Ruby On Rails and redmine Aglie plugin fixing - mysql

Question

Well, as maybe you know guys, in redmine base sturcture there are tables issues, projects. I never used to write code in ruby before btw. But I got task, so.
Here the issues table structure:
And here is the project table structure:
The problem is I need to get all issues where project_id equals #project and project.parent_id equals #project too.
The problem is, first I don't understand what current #project contents. Second I got no idea how to access to the #project's parent_id field here. Parent_id is referenced to the project.id field by the way.
I got ruby function here.
Boss said I need to edit scope variable. So I trying to edit it like this:
def find_no_version_issues
#backlog_version = #project.versions.open.where("LOWER(#{Version.table_name}.name) LIKE LOWER(?)", "backlog").first ||
#project.versions.open.where(:effective_date => nil).first ||
Version.open.where(:project_id => #project).order("effective_date ASC").first
#current_version = Version.open.
where(:project_id => #project).
where("#{Version.table_name}.id <> ?", #backlog_version).
order("effective_date DEcSC").first
q = (params[:q] || params[:term]).to_s.strip
#scope = (params[:scope] == "all" || #project.nil? ? Issue : #project.issues).open.visible.where(:fixed_version_id => nil).sorted_by_rank
scope = Issue.open.visible.where(:fixed_version_id => nil).where("project_id = ?", ) OR #project.or(:project_id.parent_id => #project)).sorted_by_rank
#scope = Issue.open.visible.where(:project_id => #current_version) #(:project_id => #project || #project.parent_id == :project_id || #project ).sorted_by_rank
if q.present?
if q.match(/^#?(\d+)\z/)
scope = scope.where("(#{Issue.table_name}.id = ?) OR (LOWER(#{Issue.table_name}.subject) LIKE LOWER(?))", $1.to_i, "%#{q}%")
else
scope = scope.where("LOWER(#{Issue.table_name}.subject) LIKE LOWER(?)", "%#{q}%")
end
end
#issue_count = scope.count
#issue_pages = Redmine::Pagination::Paginator.new #issue_count, 20, params['page']
#version_issues = scope.offset(#issue_pages.offset).limit(#issue_pages.per_page).all
end
So, please, could somebody help me? How could I understand, what #project contains? How could I turn query into scope?
Here's working SQL-query (or at least it got rows I need). But I really have no idea how to make this scope varible contains this data?
SELECT * FROM `issues` WHERE `project_id` IN (SELECT `id` FROM `projects` WHERE `parent_id` IS NOT NULL OR `parent_id` IS NULL ) ORDER BY `id` ASC

Answer 1

Well, actually I fixed this thing this way
def find_no_version_issues
q = (params[:q] || params[:term]).to_s.strip
#scope = (params[:scope] == "all" || #project.nil? ? Issue : #project.issues).open.visible.where(:fixed_version_id => nil).sorted_by_rank
#subprojects = #project.descendants.visible.all
#subprojects = #subprojects.to_a.push #project
scope = Issue.open.visible.where(project_id:#subprojects).where(:fixed_version_id => nil).sorted_by_rank
if q.present?
if q.match(/^#?(\d+)\z/)
scope = scope.where("(#{Issue.table_name}.id = ?) OR (LOWER(#{Issue.table_name}.subject) LIKE LOWER(?))", $1.to_i, "%#{q}%")
else
scope = scope.where("LOWER(#{Issue.table_name}.subject) LIKE LOWER(?)", "%#{q}%")
end
end
#issue_count = scope.count
#issue_pages = Redmine::Pagination::Paginator.new #issue_count, 20, params['page']
#version_issues = scope.offset(#issue_pages.offset).limit(#issue_pages.per_page).all
end