I have a table like this
id | user_id | code | type | time
-----------------------------------
2 2 fdsa r 1358300000
3 2 barf r 1358311000
4 2 yack r 1358311220
5 3 surf r 1358311000
6 3 yooo r 1358300000
7 4 poot r 1358311220
I want to get the concatenated 'code' column for user 2 and user 3 for each matching time.
I want to receive a result set like this:
code | time
-------------------------------
fdsayooo 1358300000
barfsurf 1358311000
Please note that there is no yackpoot code because the query was not looking for user 4.
You can use GROUP_CONCAT function. Try this:
SELECT GROUP_CONCAT(code SEPARATOR '') code, time
FROM tbl
WHERE user_id in (2, 3)
GROUP BY time
HAVING COUNT(time) = 2;
SQL FIDDLE DEMO
What you are looking for is GROUP_CONCAT, but you are missing a lot of details in your question to provide a good example. This should get you started:
SELECT GROUP_CONCAT(code), time
FROM myTable
WHERE user_id in (2, 3)
GROUP BY time;
Missing details are:
Is there an order required? Not sure how ordering would be done useing grouping, would need to test if critical
Need other fields? If so you will likely end up needing to do a sub-select or secondary query.
Do you only want results with multiple times?
Do you really want no separator between values in the results column (specify the delimiter with SEPARATOR '' in the GROUP_CONCAT
Notes:
You can add more fields to the GROUP BY if you want to do it by something else (like user_id and time).
I have a table named tbl_Question and a column named INT_MARK which has different marks for different questions. Like this:
VH_QUESTION INT_MARK
----------- --------
Q1 2
Q2 4
My question is: How to get a random set of 20 questions whose total sum of marks is 50?
select VH_QUESTION, sum(INT_MARK) from tbl_Question
group by VH_QUESTION
having sum(INT_MARK) > 50
order by rand() limit 1
I think this question may help you - seems a very similar problem.
If that don't work, I'd try to divide the problem in two: first, you make a combinatory of your questions. Then, you filter them by it's sum of points.
I couldn't find, however, how to produce all combinations of the table. I don't know how difficult that would be.
select VH_QUESTION, sum(INT_MARK) from tbl_Question
group by VH_QUESTION
having sum(INT_MARK) >= 50
order by rand() limit 20
Quick answer
SELECT * ,SUM(INT_MARK) as total_mark FROM tbl_Question
GROUP BY VH_QUESTION
HAVING total_mark="50"
ORDER BY RAND()
LIMIT 5
it returns 0 line when no answers are possible but each time it finds one the questionsare random.
You could check the benchmark to see if you can have a faster query for large tables.
I have a table called answers with 2 rows:
questionid - answer
as you can probably guess questionid stores the question id number and answer stores the answer, the answers are just numbers 1 to 8
I want to display the top answer.
eg:
questionid - answer
4 - 7
4 - 3
4 - 3
2 - 3
6 - 7
7 - 1
9 - 8
1 - 5
top answer = 3
i've tried:
SELECT answer FROM answers WHERE questionid='$qid' ORDER BY answer DESC LIMIT 1
and
SELECT DISTINCT answer FROM answers WHERE questionid='$qid' ORDER BY answer DESC LIMIT 1
$qid = page id ie: /question.php?qid=4
but both return incorrect.
Update:
Is there away of showing the result without using:
while($row = mysql_fetch_array($result)) {
// stuff here
}
as I just want to show 1 result (ie the top answer) based on $qid
There are multiple ways to do this (HAVING(), WHERE, MAX(), etc) The commonality is GROUP BY.
SELECT answer, COUNT(answer) FROM questions GROUP BY answer ORDER BY COUNT(answer) DESC LIMIT 1
This will return:
3 - 3
Read more about GROUP BY.
UPDATE
Seems you modified your question after I posted this answer.
If you want to limit the query to a specific question, add a WHERE clause as the other questions.
... FROM questions WHERE questionid = X GROUP BY ...
Note: Be mindful of SQL Injection.
When you only have 1 record, you can forego the while loop and just access the top result.
$result = mysql_query($sql);
$row = mysql_fetch_array($result);
Note: You'll like want to do more error checking (e.g. ensure a result was returned). Also, don't use mysql_* functions as they are now deprecated. Use MySQLi or PDO instead.
SELECT count(*) AS answer_count, answer FROM answers WHERE questionid='$qid' GROUP BY answer ORDER BY answer_count DESC LIMIT 1
I have a table with order numbers, first name, last name, question and answers. There are 5 questions asked to the user, each answer to a question generates 1 row of data, which produces 5 rows per user. I need a query that returns order number, first name, last name and the questions and answers converted to columns, returning 1 row per user.
Any help would be appreciated
Thanks,
Larry
Seems like you want to join the table to itself 5 times.
Something like
select q1.first_name, q1.last_name, max(q1.question), max(q1.answer), max(q2.question), max(q2.answer),max(q3.question), max(q3.answer),...
from questions q1
join questions q2 on q1.first_name=q2.first_name and q1.last_name=q2.last_name
join questions q3 on q1.first_name=q3.first_name and q1.last_name=q3.last_name
where q1.order_number = 1 and q2.order_number = 2 and q3.order_number = 3 ...
group by q1.first_name, q1.last_name
Using max will collapse down the rows into unique first name/last name pairs.
Is it possible to do a SELECT statement with a predetermined order, ie. selecting IDs 7,2,5,9 and 8 and returning them in that order, based on nothing more than the ID field?
Both these statements return them in the same order:
SELECT id FROM table WHERE id in (7,2,5,9,8)
SELECT id FROM table WHERE id in (8,2,5,9,7)
I didn't think this was possible, but found a blog entry here that seems to do the type of thing you're after:
SELECT id FROM table WHERE id in (7,2,5,9,8)
ORDER BY FIND_IN_SET(id,"7,2,5,9,8");
will give different results to
SELECT id FROM table WHERE id in (7,2,5,9,8)
ORDER BY FIND_IN_SET(id,"8,2,5,9,7");
FIND_IN_SET returns the position of id in the second argument given to it, so for the first case above, id of 7 is at position 1 in the set, 2 at 2 and so on - mysql internally works out something like
id | FIND_IN_SET
---|-----------
7 | 1
2 | 2
5 | 3
then orders by the results of FIND_IN_SET.
Your best bet is:
ORDER BY FIELD(ID,7,2,4,5,8)
...but it's still ugly.
Could you include a case expression that maps your IDs 7,2,5,... to the ordinals 1,2,3,... and then order by that expression?
All ordering is done by the ORDER BY keywords, you can only however sort ascending and descending. If you are using a language such as PHP you can then sort them accordingly using some code but I do not believe it is possible with MySQL alone.
This works in Oracle. Can you do something similar in MySql?
SELECT ID_FIELD
FROM SOME_TABLE
WHERE ID_FIELD IN(11,10,14,12,13)
ORDER BY
CASE WHEN ID_FIELD = 11 THEN 0
WHEN ID_FIELD = 10 THEN 1
WHEN ID_FIELD = 14 THEN 2
WHEN ID_FIELD = 12 THEN 3
WHEN ID_FIELD = 13 THEN 4
END
You may need to create a temp table with an autonumber field and insert into it in the desired order. Then sort on the new autonumber field.
Erm, not really. Closest you can get is probably:
SELECT * FROM table WHERE id IN (3, 2, 1, 4) ORDER BY id=4, id=1, id=2, id=3
But you probably don't want that :)
It's hard to give you any more specific advice without more information about what's in the tables.
It's hacky (and probably slow), but you can get the effect with UNION ALL:
SELECT id FROM table WHERE id = 7
UNION ALL SELECT id FROM table WHERE id = 2
UNION ALL SELECT id FROM table WHERE id = 5
UNION ALL SELECT id FROM table WHERE id = 9
UNION ALL SELECT id FROM table WHERE id = 8;
Edit: Other people mentioned the find_in_set function which is documented here.
You get answers fast around here, don't you…
The reason I'm asking this is that it's the only way I can think of to avoid sorting a complex multidimensional array. I'm not saying it would be difficult to sort, but if there were a simpler way to do it with straight sql, then why not.
One Oracle solution is:
SELECT id FROM table WHERE id in (7,2,5,9,8)
ORDER BY DECODE(id,7,1,2,2,5,3,9,4,8,5,6);
This assigns an order number to each ID. Works OK for a small set of values.
Best I can think of is adding a second Column orderColumn:
7 1
2 2
5 3
9 4
8 5
And then just do a ORDER BY orderColumn