I'm trying to merge rows in MySQL using the following code:
SELECT
type,
name,
GROUP_CONCAT(code SEPARATOR ',') AS code
FROM
`table1`
WHERE
name = '%name%' AND type = 'type'
GROUP BY
name
However no changes to DB entries occur which is the first problem.
The database looks like this:
type | name | code
-----|-------|-------
A | Milk2 | 143521
-----|-------|-------
A | Milk3 | 987564
-----|-------|-------
B | Oil | 656435
-----|-------|-------
Which I'm trying to make look like:
type | name | code
-----|-------|---------------
A | Milk | 143521, 987564
-----|-------|---------------
B | Oil | 656435
-----|-------|---------------
As you can see, names may be slightly different so this is another problem.
I am wondering whether there is any way to merge rows when, say the first four letters of the name match?
Thanks in advance.
MySQL has several string functions which might help. There's LEFT(name, 4) and you might also want to look at SOUNDEX(name), which implements the Soundex algorithm to hash words alike which sound alike. For example:
select soundex('smith'), soundex('smythe')
+ --------------------- + ---------------------- +
| soundex('smith') | soundex('smythe') |
+ --------------------- + ---------------------- +
| S530 | S530 |
+ --------------------- + ---------------------- +
1 rows
Or, using the example from your question:
select soundex('milk2'), soundex('milk3')
+ --------------------- + --------------------- +
| soundex('milk2') | soundex('milk3') |
+ --------------------- + --------------------- +
| M420 | M420 |
+ --------------------- + --------------------- +
1 rows
Your query would look something like this:
SELECT
type,
GROUP_CONCAT(DISTINCT(name) SEPARATOR ',') AS name, // note that since you've grouped on SOUNDEX(name) you can't just select name (MySQL may let you but will choose the first one
GROUP_CONCAT(code SEPARATOR ',') AS code
FROM
`table1`
WHERE
name LIKE '%name%' AND type = 'type'
GROUP BY
type, SOUNDEX(name)
I hope this is helpful!
You cannot use GROUP BY name here, as the name is always different, and you need to use LIKE instead of = when using wildcards.
The following should give you the result you're looking for
SELECT
type , name, GROUP_CONCAT( code SEPARATOR ',' ) AS all_codes
FROM `table1`
name LIKE '%name%' AND type = 'type'
Related
i'm working with MYSQL, and have a problem with group by column that data has to be trimed first.
here is my table:
src
dst
source one
some_character1/dst_one-random_value1
source one
some_character1/dst_one-random_value2
source one
some_character2/dst_two-random_value3
source two
some_character4/dst_two-random_value1
source two
some_character4/dst_three-random_value2
source two
some_character2/dst_three-random_value7
i want to group by this table into like this :
dst_group_by
dst_one
dst_two
dst_three
the dst value has 3 section.
The first section is seperated by '/', and the last section is seperated by '-'.
First section and last section character length is random, and i can determined it.
I only want to group by the middle section.
Is there any effective query to do that ?
Thanks before.
Use SUBSTRING_INDEX to get the between value you want to GROUP BY:
SELECT a.src, a.dst_group_by
FROM (SELECT src, SUBSTRING_INDEX(SUBSTRING_INDEX(dst, '/', -1), '-', 1) AS dst_group_by
FROM sample) a
GROUP BY a.src, a.dst_group_by
Result:
| src | dst_group_by |
|------------|---------------|
| source one | dst_one |
| source one | dst_two |
| source two | dst_two |
| source two | dst_three |
Or if you want to return the DISTINCT values:
SELECT DISTINCT
SUBSTRING_INDEX(SUBSTRING_INDEX(dst, '/', -1), '-', 1) AS dst_group_by
FROM sample
Result:
| dst_group_by |
|---------------|
| dst_one |
| dst_two |
| dst_three |
Fiddle here.
MySQL has substring function, you can define like that
select src,substring(dst,start_position,substring_length)
group by substring(dst,start_position,substring_length)
I don't know if the position is indexed by 0 or by 1 but the idea is like:
select src, substring(dst,16,6)
from table_name
group by substring(dst,16,6)
I hope this can help you
I'm trying to create a report in ReportBuilder (Digital Metaphors, not Microsoft) and I'm having trouble getting the SQL to do what I want.
I have one table with a field building:
| building |
+------------+
| WhiteHouse |
| TajMahal |
and another table with a field locations:
| id | locations |
+----+-----------------------------------------------------------------+
| 1 | WhiteHouse:RoseGarden,WhiteHouse:MapRoom,TajMahal:MainSanctuary |
| 2 | TajMahal:NorthGarden,WhiteHouse:GreenRoom |
I would like to create a table showing how many times each building is used in locations, like so:
| building | count |
+------------+-------+
| WhiteHouse | 3 |
| TajMahal | 2 |
The characters : and , are never used in building or room names. Even a quick-and-dirty solution that assumes that building names never appear in room names would be good enough for me.
Of course this would be easy to do in just about any sane programming language (total over something like /\bWhiteHouse:/); the trick will be getting RB to do it. Suggestions for workarounds are welcome.
it is possible to split locations string into pieces using the "," and ":" characters as seperators as follows in SQL Server with the help of a custom sql split function
select
p2.val,
count(p2.val)
from locations l
cross apply dbo.split(l.locations,',') p1
cross apply dbo.split(p1.val,':') p2
inner join building b
on b.building = p2.val
group by p2.val
I'm not sure there is a similar one in mysql, if so please check following solution as a template
You can try this, probably not the fastest, but certainly easier solution.
SELECT t1.building,
( SELECT SUM( ROUND( (LENGTH(t2.locations)
- LENGTH(REPLACE(t2.locations, concat(t1.building, ':'), ''))
) / (LENGTH(t1.building) + 1)
)
)
FROM table2 AS t2
) as count
FROM table1 as t1
SQL Fiddle Demo
I'm working with a MySQL database that contains a substantial amount of data (about 10.000 records). The data in the database is logging of a machine maintenance, one of the fields contains a basic timeline (just steps that are timestamped) explaining all the work done. In this field I'm looking for certain strings that can indicate certain procedures (i.e. ABC123.ABC, abc111.abc, abc001.abc).
I'm looking for matches in this field with pattern matching like such
SELECT * FROM [tablename]
WHERE `work_performed` LIKE '% ______.___ %'
ORDER BY id DESC;`
The regex is very general but I can specify that further myself.
However, since the field which contains the string I'm looking for can be very large (up to 2364763 characters) i want to return the records matching the pattern specified but I also want to return a field that contains just the matched expression so I can confirm it is actually what I'm looking for and can use that string further.
I have found people with the same issue but I cannot reproduce their results.
Something like this might work?:
SELECT *, SUBSTRING(`work_performed`,
patindex('%[0-9][0-9][0-9]%', `work_performed`)-1, 5) as match
FROM [tablename]
WHERE `work_performed`LIKE '% ______.___ %'
I would like to get output that looks somewhat like this:
+----+-------------------------------------------+------------+
| id | work_performed | match |
+----+-------------------------------------------+------------+
| 1 | 2017-02-26|10:59| Arrival: admin1 | ABCD12.adb |
| | 2017-02-26|10:59| diagnosed error ab-0001 | |
| | 2017-02-26|11:02| ran ABCD12.adb | |
| | 2017-02-26|11:03| system back online | |
+----+-------------------------------------------+------------+
| 2 | 2017-02-26|10:59| Arrival: admin34 | abc123.ags |
| | 2017-02-26|10:59| diagnosed error WP1234 | |
| | 2017-02-26|11:02| ran abc123.ags | |
| | 2017-02-26|11:03| system back online | |
+----+-------------------------------------------+------------+
I apologise if I didn't give enough details but I'm an intern at a major company and we have very strict rules about confidentiality.
If there is a need for any additional information I will try to.
EDIT
I have been trying to search for the string I'm looking for with regexp, but I cant get it to work as I want to, here is what I tried:
SELECT * FROM tablename
WHERE `work_performed` regexp '% ([a-z]^3)([0-9]^3).([a-z]^3) %'
ORDER BY id DESC;
The solution using CONCAT, SUBSTR, SUBSTRING_INDEX and LOCATE functions:
SELECT
CONCAT(SUBSTRING_INDEX(SUBSTRING_INDEX(work_performed, '.', 1), ' ', - 1),
'.',
SUBSTR(SUBSTRING_INDEX(work_performed, '.', - 1), 1,
LOCATE(' ', SUBSTRING_INDEX(work_performed, '.', - 1))
)
) m
FROM
tablename
https://dev.mysql.com/doc/refman/5.7/en/string-functions.html
DEMO link
I have a table "story" as follows:
+++++++++++++++++++++++++++++++++++++++++++
| id | keywords |
+++++++++++++++++++++++++++++++++++++++++++
| 1 | romance,movie,drama |
| 2 | newmovie,horor,comedy |
| 3 | movie,scifi |
| 4 | newmovie,romance,drama,asia |
| 5 | kids,movie |
+++++++++++++++++++++++++++++++++++++++++++
I try a query to search 'movie' in keywords field as below:
SELECT id FROM story WHERE keywords LIKE '%movie%'
and the result is
1,2,3,4,5
but in this case I wanted the result is 1,3,5 (field value with newmovie not include). Can someone help me how the query to do it?
Thank you for your help..
You want to use find_in_set like this:
SELECT id FROM story WHERE find_in_set('movie', keywords) > 0;
Though you should really consider normalizing your table structure.
In this case, you could've stored one single keyword in one row, then the query would be simply like:
select id from story where keyword = 'movie';
and that would've been the end of it. No heavy string functions needed.
You could have structure like this:
keywords(id, name);
story(story_id,. . ., keyword_id);
then, you could simply join the two like this:
select s.*
from story s
inner join keywords k on s.keyword_id = k.id
where k.name = 'movie';
Your problem is that "newmovie" can be found by "%movie%" you need only search "movie".
We have a table which contains card_no information. containing data like:
-----------------------------------------
| id [int(11)] | card_no [varchar(16)] |
-----------------------------------------
| 1 | 0124578965874563 |
| 2 | 1245789658478596 |
| 3 | 8471452369587458 |
-----------------------------------------
Now we need a query to find card number(s) which contains 7 in 6th position. Or which contains 4 in 2nd position.
This is actually needed when we printed card numbers and find some numbers unreadable. so we need to identify the card with rest of the numbers. For example we have data like:
1245_896584_8596
Now we need to identify the card with this data.
Thanks in advance.
You can use function SUBSTRING:
SELECT id, card_no
FROM mytable
WHERE SUBSTRING(card_no, 6, 1) = '7' OR SUBSTRING(card_no, 2, 1) = '4'
Demo here
Use SUBSTR string function
SELECT *
FROM yourtable
WHERE SUBSTR(card_no,2,1) = 4
OR SUBSTR(card_no,6,1) = 7
Use like in where clause and wildcard for exactly one symbol _
Something like
select * from table where card_no like '_____7℅'