I am using Gulp for watch and sass complier. When I start "watch" first time then "sass" complier runs and its create the css files as per given path. However when I change the .scss files then it doesn't call "sass" complier again. Following is is my these two tasks and variables.
gulp.task('sass', function () {
gulp.src(config.sassPath)
.pipe(sass())
.pipe(gulp.dest(config.cssPath))
.pipe(livereload());
});
gulp.task('watch', false, function () {
livereload.listen(8189);
gulp.src(config.watchPaths)
.pipe(watch(config.watchPaths, function (event) {
gulp.start( 'sass', 'js-hint', 'server','test');
livereload();
}))
.pipe(livereload());
});
Following command i use to run "watch" task
gulp watch
I do see "watch" is reloading when I am changing the .scss file. Following is log for this.
[19:49:30] public/sass/html-controls.scss was changed
[19:49:30] /Users/dkuma204/Desktop/Dilip/Projects/OPEN/SourceCode/AWF/OPENApp/application/public/sass/html-controls.scss reloaded.
Not sure what I am missing here. Please help.
Why it is so complicated? Try this:
gulp.task('watch', false, function () {
livereload.listen(8189);
gulp.watch(config.watchPaths,['sass', 'js-hint', 'server', 'test'])
});
And your every task which requires livereload should have .pipe(livereload()) at the end.
You shouldn't use gulp start. Here is one of comment from github discussion:
gulp.start is undocumented on purpose because it can lead to
complicated build files and we don't want people using it
Related
Years back I setup vs code to somewhat replicate the current methods I was using to design my sites (using standalone apps). I decided at the time I would just stick to what I was using. Since those apps are no longer maintained I am coming across compiling issues now - the time has come to make the jump.
I am having trouble with my gulpfile.js which is from back when I originally tried this all out. I saved it in case I needed to return to using vs code. Problem is apparently this format no longer works because gulp has updated. All of this is basically foreign to me right now and while I understand what things are doing I don't understand enough to modify this to the current method for gulp 4^.
Any chance someone can help me out with this one? I've looked at the guides about series and parallel and so on. I guess it's easier for me to understand by looking at a working example.
my old gulpfile.js
var gulp = require('gulp');
var sass = require('gulp-sass');
var cleanCSS = require('gulp-clean-css');
var uglify = require('gulp-uglify');
//processes the scss files in this folder
//minimizes them
gulp.task('sass', function () {
return gulp.src('_config/scss/**/*.scss')
.pipe(sass().on('error', sass.logError))
.pipe(cleanCSS())
.pipe(gulp.dest('assets/css'));
});
//minifies all js files in this folder
gulp.task('js', function () {
return gulp.src('_config/js/**/*.js')
.pipe(uglify())
.pipe(gulp.dest('assets/js'));
});
//minifies all js files in this folder
gulp.task('scripts', function () {
return gulp.src('_config/scripts/**/*.js')
.pipe(uglify())
.pipe(gulp.dest('assets/scripts'));
});
//creates 'watchers' that run tasks on specific activities
gulp.task('watch', function () {
gulp.watch('_config/scss/**/*.scss', ['sass']);
gulp.watch('_config/js/**/*.js', ['js']);
gulp.watch('_config/scripts/**/*.js', ['scripts']);
gulp.watch('_config/img/**/*', ['img']);
});
//this is the default task that runs everything
gulp.task('default', ['sass', 'js', 'scripts', 'watch']);
You are not that far from where you need to be. Change this code:
gulp.task('watch', function () {
gulp.watch('_config/scss/**/*.scss', ['sass']);
gulp.watch('_config/js/**/*.js', ['js']);
gulp.watch('_config/scripts/**/*.js', ['scripts']);
gulp.watch('_config/img/**/*', ['img']);
});
gulp.task('default', ['sass', 'js', 'scripts', 'watch']);
to
gulp.task('watch', function () {
gulp.watch('_config/scss/**/*.scss', gulp.series('sass'));
gulp.watch('_config/js/**/*.js', gulp.series('js'));
gulp.watch('_config/scripts/**/*.js', gulp.series('scripts'));
gulp.watch('_config/img/**/*', gulp.series('img'));
});
gulp.task('default', gulp.series('sass', 'js', 'scripts', 'watch'));
gulp.task now has this signature: gulp.task([taskName], taskFunction)
Before gulp v3 used an array of tasks as the second argument. gulp v4 uses a function, like gulp.series() or gulp.parallel(), as the second argument. And gulp.series() takes a list of tasks as its arguments. Since you used the gulp.task() method to create your tasks, the task names in series should appear as strings, like 'sass', 'js', etc.
Note: The preferred way to create tasks in v4 is as functions like:
function scripts() {
return gulp.src('_config/scripts/**/*.js')
.pipe(uglify())
.pipe(gulp.dest('assets/scripts'));
});
Then you would use those function names in series as gulp.series(scripts, js) - not as strings. You should look into using this form of tasks.
gulp.watch() signature: gulp.watch(globs, [options], [task])
The [task] can be a single task name, like your 'sass' or a composed task, which just means one generated using series or parallel.
In your case, you are running only one task in each watch statement, so
gulp.watch('_config/scss/**/*.scss', 'sass');
should suffice. I showed them as composed tasks like:
gulp.watch('_config/scss/**/*.scss', gulp.series('sass'));
in case in the future you want to run more than one task upon a file change. In which case you could use something like:
gulp.watch('_config/scss/**/*.scss', gulp.series('sass', 'serve'));
for example.
Finally switch out gulp-uglify for gulp-terser. gulp-terser will handle es6 syntax that gulp-uglify cannot. gulp-terser
I have a gulpfile in which is a watch task, below
gulp.task('watch', function() {
gulp.watch('template/slick/assets/less/*.less', ['less']); // Watch all the .less files, then run the less task
});
This then invokes a less compile to css of that directory and moves it to a /css/ folder.
I then have 2 other tasks already scripted up to min, concat and move these .css files to a dist folder.
What I need to know is that when my watch invoked less task completes can I notify/run the stylesmin, cssconcats tasks? I do need to add more code to do it. I can't see to find a decent notify/end style way of doing things.
Here's the less task which is invoked by watch
gulp.task('less', function () {
return gulp.src('game/http/template/slick/assets/less/*.less')
.pipe(less())
.pipe(gulp.dest('game/http/template/slick/assets/css/'))
.pipe(notify({message: 'Less compiled'}));
});
You can define your tasks as dependencies of each other with [] syntax like below. (I'm assuming you are using something like connect to start up a server before you start watching the files)
gulp.task('less', function() {
console.log('less');
})
gulp.task('stylesmin', ['less'], function() {
console.log('stylesmin');
})
gulp.task('cssconcats', ['stylesmin'], function() {
console.log('cssconcats');
})
gulp.task('test', ['connect', 'watch']);
Modify your watch to kick off the last task, cssconcats and gulp will run the dependencies first
gulp.task('watch', function() {
gulp.watch('template/slick/assets/less/*.less', ['cssconcats']); // Watch all the .less files, then run the less task
});
Change any .less file and the output shows that the tasks are run correctly in this order;
less, stylesmin, cssconcats
There is the following gulp tasks:
// Processing templates task
gulp.task('templates', function() {
return gulp.src('app/**/*.slim')
.pipe(slim({pretty: true}))
.pipe(minifyHTML())
.pipe(gulp.dest(dist));
});
// Watching files for changes task
gulp.task('watch', function() {
gulp.watch('app/**/*.slim', ['templates']);
});
As you can see templates task finds and transforms all .slim files in .html file. It works good. Also there is watch task which watches changes and executes templates task after it. But I want that after watch task finds some changes in template A gulp will transform only template A, not all templates. I don't understand how I can get changed file and transform it. Please, help me. Thanks in advance.
I think you can try Incremental build.
gulp.task('default', function () {
return gulp.src('app/**/*.slim')
.pipe(watch('app/**/*.slim'))
.pipe(slim({pretty: true}))
.pipe(minifyHTML())
.pipe(gulp.dest(dist));
});
I'm new to using gulp and I think I have it setup correctly, but it does not seem to be doing what it should be doing.
My gulpfile.js has
gulp.task('compass', function() {
return gulp.src('sites/default/themes/lsl_theme/sass/**/*.scss')
.pipe(compass({
config_file: 'sites/default/themes/lsl_theme/config.rb',
css: 'css',
sass: 'scss'
}))
.pipe(gulp.dest('./sites/default/themes/lsl_theme/css'))
.pipe(notify({
message: 'Compass task complete.'
}))
.pipe(livereload());
});
with
gulp.task('scripts', function() {
return gulp.src([
'sites/default/themes/lsl_theme/js/**/*.js'
])
.pipe(plumber())
.pipe(concat('lsl.js'))
.pipe(gulp.dest('sites/default/themes/lsl_theme/js'))
// .pipe(stripDebug())
.pipe(uglify('lsl.js'))
.pipe(rename('lsl.min.js'))
.pipe(gulp.dest('sites/default/themes/lsl_theme/js'))
.pipe(sourcemaps.write())
.pipe(notify({
message: 'Scripts task complete.'
}))
.pipe(filesize())
.pipe(livereload());
});
and the watch function
gulp.task('watch', function() {
livereload.listen();
gulp.watch('./sites/default/themes/lsl_theme/js/**/*.js', ['scripts']);
gulp.watch('./sites/default/themes/lsl_theme/sass/**/*.scss', ['compass']);
});
when I run gulp, the result is
[16:14:36] Starting 'compass'...
[16:14:36] Starting 'scripts'...
[16:14:36] Starting 'watch'...
[16:14:37] Finished 'watch' after 89 ms
and no changes are registered.
for file structure, my gulpfile.js is in the root directory and the sass, css, and js are all in root/sites/default/themes/lsl_theme with the sass folder containing the folder 'components' full of partials.
My assumption is that you are on windows? Correct me if I'm wrong.
There is this problem that gulp-notify tends to break the gulp.watch functions. Try commenting out
// .pipe(notify({
// message: 'Scripts task complete.'
// }))
and see if the problem still exists.
If that does fix the issue, a solution from this thread may be helpful.
You can use the gulp-if
plugin in combination with
the os node module
to determine if you are on Windows, then exclude gulp-notify, like
so:
var _if = require('gulp-if');
//...
// From https://stackoverflow.com/questions/8683895/variable-to-detect-operating-system-in-node-scripts
var isWindows = /^win/.test(require('os').platform());
//...
// use like so:
.pipe(_if(!isWindows, notify('Coffeescript compile successful')))
It turns out that a large part of my issue was just simply being a rookie with Gulp. When I removed 'scripts' from my gulp watch it started working.
I then made the connection that it was watching the same directory that it was placing the new concatenated and minified js files in so it was putting the new file, checking that file, and looping over and over causing memory issues as well as not allowing 'compass' to run.
After creating a 'dest' folder to hold the new js everything started working just peachy.
I have a very minimal gulpfile as follows, with a watch task registered:
var gulp = require("gulp");
var jshint = require("gulp-jshint");
gulp.task("lint", function() {
gulp.src("app/assets/**/*.js")
.pipe(jshint())
.pipe(jshint.reporter("default"));
});
gulp.task('watch', function() {
gulp.watch("app/assets/**/*.js", ["lint"]);
});
I cannot get the watch task to run continuously. As soon as I run gulp watch, it terminates immediately.
I've cleared my npm cache, reinstalled dependencies etc, but no dice.
$ gulp watch
[gulp] Using gulpfile gulpfile.js
[gulp] Starting 'watch'...
[gulp] Finished 'watch' after 23 ms
It's not exiting, per se, it's running the task synchronously.
You need to return the stream from the lint task, otherwise gulp doesn't know when that task has completed.
gulp.task("lint", function() {
return gulp.src("./src/*.js")
^^^^^^
.pipe(jshint())
.pipe(jshint.reporter("default"));
});
Also, you might not want to use gulp.watch and a task for this sort of watch. It probably makes more sense to use the gulp-watch plugin so you can only process changed files, sort of like this:
var watch = require('gulp-watch');
gulp.task('watch', function() {
watch({glob: "app/assets/**/*.js"})
.pipe(jshint())
.pipe(jshint.reporter("default"));
});
This task will not only lint when a file changes, but also any new files that are added will be linted as well.
To add to OverZealous' answer which is correct.
gulp.watch now allows you to pass a string array as the callback so you can have two separate tasks. For example, hint:watch and 'hint'.
You can then do something like the following.
gulp.task('hint', function(event){
return gulp.src(sources.hint)
.pipe(plumber())
.pipe(hint())
.pipe(jshint.reporter("default"));
})
gulp.task('hint:watch', function(event) {
gulp.watch(sources.hint, ['hint']);
})
This is only an example though and ideally you'd define this to run on say a concatted dist file.