My table beers is made by:
userid, tohave
I use this:
INSERT INTO beers (userid,tohave) VALUES (1,1) ON DUPLICATE KEY UPDATE tohave=VALUES (tohave)
Is fine because the userid value (userid is PRIMARY) exists just updates the row but in my case if userid exists I want to add 1 to column tohave.
Is it possible doing it with one query?
Add +1?
INSERT INTO beers (userid,tohave)
VALUES (1,1) ON DUPLICATE KEY
UPDATE tohave = VALUES(tohave) + 1
Related
I have a table to store client's answers.I want to use one mysql query to insert or update this table.
My Table name : questionform_answer
and columns > ClientID QuestionID OptionID
Each client can only have one same question id.For example
ClientID QuestionID OptionID
1 1 1
1 2 5
2 1 3
I want to update OptionID if already exist ClientID and QuestionID.I don't want to use select query so taking so time.
I tried
ON KEY UPDATE
Replace Into
But I could not.
I use php so I tried first update query and if mysqli return fail insert row but it is also slow.
MY insert and update code :
Insert Into questionform_answer (ClientID,QuestionID,OptionID) values
('$ClientID','$soruid','$cevapid')
Update questionform_answer set OptionID='$cevapid' where
ClientID='$ClientID' and QuestionID='$soruid'
One way around this is to add a unique key over (ClientID, QuestionID) and use an INSERT ... ON DUPLICATE KEY UPDATE query:
ALTER TABLE table1
ADD UNIQUE INDEX (ClientID, QuestionID);
INSERT INTO table1
VALUES (1, 1, 4)
ON DUPLICATE KEY UPDATE
OptionID = VALUES(OptionID)
Demo on dbfiddle
First of all, you should use prepared statements to avoid SQL injections.
If you have a unique key on (ClientID,QuestionID), you can do INSERT INTO ... ON DUPLICATE KEY like this:
INSERT INTO questionform_answer (ClientID,QuestionID,OptionID)
values ('$ClientID','$soruid','$cevapid')
on duplicate key update OptionID='$cevapid'
I've got the following table:
productId price
1 price_value1
2 price_value2
3 price_value3
I would like to insert a new product into the table and assign it a new productId. In this case its value equals to 4.
So I want my new table to look like so:
productId price
1 price_value1
2 price_value2
3 price_value3
4 price_value4
So as far as I understand, in order to do that I have to somehow retrieve the max value of productId and insert it using INSERT INTO mytable VALUES (productId + 1, price_value4).
But how do I find out the maximum value of productId?
I tried INSERT INTO mytable VALUES (SELECT MAX(productId) + 1 FROM mytable, price_value4) but it didn't work.
This should Work:
Select the max(productID) and price_value4 as a columns from mytable and insert the result.
INSERT INTO mytable (SELECT MAX(productId) + 1, 'price_value4' FROM mytable);
However, if you are not going to jump some number you can just add an auto increment id key to product_id and then you will have only to insert the price, the product ID will be incremented automatically..
This will do so :
ALTER TABLE mytable
MODIFY COLUMN `productId` INT(10) UNSIGNED PRIMARY KEY AUTO_INCREMENT;
you can change INT(10) with the INT(5) for example depanding on the size you want to give to your productId column
EDIT :
In return to the OP question in comments why his solution wouldn't work
Some suggetions says you have to make the SELECT statment in insert always between parenthesis
INSERT INTO mytable VALUES ( (SELECT MAX(ID)+1 FROM mytable) , price_value4)
.. In my Case it Return
(1093): You can't specify target table
'mytable' for update in FROM clause
AND HERE IS WHY (Quoting From the documentation)
When selecting from and inserting into the same table, MySQL creates
an internal temporary table to hold the rows from the SELECT and then
inserts those rows into the target table. However, you cannot use
INSERT INTO t ... SELECT ... FROM t when t is a TEMPORARY table,
because TEMPORARY tables cannot be referred to twice in the same
statement
BUT there is away to overcome by using a query instead of the table itself in the FROM, which has the effect of copying the requested table values instead of referencing the one that you are updating..
INSERT INTO mytable VALUES (
(SELECT MAX(ID)+1 FROM (SELECT * FROM mytable ) as mytmp ),
'price_value4');
OR (Quoting From the documentation)
To avoid ambiguous column reference problems when the SELECT and the
INSERT refer to the same table, provide a unique alias for each table
used in the SELECT part, and qualify column names in that part with
the appropriate alias.
INSERT INTO mytable Values ( (SELECT MAX(ID)+1 FROM mytable as mytmp) , 'price_value4')
This is a duplicate question. In order to take advantage of the auto-incrementing capability of the column, do not supply a value for that column when inserting rows.
A simple syntax to create table
CREATE TABLE Product (
productId MEDIUMINT NOT NULL AUTO_INCREMENT,
price INT NOT NULL,
PRIMARY KEY (productid)
);
While inserting supplied default or leave column as blank or supplied value as NULL. Take a look at below code snippet.
INSERT INTO Product (price) VALUES
('10'),('20'),('4'),
('30');
refer this link
If I have 2 tables and Table 1 has a primary key(userID) AutoIncrement and Table 2 has a foreign Key(userID) to Table 1's (userID)
When I insert a new row into Table 1 first row will have userID = 1
Then if I insert again, userID = 2.
So how do I go about keeping Table 2's userID the same when inserting in Table 1. For instance, in Table 2, I am adding the password into another table.
My question is should I add an AUTOINCREMENT to Table 2(userID) and insert a new value into both tables when I create a user OR is there another way?
You have to manually insert data with correct id in Table2. There is no such built-in functionality in MySQL.
The algorithm is as follows:
Insert row in Table1.
Get Id of the new row.
Insert row with new id in Table2.
I think what you are looking for is this ... Assuming your ID is PK and AI
INSERT INTO yourTable (var1, var2 etc etc) VALUES ('val1', 'val2' etc etc);
SELECT LAST_INSERT_ID();
To further it ..
INSERT INTO yourTable (var1, var2 etc etc) VALUES ('val1', 'val2' etc etc);
SET #last_id = LAST_INSERT_ID();
INSERT INTO yourTable2 (id, var1, var2) VALUES (#last_id, 'blah', 'blah');
I have a table where each row has a primary key ID (ordered ASC), which is just a number. Is there a way to insert a row between two others by first shifting all of the rows below it by one?
Yes you can like you want to insert row with id 2 you can do so
CREATE TABLE Table1
(id INT,`test` varchar(10))
;
INSERT INTO Table1
(id,`test`)
VALUES
(1,'val'),
(2,'val'),
(3,'val')
;
Demo table has 3 records and id 2 is already assigned now you want to add row for id 2 and increment all the ids by 1
update Table1
set id =id+1
where id >1
ORDER BY id DESC;
INSERT INTO Table1
(id,`test`)
VALUES
(2,'my val');
In update query ORDER BY id DESC is necessary for primary key to ignore the duplicate entry error
SELECT * FROM Table1 order by id
Fiddle Demo
Structure table:
id (int primary key)
name (varchar 100)
date(datetime)
For insert I use query:
INSERT INTO table (name, date) VALUES ('t1','$date');
For delete row I use query:
DELETE FROM table WHERE name = 't1';
I would like want how make 1 query: first insert, if row with it name already exist, than delete row, and insert again.
Tell me please how to make it?
Create a UNIQUE index over your name column:
ALTER TABLE `table` ADD UNIQUE (name);
If you genuinely want to "delete row and insert again", then you can use REPLACE instead of INSERT. As documented:
REPLACE works exactly like INSERT, except that if an old row in the table has the same value as a new row for a PRIMARY KEY or a UNIQUE index, the old row is deleted before the new row is inserted.
Therefore, in your case:
REPLACE INTO `table` (name, date) VALUES ('t1','$date');
However, if instead of deleting the existing record and then inserting a new one you merely want to update the existing record, you can use INSERT ... ON DUPLICATE KEY UPDATE:
INSERT INTO `table` (name, date) VALUES ('t1','$date')
ON DUPLICATE KEY UPDATE date = VALUES(date);
The most material difference is in the treatment of columns for which you do not provide explicit values (such as id in your example): REPLACE will result in the new record having the default value, whereas INSERT ... ON DUPLICATE KEY UPDATE will result in the old value being retained.
What you want to do is use MySQL's on duplicate update feature.
Can be used like this :
INSERT INTO table (name, date) VALUES ('t1','$date')
ON DUPLICATE KEY UPDATE name=VALUES(name),dateVALUES(date);
Of course for that to happen a dupliate violation must occur.
insert into table (name, date) values('t1','$date') on duplicate key update name=values(name), date=values(date)
Are you looking for an update query?
Update will set a value on an already existing row.
UPDATE table SET date = '$newdate' WHERE name = 't1';
The best way to do this is using the mysql methods together with your query.
If you make the 'name' field unique:
id (int primary key)
name (varchar 100) NOT NULL UNIQUE
date(datetime)
And alter the query to:
INSERT INTO table
(name, date) VALUES ('t1','$date')
ON DUPLICATE KEY UPDATE date = "$date"