Generate link in cakephp using Html helper - html

I am trying to simply create a link in my controller using the Html helper and I get the below error although I have added the necessary helper:
Call to a member function link() on a non-object
public $helpers = array('Html', 'Form');
$url = $this->Html->link(
'',
'http://www.example.com/',
['class' => 'button', 'target' => '_blank']
);

You can use Helpers inside your view files but not inside your controller
http://book.cakephp.org/2.0/en/views/helpers.html#using-helpers.
For example in your index.ctp
echo $this->Html->link(
__('My link'),
'http://www.example.com/',
array('class' => 'button', 'target' => '_blank')
);
Enabling Html Helper in your Controller is same as in your code.
class ExamplesController extends AppController {
$helpers = array('Html', 'Form');
public function index() {
//
}
}

This is a good question. I think your a little confused with MVC and the separation of concerns the design pattern provides. Take a look (again) at how CakePHP implements MVC: http://book.cakephp.org/2.0/en/cakephp-overview/understanding-model-view-controller.html.
The important thing to remember is that your controllers should never be concerned with creating anchor tags. That's the job of your views. Since helpers are a way to keep your views DRY (Don't Repeat Yourself) having one thats sole responsibility is to create HTML elements is really handy. Views are dependent on controllers to determine what variables are set, what their value is, as well as what helpers are loaded. For more information on Helpers as well as components for controllers and behaviors for models check out http://book.cakephp.org/2.0/en/getting-started/cakephp-structure.html as well as each of their individual documentation pages:
Helpers - http://book.cakephp.org/2.0/en/views/helpers.html
Components - http://book.cakephp.org/2.0/en/controllers/components.html,
Behaviors - http://book.cakephp.org/2.0/en/models/behaviors.html.
Now that you have a better understanding of MVC, let's take a look at your specific issue. Your wanting to create a link in your controller. I assume it might be dynamic depending on some other variables so I'm going to roll with that.
A common problem that you can solve you want to show a login/logout link depending on if the user is already logged in.
In app/Controller/ExampleController.php
class ExampleController extends AppController {
public $components = array('Auth');
public $helpers = array('Html', 'Form');
public function beforeRender() {
parent::beforeRender();
//if Auth::user() returns `null` the user is not logged in.
if ($this->Auth->user() != null) {
$logInOutText = 'Log out';
$logInOutUrl = array('controller' => 'users', 'action' => 'login');
} else {
$logInOutText = 'Log in';
$logInOutUrl = array('controller' => 'users', 'action' => 'logout');
}
$this->set(compact('logInOutText', 'logInOutUrl'));
}
}
You can then so something simple in your view. In this case I'm choosing the default layout because I want the links in every rendered page. app/View/Layouts/default.ctp
<!-- More HTML above -->
<?php
// "Html" in `$this->Html` refers to our HtmlHelper. Note that in a view file
// like a `.ctp`, `$this` referes to the View object, while above in the
// controller `$this` refers to the Controller object. In the case
// `$this->Html`, "Html" would refer to a component. The same goes for Models
// and behaviors.
echo $this->Html->link($logInOutText, $logInOutUrl); // Easy!
?>
<!-- More HTML below -->
I hope this helps. I know it's a lot to put together at one time.

Though it is not good practice. However still if you need this you can use following code in your controller
App::uses('HtmlHelper', 'View/Helper');
$yourTmpHtmlHelper = new HtmlHelper(new View());
$url=$yourTmpHtmlHelper->link(
'',
'http://www.example.com/',
['class' => 'button', 'target' => '_blank']
);
This should work for cakephp 2.*
Thanks

Related

How to use article name on the url on Yii2?

I need to use article name on the url on Yii2 which is like http://example.com/article?id=1, just replace id=1 to article_name, like http://example.com/article/article_name or is it.
This is my controller code-
$model = Articles::find()->orderBy(['id' => SORT_DESC])->one();
View-
<?= Html::a('<b>Read more ...</b>', ['article-details','id' => $model->id], ['target'=>'_blank']) ?>
Thanks advance
You may use yii2 sluggable behavior Refer this.
There are few steps.
You must add the following urlManager rule :
'article/<slug>' => 'article/view',
You should build url in your view files like this :
\yii\helpers\Url::to(['article/view', 'slug'=>$model->title])
or
\yii\helpers\Url::to(['article/'.$model->title]);
And in your action
public function actionArticle($slug){
$model = Articles::find()->where(["title"=>$slug])->orderBy(['id' => SORT_DESC])->one();
//and other code
}
Also your article titles must be valid for url.You can do it easly by trimming whitespaces and so on But also you can add url some identification propery. or add column stored unique slugs for every article
You have two way
one change the related action in the controller changing id with name in the related function declaration
or declare a new action with the name as parameter
public function findModelName($article_name)
{
$model = Article::findOne(['name'=> $article_name]);
........ your related code
}
you can find the model by name this way
Article::findOne(['name'=> $article_name]);

How I can to turn off a theme in a especific yii2's view?

I am using yii2 with a bootstrap's theme, the theme is great but I need to turn off in one especific view of my controller. How I can do that?
You can change the theme at runtime by overriding the theme mapping. Adjust these for the routes you want to use, so if you are using a different theme, then point the pathMap and baseUrl to that theme, otherwise just point back to the original yii2 view files;
$this->getView()->theme = Yii::createObject([
'class' => '\yii\base\Theme',
'pathMap' => ['#app/views' => '#app/views'],
'baseUrl' => '#web/views',
]);
If you want change layout use in controller:
public $layout = 'YOUR_LAYOUT_NAME';
Or in special action:
public function actionView(){
$this->layout = 'YOUR_LAYOUT_NAME';
Read for $layout property http://www.yiiframework.com/doc-2.0/yii-base-controller.html#$layout-detail

zend framework 2, return the rendered contents of a view inside a JSON Model

I am trying to create a JsonModel with an item in the variables 'html' containing the current rendered view. I would like to add this code to an event:
rather than this method: How to render ZF2 view within JSON response? which is in the controller, I would like to automate the process by moving it to an Event
I have the strategy in my module.config.php:
'strategies' => array(
'ViewJsonStrategy',
)
I have set up a setEventManager in the controller:
$events->attach(MvcEvent::EVENT_RENDER, function ($e) use ($controller) {
$controller->setRenderFormat($e);
}, -20);
Is this the best event to attach it to? would the RENDER_EVENT be better?
Now I would like to change the render of the page based on !$this->getRequest()->isXmlHttpRequest(), (commented out for debug)
public function setRenderFormat($e)
{
//if(!$this->getRequest()->isXmlHttpRequest())
//{
$controller = $e->getTarget();
$controllerClass = get_class($controller);
//Get routing info
$controllerArr = explode('\\', $controllerClass);
$currentRoute = array(
'module' => strtolower($controllerArr[0]),
'controller' => strtolower(str_replace("Controller", "", $controllerArr[2])),
'action' => strtolower($controller->getEvent()->getRouteMatch()->getParam('action'))
);
$view_template = implode('/',$currentRoute);
$viewmodel = new \Zend\View\Model\ViewModel();
$viewmodel->setTemplate($view_template);
$htmlOutput = $this->getServiceLocator()->get('viewrenderer')->render($viewmodel, $viewmodel);
$jsonModel = new JsonModel();
$jsonModel->setVariables(array(
'html' => $htmlOutput,
'jsonVar1' => 'jsonVal2',
'jsonArray' => array(1,2,3,4,5,6)
));
return $jsonModel;
//}
}
Strangely, (or not) this code works and produces the $jsonModel, however is doesn't overwite the normal HTML view with the json, but the same code (without the event) in a controller method, overwrites perfectly.
p.s Is there a better method to do the whole concept?
p.p.s how can I obtain the current View Template from within the controller, without resorting to 8 lines of code?
Thanks in advance!
Aborgrove
you are returning the view model from an event I thinks this doesn't have any effect in current viewmanager view model, fetch the current viewmodel from viewmanager and call setTerminal(true). or replace the created jsonmodel using the viewmanager

Use a widget in a statically-called method

Normally a widget is used by calling CController::widget() on an instance of CController, typically $this in a view.
But if I'm writing a static method, a helper, say, then I don't have access to an instance of CController. So how do I use a widget?
Let's say further that this helper method is invoked in the eval()’ed expression in a CDataColumn's value property. That poor expression has almost no context at all. How should the helper use a widget?
EDIT: Code example
As requested, a view example:
$this->widget('zii.widgets.grid.CGridView', array(
'dataProvider' => $model->search(),
'columns' => array(
array(
'name' => 'attrName',
'value' => '--USE WIDGET HERE--',
),
)
));
This answer doesn't answer the question in general but in the specific case—how to access the controller and use a widget in the context of the evaluated expression of CDataColumn::$value—you can use this:
$this->widget('zii.widgets.grid.CGridView', array(
'dataProvider' => $model->search(),
'columns' => array(
array(
'name' => 'attrName',
'value' => function ($data, $row, $column) {
$controller = $column->grid->owner;
$controller->widget(/* ... etc ... */);
},
),
)
));
The trick was discovering that CDataColumn::renderDataCellContent() uses CComponent::evaluateExpression(), which injects the component instance into the callback as the last parameter. In this case that omponent is the CDataColumn, which references the controller as shown.
I don't like writing PHP expressions as string literals so I'm pleased to find this option.
A comment on http://www.yiiframework.com/doc/api/1.1/CDataColumn#value-detail shows another way to us a widget in a column value that I haven't tried.
This one is working solution for calling widgets in static methods in Yii
Yii::app()->controller->widget('widget');
There's no direct way to call a widget out of controller because you shouldn't do so. It's all about MVC. Widgets are only needed and/or useful in views, and views are only accessed via controllers. That's the theory.
I guess you're approaching the problem mistakenly. A proper, MVC-friendly way to do what your're trying to do involves using renderPartial(). You know: you a have certain content and you want to decorate it (in your case you want to imbibe it inside a widget, right?) before displaying it to final user; so, from the view, you call renderPartial(). It will send your data to a file where it will properly decorated. renderPartial() returns the content properly formatted and now you can display it in the view.
Unfortunately, in your particular case, you're working with grid view (right?) and, at least from my point of view, it makes the things a bit harder. In order to decorate content for a CGridColumn-subclass element (like CDataColumn), you need to override the renderDataCellContent() method. Check it out here: http://www.yiiframework.com/doc/api/1.1/CDataColumn#renderDataCellContent-detail

Zend Forms and Ext.grid.Panel

I am working for a company who use tabulated html/JS interfaces. These are home grown (real honest to god s) with query events attached to each cell. For the old usage they were suitable, but the interactions required between rows and cells are becoming much more complex on the client side. Specifically they want both server and client side validation.
To facilitate this, the devs I report to are super keen on Zend_Forms, and insist that to use a framework like ExtJS, they don't want to have to write back end and front end code twice (please ignore that if it's all home grown they'll have to do this anyway).
So with that in mind, I'm trying to leverage Zend_Form decorators to create Ext.grid.Panel column defintions. For this, I would need to use decorators to export an array (and then json it using the ViewHelper), or render a JSON string directly.
So this would be something like:
$dateElement = new Zend_Form_Element_Text('startDate', array(
'label' => 'Start Date',
'validators' => array(
new Zend_Validate_Date()
)
));
echo (string)$dateElement;
would output:
{ text: 'Start Date', dataIndex:'startDate', xtype:'datecolumn'}
or (obviously not with string cast, but maybe with ->toArray() or something):
array( 'text' => 'Start Date', 'dataIndex' => 'startDate', 'xtype' => 'datecolumn')
I think if I could get it to this stage, I could get what I need out of it.
Has anyone here tried to do anything similiar to this (getting a JSON/XML/other markups output, rather than HTML from Zend_Forms using Decorators) or if they could point me to any resources?
I think I have a solution...
Make a decorator similar to this:
class My_Form_JSON_Decorator extends Zend_Form_Decorator_Abstract{
protected $xtype;
protected $dataIndex;
public function __construct($dataIndex,$xtype){
$this->xtype=$xtype;
$this->dataIndex=$dataIndex;
}
public function render($content){
$element=$this->getElement();
$label=$element->getLabel
//if you need errors here too do the same with $element->getMessages();
return 'array ("text"=>"'.$label.'","dataIndex"=>"'.$this->dataIndex.'","datecolumn"=>"'.$this->xtype.'")';
}
}
Then, on the form, use something similar to this:
$dateElement = new Zend_Form_Element_Text('startDate', array(
'label' => 'Start Date',
'validators' => array(
new Zend_Validate_Date()
)
$dateElement->setDecorators(array(
new My_Form_JSON_Decorator("startDate","datecolumn");
));
And finally, on the View, you should have this:
{
Date: <?php echo $this->form->startDate; ?>,
}
I didn't tried the code above but, I did it with a similar code I used once when I needed to change Decorators of a Form.
It could not be all correct but, I think that it shows you a way of doing that.
Good work =)