I have a table with a timestamp column in it and I want to select any rows of any date where the time is 00:00:00
Is there a better way to do this other than filtering on the last 8 characters as a substring?
Use the TIME() function.
WHERE TIME(yourfield) = '00:00:00'
Related
I get a datetime field, that's currently in the query as:
SELECT DATE_FORMAT(x.date_entered, '%Y-%m-%d') AS date FROM x ORDER BY date ASC
What I want to do is to subtract 3 hours from that date (GMT issues), but I can't do it in PHP as PHP only knows the date part, not the time.
mySQL has DATE_SUB():
SELECT DATE_SUB(column, INTERVAL 3 HOUR)....
but would it not be better to try and sort out the underlying time zone issue instead?
Assuming you have some timezone issue and know source and destination timezone, you could convert it like so
SELECT DATE_FORMAT(CONVERT_TZ(x.date_entered, 'UTC', 'Europe/Berlin'),
'%Y-%m-%d') AS date
FROM x ORDER BY date ASC;
Normal select query.
Once applied DATE_ADD() function in MySQL
select lastname,
date_add(changedat, interval -24 hour) as newdate
from employee_audit;
lastname and changedat is field name and employee_audit is table name.
I am building out a query to search a table by a timestamp column value. An example of the format I am passing to the api is 2018-10-10. The user has the ability to select a date range. Often times the date range start date is 2018-10-10 and end date is the same day, 2018-10-10. The below doesn't seem to do the trick. What is the simplest way to accomplish this without having to specify the time? Obviously, I'd like to query for the entire day of 2018-10-10 from start to end of day.
SELECT
count(*)
FROM
contact
WHERE
created_at >= '2018-10-10'
AND created_at <= '2018-10-10';
The problem here is that Timestamp datatype will have HH:MM:SS (time) values also. While comparing a datetime with date, MySQL would automatically assume 00:00:00 as HH:MM:SS for the date value.
So, 2018-10-10 12:23:22 will not match the following condition: created_at <= '2018-10-10'; since it would be treated as: 2018-10-10 12:23:22 <= '2018-10-10 00:00:00, which is false
To handle this, you can add one day to the date (date_to in the filter), and use < operator for range checking.
SELECT
count(*)
FROM
contact
WHERE
created_at >= '2018-10-10'
AND created_at < ('2018-10-10' + INTERVAL 1 DAY);
I want to select records of 5 days ago with mysql, but the problem is that my date column is varchar and in the following format yyyy-mm-dd 00:00:00 AM/PM.
How can I convert this date format to mysql date and select records from 5 days back?
my date column name is 'date_time'
This is a job for STR_TO_DATE().
Try this.
... WHERE DATE(STR_TO_DATE(date_time,'%Y-%m-%d %h:%i:%s %p')) = CURDATE() - INTERVAL 5 DAY
The '%Y-%m-%d %h:%i:%s %p' DATE_FORMAT() string matches your textual date format.
This will never be fast if you have to search through a large number of rows, because it isn't sargable. It can't exploit an index.
I have a field in my table called created_date. The date format is 2010-02-28. I just wondering is it possible to do a mysql statement, only return the day instead of the entire date. eg. 28
SELECT
day(created_date)
FROM
table
This above query throw me error, is there a way i can do similar stuff?
cheers
Use MySQL built-in function called DAYOFMONTH
mysql> SELECT DAYOFMONTH('2007-02-03');
-> 3
DAYOFMONTH()
From Docs,
Returns the day of the month for date, in the range 1 to 31, or 0 for
dates such as '0000-00-00' or '2008-00-00' that have a zero day part.
MySql EXTRACT function extracts day, month or year from a given date.
select extract(day from created_date) as created_day from table
you can fetch the whole date in your format and display only the required field that is date by using this
date("j", strtotime(date('Y-m-d')) );
I am trying to select records from a database only if they match today's date. The format for the date in the database is 2012-06-20 9:30:00 I am using the statement SELECT id FROMnewsreportsWHERE DATE(newsdate) = CURDATE() but it doesn't not return any records for today?
Screenshot of column with dates
http://img135.imageshack.us/img135/8399/2347f03df0394cd898c7fc5.png
DATE_FORMAT(NOW(),'%Y-%m-%d') = FORMAT_DATE(NOW(newsdate), '%Y-%m-%d')
Or better:
DATE(newsdate) = DATE(NOW())
The best way is to store the additional column with 2001-09-11 date format and compare this one
Example, thanks to #Conrad Frix
It looks like the curdate function is going to give you something different than the date format you've got in the database.
Take a look at the docs here
MySQL Date and Time Functions
It's supposed to return a date in this format:
2008-11-11
So, you could either search for a date range between curdate() and curdate() + INTERVAL 1 DAY (untested), or store the dates in the curdate() format.