Dropping indexes in SQL Server database - sql-server-2008

Question

How do you drop indexes in a SQL Server 2008 database? This is what I've got so far:
declare #procname varchar(500)
declare cur cursor
for
select name from sysindexes
open cur
fetch next from cur into #procname
while ##FETCH_STATUS=0
begin
exec ('drop index ' + #procname)
fetch next from cur into #procname
end
close cur
deallocate cur

Answer 1

You need to use something like this, because the DROP INDEX statement requires you to specify the table name:
-- define variables for index, schema and table name
DECLARE #indexname sysname
DECLARE #schemaname sysname
DECLARE #tablename sysname
-- declare variable for actual DROP statement
DECLARE #dropstatement NVARCHAR(1000)
-- declare cursor for iterating over all indexes
DECLARE index_cursor CURSOR LOCAL FAST_FORWARD
FOR
SELECT ix.name, t.name, s.name
FROM sys.indexes ix
INNER JOIN sys.tables t ON t.object_id = ix.object_id
INNER JOIN sys.schema s ON t.schema_id = s.schema_id
WHERE t.is_ms_shipped = 0
-- open cursor
OPEN index_cursor
-- get first index, table and schema name
FETCH NEXT FROM index_cursor INTO #indexname, #tablename, #schemaname
WHILE ##FETCH_STATUS = 0
BEGIN
-- define the DROP statement
SET #dropstatement = N'DROP INDEX ' + QUOTENAME(#indexname) +
N' ON ' QUOTENAME(#schemaname) + N'.' +
QUOTENAME(#tablename)
-- execute the DROP statement
EXEC sp_executesql #dropstatement
-- get next index, table and schema name
FETCH NEXT FROM index_cursor INTO #indexname, #tablename, #schemaname
END
CLOSE index_cursor
DEALLOCATE index_cursor