL 8+ solution would be utilizing the Row_Number() functionality:
CREATE VIEW `MOSTTIME` (`main-id`,`place-id`,`total`) AS
SELECT b.main_id, b.place_id, b.total
FROM
(
SELECT dt.main_id,
dt.place_id,
dt.total
ROW_NUMBER() OVER (PARTITION BY dt.main_id
ORDER BY dt.total DESC) AS row_num
FROM
(
SELECT `main-id` AS main_id,
`place-id` AS place_id,
SUM(DATEDIFF(`end-date`, `begin-date`)) AS total
FROM BOOKINGS
GROUP BY main_id, place_id
) AS dt
GROUP BY dt.main_id
) AS b
WHERE b.row_num = 1
I have my data base like this
id project_id client_id price
1 1 1 200
2 2 1 123
3 2 1 100
4 1 1 87
5 1 1 143
6 1 1 100
7 3 3 123
8 3 3 99
9 4 3 86
10 4 3 43
11 4 3 145
12 4 3 155
Now here I want that it will sum the price columns with the same client_id.
For that I just made my query like this
Select `project_id`, SUM(`price`) FROM `table-name` GROUP BY `client_id`
This one is doing sum the price but I am getting only two project_id in the result. I want the result should be all the distinct project for the client id and the price will be summed for the group clients.
So can someone tell me how to do this? Any help and suggestions will be really appreciable. Thanks
You should not have "bare" column in a group by query that are not in the group by statement.
If you want the list of projects, you can get them in a list like this:
SELECT client_id, GROUP_CONCAT(project_id), SUM(price)
FROM table-name
GROUP BY client_id;
you only have two client that why you are getting only two record , you can group by two column,
Select `project_id`, SUM(`price`) FROM `table-name` GROUP BY `client_id`, `project_id`
I have a table of data like this:
id user_id A B C
=====================
1 15 1 2 3
2 15 1 2 5
3 20 1 3 9
4 20 1 3 7
I need to remove duplicate user ids and keep the record that sorts lowest when sorting by A then B then C. So using the above table, I set up a temp query (qry_temp) that simply does the sort--first on user_id, then on A, then on B, then on C. It returns the following:
id user_id A B C
====================
1 15 1 2 3
2 15 1 2 5
4 20 1 3 7
3 20 1 3 9
Then I wrote a Totals Query based on qry_temp that just had user_id (Group By) and then id (First), and I assumed this would return the following:
user_id id
===========
15 1
20 4
But it doesn't seem to do that--instead it appears to be just returning the lowest id in a group of duplicate user ids (so I get 1 and 3 instead of 1 and 4). Shouldn't the Totals query use the order of the query it's based upon? Is there a property setting in the query that might impact this or another way to get what I need? If it helps, here is the SQL:
SELECT qry_temp.user_id, First(qry_temp.ID) AS FirstOfID
FROM qry_temp
GROUP BY qry_temp.user_id;
You need a different type of query, for example:
SELECT tmp.id,
tmp.user_id,
tmp.a,
tmp.b,
tmp.c
FROM tmp
WHERE (( ( tmp.id ) IN (SELECT TOP 1 id
FROM tmp t
WHERE t.user_id = tmp.user_id
ORDER BY t.a,
t.b,
t.c,
t.id) ));
Where tmp is the name of your table. First, Last, Min and Max are not dependent on a sort order. In relational databases, sort orders are quite ephemeral.