Group by with text and date time combination - sql-server-2008

Question

I have a table
id col1 col2 namecol1 datetime1 teamcol1 namecol2 datetime2
1 12345 2345 name1 2014-10-13 11:57:24.713 teama
2 12345 2345 name1 2014-10-13 11:57:24.713 teamb abc 2014-11-29 09:55:38.533
3 12345 2345 name1 2014-10-13 11:57:24.713 teamb bcd 2014-12-02 06:35:38.917
4 12345 2345 name1 2014-10-13 11:57:24.713 teamc def 2014-12-22 11:57:54.863
5 12345 2345 name1 2014-10-13 11:57:24.713 teamd efg 2015-01-03 13:28:24.717
I need this output:
col1 col2 Team1 DateTime1 Team2 DateTime2 Team3 DateTime3
12345 2345 bcd 2014-12-02 06:35:38.917 def 2014-12-22 11:57:54.863 efg 2015-01-03 13:28:24.717
I tried this query:
SELECT
MAX(CASE WHEN teamcol1='teamb' THEN namecol2 END) AS Team1,
CONVERT(DATE, MAX(CASE WHEN teamcol1='teamb' THEN datetime2 END), 105) AS DateTime1,
MAX(CASE WHEN teamcol1='teamc' THEN namecol2 END) AS PRECON_AUDIT,
CONVERT(DATE,MAX(CASE WHEN teamcol1='teamc' THEN datetime2 END), 105) AS DateTime2,
MAX(CASE WHEN teamcol1 IN ('teamd') THEN namecol2 END) AS Team3,
CONVERT(DATE,MAX(CASE WHEN teamcol1 IN ('teamd') THEN datetime2 END),105) AS DateTime3,
col1, col2
FROM
(SELECT *
FROM table1) Z
WHERE
col1 = '12345'
GROUP BY
col1, col2
Output of this query:
col1 col2 Team1 DateTime1 Team2 DateTime2 Team3 DateTime3
12345 2345 abc 2014-12-02 06:35:38.917 def 2014-12-22 11:57:54.863 efg 2015-01-03 13:28:24.717
I am using SQL Server 2008.
Thanks in advance.
[EDIT]
Table1 is like audit table which will have multiple entries with different combination of col1,col2.
I need to display for each combination of col1,col2 different team names and with appropriate namecol2 and datetime2 columns.
When i use the query mentioned above it is giving me the output correctly if there is no repetition in teamcol1. If there is a repetition in teamcol1 (as mentioned in question) it is giving me the wrong namecol2.
In case of repetition in teamcol1 i need latest namecol2 and datetime2 ( from the table i need namecol2 -- bcd and datetime2 -- 2014-12-02 06:35:38.917)

Answer 1

At first make a list of all groups (DISTINCT col1, col2).
Then for each group find one row with the latest datetime2. Do it three times, for each teamb, teamc, teamd.
You can put complex query inside OUTER APPLY with whatever logic and ordering you need.
DECLARE #T TABLE (id int, col1 int, col2 int, namecol1 varchar(255), [datetime1] datetime, teamcol1 varchar(255), namecol2 varchar(255), [datetime2] datetime);
INSERT INTO #T (id, col1, col2, namecol1, datetime1, teamcol1, namecol2, datetime2) VALUES (1, 12345, 2345, 'name1', '2014-10-13 11:57:24.713', 'teama', NULL, NULL);
INSERT INTO #T (id, col1, col2, namecol1, datetime1, teamcol1, namecol2, datetime2) VALUES (2, 12345, 2345, 'name1', '2014-10-13 11:57:24.713', 'teamb', 'abc', '2014-11-29 09:55:38.533');
INSERT INTO #T (id, col1, col2, namecol1, datetime1, teamcol1, namecol2, datetime2) VALUES (3, 12345, 2345, 'name1', '2014-10-13 11:57:24.713', 'teamb', 'bcd', '2014-12-02 06:35:38.917');
INSERT INTO #T (id, col1, col2, namecol1, datetime1, teamcol1, namecol2, datetime2) VALUES (4, 12345, 2345, 'name1', '2014-10-13 11:57:24.713', 'teamc', 'def', '2014-12-22 11:57:54.863');
INSERT INTO #T (id, col1, col2, namecol1, datetime1, teamcol1, namecol2, datetime2) VALUES (5, 12345, 2345, 'name1', '2014-10-13 11:57:24.713', 'teamd', 'efg', '2015-01-03 13:28:24.717');
WITH
CTE_Groups
AS
(
SELECT DISTINCT col1, col2
FROM #T
)
SELECT *
FROM
CTE_Groups
OUTER APPLY
(
SELECT TOP(1)
TT.namecol2 AS Team1
, TT.[datetime2] AS DateTime1
FROM #T AS TT
WHERE
TT.teamcol1 = 'teamb'
AND TT.col1 = CTE_Groups.col1
AND TT.col2 = CTE_Groups.col2
ORDER BY TT.[datetime2] DESC
) OA_teamb
OUTER APPLY
(
SELECT TOP(1)
TT.namecol2 AS Team2
, TT.[datetime2] AS DateTime2
FROM #T AS TT
WHERE
TT.teamcol1 = 'teamc'
AND TT.col1 = CTE_Groups.col1
AND TT.col2 = CTE_Groups.col2
ORDER BY TT.[datetime2] DESC
) OA_teamc
OUTER APPLY
(
SELECT TOP(1)
TT.namecol2 AS Team3
, TT.[datetime2] AS DateTime3
FROM #T AS TT
WHERE
TT.teamcol1 = 'teamd'
AND TT.col1 = CTE_Groups.col1
AND TT.col2 = CTE_Groups.col2
ORDER BY TT.[datetime2] DESC
) OA_teamd
Result set:
col1 col2 Team1 DateTime1 Team2 DateTime2 Team3 DateTime3
12345 2345 bcd 2014-12-02 06:35:38.917 def 2014-12-22 11:57:54.863 efg 2015-01-03 13:28:24.717
If there is no teamb for a certain combination of col1 and col2, there will be NULLs in Team1 and DateTime1. Same for teamc and teamd.