mysql statement wont insert - mysql

Hey guys I've searched for answers through the forums but to no avail so I'm using MySql and I'm trying to insert statements for certain tables and they aren't going into the tables and I'm getting errors like "Msg 8152, Level 16, State 14, Line 1
String or binary data would be truncated. The statement has been terminated."
These are the statements I'm having problems with.`INSERT INTO Course VALUES
INSERT INTO Course VALUES (12345, 'DatabaseManagement', '2015-2-1', '2014-5-9');
INSERT INTO Course VALUES (12346, 'Calculus', '2015-1-12', '2015-5-9');
INSERT INTO Course VALUES (12347, 'Biology', '2015-1-3', '2015-5-9');
INSERT INTO Course VALUES (12348, 'Chemistry', '2015-1-2', '2015-5-9');
INSERT INTO Grade VALUES (10, 12345, 012, 'A');
INSERT INTO Grade VALUES (11, 12346, 013, 'B');
INSERT INTO Grade VALUES (12, 12347, 014, 'C');
INSERT INTO Grade VALUES (13, 12348, 015, 'D');
INSERT INTO Grade VALUES (14, 12345, 016, 'B');
INSERT INTO Student VALUES (54321, 'Rachel', 'Cotterel', '2013-4-15', '2016-3-4');
INSERT INTO Student VALUES (54320, 'John', 'Smith', '2012-1-23', NULL);
INSERT INTO Student VALUES (54319, 'Johny', 'Depp', '2010-5-12', '2012-10-10');
INSERT INTO Student VALUES (54318, 'Orlando', 'Bloom', '2014-6-24', NULL);
INSERT INTO Student VALUES (54317, 'Linda', 'Jacob', '2015-4-4', '2019-8-6');

I didn't get any error for insert into Course statements. I got error for INSERT INTO Grade statements. Its because there is no reference available for StudentID 012,013 etc in Student table. And you are trying to add them in grade table.

Try using this:
INSERT INTO table1 (column1,column2,column3,...)
VALUES (value1,value2,value3,...);

These are the field types:
CREATE TABLE Course
(
CourseID int,
Description varchar(20) NOT NULL,
StartDate DATE NOT NULL,
EndDate DATE NOT NULL,
CONSTRAINT [PK_CourseID] PRIMARY KEY (CourseID)
);
CREATE TABLE Grade
(
GradeID integer(10) NOT NULL,
CourseID integer(10) NOT NULL,
StudentID integer(10) NOT NULL,
Grade varchar (10) NULL,
CONSTRAINT [PK_GradeID] PRIMARY KEY (GradeID),
CONSTRAINT [FK_CourseID] FOREIGN KEY (CourseID) REFERENCES Course(CourseID),
CONSTRAINT [FK_StudentID] FOREIGN KEY (StudentID) REFERENCES Student(StudentID)
);
CREATE TABLE Student
(
StudentID integer(10) NOT NULL,
FirstName varchar(45) NOT NULL,
LastName varchar(45) NOT NULL,
RegistrationDate varchar (45) NOT NULL,
GraduationDate DATE NULL,
CONSTRAINT [PK_StudentlID] PRIMARY KEY (StudentID)
);

String or binary data would be truncated
The reason that you get this message should be that you are trying to insert some value to some field to which you haven't assigned enough size to hold the value.
Can you send what the exact error message you get?
I tried to do it myself.But the error I got was from you insertion query to Grade table foreign key fails which refer Student table because you are trying to insert Student_IDs which are not there in you Student table

Related

Why can't I insert these values into the table I added to this database?

I'm new to SQL and learning its basic functions, i've been instructed to create a table and add it to my database, whilst then adding the appropriate values to each field in the table. But I keep getting a syntax error in the line:
INSERT into Weather_db.client_data
Here is my code so far. Let me know what I should change:
Q1.) Using the CREATE TABLE statement, create a table called client_data with fields
CREATE TABLE Weather_db.client_data (
ID int PRIMARY KEY,
First_name varchar(40) NOT NULL,
Last_name varchar(40),
Nationality varchar(40),
Age Float Check (age>18))
Q2.) Insert the following records in the database using the INSERT statement
INSERT into Weather_db.client_data
VALUES ('John', 'S',
'British', 'null'),
('Peter', 'Jackson', 'null', '20'),
('Tom', 'W', 'null', '20'),
('Jack', 'Patrick', 'American', '30');
ID int PRIMARY KEY,
This column definition is legal, but it doesn't have any automatic behavior to generate unique values. So you must supply a value yourself in your INSERT statement, and it's up to you to make sure the value is unique, i.e. it is not already used on any existing row in this table.
MySQL provides an option for integer primary keys to generate new unique values automatically:
ID int AUTO_INCREMENT PRIMARY KEY,
By using this, you don't have to specify a value in your INSERT statement.
You may like to read this manual page for more information: https://dev.mysql.com/doc/refman/8.0/en/example-auto-increment.html
Your statement has a few syntax issues.
Firstly you are not providing values for all the defined columns.
It's also good practice to always specifically list the columns in the insert statement.
You should not be quoting numeric values, or null values.
You should probably define the ID as auto_increment which means the database will supply a default value.
See a working example
CREATE TABLE client_data (
ID int PRIMARY key auto_increment,
First_name varchar(40) NOT NULL,
Last_name varchar(40),
Nationality varchar(40),
Age Float Check (age>18));
INSERT into client_data (first_name, last_name, Nationality, Age)
VALUES ('John', 'S','British', null),
('Peter', 'Jackson', null, 20),
('Tom', 'W', null, 20),
('Jack', 'Patrick', 'American', 30);

MySQL Foreign Key value is NULL

I am trying to create a table called "Borrower" or "Lånetagare" and want to insert the value from table Lån with the ID from there. The result I get is NULL. How come?
create table Lån
(
Lån_ID INT auto_increment primary key,
Lånedatum DATETIME,
Inlämningsdatum DATETIME,
Omlån DATETIME
);
INSERT INTO Lån (Lånedatum, Inlämningsdatum, Omlån)
VALUES ('2017-09-12', '2017-09-15', '2017-09-15');
CREATE TABLE Lånetagare
(
Lånetagare_ID INT(10) auto_increment primary key,
Lösenord varchar(50),
Förnamn varchar(50),
Efternamn varchar(50),
Adress varchar (50),
Ort varchar(50),
Postnummer int(5),
Email varchar(50),
Telefonnummer int(20),
Lånekort int(50),
Lån_ID int(50),
FOREIGN KEY (Lån_ID) REFERENCES Lån(Lån_ID)
);
INSERT INTO Lånetagare (Lösenord, Förnamn, Efternamn, Adress, Ort, Postnummer, Email, Telefonnummer, Lånekort)
VALUES ('hej135', 'Victor', 'Chi', 'Blekingegatan 28', 'Stockholm', 11856, 'Tim#hotmail.com', 0704582235, 56);
SELECT * FROM Lånetagare;
If you want to associate a row in Lånetagare with the previously-inserted row in Lån, you must set a value for the foreign key.
Here's a common way to do it:
INSERT INTO Lån (Lånedatum, Inlämningsdatum, Omlån)
VALUES ('2017-09-12', '2017-09-15', '2017-09-15');
INSERT INTO Lånetagare (...other columns..., Lån_ID)
VALUES (...other values..., LAST_INSERT_ID());
The LAST_INSERT_ID() function returns the most recent auto-increment id created by an INSERT statement during your session. Read more about this function here: https://dev.mysql.com/doc/refman/5.7/en/information-functions.html#function_last-insert-id
Try
INSERT INTO Lånetagare (Lösenord, Förnamn, Efternamn, Adress, Ort, Postnummer, Email, Telefonnummer, Lånekort, Lån_ID)
VALUES ('hej135', 'Victor', 'Chi', 'Blekingegatan 28', 'Stockholm', 11856, 'Tim#hotmail.com', 0704582235, 56, (SELECT Lån_ID FROM Lån WHERE <put your select criteria here>));

Adding items in MySQL table

I was preparing to create a website using PHPMyAdmin and I bang into a problem : I don't understant why my code does things I don't want.
This is the code to create the tables and some random entries :
create table stud (
matrnr int primary key,
pname Varchar(30) not null
);
create table prof (
persnr int primary key,
pname Varchar(50) not null
);
create table vorl (
vorlnr int primary key,
titel varchar(50),
prof int references prof(persnr) on delete set null
);
create table prüfen (
stud int references stud(matrnr) on delete cascade,
vorl int references vorl(vorlnr),
prof int references prof(persnr) on delete set null,
note float,
primary key(Stud, vorl)
);
insert into stud values
(1, 'G'),
(2, 'F'),
(3, 'C');
insert into Prof values
(1, 'M'),
(2, 'L'),
(3, 'M');
insert into vorl values
(1, 'Info1', 'M'),
(1, 'Info2', 'L'),
(1, 'Info3', 'M');
insert into prüfen values
(1, 1, 1, 2.0),
(1, 2, 1, 1.7),
(2, 3, 2, 2.3);
At this position I tried
Insert into prüfen values (3, 1, 4, 2.0);
but the was still only 3 lines in the table prüfen.
Any help is wellcome.
Have a good week.
Your final insert failed because it references a professor with a prof ID of 4, which does not exist in the prof table.
If you look closely at your definition for the prüfen table, this will be more clear:
create table prüfen (
stud int references stud(matrnr) on delete cascade,
vorl int references vorl(vorlnr),
prof int references prof(persnr) on delete set null,
note float,
primary key(Stud, vorl)
);
The field prof is a foreign key into the prof table. MySQL will require that this field references a professor which actually exists. It does not in the case of your final insert. To get around this error, you could create such a professor, e.g.
insert into Prof values
(4, 'M');
You didn't report an error in your question, which seems off to me. Maybe you failed to mention it, or perhaps your error reporting is turned off for some reason.

Msg 2627 Violation of PRIMARY KEY constraint

trying to make a database for teams in a tv show here.
but when I try and insert data into tblShowteam
the following error made its appearance.
Msg 2627, Level 14, State 1, Line 2
Violation of PRIMARY KEY constraint 'PK__tblShowt__F693078C03317E3D'. Cannot insert duplicate key in object 'dbo.tblShowteam'.
tables
-- tabbellen aanmaken
create table tblShow(
setId int,
Datum date,
teams int
primary key (setId));
create table tblShowteam(
SetId int,
datum date,
teams int,
primary key (teams));
create table tblTeam(
TeamId int,
Coach varchar(35),
CoachId int,
teams int
primary key (CoachId));
-- participant table
create table tblDeelnemer(
DeelnemerId int identity(1, 1),
DeelnemerV varchar(35),
deelnemerT_V varchar(10),
DeelnemerA varchar(35),
CoachId int,
datum_optreden date
primary key (DeelnemerId));
--table for the public viewers
create table tblKijker(
Kijkerv varchar(35),
KijkerT_V varchar(10),
KijkerA varchar(35),
Stoelnummer int identity(1,3),
ShowId int Not null,
Email varchar(35)
primary key (Email));
my inserts would look like this:
insert into tblShowteam values (1, '2014-06-28', 1)
insert into tblShowteam values (2, '2014-06-05', 1)
insert into tblShowteam values (3, '2014-06-12', 1)
insert into tblShowteam values (4, '2014-06-19', 1)
insert into tblShowteam values (5, '2014-06-26', 1)
all other inserts (in diffrent tables) work like normal.
what am i doing wrong here?
your problem is here
primary key (teams));
i guess you have to do it like that
primary key (setId));
like that:
create table tblShowteam(
SetId int,
datum date,
teams int,
primary key (setId));
because you are inserting same teams 1 while you are using teams as primary key which means no duplicates.
your inserts:
insert into tblShowteam values (1, '2014-06-28', 1)
insert into tblShowteam values (2, '2014-06-05', 1)
...
DB translate it like this:
insert into tblShowteam (SetId, datum, teams) values (1, '2014-06-28', 1);
cause the third column is your primary key, you got this error.

Aggregate Query depending on several tables

I want to create a database with information of employees, their jobs, salaries and projects
I want to keep information of the cost of a project (real value of project and the days a employee invested)
For employee and project each Employee has one role on the Project through the PK constraint, and allows for the addition of a new role type ("Tertiary" perhaps) in the future.
CREATE TABLE Employee(
EmployeeID INTEGER NOT NULL PRIMARY KEY,
Name VARCHAR(30) NOT NULL,
Sex CHAR(1) NOT NULL,
Address VARCHAR(80) NOT NULL,
Security VARCHAR(15) NOT NULL,
DeptID INTEGER NOT NULL,
JobID INTEGER NOT NULL
);
CREATE TABLE Departments (
DeptID INTEGER NOT NULL PRIMARY KEY,
DeptName VARCHAR(30) NOT NULL
);
CREATE TABLE Jobs (
JobID INTEGER NOT NULL PRIMARY KEY,
JobName VARCHAR(30) NOT NULL,
JobSalary DOUBLE(15,3) NOT NULL default '0.000',
JobSalaryperDay DOUBLE(15,3) NOT NULL default '0.000',
DeptID INTEGER NOT NULL
);
CREATE TABLE Project(
ProjectID INTEGER NOT NULL PRIMARY KEY,
ProjectDesc VARCHAR(200) NOT NULL,
StartDate DATE NOT NULL,
EndDate DATE NOT NULL,
DaysOfWork INTEGER NOT NULL,
NoEmployees INTEGER NOT NULL,
EstimatedCost DOUBLE(15,3) NOT NULL default '0.000',
RealCost DOUBLE(15,3) NOT NULL default '0.000'
);
CREATE TABLE `Project-Employee`(
ProjectID INTEGER NOT NULL,
EmployeeID INTEGER NOT NULL,
Note VARCHAR(200),
DaysWork INTEGER NOT NULL,
CONSTRAINT fk_ProjectID FOREIGN KEY (ProjectID) REFERENCES Project(ProjectID),
CONSTRAINT fk_EmployeeID FOREIGN KEY (EmployeeID) REFERENCES Employee(EmployeeID)
);
INSERT INTO `Departments` VALUES (1, 'Outsourcing');
INSERT INTO `Departments` VALUES (2, 'Technician');
INSERT INTO `Departments` VALUES (3, 'Administrative');
INSERT INTO `Jobs` VALUES (1, 'welder' ,500.550,16.7 ,2);
INSERT INTO `Jobs` VALUES (2, 'turner' ,500.100,16.67,2);
INSERT INTO `Jobs` VALUES (3, 'assistant' ,650.100,21.67,2);
INSERT INTO `Jobs` VALUES (4, 'supervisor',800.909,26.70,3);
INSERT INTO `Jobs` VALUES (5, 'manager' ,920.345,30.68,3);
INSERT INTO `Jobs` VALUES (6, 'counter' ,520.324,17.35,1);
INSERT INTO `Employee` VALUES (10, 'Joe', 'M', 'Anywhere', '927318344', 1, 3);
INSERT INTO `Employee` VALUES (20, 'Moe', 'M', 'Anywhere', '827318322', 2, 3);
INSERT INTO `Employee` VALUES (30, 'Jack', 'M', 'Anywhere', '927418343', 3, 4);
INSERT INTO `Employee` VALUES (40, 'Marge','F', 'Evererre', '127347645', 1, 6);
INSERT INTO `Employee` VALUES (50, 'Greg' ,'M', 'Portland', '134547633', 3, 5);
INSERT INTO `Project` VALUES (1, 'The very first', '2008-7-04' , '2008-7-24' , 20, 5, 3000.50, 2500.00);
INSERT INTO `Project` VALUES (2, 'Second one pro', '2008-8-01' , '2008-8-30' , 30, 5, 6000.40, 6100.40);
INSERT INTO `Project-Employee` VALUES (1, 10, 'Worked all days' , 20);
INSERT INTO `Project-Employee` VALUES (1, 20, 'Worked just in defs', 11);
INSERT INTO `Project-Employee` VALUES (1, 30, 'Worked just in defs', 17);
INSERT INTO `Project-Employee` VALUES (1, 40, 'Contability ' , 8);
INSERT INTO `Project-Employee` VALUES (1, 50, 'Managed the project', 8);
So to get the total amount of the cost of a project and have it for future Work quote I would just sum the working days of each job for each employee in an aggregate query.
What would be the query to sum all working days knowing the employees involved in a particular project to know the cost generated for their work, Is it possible to know this with this design?
So lets suppose I know that in project 1, 5 employees were involved, and I know by other table "jobs" the salary I would pay each one of them per day
I am doing some queries here with sqlfiddle
UPDATE
CREATE TABLE `Sexes` (
Sex char(1) primary key
);
INSERT INTO Sexes values ('M');
INSERT INTO Sexes values ('F');
CREATE TABLE `Employee`(
EmployeeID INTEGER NOT NULL PRIMARY KEY,
Name VARCHAR(130) NOT NULL,
Sex CHAR(1) NOT NULL,
Address VARCHAR(380) NOT NULL,
Security VARCHAR(15) NOT NULL,
FOREIGN KEY (Sex) references Sexes (Sex),
CONSTRAINT `uc_EmployeeInfo` UNIQUE (`EmployeeID`,`Name`,`Security`)
);
CREATE TABLE `Department` (
DeptID INTEGER NOT NULL PRIMARY KEY,
DeptName VARCHAR(30) NOT NULL,
CONSTRAINT `uc_DeptName` UNIQUE (`DeptID`,`DeptName`)
);
CREATE TABLE `Dept-Employee`(
EmployeeID INTEGER NOT NULL,
DeptID INTEGER NOT NULL,
CONSTRAINT fk_DeptID FOREIGN KEY (DeptID) REFERENCES `Department`(DeptID),
CONSTRAINT fk_EmployeeID FOREIGN KEY (EmployeeID) REFERENCES `Employee`(EmployeeID)
);
CREATE TABLE `Dept-Manager`(
EmployeeID INTEGER NOT NULL,
DeptID INTEGER NOT NULL,
CONSTRAINT fk_DeptIDs FOREIGN KEY (DeptID) REFERENCES `Department`(DeptID),
CONSTRAINT fk_EmployeeIDs FOREIGN KEY (EmployeeID) REFERENCES `Employee`(EmployeeID)
);
CREATE TABLE `Jobs` (
JobID INTEGER NOT NULL PRIMARY KEY,
JobName VARCHAR(30) NOT NULL,
JobSalary DECIMAL(7,3) NOT NULL default '0000.000',
JobSalaryperDay DECIMAL(7,3) NOT NULL default '0000.000',
CONSTRAINT `uc_jobs` UNIQUE (`JobID`,`JobName`)
);
CREATE TABLE `Jobs-Employee`(
EmployeeID INTEGER NOT NULL,
JobID INTEGER NOT NULL,
CONSTRAINT fk_JobIDs FOREIGN KEY (JobID) REFERENCES `Jobs`(JobID),
CONSTRAINT fk_EmployeeIDss FOREIGN KEY (EmployeeID) REFERENCES `Employee`(EmployeeID)
);
CREATE TABLE `Project`(
ProjectID INTEGER NOT NULL PRIMARY KEY,
ProjectName VARCHAR(200) NOT NULL,
StartDate DATE NOT NULL,
DaysOfWork INTEGER NOT NULL,
NoEmployees INTEGER NOT NULL,
EstimatedCost DECIMAL(9,3) NOT NULL default '000000.000',
RealCost DECIMAL(9,3) NOT NULL default '000000.000',
CONSTRAINT `uc_project` UNIQUE (`ProjectID`,`ProjectName`)
);
CREATE TABLE `Project-Employee`(
ProjectID INTEGER NOT NULL,
EmployeeID INTEGER NOT NULL,
Note VARCHAR(200),
DaysWork INTEGER NOT NULL,
CONSTRAINT fk_ProjectIDsss FOREIGN KEY (ProjectID) REFERENCES `Project`(ProjectID),
CONSTRAINT fk_EmployeeIDsss FOREIGN KEY (EmployeeID) REFERENCES `Employee`(EmployeeID)
);
INSERT INTO `Department` VALUES (1, 'Outsourcing');
INSERT INTO `Department` VALUES (2, 'Technician');
INSERT INTO `Department` VALUES (3, 'Administrative');
INSERT INTO `Jobs` VALUES (1, 'welder' ,500.550, 16.7 );
INSERT INTO `Jobs` VALUES (2, 'turner' ,500.100, 16.67);
INSERT INTO `Jobs` VALUES (3, 'assistant' ,650.100, 21.67);
INSERT INTO `Jobs` VALUES (4, 'supervisor',800.909, 26.70);
INSERT INTO `Jobs` VALUES (5, 'manager' ,920.345, 30.68);
INSERT INTO `Jobs` VALUES (6, 'counter' ,520.324, 17.35);
INSERT INTO `Employee` VALUES (10, 'Joe', 'M', 'Joewhere', '927318344');
INSERT INTO `Employee` VALUES (20, 'Moe', 'M', 'Moewhere', '827318322');
INSERT INTO `Employee` VALUES (30, 'Jack', 'M', 'Jaswhere', '927418343');
INSERT INTO `Employee` VALUES (40, 'Marge','F', 'Evererre', '127347645');
INSERT INTO `Employee` VALUES (50, 'Greg' ,'M', 'Portland', '134547633');
INSERT INTO `Dept-Employee` VALUES (10,1);
INSERT INTO `Dept-Employee` VALUES (20,2);
INSERT INTO `Dept-Employee` VALUES (30,3);
INSERT INTO `Dept-Employee` VALUES (40,1);
INSERT INTO `Dept-Employee` VALUES (50,3);
INSERT INTO `Jobs-Employee` VALUES (10,3);
INSERT INTO `Jobs-Employee` VALUES (20,3);
INSERT INTO `Jobs-Employee` VALUES (30,4);
INSERT INTO `Jobs-Employee` VALUES (40,6);
INSERT INTO `Jobs-Employee` VALUES (50,5);
INSERT INTO `Project` VALUES (1, 'The very first', '2008-7-04' , 20, 5, 3000.50, 2500.00);
INSERT INTO `Project` VALUES (2, 'Second one pro', '2008-8-01' , 30, 5, 6000.40, 6100.40);
INSERT INTO `Project-Employee` VALUES (1, 10, 'Worked all days' , 20);
INSERT INTO `Project-Employee` VALUES (1, 20, 'Worked just in defs', 11);
INSERT INTO `Project-Employee` VALUES (1, 30, 'Worked just in defs', 17);
INSERT INTO `Project-Employee` VALUES (1, 40, 'Contability ' , 8);
INSERT INTO `Project-Employee` VALUES (1, 50, 'Managed the project', 8);
To the new structure I did this
CREATE VIEW `Emp-Job` as
SELECT e.*,j.jobID
FROM Employee e,`Jobs-Employee` j
WHERE e.EmployeeID = j.EmployeeID;
CREATE VIEW `employee_pay` as
select e.*, j.jobname, j.jobsalary, j.jobsalaryperday
from `Emp-Job` e
inner join `Jobs` j
on e.JobID = j.JobID;
create view project_pay as
select pe.projectid, pe.employeeid, pe.dayswork,
e.jobsalaryperday, (e.jobsalaryperday * dayswork) as total_salary
from `Project-Employee` pe
inner join `employee_pay` e
on e.employeeid = pe.employeeid
The data at the end of your question doesn't seem to match the data in your INSERT statements.
Have you ever heard of "divide and conquer"? This is a good time to use it. Here's what I'd do.
create view employee_pay as
select e.*, j.jobname, j.jobsalary, j.jobsalaryperday
from employee e
inner join jobs j on e.jobid = j.jobid
create view project_pay as
select pe.projectid, pe.employeeid, pe.dayswork,
e.jobsalaryperday, (e.jobsalaryperday * dayswork) as total_salary
from project_employee pe
inner join employee_pay e
on e.employeeid = pe.employeeid
I'd do that, because I expect those views to be generally useful. (Especially for debugging.) Having created those views, the total for a project is dead simple.
select projectid, sum(total_salary) as total_salaries
from project_pay
group by projectid
projectid total_salaries
--
1 1509.91
You really don't want to use DOUBLE for money. Use DECIMAL instead.
Use this query to sort out why my sum doesn't match yours.
select p.*, e.name
from project_pay p
inner join employee e on e.employeeid = p.employeeid;
projectid employeeid dayswork jobsalaryperday total_salary name
1 10 20 21.67 433.4 Joe
1 20 11 21.67 238.37 Moe
1 30 17 26.7 453.9 Jack
1 40 8 17.35 138.8 Marge
1 50 8 30.68 245.44 Greg
Anti-patterns
Broken identity
Whenever you see a table like this one
CREATE TABLE Departments (
DeptID INTEGER NOT NULL PRIMARY KEY,
DeptName VARCHAR(30) NOT NULL
);
you should assume its structure is wrong, and dig deeper. (It's presumed guilty until proven innocent.) The anti-pattern you look for
integer as an artificial primary key, along with
no other unique constraints.
A table like this allows the real data to be duplicated, eliminating the usefulness of an artificial key.
DeptID DeptName
--
1 Wibble
2 Wibble
...
175 Wibble
A table like this will allow multiple foreign key references, too. That means some of the foreign keys might reference Wibble (DeptID = 1), some might reference Wibble (DeptID = 175), and so on.
To fix that, add a UNIQUE constraint on DeptName.
Missing foreign key references
Whenever you see a table like this one
CREATE TABLE Employee(
EmployeeID INTEGER NOT NULL PRIMARY KEY,
Name VARCHAR(30) NOT NULL,
...
DeptID INTEGER NOT NULL,
JobID INTEGER NOT NULL
);
you should assume its structure is wrong, and dig deeper. (Again, it's presumed guilty until proven innocent.) The anti-pattern you look for
ID numbers from other tables, along with
no foreign key constraints referencing those tables.
To fix that, add foreign key constraints for DeptID and JobID. On MySQL, make sure you're using the INNODB engine, too. (As of MySQL 5.6, MyISAM still won't enforce foreign key constraints, but it won't give you an error or warning if you write them. They're parsed and ignored.)
If you come to MySQL from another dbms, you'll be surprised to find that MySQL doesn't support inline foreign key reference syntax. That means you can't write this.
DeptID integer not null references Departments (DeptID)
Instead, you have to write a separate foreign key clause in the CREATE TABLE statement. (Or use a separate ALTER TABLE statement to declare the FK reference.)
DeptID integer not null,
foreign key (DeptID) references Departments (DeptID)
Search this page for "inline ref", but read the whole thing.
Missing CHECK() constraints
MySQL doesn't enforce CHECK() constraints, so for columns that beg for a CHECK() constraint, you need a table and a foreign key reference. When you see a structure like this
CREATE TABLE Employee(
EmployeeID INTEGER NOT NULL PRIMARY KEY,
Name VARCHAR(30) NOT NULL,
Sex CHAR(1) NOT NULL,
the column "Sex" begs for a CHECK() constraint.
CREATE TABLE Employee(
EmployeeID INTEGER NOT NULL PRIMARY KEY,
Name VARCHAR(30) NOT NULL,
Sex CHAR(1) NOT NULL CHECK( Sex IN ('M', 'F')),
But MySQL doesn't enforce CHECK() constraints, so you need another table and a foreign key reference.
create table sexes (
sex char(1) primary key
);
insert into sexes values ('M');
insert into sexes values ('F');
CREATE TABLE Employee(
EmployeeID INTEGER NOT NULL PRIMARY KEY,
Name VARCHAR(30) NOT NULL,
Sex CHAR(1) NOT NULL,
...
foreign key (Sex) references Sexes (Sex)
I'd consider CHECK() constraints for most of these columns. Some can be implemented as tables with foreign key references.
Employee.Security
Jobs.JobSalary
Jobs.JobSalaryperDay
Project.DaysOfWork
Project.NoEmployees
Project.EstimatedCost
Project.RealCost
Project_Employee.DaysWork
Using floating-point data types for money
Don't do that. Floating-point numbers are useful approximations, but they're still approximations. Use DECIMAL instead.