Converting SQL statement to equivalent SQLAlchemy - mysql

Question

I have the following SQL query (MySQL database)
SELECT distinct filename, DATE(created)
FROM FileTable
WHERE created > DATE_SUB(NOW(), INTERVAL 7 DAY);
My table definition:
**FileTable**
id : PK
filename :varchar
created :date
How to write an equivalent SQLAlchemy query for the above SQL statement and fetch results?
I tried this
myvar=session.query(FileTable).filter(created > DATE_SUB(NOW(), INTERVAL 7 DAY)).first()
return x.filename,x.DATE(created) for x in myvar
But it says the syntax is invalid. Please help. Thanks and regards :)

Answer 1

I suggest you are looking for magic func of sqlalchemy.sql.functions. Here is an example:
from sqlalchemy import *
metadata = MetaData()
FileTable = Table(
'FileTable',
metadata,
Column('id', Integer, primary_key=True),
Column('filename', String),
Column('created', DateTime))
print select([
distinct(FileTable.columns.filename),
func.date(FileTable.columns.created)
]).where(
FileTable.columns.created > func.date_sub(func.now(), 7))
# Output:
# SELECT DISTINCT "FileTable".filename, date("FileTable".created) AS date_1
# FROM "FileTable"
# WHERE "FileTable".created > date_sub(now(), :date_sub_1)

Answer 2

You can try this but it may results the rows those filenames are distinct in each dates(I've tested in PostgreSQL).
query = session.query(FileTable.filename.distinct(),
func.date(FileTable.created))\
.filter(created > func.adddate(func.now(), -7))
return query.all()
If you find yourself wanting to retrieve only single row per single filename then you can transform query to fetch filenames and its (in example) latest created times like below:
query = session.query(FileTable.filename,
func.date(func.max(FileTable.created)))\
.filter(created > func.adddate(func.now(), -7))\
.group_by(FileTable.filename)
return query.all()